新高考數(shù)學一輪復習講與練第11講 三角函數(shù)的圖像與性質（練）（原卷版）

第01講三角函數(shù)的圖像與性質一、單選題1．若SKIPIF1<0在SKIPIF1<0是增函數(shù)，則a的最大值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內存在最小值，則SKIPIF1<0的值可以是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．下列有關命題的說法正確的是（

）A．若集合SKIPIF1<0中只有兩個子集，則SKIPIF1<0B．SKIPIF1<0的增區(qū)間為SKIPIF1<0C．若SKIPIF1<0終邊上有一點SKIPIF1<0，則SKIPIF1<0D．函數(shù)SKIPIF1<0是周期函數(shù)，最小正周期是SKIPIF1<05．已知函數(shù)SKIPIF1<0在SKIPIF1<0上是單調函數(shù)，其圖象的一條對稱軸方程為SKIPIF1<0，則SKIPIF1<0的值可能是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．SKIPIF1<06．設函數(shù)SKIPIF1<0(其中SKIPIF1<0的大致圖象如圖所示，則SKIPIF1<0的最小正周期為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0的最大值為3，最小值為1B．SKIPIF1<0的最大值為3，最小值為-1C．SKIPIF1<0的最大值為SKIPIF1<0，最小值為SKIPIF1<0D．SKIPIF1<0的最大值為SKIPIF1<0，最小值為SKIPIF1<0二、填空題8．已知函數(shù)SKIPIF1<0，若SKIPIF1<0對任意實數(shù)x都成立，則SKIPIF1<0的一個取值為____________．9．已知函數(shù)SKIPIF1<0圖象的一部分如圖所示，則SKIPIF1<0SKIPIF1<0____________．10．已知SKIPIF1<0是奇函數(shù)，則SKIPIF1<0的值為______．三、解答題11．已知函數(shù)SKIPIF1<0，SKIPIF1<0為奇函數(shù)，且其圖象上相鄰的一個最高點與一個最低點之間的距離為SKIPIF1<0．(1)求SKIPIF1<0的解析式；(2)若已知三點坐標SKIPIF1<0，SKIPIF1<0，SKIPIF1<0．若SKIPIF1<0，且SKIPIF1<0，求SKIPIF1<0的值．一、單選題1．已知SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個單位，得到函數(shù)SKIPIF1<0的圖象，則SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．03．已知SKIPIF1<0，其部分圖象如圖所示，則SKIPIF1<0的解析式為A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．函數(shù)SKIPIF1<0的圖像向左平移SKIPIF1<0個單位長度后對應的函數(shù)是奇函數(shù)，函數(shù)SKIPIF1<0．若關于SKIPIF1<0的方程SKIPIF1<0在SKIPIF1<0內有兩個不同的解SKIPIF1<0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．如果函數(shù)SKIPIF1<0的圖像關于點SKIPIF1<0對稱，則SKIPIF1<0的最小值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．函數(shù)SKIPIF1<0圖像上一點SKIPIF1<0向右平移SKIPIF1<0個單位，得到的點SKIPIF1<0也在SKIPIF1<0圖像上，線段SKIPIF1<0與函數(shù)SKIPIF1<0的圖像有5個交點，且滿足SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0與SKIPIF1<0有兩個交點，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．三個數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小關系是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0二、填空題8．函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個單位得到函數(shù)SKIPIF1<0的圖象，則下列函數(shù)SKIPIF1<0的結論：①一條對稱軸方程為SKIPIF1<0；②點SKIPIF1<0是對稱中心；③在區(qū)間SKIPIF1<0上為單調增函數(shù)；④函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0.其中所有正確的結論為______.（寫出正確結論的序號）9．已知平面向量SKIPIF1<0，SKIPIF1<0，若函數(shù)SKIPIF1<0在SKIPIF1<0上是單調遞增函數(shù)，則SKIPIF1<0的取值范圍為______．10．已知函數(shù)SKIPIF1<0的部分圖像如圖所示，則滿足條件SKIPIF1<0的最小正整數(shù)x為________．三、解答題11．已知函數(shù)SKIPIF1<0的最小正周期為SKIPIF1<0，且SKIPIF1<0.（1）求SKIPIF1<0和SKIPIF1<0的值.（2）將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個單位長度(縱坐標不變)，得到函數(shù)SKIPIF1<0的圖象，①求函數(shù)SKIPIF1<0的單調遞增區(qū)間；②求函數(shù)SKIPIF1<0在SKIPIF1<0上的最大值.12．已知向量SKIPIF1<0,設函數(shù)SKIPIF1<0（1）求SKIPIF1<0的最小正周期．（2）求函數(shù)SKIPIF1<0的單調遞減區(qū)間．（3）求SKIPIF1<0在SKIPIF1<0上的最大值和最小值．一、單選題1．（2022·天津·高考真題）已知SKIPIF1<0，關于該函數(shù)有下列四個說法：①SKIPIF1<0的最小正周期為SKIPIF1<0；②SKIPIF1<0在SKIPIF1<0上單調遞增；③當SKIPIF1<0時，SKIPIF1<0的取值范圍為SKIPIF1<0；④SKIPIF1<0的圖象可由SKIPIF1<0的圖象向左平移SKIPIF1<0個單位長度得到．以上四個說法中，正確的個數(shù)為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·北京·高考真題）已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0在SKIPIF1<0上單調遞減 B．SKIPIF1<0在SKIPIF1<0上單調遞增C．SKIPIF1<0在SKIPIF1<0上單調遞減 D．SKIPIF1<0在SKIPIF1<0上單調遞增3．（2022·全國·高考真題（理））設函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0恰有三個極值點、兩個零點，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國·高考真題（文））將函數(shù)SKIPIF1<0的圖像向左平移SKIPIF1<0個單位長度后得到曲線C，若C關于y軸對稱，則SKIPIF1<0的最小值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·浙江·高考真題）為了得到函數(shù)SKIPIF1<0的圖象，只要把函數(shù)SKIPIF1<0圖象上所有的點（

）A．向左平移SKIPIF1<0個單位長度 B．向右平移SKIPIF1<0個單位長度C．向左平移SKIPIF1<0個單位長度 D．向右平移SKIPIF1<0個單位長度6．（2021·全國·高考真題（理））把函數(shù)SKIPIF1<0圖像上所有點的橫坐標縮短到原來的SKIPIF1<0倍，縱坐標不變，再把所得曲線向右平移SKIPIF1<0個單位長度，得到函數(shù)SKIPIF1<0的圖像，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<07．（2020·天津·高考真題）已知函數(shù)SKIPIF1<0．給出下列結論：①SKIPIF1<0的最小正周期為SKIPIF1<0；②SKIPIF1<0是SKIPIF1<0的最大值；③把函數(shù)SKIPIF1<0的圖象上所有點向左平移SKIPIF1<0個單位長度，可得到函數(shù)SKIPIF1<0的圖象．其中所有正確結論的序號是（

）A．① B．①③ C．②③