24個(gè)匯編實(shí)例小程序

1、24個(gè)匯編小程序題目列表：逆序輸出字符串“ BASED ADDRESSING ”從鍵盤上輸入兩個(gè)數(shù)，分別放到x, y單元，求出它們的和是編寫一段程序，要求在長度為10h的數(shù)組中，找出大于42h的無符號(hào)數(shù)的個(gè)數(shù)并存入地址為up開始區(qū)域，找出小于 42h的無符號(hào)數(shù)的個(gè)數(shù)并存入地址為down的開始區(qū)域鍵盤輸入一段字符串，其中小寫字母以大寫字母輸出，其他字符不變輸出從鍵盤上就收一個(gè)小寫字母，找出它的前導(dǎo)字符和后續(xù)字符，在順序顯示這三個(gè)字符把一個(gè)包含20個(gè)數(shù)據(jù)的數(shù)組 M分成兩組：正整數(shù)組P和負(fù)整數(shù)組N，分別把這兩個(gè)數(shù)組中 的數(shù)據(jù)的個(gè)數(shù)顯示出來求出首地址為data的100個(gè)字?jǐn)?shù)組中的最小偶數(shù)，并把它放在a

2、x中輸入兩船字符串string1和string2，并比較兩個(gè)字符串是否相等，相等就顯示"match”，否貝U顯示"no match”從鍵盤接收一個(gè)四位的十六進(jìn)制數(shù)，并在終端顯示與它等值的二進(jìn)制數(shù)從鍵盤輸入一系列以$為結(jié)束符的字符串，然后對(duì)其中的非數(shù)字字符計(jì)數(shù)，并顯示計(jì)數(shù)結(jié)果有一個(gè)首地址為 mem的100個(gè)字的數(shù)組，試編程序刪除數(shù)組中所有為零的項(xiàng)，并將后續(xù)項(xiàng)向前壓縮，最后將數(shù)組的剩余部分補(bǔ)上零從鍵盤上輸入一串字符（用回車鍵結(jié)束，使用10號(hào)功能調(diào)用）放在 string中，是編制一個(gè)程序測(cè)試字符串中是否存在數(shù)字。如有，則把cl的第五位置1,否則將該位置置 0在首地址為data的字

3、數(shù)組中，存放了 100h的16位字?jǐn)?shù)據(jù)，試編寫一個(gè)程序，求出平均值放在ax寄存器中，并求出數(shù)組中有多少個(gè)數(shù)小于此平均值，將結(jié)果放在bx寄存器中（f分別考慮有符號(hào)數(shù)、無符號(hào)數(shù)情況 ）一直數(shù)組A包含15個(gè)互不相等的整數(shù)，數(shù)組 B包含20個(gè)互不相等的整數(shù)。試編制一個(gè)程序，把既在 A中又在B中出現(xiàn)的整數(shù)存放于數(shù)組C中設(shè)在A、B和D單元中分別存放著三個(gè)數(shù)。若三個(gè)數(shù)都不是0,則求出三個(gè)數(shù)的和并存放在S單元，若其中有一個(gè)數(shù)為0，則把其它兩個(gè)單元也清零。請(qǐng)編寫此程序從鍵盤輸入一系列字符（以回車鍵結(jié)束），并按字母、數(shù)字和其他字符分類計(jì)數(shù)，最后顯示這三類的計(jì)數(shù)結(jié)果已定義兩個(gè)整數(shù)變量 A和B,試編寫程序完成以下功能

