天津理工大學(xué)《高等數(shù)學(xué)》課件-曲線積分

高等數(shù)學(xué)天津理工大學(xué)曲線積分一?對(duì)弧長(zhǎng)的曲線積分（第一類曲線積分）一?對(duì)弧長(zhǎng)的曲線積分（第一類曲線積分）(xi,yi)xOBLAM1M2MiMi1Mn1y一?對(duì)弧長(zhǎng)的曲線積分（第一類曲線積分）1?對(duì)弧長(zhǎng)曲線積分的概念與性質(zhì)1?對(duì)弧長(zhǎng)曲線積分的概念與性質(zhì)1?對(duì)弧長(zhǎng)曲線積分的概念與性質(zhì)2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法Ly=x2yOx1B(1,1)▲▲▲2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法▲▲▲R2RtRxyO2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法axyO▲▲▲▲▲▲2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2ayOxaa2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法▲▲▲2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法A(1,0)yxOB(1,1)2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法A(1,0)yxOB(1,1)2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法aPtQOyxz2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法2?對(duì)弧長(zhǎng)曲線積分的計(jì)算方法Oyxzx+y+z=0▲▲▲*3?對(duì)弧長(zhǎng)曲線積分的物理應(yīng)用*3?對(duì)弧長(zhǎng)曲線積分的物理應(yīng)用*3?對(duì)弧長(zhǎng)曲線積分的物理應(yīng)用LRxOy二?對(duì)坐標(biāo)的曲線積分（第二類曲線積分）OabBAF(x)x二?對(duì)坐標(biāo)的曲線積分（第二類曲線積分）▲▲▲FBAyxO二?對(duì)坐標(biāo)的曲線積分（第二類曲線積分）F(i,i)MiM2M1A=M0xOyB=MnMn-1Mi1yixiL▲▲▲二?對(duì)坐標(biāo)的曲線積分（第二類曲線積分）1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)1?對(duì)坐標(biāo)的曲線積分的概念與性質(zhì)2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法▲▲▲B(1,1)A(1,-1)1xOyLxy=y=x_2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法AOxy2?對(duì)坐標(biāo)的曲線積分計(jì)算方法A(1,0)xOyB(0,1)2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法D(0,1)B(1,1)C(1,0)yOx▲▲▲2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法2?對(duì)坐標(biāo)的曲線積分計(jì)算方法A(1,0)B(0,1)y