機(jī)構(gòu)分析與綜合作業(yè)

1、機(jī)構(gòu)分析與綜合期末作業(yè)鉸鏈?zhǔn)筋€式破碎機(jī)機(jī)構(gòu) 姓 名： XXX 學(xué) 號(hào)： 2014405003 班 級(jí): 專業(yè)(1)班 指導(dǎo)老師： XXX 學(xué)科、專業(yè)： XXXXXXX 所在學(xué)院： XXXXXXXXXXXX 2015年7月 鉸鏈?zhǔn)筋€式破碎機(jī)機(jī)構(gòu)一.機(jī)構(gòu)簡(jiǎn)介與設(shè)計(jì)數(shù)據(jù)1.機(jī)構(gòu)簡(jiǎn)介 顎式破碎機(jī)是一種破碎礦石的機(jī)械，如圖所示，機(jī)器經(jīng)皮帶（圖中未畫(huà)）使曲柄2順時(shí)針回轉(zhuǎn)，然后通過(guò)構(gòu)件3，4，5使動(dòng)顎板6往復(fù)擺動(dòng)。當(dāng)動(dòng)顎板6向左擺向固定于機(jī)架1上的定額板7時(shí)，礦石即被軋碎；當(dāng)動(dòng)顎板6向右擺離定額板7時(shí)，被軋碎的礦石即下落。由于機(jī)器在工作過(guò)程中載荷變化很大，將影響曲柄和電動(dòng)機(jī)的勻速運(yùn)轉(zhuǎn)。為了減小主軸速度的波動(dòng)

2、和電動(dòng)機(jī)的容量，在O2軸的兩端各裝一個(gè)大小和重量完全相同的飛輪，其中一個(gè)兼作皮帶輪用。圖1.1 顎式破碎機(jī)工作原理設(shè)計(jì)內(nèi)容連桿機(jī)構(gòu)的運(yùn)動(dòng)分析符號(hào)n2Lo2AL1L2h1h2LALO4BLBCLo6C單位r/minmm數(shù)據(jù)170100100094085010001250100011501960導(dǎo)桿機(jī)構(gòu)的動(dòng)態(tài)靜力分析飛輪轉(zhuǎn)動(dòng)慣量的確定LO6DG3JS3G4JS4G5JS5G6JS6mmNKgm2NKgm2NKg m2NKm2600500025.520009200099000500.152.設(shè)計(jì)數(shù)據(jù)3.設(shè)計(jì)要求1.連桿機(jī)構(gòu)的運(yùn)動(dòng)分析已知：各機(jī)構(gòu)尺寸及質(zhì)心位置（構(gòu)件2的質(zhì)心在O2，其余構(gòu)件的質(zhì)心均位于

3、構(gòu)件的中心），曲柄轉(zhuǎn)速為n2。要求：進(jìn)行運(yùn)動(dòng)分析，作機(jī)構(gòu)運(yùn)動(dòng)簡(jiǎn)圖，機(jī)構(gòu)12個(gè)位置的速度和加速度多邊形。2.連桿機(jī)構(gòu)的動(dòng)態(tài)靜力分析已知：各構(gòu)件重力G及對(duì)質(zhì)心軸的轉(zhuǎn)動(dòng)慣量Js，工作阻力Fr曲線如圖所示，F(xiàn)r的作用點(diǎn)為D，方向垂直于O6C；運(yùn)動(dòng)分析中所得結(jié)果。要求：確定機(jī)構(gòu)一個(gè)位置的各運(yùn)動(dòng)副反作用力及需加在曲柄上的平衡力矩Mb。圖1.2 工作阻力3.用解析法校核機(jī)構(gòu)運(yùn)動(dòng)分析和動(dòng)態(tài)靜力分析結(jié)果編寫(xiě)機(jī)構(gòu)運(yùn)動(dòng)分析和力分析主程序，得到給定位置的計(jì)算結(jié)果。根據(jù)解析法的結(jié)果，分析圖解法的誤差及產(chǎn)生的原因。4.飛輪設(shè)計(jì)已知：機(jī)器運(yùn)動(dòng)的速度不均勻系數(shù)，由動(dòng)態(tài)靜力分析所得的平衡力矩Mb以及驅(qū)動(dòng)力矩Md為常數(shù)。要求：確