4、（1） 若兩個(gè)樹種有一個(gè)是奇數(shù)，則將奇數(shù)存入A中，偶數(shù)存入B中（2）若兩個(gè)數(shù)均為奇數(shù)，則將兩個(gè)數(shù)加 1后存回原變量（3）若兩個(gè)數(shù)均為偶數(shù)，則兩個(gè)變量均不變寫一段子程序skiplines，完成輸出空行的功能。空行的行數(shù)由用戶在主程序中通過鍵盤輸入， 并將行數(shù)放在ax寄存器中設(shè)有10個(gè)學(xué)生成績分別是 76, 69，84, 73, 88, 99, 63，100和80。試編寫一個(gè)子程序統(tǒng) 計(jì)60-69分，70-79分，80-89分，90-99分和100分的人數(shù)，并分別放到S6，S7，S8，S9,S10單元中編寫子程序嵌套結(jié)構(gòu)的程序，把整數(shù)分別用二進(jìn)制和八進(jìn)制顯示出來在D盤根目錄建立一個(gè)文件abc.tx

5、t，第一次向文件寫入“ 123456”六個(gè)字符，第二次增加“ abcdefg ”幾個(gè)字符從鍵盤上輸入文本文件：“d:temp.txt ”的內(nèi)容后，然后新建一個(gè)文件“d:temp2.txt ”，把前一個(gè)文件的所有內(nèi)容復(fù)制到后一個(gè)文件中從鍵盤上輸入一個(gè)十進(jìn)制數(shù)，以十六進(jìn)制數(shù)顯示出來。要求子程序用寄存器參數(shù)傳送方法試編制一個(gè)程序，把bx寄存器中的二進(jìn)制數(shù)用十六進(jìn)制數(shù)的形式在屏幕上顯示出來代碼:1逆序輸出字符串“ BASED ADDRESSINGs1tops1segme nt stack dw100label word;定義棧段s1dup;定義棧空間為100;top指向棧頂s2S2s3en dsseg

6、me ntdben ds;定義數(shù)據(jù)段s2'BASED ADDRESSING',*;定義字符串 ssegment;定義代碼段 s3assume cs:s3,ds:s2,ss:s1mai nproc mov mov leafarax,s1ss,axsp,top;棧初始化棧初始化movax,s2;數(shù)據(jù)段初始化一一movds,ax;數(shù)據(jù)段初始化movsi,151:movdl,ssi;dl獲取字符串s的最后一個(gè)（從零開始的第十movah,2;調(diào)用int 21h 2號(hào)功能輸出dl上的值int21hdecsi;寄存器減一，準(zhǔn)備獲取卜一個(gè)字符cmpsi,0jalmovah,4ch;終止int2

7、1hmai nen dps3en dsendmai n2從鍵盤上輸入兩個(gè)數(shù)，分別放到x,y單元，求出它們的和sisegme nt stackdw100hduptoplabel wordsien dss2segme nthidb'Please in put x:','$'提示輸入h2db'Please in put y:','$'提示輸入h3db'z=x+y:','$'提示輸出crlfdb0dh,0ah,24h;定義回車換行xdw?ydw?s2en dss3segme ntassumecs:s3,ds

8、:s2,ss:s3mai nprocfar;初始化ax,s1mov卜五個(gè)字符）mov leamovss,axsp,topax,s2movds,ax;初始化leadx,h1;int 21h 9號(hào)功能輸出“提示輸入x”的字符串movah,9int21hxorbx,bx;bx清零，即把bx置零ah,1;輸入一個(gè)字符int21hcmpal,0dh;判斷時(shí)候?yàn)椤盎剀嚒弊址鹙zexit1;如果是回車字符就跳轉(zhuǎn)到exit1cmpal,30h和30h （即字符0的asii值）比較jlexit1;如果輸入字符小于'0'，跳轉(zhuǎn)到exit1cmpal,39h和39h（即字符9的ascii值）比較jg

9、exit1;如果輸入字符大于 9，跳轉(zhuǎn)到exit1subal,30h;al減去30h,輸入字符轉(zhuǎn)化成數(shù)字（從這一行開始到后面的為輸入字符轉(zhuǎn)化為數(shù)字的處理方法）cbw;al擴(kuò)充為axxchgax,bxmovcx,10mulcxxchgax,bxaddbx,ax;sub al,30h開始到這一行為輸入字符轉(zhuǎn)化為數(shù)字的處理方j(luò)mpIn putX;把輸入的存于bx的放到x中add bx,axIn putX:movx,bxmovexitl:leadx,crlfmovah,9int21hleadx,h2movah,9int21hIn putY:movah,1int21hcmpal,0dhjzexit2cm

