




版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
1、精選優(yōu)質(zhì)文檔-傾情為你奉上機(jī)器學(xué)習(xí)課內(nèi)實(shí)驗(yàn)報(bào)告(1) ID算法實(shí)現(xiàn)決策樹2015 - 2016學(xué)年 第 2 學(xué)期專業(yè):智能科學(xué)與技術(shù)班級(jí):智能1301班學(xué)號(hào):姓名:張爭(zhēng)輝一、 實(shí)驗(yàn)?zāi)康模豪斫釯D3算法的基本原理,并且編程實(shí)現(xiàn)。二、 實(shí)驗(yàn)要求:使用C/C+/MATLAB實(shí)現(xiàn)ID3算法。輸入:若干行,每行 5 個(gè)字符串,表示Outlook Temperature Humidity Wind Play ball如上表。輸出:決策樹。實(shí)驗(yàn)結(jié)果如下:輸入: Sunny Hot High Weak No Sunny Hot High Strong No Overcast Hot High Weak Yes
2、 Rain Mild High Weak Yes Rain Cool Normal Weak Yes Rain Cool Normal Strong No Overcast Cool Normal Strong Yes Sunny Mild High Weak No Sunny Cool Normal Weak Yes Rain Mild Normal Weak Yes Sunny Mild Normal Strong Yes Overcast Mild High Strong Yes Overcast Hot Normal Weak Yes Rain Mild High Strong No輸
3、出:Outlook Rain Wind Strong No Weak Yes Overcast Yes Sunny Humidity Normal Yes High No 三、 具體實(shí)現(xiàn):實(shí)現(xiàn)算法如下:#include <iostream>#include <fstream>#include <math.h>#include <string>using namespace std;#define ROW 14#define COL 5#define log2 0.typedef struct TNode char data15; char wei
4、ght15; TNode * firstchild,*nextsibling;*tree;typedef struct LNode char OutLook15; char Temperature15; char Humidity15; char Wind15; char PlayTennis5; LNode *next;*link;typedef struct AttrNode char attributes15;/屬性 int attr_Num;/屬性的個(gè)數(shù) AttrNode *next;*Attributes;char * ExamplesROWCOL = /"OverCast
5、","Cool","High","Strong","No", /"Rain","Hot","Normal","Strong","Yes", "Sunny","Hot","High","Weak","No", "Sunny","Hot","High",
6、"Strong","No", "OverCast","Hot","High","Weak","Yes", "Rain","Mild","High","Weak","Yes", "Rain","Cool","Normal","Weak","Yes", "
7、;Rain","Cool","Normal","Strong","No", "OverCast","Cool","Normal","Strong","Yes", "Sunny","Mild","High","Weak","No", "Sunny","Cool",&quo
8、t;Normal","Weak","Yes", "Rain","Mild","Normal","Weak","Yes", "Sunny","Mild","Normal","Strong","Yes", "OverCast","Mild","Normal","Strong"
9、;,"Yes", "OverCast","Hot","Normal","Weak","Yes", "Rain","Mild","High","Strong","No" ;char * Attributes_kind4 = "OutLook","Temperature","Humidity","Wind&quo
10、t;int Attr_kind4 = 3,3,2,2;char * OutLook_kind3 = "Sunny","OverCast","Rain"char * Temperature_kind3 = "Hot","Mild","Cool"char * Humidity_kind2 = "High","Normal"char * Wind_kind2 = "Weak","Strong"/*int
11、 i_Exampple145 = 0,0,0,0,1, 0,0,0,1,1, 1,0,0,1,0, 2,1,0,0,0, 2,2,1,0,0, 2,2,1,1,1, 1,2,1,1,0, 0,1,0,0,1, 0,2,1,0,0, 2,1,1,0,0, 0,1,1,1,0, 1,1,1,1,0, 1,1,1,0,0, 2,1,0,0,1 ;*/void treelists(tree T);void InitAttr(Attributes &attr_link,char * Attributes_kind,int Attr_kind);void InitLink(link &L,
12、char * ExamplesCOL);void ID3(tree &T,link L,link Target_Attr,Attributes attr);void PN_Num(link L,int &positve,int &negative);double Gain(int positive,int negative,char * atrribute,link L,Attributes attr_L);void main() link LL,p; Attributes attr_L,q; tree T; T = new TNode; T->firstchil