4、定安裝在軸O2上的飛輪的轉(zhuǎn)動(dòng)慣量JF。二.連桿機(jī)構(gòu)的運(yùn)動(dòng)分析（1）曲柄在1位置時(shí)，構(gòu)件2和3成一直線，構(gòu)件4在最低位置時(shí)，L=AB+AO2=1.25+0.1=1.35=1350mm，以O(shè)2為圓心，以0.1m為半徑畫(huà)圓，以O(shè)4為圓心，以1m為半徑畫(huà)圓，通過(guò)圓心O2在兩弧上量取1350mm，從而確定出1位置連桿和曲柄的位置。再以O(shè)6 為圓心，以1960mm為半徑畫(huà)圓，在圓O6和O4的圓弧上量取1150mm從而確定出B4C1桿的位置。（2）曲柄在2位置時(shí)，在1位置基礎(chǔ)上順時(shí)針轉(zhuǎn)動(dòng)240。以O(shè)2為圓心，以0.1m為半徑畫(huà)圓，則找到A點(diǎn)。再分別以A和O4為圓心，以1.25m和1m為半徑畫(huà)圓，兩圓的下方的

5、交點(diǎn)則為B點(diǎn)。再分別以B和O6為圓心，以1.15m和1.96m為半徑畫(huà)圓，兩圓的下方的交點(diǎn)則為C點(diǎn)，再連接AB、O4B、BC和O6C。此機(jī)構(gòu)各桿件位置確定。（3）曲柄在3位置時(shí)，在1位置基礎(chǔ)上順時(shí)針轉(zhuǎn)動(dòng)180過(guò)A4點(diǎn)到圓O4的弧上量取1250mm，確定出B4點(diǎn)，從B3點(diǎn)到圓弧O6上量取1150mm長(zhǎng)，確定出C4，此機(jī)構(gòu)各位置確定。1.連桿機(jī)構(gòu)速度分析位置1：2=pn/30=3.14*170/30=17.8rad/sVB = VA + VBA? AO22 ?O4B AO2 ABVA= AO22=0.117.8=1.78m/s 根據(jù)速度多邊形，按比例尺=0.05(m/S)/mm，在圖2中量取VB和

6、VBA的長(zhǎng)度數(shù)值：則VB=36.22X=1.81m/sVBA=8.99X=0.45m/sVC = VB + VCB? ?O6C BC 根據(jù)速度多邊形，按比例尺=0.05(m/s)/mm，在圖3中量取VC 和VCB的長(zhǎng)度數(shù)值：VC=13.35=0.67m/sVCB=34.26=1.71m/s2.加速度分析 2=17.8rad/s a B= anBo4 + atBo4 = aA4 + anBA + atAB ? ? /BO4 BO4 /AO2 /BA AB aA= AO2 22 =31.7m/s2anBA= VBA * VBA/ BA =0.33m/s2anBo4 = VB * VB /BO4 =

7、3.28 m/s2 根據(jù)加速度多邊形圖按比例尺=0.1(m/s2)/mm量取atBo4、atAB和a B 值的大?。?atBo4 =23.2=2.32 m/s2 atAB =279.8 =27.98m/s2a B=280 =28.00 m/s2ac= ano6C + ato6C= aB + at CB+ an CB ? ? /O6C O6C /BO6 CB /CB根據(jù)加速度多邊形按圖3按比例尺=0.1(m/s2)/mm量取aC、ato6C和at CB數(shù)值：aC =64.7 =6.47m/s2ato6C=64.6 =6.46m/s2at CB=14.3 =1.43m/s2 3.連桿機(jī)構(gòu)的動(dòng)態(tài)靜力

8、分析對(duì)各受力桿件列力平衡方程和力矩平衡方程：桿6 Fry+F56x-F16x=m6a6Fi6y-Fry-F56y+G6y=m6a6y對(duì)O6取矩F56xx+1/2G6x+F56yy+1/2Frxy=J66的方程Fi6=1/2ao6c*m6=2968.7N Mi6= ao6Bt/Lo4B*Js4 =JS66=165.26N.m Fr16x+Fr*cos(4.96)+Fr56x-Fi6*cos(2.95)=0 Fry-Frsin(4.96)+Fi6*sin(2.95)+Fr56y-G6=0Fr*LCD+1/2Lo6c*G6*sin(4.96)+Fr56x*Lo6c*cos(4.96)-Mi6-Fr5