10、pal,30hjlexit2;和InputX類似，輸入yxorbx,bxcmpal,39hjgexit2subal,30hcbwxchgax,bxmovcx,10mulcxxchgax,bxaddbx,axjmpIn putYexit2: movy,bx;把輸入的存于bx的放到y(tǒng)中mov bx,xaddbx,y;此時(shí)bx為兩數(shù)加和leadx,crlfmovah,9int21Hleadx,h3movah,9int21hxor si,si mov ax,bxl4:movcl,10;把和連續(xù)除以divclmovdl,ahmovdh,0pushdxincsimov ah,0連要,不能漏寫;si清零，用

11、作計(jì)數(shù);把和放到ax上10知道和變?yōu)榱?，余?shù)依次進(jìn)棧cmp al,0jnz 1415:pop dxadd dl,30h movah,2int21hdec si cmpsi,0jnzl5;余數(shù)依次出棧;余數(shù)轉(zhuǎn)換為顯示的余數(shù)字符;輸入余數(shù)字符mov ah,4chmai ns3inten dp en ds end21Hmai n3是編寫一段程序,要求在長度為10的數(shù)組中，找出大于42h的無符號(hào)數(shù)的個(gè)數(shù)并存入地址為up開始區(qū)域,找出小于 42h的無符號(hào)數(shù)的個(gè)數(shù)并存入地址為down的開始區(qū)域，并分別顯示up、down數(shù)組的個(gè)數(shù)和數(shù)組內(nèi)的數(shù)字sisegme nt stackdw100hduptoplabe

12、l wordsien dss2segme nthi db'the numof up array and the up array are(pri nts in decimalism) :','$'h2 db'the numof dow n array and the dow n array are(pri nts in decimalism) :','$'crlfdbi0dh,0ah,24harraydb0,50h,11h,61h,22h,72h,33h,73h,41h,74h,'$'定義數(shù)組 arrayupdb1

13、0 dup(?);定義up數(shù)組dow ndb10 dup(?);定義 down 數(shù)組s2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axmovsi,0movdi,1movbp,1repeat: cmp arraysi,42h;把a(bǔ)rray數(shù)組中小于 42h的值放到down數(shù)組里，大于42h的值放到up數(shù)組里面jbdow narraymovdl,arraysimovupbp,dlincsicmpsi,10jzexit1incbpjmprepeatdow narra

14、y:movmovincdl,arraysidow n di,dlsiinccmp jzdisi,10exit2jmprepeatexit1:jmpexit2:subexitdi,1subbp,1dx,bpexit:mov便于后面的輸出結(jié)束;把分配好的up數(shù)組和down數(shù)組在其有效數(shù)字后面添加'$',movinc bpupO,dlmovmovmovupbp,'$'dx,didow n 0,dlinc dimovdow ndi,'$'movmovcl,10si,0lea dx,h1mov ah,9 int 21hPrin tUparray:cmp j

15、zmov al,upsicallupsi,'$' n extn ext:incjmpprintsiPrin tUparraylea dx,crlf mov ah,9 int 21hlea dx,h2int 21hxor si,siPrin tDow nArray:cmpdow nsi,'$'jz ate ndmov al,dow nsicall inc jmpprintsiPrin tDow nArrayprintprocnear;print為輸出十進(jìn)制輸出某個(gè)數(shù)的子程序movdi,0rediv:movah,0divclmovdl,ahmovdh,0pushdx