13、d = T->nextsibling = NULL; strcpy(T->weight,""); strcpy(T->data,""); attr_L = new AttrNode; attr_L->next = NULL; LL = new LNode; LL->next = NULL; /成功建立兩個(gè)鏈表 InitLink(LL,Examples); InitAttr(attr_L,Attributes_kind,Attr_kind); ID3(T,LL,NULL,attr_L); cout<<"決
14、策樹以廣義表形式輸出如下:"<<endl; treelists(T);/以廣義表的形式輸出樹/cout<<Gain(9,5,"OutLook",LL,attr_L)<<endl; cout<<endl;/以廣義表的形式輸出樹void treelists(tree T) tree p; if(!T) return; cout<<""<<T->weight<<"" cout<<T->data; p = T->firs
15、tchild; if (p) cout<<"(" while (p) treelists(p); p = p->nextsibling; if (p)cout<<',' cout<<")" void InitAttr(Attributes &attr_link,char * Attributes_kind,int Attr_kind) Attributes p; for (int i =0;i < 4;i+) p = new AttrNode; p->next = NULL;
16、strcpy(p->attributes,Attributes_kindi); p->attr_Num = Attr_kindi; p->next = attr_link->next; attr_link->next = p; void InitLink(link &LL,char * ExamplesCOL) link p; for (int i = 0;i < ROW;i+) p = new LNode; p->next = NULL; strcpy(p->OutLook,Examplesi0); strcpy(p->Tempe
17、rature,Examplesi1); strcpy(p->Humidity,Examplesi2); strcpy(p->Wind,Examplesi3); strcpy(p->PlayTennis,Examplesi4); p->next = LL->next; LL->next = p; void PN_Num(link L,int &positve,int &negative) positve = 0; negative = 0; link p; p = L->next; while (p) if (strcmp(p->P
18、layTennis,"No") = 0) negative+; else if(strcmp(p->PlayTennis,"Yes") = 0) positve+; p = p->next; /計(jì)算信息增益/link L: 樣本集合S/attr_L:屬性集合double Gain(int positive,int negative,char * atrribute,link L,Attributes attr_L) int atrr_kinds;/每個(gè)屬性中的值的個(gè)數(shù) Attributes p = attr_L->next; link
19、q = L->next; int attr_th = 0;/第幾個(gè)屬性 while (p) if (strcmp(p->attributes,atrribute) = 0) atrr_kinds = p->attr_Num; break; p = p->next; attr_th+; double entropy,gain=0; double p1 = 1.0*positive/(positive + negative); double p2 = 1.0*negative/(positive + negative); entropy = -p1*log(p1)/log2
20、 - p2*log(p2)/log2;/集合熵 gain = entropy; /獲取每個(gè)屬性值在訓(xùn)練樣本中出現(xiàn)的個(gè)數(shù) /獲取每個(gè)屬性值所對(duì)應(yīng)的正例和反例的個(gè)數(shù) /聲明一個(gè)3*atrr_kinds的數(shù)組 int * kinds= new int * 3; for (int j =0;j < 3;j+) kindsj = new intatrr_kinds;/保存每個(gè)屬性值在訓(xùn)練樣本中出現(xiàn)的個(gè)數(shù) /初始化 for (int j = 0;j< 3;j+) for (int i =0;i < atrr_kinds;i+) kindsji = 0; while (q) if (str
21、cmp("OutLook",atrribute) = 0) for (int i = 0;i < atrr_kinds;i+) if(strcmp(q->OutLook,OutLook_kindi) = 0) kinds0i+; if(strcmp(q->PlayTennis,"Yes") = 0) kinds1i+; else kinds2i+; else if (strcmp("Temperature",atrribute) = 0) for (int i = 0;i < atrr_kinds;i+) if
22、(strcmp(q->Temperature,Temperature_kindi) = 0) kinds0i+; if(strcmp(q->PlayTennis,"Yes") = 0) kinds1i+; else kinds2i+; else if (strcmp("Humidity",atrribute) = 0) for (int i = 0;i < atrr_kinds;i+) if(strcmp(q->Humidity,Humidity_kindi) = 0) kinds0i+; if(strcmp(q->Play
23、Tennis,"Yes") = 0) kinds1i+;/ else kinds2i+; else if (strcmp("Wind",atrribute) = 0) for (int i = 0;i < atrr_kinds;i+) if(strcmp(q->Wind,Wind_kindi) = 0) kinds0i+; if(strcmp(q->PlayTennis,"Yes") = 0) kinds1i+; else kinds2i+; q = q->next; /計(jì)算信息增益 double * gain