9、6y*Lo6c*sin(4.96)=0桿5 F45x-F65x=m5a5x F65y-F45y+G5y=m5a5y對(duì)B點(diǎn)取矩 F65xy+1/2G5x-F65yx=J55的方程Fi5=a5*m5=660.9N Mi5=JS55 =50.6 N.mFr45x-Fr56x-Fi5*cos(1.1)=0Fr45y-Fr56y+Fi5sin(1.1)-G5y=01/2Fi5*LBC*sin( -7.26)-Mi5-Fr56y*LBC*cos(7.260)-Fr56x*LBC*sin(7.26)-1/2G5*LBC*cos(7.29)=0桿4 F14x-F43x=m4a4xF14y-F43y+G4y=m

10、4a4y對(duì)B取矩 F14xx-1/2G4x-F14yy=J44的方程Fi4=a4*m4=424.9N Mi4=ao4Bt/Lo4B*Js4=20.87 N.mFr14x-Fr45x-Fr43x-Fi4*cos(20.9)=0Fr14y-Fr45y-Fr43y+Fi4*sin(20.9)-G4=01/2Fi4*Lo4B*sin(35.26)+(Fr45x+Fr43x)*Lo4B*sin(14.36)+Mi4-(Fr45y+Fr43y+1/2G4)*Lo4B*cos(14.36)=0桿3 -F23x-F43x=m3a3x F23y-F43y+G3=m3a3y對(duì)B取矩 F23xx+1/2G3x-F2

11、3yy=J33的方程Fi3=a3*m3=709.26N Mi3= JS33=570.87 N.mFr23x+Fr43xFi3*cos(5.11)=0Fr23y+Fr43yG3+Fi3*sin(5.11)=01/2Fi3LAB*cos(5.11)+1/2G3*LAB*sin(3.27)-Mi3-Fr43y*LAB*sin(3.27)-Fr43x*LAB*cos(3.27)=02的方程Fr12x-Fr23x=0Fr12y-Fr23y-G2=0當(dāng)曲柄處于180。時(shí)，, 通過(guò)列矩陣求解：F12y =21230.3N F12x= 1578.42 N F32x=-4684N F32y =17812N F4

12、3x=6451N F43y =12970N F14x =-26061N F14y=-5790N F45x = -32915N F45y = 5332N F56x =-33575N F56y=3332 N F16x =-5335N F16y =20434N 三.桿組法顎式破碎機(jī)的運(yùn)動(dòng)分析及動(dòng)態(tài)靜力分析 機(jī)構(gòu)的結(jié)構(gòu)分析六桿鉸鏈?zhǔn)椒鬯闄C(jī)拆分為機(jī)架和主動(dòng)件，構(gòu)件組成的RRR桿組，構(gòu)件組成的RRR桿組。+（1）調(diào)用bark函數(shù)對(duì)主動(dòng)件進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表3.1。表 3.1形式參數(shù)n1n2n3kr1r2gamtwepvpap實(shí)值1201r120.00.0twepvpap（2）調(diào)用rrrk函數(shù)對(duì)由構(gòu)件組成的R

13、RR桿組進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表4.2。表 3.2形式參數(shù)mn1n2n3k1k2r1r2twepvpap實(shí)值142332r34r23twepvpap（3）調(diào)用rrrk函數(shù)對(duì)由構(gòu)件組成的RRR桿組進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表4.3。表3.3形式參數(shù)mn1n2n3k1k2r1r2twepvpap實(shí)值136545,r35r56twepvpap（4）程序清單：#include graphics.h#include subk.c#include draw.cmain() static double p202,vp202,ap202; static double t10,w10,e10,del; static doubl

14、e pdraw370,vpdraw370,apdraw370,wdraw370; static int ic; double r12,r23,r34,r35,r56; double pi,dr; int i; FILE *fp; r12=0.1; r34=1.0; r23=1.250; r35=1.15; r56=1.96; p11=0.0; p12=0.0; p41=0.94; p42=-1.0; p61=-1.0; p62=0.85; pi=4.0*atan(1.0); dr=pi/180.0; t1=0.0; w1=-17*pi/3; e1=0.0; del=15; printf(n T