16、incdicmpal,0jnzredivbreak:popdxadddl,30hmovah,2int21hdecdicmpdi,0jnzbreakmovdl,''movah,2int21Hretprinten dpaten d:movah,4chint21Hmai nen dps3en dsend4鍵盤輸入一段字符串，其中小寫字母以大寫字母輸出，其他字符不變輸出sisegme nt stackdw100hduptoplabel words1en dss2segme nth1db'Please in put a stri ng:'h2db'The cha

17、nged stri ng iscrlfdb0dh,0ah,24htempdb?s2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axleadx,h1movah,9int21hmov si,0I:mov ah,1int 21hcmp al,0dh jz exit cmp al,'a' jlput in;把小寫字符變?yōu)榇髮懽址鹀mp al,'z' jgput insub al,20hputi n:mov tempsi,al;把字符放到t

18、emp數(shù)組里incsijmp lexit:leadx,crlf;輸出tmp數(shù)組mov int lea mov intah,9 21h dx,h2ah,9 21hincsimovtempsi,'$'leadx,tempmovah,9int21hmovah,4chint21Hmai nen dps3en dsendmai n5從鍵盤上就收一個(gè)小寫字母，找出它的前導(dǎo)字符和后續(xù)字符，在順序顯示這三個(gè)字符s1tops1segme nt stackdwlabel 、 en ds100hdupwords2segme nth1db'Please in put a lowercaseh2

19、db'The the three chars are:'crlfdb0dh,0ah,24hs2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axl:leadx,h1movah,9int21h I:,$,'$'mov ah,1int 21h cmp al,'a' jl lcmp al,'z' jg lmovcl,alleadx,crlfmovah,9int21Hlea dx,h2 mov ah,9 in

20、t 21hdecclmovdl,clmovah,2int21h;輸出前導(dǎo)字符movdl,''movah,2int21hincclmovdl,clmov ah,2int 21hmovdl,''movah,2int21hincclmovdl,clmovah,2int 21h;輸出該字符;輸出后導(dǎo)字符mov ah,4chint21Hmainendps3endsendmai n6把一個(gè)包含20個(gè)數(shù)據(jù)的數(shù)組M分成兩組：正整數(shù)組 P和負(fù)整數(shù)組N，分別把這兩個(gè)數(shù)組 中的數(shù)據(jù)的個(gè)數(shù)顯示出來dw100hduptoplabel wordsien dss2segme nthidb&#

21、39;the positive nu mber is: ','$'h2db'the n egative nu mber is: ','$'crlfdb0dh,0ah,24harray50h,-11h,61h,-22h,72h,-33h,73h,-41h,74h,21h,67h,-90h,73h,77h,-1h,-89h,-11h,61h,-22h,20h,'$s2en dss3segme ntassumecs:s3,ds:s2,ss:s3mainprocfarmovax,s1movss,axleasp,topmovax,s2mov

22、ds,axmovbx,0movsi,0l:movdx,arraysicmpdx,0jladdlow;有符號(hào)數(shù)比較用jladdsi,2cmpsi,40jzexitjmpladdlow: inc1bxaddsi,2cmpsi,40jzexitjmplexit:leadx,h2movah,9sisegme nt stackdwint21hmov callax,bx printleadx,crlfmovah,9int21hleadx,h1movah,9int21hmov ax,20subax,bxcallprintjmpate ndprintprocn earmovcl,10movsi,0repeat

23、: divclmovdl,ahadd dl,30hmovdh,0pushdxincsimov ah,0cmpal,0jnzrepeat12:popdxmovah,2int21hdecsicmpsi,0jnzl2retprinten dpate nd: movah,4chint21H;打印數(shù)字字符的子程序main endpen dsS3endmain 7打印輸出首地址為 data的20個(gè)字?jǐn)?shù)組中的最小偶數(shù)sisegme nt stackdw100hdup14:cmp jnl negdivmovax,0l4axclal,ah；如果是負(fù)數(shù)，則求補(bǔ)s1en dss2segme nth1db't

