2014年高考海南卷物理試題 全解全析 純Word版

1．如圖，在一水平、固定的閉合導(dǎo)體圓環(huán)上方。有一條形磁鐵(NS極朝下)B1.CC21:2B2:lC2:3D3:22.BI11,I22uIu2pp12,1AuI2u121213tt12t0t>tt<t10211Bt<tt>t102t.>tt>t2021t<tt<t10213.Bagaatvgttt，12110001121atattBt2221122214d，lPPldlldgggg．B．．．dddldl4.AuudE1mgEEq1，dl2有dgEqmamgAla2/5OOM的物體；‘L23MM2MM．．B．．22D為AO'AL,DO’0A6TMGGMT2GMT2．．B．．GMT222R33GMT222RR33GMT2RGMT2GMT2GMT26.AR2F,22FF'FF'FFFm向RF'mR，萬(wàn)向萬(wàn)向T2R2T2②式，可得,A7BABDC82L，通有大小相等、方向相同的恒定電流，abcl、和l3l2acBbcacb【答案】ba處c處產(chǎn)生的場(chǎng)強(qiáng)，ac9a表示某電場(chǎng)中一條電場(chǎng)線，ab從aabv-t圖線如圖（ba、bEEWW、、ab、abababEE＞．．＞B．D．a(chǎn)babEE＜WW＞abab9.由v-ta到bEE＞W(wǎng)W＞abab10a、ba在水平桌面的上方，bb使ab靜止，撤去此壓力后，aa下降的過(guò)程中，babBaab10.【答案】1vvcosE，為b22abkAaabbaabbD11a）和圖（b12IUDL，、IU。DU(5)(1)(2))(2)(2)(14IL【解析】螺旋測(cè)微器讀數(shù)：×，游標(biāo)卡尺讀數(shù)：×2DUllR==0.05mm=42.40mm2。4ILs12E9V50mAV5VV10V12A50mAA100mA12300ΩR200Ω1/8WR220Ω1W12123.。4.(10)(1)(a)(5(b)23)(2)R(1)2(2)(4)(此答案對(duì)應(yīng)于圖:(分，其他合理答案也給分)137.5ma5m/ss10m2，/as和s121s20211ssa(2t)22120ts05m/s2attv121sttt12vat11s2212s/1s/212s/10m14xBxx0qq0v從yPy0T01Px2P5m2mvt1E，04qBqT01RTv20RqvBm02RTv054xt為15tT815mt14qB20xvta02E1v2022mv得t02qEPtT202mvE0qT0153-31BE2PaⅠ03:1bg(41224分;4))p20pp、21ppSpp12SV0VVpp00241VVpp002424pSm105g163-41x軸傳播，ab為xx=0（x0av=10m/sbbb0.05mx軸正向傳播，xbBx軸正向傳播，xbx軸負(fù)向傳播，xbx軸負(fù)向傳播，xb2l1l和2l。3(1)(422.4)(2)(8)nθθ12律sinsinn12h1l21h2h2hl222ll2221hh22nθ313nl33l23H2ll22Hl1lh321173-51B2αα粒子及一新核，αBRα