C實驗報告-實驗4繼承與派生

1、實驗4 繼承與派生一、實驗?zāi)康暮鸵螅?）掌握派生類的定義方法和派生類構(gòu)造函數(shù)的定義方法。（2）掌握不同繼承方式的情況下，基類成員在派生類中的訪問權(quán)限。（3）掌握在多繼承方式的情況下，構(gòu)造函數(shù)與析構(gòu)函數(shù)的調(diào)用時機與順序。二、實驗內(nèi)容和原理（1）實驗指導書P86 12任選一題。（2）實驗指導書P89 34任選一題。三、實驗環(huán)境聯(lián)想計算機，Windows XP操作系統(tǒng)，Visual C+ 6.0四、算法描述及實驗步驟（1）輸入源程序。（2）檢查程序有無錯誤(包括語法錯誤和邏輯錯誤)，有則改之。（3）編譯和連接，仔細分析編譯信息，如有錯誤應(yīng)找出原因并改正之。（4）運行程序，分析結(jié)果，在原有程序得出正

2、確結(jié)果后，修改程序，將其改寫為在類模板外定義，再按第（3）步驟運行。（5）將調(diào)試好的程序保存在自己的用戶目錄中，文件名自定。五、調(diào)試過程（1）2（2）4六、實驗結(jié)果（1）2(2)4七、總結(jié)（1）掌握構(gòu)造函數(shù)和析構(gòu)函數(shù)的定義方法（2）構(gòu)造函數(shù)調(diào)用順序：先調(diào)用所有基類的構(gòu)造函數(shù)，然后調(diào)用派生類的構(gòu)造函數(shù)；（3）析構(gòu)函數(shù)調(diào)用順序：先調(diào)用派生類的析構(gòu)函數(shù)，然后調(diào)用基類的析構(gòu)函數(shù)，其順序正好與構(gòu)造函數(shù)調(diào)用順序相反。八、附錄：（1）代碼如下#includeusing namespace std;class Base1public:Base1()coutconstructing Base1endl;Base

3、1()coutdestructing Base1endl;class Base2public:Base2()coutconstructing Base2endl;Base2()coutdestructing Base2endl;class Derived1:public Base1,virtual public Base2public:Derived1()coutconstructing Derived1endl;Derived1()coutdestructing Derived1endl;class Derived2:public Base1,virtual public Base2publ

4、ic:Derived2()coutconstructing Derived2endl;Derived2()coutdestructing Derived2endl;class Derived3:public Derived1,virtual public Derived2public:Derived3()coutconstructing Derived3endl;Derived3()coutdestructing Derived3endl;int main()Derived3 obj;return 0;（2）4代碼如下#includeusing namespace std;const doub

5、le PI=3.14;class Shapepublic:double area()constreturn 0.0;void display();class TwoDimShape:virtual public Shape;class ThreeDimShape:virtual public Shape;class Circle:public TwoDimShapepublic:Circle(double myr)R=myr;double area()constreturn PI*R*R;void display()coutArea of circle is ;private:double R

6、;class Rectangle:public TwoDimShapepublic:Rectangle(double myl,double myw)L=myl;W=myw;double area()constreturn L*W;void display()coutArea of rectangle is;private:double L,W;class Cylinder:public ThreeDimShapepublic:Cylinder(double myr,double myh)R=myr;H=myh;double area()constreturn 2*PI*R*(H+R);void

7、 display()coutsuperficial area of cylinder is;private:double R,H;class Cube:public ThreeDimShapepublic:Cube(double myl,double myw,double myh)L=myl;W=myw;H=myh;double area()const return 2*(L*W+L*H+W*H);void display()coutSuperficial area of rectangularparallelepied is ;private:double L,W,H;int main()Circle c(3.0); double area(); area=c.area(); c.display(); coutareaendl; Rectangle rec(4.0,5.0); area=rec.area(); rec.display(); coutareaendl; Cylinder cy(3.0,4.0);