24、he min even nu mber is: ','$'crlfdb0dh,0ah,24hdatadw50,-11,61,-22,72,-33,73,-41,74,21,67,-90,73,77,-1s2en dss3segme ntassumecs:s3,ds:s2,ss:s1mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axmovbx,65534;bx存最小數(shù)，初始令最小值置為movmov cl,100mov dl,2si,012:movax,datasitop65534,-89,-11,61,-22,20,

25、'$'label wordmov ah,0div dlcmp ah,0jnz 11cmp bx,datasijl 11mov bx,datasi;比較最小值和數(shù)組中的每個(gè)數(shù);如果數(shù)組中的數(shù)大于最小值跳轉(zhuǎn)到11;如果數(shù)組中的數(shù)小于最小值則將其賦給最小值11:add si,2 cmp si,40 jz exit jmp 12exit:leadx,h1movah,9int21hcmpbx,0jnll5negbxmovdl,'-'movah,2int21h15:movax,bxcallprintjmpate ndprintprocn earmovcl,10movsi,0

26、repeat: divclmovadd dl,30hdl,ahmovdh,0pushdxincmov ah,0sicmpal,0jnzrepeat13:popdxmovah,2;調(diào)用子程序輸出最小值int dec cmp jnz21hsisi,013printret en dpate nd:movah,4chint21Hmai nen dps3en dsendmai n8輸入兩船字符串stringl和string2，并比較兩個(gè)字符串是否相等，相等就顯示“match”貝U顯示"no match”s1segme nt stackdw100hdup(?)toplabel words1en

27、dss2 segme nthldb'Please input the first stri ng: ','$'h2db'Please in put the sec ond stri ng: ','$'h3 db 'MATCH','$'h4 db 'NO MATCH','$'crlfdb0dh,0ah,24hstr1db50,?,50 dup('$')str2db50,?,50 dup('$')s2en dss3segme ntassum

28、ecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axlea dx,h1mov ah,9int 21hleadx,str1mov ah,0ahint21hleadx,crlfmov ah,9int21hleadx,h2int21hleadx,str2mov ah,0ahint21hleadx,crlfmov ah,9int21h12:I:I3:movcmp jnzmovmovcmp jnz inccmp jz jmpleamovintleamovintmovintdl,str1+1dl,str2+1si,2

29、dl,str1sidl,str2silsisi,50l3l2dx,h4ah,921hdx,h3ah,921hah,4ch21H;str1+1為strl實(shí)際的字符個(gè)數(shù);str2+1為str2實(shí)際的字符個(gè)數(shù);輸出不匹配信息;輸出匹配信息main endpen dsS3endmaindx,h19從鍵盤接收一個(gè)四位的十六進(jìn)制數(shù)，并在終端顯示與它等值的二進(jìn)制數(shù)dw100hduptoplabel words1en dss2segme nth1db'Please in put a hexadecimal nu mber: ','$h2db'The nu mber is pri

30、n ted in binary nu mber:tempdb17 dup('$')crlfdb0dh,0ah,24hs2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axsisegme nt stack','$'repeat: lea mov ah,9 int 21hmovmovbx,0cx,4n ewchar:;接收新字符movah,1int21hcmpal,30hjbrepeatcmpal,46hjgrepeatcmpa

31、l,39hjnbl1；如果輸入字符大于9跳到1111:12:subjmpal,30hl2cmpal,41hjbrepeat;如果輸入字符小于A，則輸入錯(cuò)誤，跳到subal,37h;輸入字符為AZ,故相應(yīng)地要減37hjmpl2cbw;l2為把輸入字符轉(zhuǎn)化為數(shù)值xchgax,bxmovdx,10hmuldxxchgax,bxaddbx,ax;loopn ewcharrepeatdec exemp ex,0 jnz15:13:14:n ewcharleadx,crlfmovah,9int21hleadx,h2int21hmovsi,0movcx,10hrolbx,1jcl3movtempsi,