24、_kind = new doubleatrr_kinds; int positive_kind = 0,negative_kind = 0; for (int j = 0;j < atrr_kinds;j+) if (kinds0j != 0 && kinds1j != 0 && kinds2j != 0) p1 = 1.0*kinds1j/kinds0j; p2 = 1.0*kinds2j/kinds0j; gain_kindj = -p1*log(p1)/log2-p2*log(p2)/log2; gain = gain - (1.0*kinds0j/
25、(positive + negative)*gain_kindj; else gain_kindj = 0; return gain;/在ID3算法中的訓(xùn)練樣本子集合與屬性子集合的鏈表需要進(jìn)行清空void FreeLink(link &Link) link p,q; p = Link->next; Link->next = NULL; while (p) q = p; p = p->next; free(q); void ID3(tree &T,link L,link Target_Attr,Attributes attr) Attributes p,max,
26、attr_child,p1; link q,link_child,q1; tree r,tree_p; int positive =0,negative =0; PN_Num(L,positive,negative); /初始化兩個(gè)子集合 attr_child = new AttrNode; attr_child->next = NULL; link_child = new LNode; link_child->next = NULL; if (positive = 0)/全是反例 strcpy(T->data,"No"); return; else if
27、( negative = 0)/全是正例 strcpy(T->data,"Yes"); return; p = attr->next; /屬性鏈表 double gain,g = 0; /*/ /* 建立屬性子集合與訓(xùn)練樣本子集合有兩個(gè)方案: 一:在原來鏈表的基礎(chǔ)上進(jìn)行刪除; 二:另外申請(qǐng)空間進(jìn)行存儲(chǔ)子集合; 采用第二種方法雖然浪費(fèi)了空間,但也省了很多事情,避免了變量之間的應(yīng)用混亂 */ /*/ if(p) while (p) gain = Gain(positive,negative,p->attributes,L,attr); cout<<
28、p->attributes<<" "<<gain<<endl; if(gain > g) g = gain; max = p;/尋找信息增益最大的屬性 p = p->next; strcpy(T->data,max->attributes);/增加決策樹的節(jié)點(diǎn) cout<<"信息增益最大的屬性:max->attributes = "<<max->attributes<<endl<<endl; /下面開始建立決策樹 /創(chuàng)建屬性子集合
29、 p = attr->next; while (p) if (strcmp(p->attributes,max->attributes) != 0) p1 = new AttrNode; strcpy(p1->attributes,p->attributes); p1->attr_Num = p->attr_Num; p1->next = NULL; p1->next = attr_child->next; attr_child->next = p1; p = p->next; /需要區(qū)分出是哪一種屬性 /建立每一層的第一
30、個(gè)節(jié)點(diǎn) if (strcmp("OutLook",max->attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,OutLook_kind0); T->firstchild = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (strcmp(q->OutLook,OutLook_kind0) = 0) q1
31、 = new LNode; strcpy(q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_child->next; link_child->next = q1; q = q
32、->next; else if (strcmp("Temperature",max->attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,Temperature_kind0); T->firstchild = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (strcmp(q->Temperatur
33、e,Temperature_kind0) = 0) q1 = new LNode; strcpy(q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_child->next; lin
34、k_child->next = q1; q = q->next; else if (strcmp("Humidity",max->attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,Humidity_kind0); T->firstchild = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (s
35、trcmp(q->Humidity,Humidity_kind0) = 0) q1 = new LNode; strcpy(q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_chi