32、9;O'jmpl4movtempsi,'1'incsiloopl5leadx,tempmovah,9int21hmovah,4chint21H；cx作計(jì)數(shù)器，即待會(huì)要循環(huán)16次;bx循環(huán)左移以為，最高位進(jìn)標(biāo)志位 ；若標(biāo)志位為1則跳轉(zhuǎn)到13mainen dpS3en dsendmain10從鍵盤輸入一系列以$為結(jié)束符的字符串，然后對(duì)其中的非數(shù)字字符計(jì)數(shù)，并顯示計(jì)數(shù)結(jié) 果sisegme nt stackdw100h duptoplabel wordsiendss2segme nthidb'Please input a stri ng: ','$

33、9;h2db'The nu mber of the chars that is not digit:','$'crlf db 0dh,0ah,24hs2endss3segme ntassume cs:s3,ds:s2,ss:s3mai nproc farmovax,s1movss,axleasp,topmovax,s2movds,axleadx,himov ah,9int 21hmovcx,0l2:mov ah,1int21hcmpal,'$'jzexitcmpal,30hjblcmpal,39hjnbljmpl2l:inc cxjmpl2exi

34、t:leadx,crlfmovah,9int21hleadx,h2int21hmovsi,0movbl,10movax,cx14:divblmovdl,ahmovdh,0pushdxincsimovah,0cmpal,0jnzl415:popdxadddl,30hmovah,2int21hdecsicmpsi,0jnzl5movah,4chint21Hmai ns3en dpen dsendmai n11.有一個(gè)首地址為 mem的10個(gè)字的數(shù)組，試編程序刪除數(shù)組中所有為零的項(xiàng)，并將后續(xù) 項(xiàng)向前壓縮，最后將數(shù)組的剩余部分補(bǔ)上零s1segme nt stackdw100hduptops1label

35、 worden dss2segme ntmemdw0,1,030,0,4,5,6,0,'$'crlfdb0dh,0ah,24hs2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axmov si,0mov di,2repeat: cmp di,20jz exitmov bx,memsimov dx,memdicmp bx,0jnz n extxchg bx,dxmov memsi,bxmov memdi,dxn ext:cmp memsi,0jz l

36、add si,2I:add di,2jmp repeatexit:mov ah,4chint21Hmainendps3endsendmai n;以下是該算法描述淀義兩個(gè)指針，當(dāng)前指針si和檢查指針di,先把si指針指向第一個(gè)字得到的值bx,;di指向第二個(gè)字得到的值dx。若bx為0，di自加2，否則，則交換這兩字，;若此時(shí)si指向字為0，則di,否則，di，si都自己加2。如此循環(huán)直到 di指向最后一個(gè)字。 ;這樣就把所有非零字至于前面了。12.從鍵盤上輸入一串字符（用回車鍵結(jié)束，使用 10號(hào)功能調(diào)用）放在 string中，是編制一個(gè)程序測(cè)試字符串中是否存在數(shù)字。如有，則把cl的第五位置1，否

37、則將該位置置 0dw100hduptoplabel words1en dss2segme nth1db'Please in put a stri ngh2db'cx: ','$'crlfdb0dh,0ah,24hstri ngdb50,?,50 dup('$')s2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axsisegme nt stack I:,$and cl,0dfh;先假設(shè)無數(shù)字，置 0lea d

38、x,h1mov ah,9int 21hlea dx,stri ngmov ah,10dint 21hmov si,212: cmp stri ngsi,'$'jz exitmov dl,stri ngsicmp dl,30hjb lcmp dl,39hjnb lor cl,20h ;有數(shù)字，置1jmp exit1:inc sijmp 12exit:leadx,crlfmovah,9int21hleadx,h2int21hmovax,cxcallprintjmpate ndprintprocn earmovcl,10movsi,0repeat: divclmovdl,ahadd

39、dl,30hmovdh,0pushdxincsimov ah,0cmpal,0jnzrepeat13:popdxmovah,2int21hdecsicmpsi,0jnzl3retprinten dpate nd: movah,4chint21Hmainen dps3en dsendmai n13.在首地址為data的字?jǐn)?shù)組中，存放了 10個(gè)16位字?jǐn)?shù)據(jù)，試編寫一個(gè)程序，求出平均值 放在ax寄存器中，并求出數(shù)組中有多少個(gè)數(shù)小于此平均值，將結(jié)果放在bx寄存器中（f分別考慮有符號(hào)數(shù)、無符號(hào)數(shù)情況）sisegme nt stackdw100hduptoplabel words1en dss2segme

40、 ntdatadw-1,0,1,-2,2,3,-3,-4,4,15,'$crlfdb0dh,0ah,24hs2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axmov si,0mov ax,013: cmp datasi,'$' jz exit mov dx,datasi cmp dx,0 jnl 11 neg dx sub ax,dx jmp l2l1: add ax,dxl2:add si,2jmp l3exit:mov cl,10;平

41、均值放到ax中div clmov ah,0mov si,0movbx,015:cmpdatasi,'$'小于平均值的數(shù)的個(gè)數(shù)放到bx中jzexit2cmpax,datasijzl6jll6incbx16:addsi,2jmpl5exit2:movah,4chint21Hmai nen dps3en dsendmai n14. 一直數(shù)組A包含15個(gè)互不相等的整數(shù)，數(shù)組B包含20個(gè)互不相等的整數(shù)。試編制一個(gè)程序，把既在 A中又在B中出現(xiàn)的整數(shù)存放于數(shù)組C中并顯示C中的數(shù)值;兩層循環(huán)比較得出兩個(gè)數(shù)組中相同的數(shù)值sisegme nt stackdw100hduptoplabel wor

42、ds1endss2segme ntdwadw1h,2h,3h,4h,5h,6h,7h,8h,9h,10h,11h,12h,13h,14h,15h,'$'b21h,22h,23h,24h,25h,6h,18h,19h,10h,11h,12h,34h,14h,53h,31h,32h,33h,36h,7h,67h,'$' c dw 16 dup('$')crlfs2dben ds0dh,0ah,24hs3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s

43、2movds,axmov si,0mov di,0 mov bp,014: cmp di,40jz 12 jmp 1312: add si,2cmp si,30 jz exit mov di,0l3: mov ax,asimov bx,bdi cmp ax,bx jnz l mov cbp,ax add bp,2l:add di,2jmp l4exit:mov bp,016: cmp cbp,'$' jzate ndmov ax,cbp call print add bp,2 mov dl,'' mov ah,2 int 21h jmp l6print proc

44、n earmovcl,10movsi,0repeat: div clmovdl,ahadd dl,30h mov dh,0 push dx inc simov ah,0cmpal,0jnzrepeat15:pop dxmovah,2int21hdecsicmpsi,0jnzl5retprint endpate nd:movah,4chint21Hmainendps3endsend mai n15.設(shè)在A、B和D單元中分別存放著三個(gè)數(shù)。若三個(gè)數(shù)都不是0,則求出三個(gè)數(shù)的和并存放在S單元，若其中有一個(gè)數(shù)為0,則把其它兩個(gè)單元也清零。請(qǐng)編寫此程序s1segme nt stackdw100h dup(?

45、)toplabel words1en dss2segme ntadw1h,'$'bdw-11h,'$'d dw0h,'$'s dw2 dup('$')crlfdb0dh,0ah,24hs2en dss3segme ntassumecs:s3,ds:s2,ss:s3mai nprocfarmovax,s1movss,axleasp,topmovax,s2movds,axmov ax,a0mov bx,bOmov dx,dOcmp ax,0jz lcmp bx,0jz lcmp dx,0jz lmov cx,0cmp ax,0jnl add_axneg ax ;