36、ld->next; link_child->next = q1; q = q->next; else if (strcmp("Wind",max->attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,Wind_kind0); T->firstchild = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (
37、q) if (strcmp(q->Wind,Wind_kind0) = 0) q1 = new LNode; strcpy(q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_chi
38、ld->next; link_child->next = q1; q = q->next; int p = 0,n = 0; PN_Num(link_child,p,n); if (p != 0 && n != 0) ID3(T->firstchild,link_child,Target_Attr,attr_child); FreeLink(link_child); else if(p = 0) strcpy(T->firstchild->data,"No"); FreeLink(link_child); /strcpy(
39、T->firstchild->data,q1->PlayTennis);/-此處應(yīng)該需要修改-:) else if(n = 0) strcpy(T->firstchild->data,"Yes"); FreeLink(link_child); /建立每一層上的其他節(jié)點(diǎn) tree_p = T->firstchild; for (int i = 1;i < max->attr_Num;i+) /需要區(qū)分出是哪一種屬性 if (strcmp("OutLook",max->attributes) = 0) r
40、 = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,OutLook_kindi); tree_p->nextsibling = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (strcmp(q->OutLook,OutLook_kindi) = 0) q1 = new LNode; strcpy(q1->OutLook,q->OutLook); str
41、cpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_child->next; link_child->next = q1; q = q->next; else if (strcmp("Temperature",max-
42、>attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,Temperature_kindi); tree_p->nextsibling = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (strcmp(q->Temperature,Temperature_kindi) = 0) q1 = new LNode; strcpy(
43、q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temperature,q->Temperature); strcpy(q1->Wind,q->Wind); strcpy(q1->PlayTennis,q->PlayTennis); q1->next = NULL; q1->next = link_child->next; link_child->next = q1; q = q->next; else if (s
44、trcmp("Humidity",max->attributes) = 0) r = new TNode; r->firstchild = r->nextsibling = NULL; strcpy(r->weight,Humidity_kindi); tree_p->nextsibling = r; /獲取與屬性值相關(guān)的訓(xùn)練樣例Example(vi),建立一個(gè)新的訓(xùn)練樣本鏈表link_child q = L->next; while (q) if (strcmp(q->Humidity,Humidity_kindi) = 0) q1 = new LNode; strcpy(q1->OutLook,q->OutLook); strcpy(q1->Humidity,q->Humidity); strcpy(q1->Temp
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 郵政快遞企業(yè)數(shù)字化轉(zhuǎn)型與智慧升級(jí)戰(zhàn)略研究報(bào)告
- 2025年醫(yī)用材料制造合作協(xié)議書
- 模塊化建筑教育設(shè)施行業(yè)跨境出海戰(zhàn)略研究報(bào)告
- 皮草背心企業(yè)縣域市場(chǎng)拓展與下沉戰(zhàn)略研究報(bào)告
- 汽車車橋企業(yè)ESG實(shí)踐與創(chuàng)新戰(zhàn)略研究報(bào)告
- 黃牛批發(fā)企業(yè)ESG實(shí)踐與創(chuàng)新戰(zhàn)略研究報(bào)告
- 模塊化急救車家具配置企業(yè)制定與實(shí)施新質(zhì)生產(chǎn)力戰(zhàn)略研究報(bào)告
- 定制家具制作協(xié)議
- 人才培養(yǎng)機(jī)制與選拔方法會(huì)議合同
- 二零二五年度港口碼頭施工安全協(xié)議規(guī)范
- 廠房改公寓出租合同范例
- 污水處理廠SBR工藝的設(shè)計(jì)說明
- 城市軌道交通行車組織 課件 項(xiàng)目二任務(wù)六 車站行車組織作業(yè)
- 2025年北方聯(lián)合電力有限責(zé)任公司招聘筆試參考題庫含答案解析
- 2025年八省聯(lián)考數(shù)學(xué)試題(原卷版)
- 高教社馬工程倫理學(xué)(第二版)教學(xué)課件02
- 《榜樣9》觀后感心得體會(huì)二
- 2024年滁州職業(yè)技術(shù)學(xué)院?jiǎn)握新殬I(yè)適應(yīng)性測(cè)試題庫帶答案
- 小學(xué)生播音主持課課件
- 二年級(jí)下冊(cè)道法大單元全冊(cè)教案
- 人工智能在智慧物流中的應(yīng)用
評(píng)論
0/150
提交評(píng)論