15、he Kinematic Parameters of Point6n); printf(No THETA1 t5 w5 e5n); printf( deg rad rad/s rad/s/sn); ic=(int)(360.0/del); for(i=0;i=ic;i+) t1=(-i)*del*dr-90*dr; bark(1,2,0,1,r12,0.0,0.0,t,w,e,p,vp,ap); rrrk(1,4,2,3,3,2,r34,r23,t,w,e,p,vp,ap); rrrk(1,3,6,5,4,5,r35,r56,t,w,e,p,vp,ap); wdrawi=t1/dr; pdra

16、wi=t5; vpdrawi=w5; apdrawi=e5; if(fp=fopen(六桿運(yùn)動(dòng)8888888.txt,w)=NULL) printf(Cant open this file./n); exit(0); for(i=0;i=ic;i+)printf(%12.3f %12.3f %12.3f %12.3fn,wdrawi,pdrawi,vpdrawi,apdrawi);fprintf(fp,%e %e %e %en,wdrawi,pdrawi,vpdrawi,apdrawi); if(i%18)=0)getch(); fclose(fp); getch(); draw1(del,p

17、draw,vpdraw,apdraw,ic);運(yùn)算結(jié)果：The Kinematic Parameters of Point5THETA1 t5 w5 e5deg rad rad/s rad/s/s-9.00000e+01 -1.63238e+00 -1.37677e-03 -1.01835e+01-1.05000e+02 -1.63348e+00 -1.45454e-01 -9.16482e+00-1.20000e+02 -1.63654e+00 -2.64803e-01 -6.90406e+00-1.35000e+02 -1.64108e+00 -3.45263e-01 -3.98081e+

18、00-1.50000e+02 -1.64647e+00 -3.81662e-01 -1.00778e+00-1.65000e+02 -1.65210e+00 -3.77125e-01 1.51876e+00-1.80000e+02 -1.65741e+00 -3.40696e-01 3.29712e+00-1.95000e+02 -1.66202e+00 -2.84290e-01 4.23741e+00-2.10000e+02 -1.66573e+00 -2.19724e-01 4.43601e+00-2.25000e+02 -1.66849e+00 -1.56345e-01 4.12137e

19、+00-2.40000e+02 -1.67036e+00 -9.95969e-02 3.58405e+00-2.55000e+02 -1.67146e+00 -5.06328e-02 3.10541e+00-2.70000e+02 -1.67188e+00 -6.91431e-03 2.89782e+00-2.85000e+02 -1.67166e+00 3.64486e-02 3.06340e+00-3.00000e+02 -1.67078e+00 8.48847e-02 3.57078e+00-3.15000e+02 -1.66912e+00 1.42323e-01 4.24740e+00

20、-3.30000e+02 -1.66655e+00 2.09172e-01 4.79134e+00-3.45000e+02 -1.66295e+00 2.80705e-01 4.81744e+00-3.60000e+02 -1.65832e+00 3.46484e-01 3.95596e+00-3.75000e+02 -1.65286e+00 3.91648e-01 2.00206e+00-3.90000e+02 -1.64698e+00 4.00498e-01 -9.32100e-01-4.05000e+02 -1.64131e+00 3.61788e-01 -4.35539e+00-4.2

21、0000e+02 -1.63658e+00 2.73734e-01 -7.50567e+00-4.35000e+02 -1.63346e+00 1.46198e-01 -9.61223e+00-4.50000e+02 -1.63238e+00 -1.37677e-03 -1.01835e+01四.機(jī)構(gòu)的動(dòng)態(tài)靜力分析六桿鉸鏈?zhǔn)筋€式破碎機(jī)的靜力分析：（1）調(diào)用bark函數(shù)對(duì)主動(dòng)件進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表3.1。（2）調(diào)用rrrk函數(shù)對(duì)由構(gòu)件組成的RRR桿組進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表3.2。（3）調(diào)用rrrk函數(shù)對(duì)由構(gòu)件組成的RRR桿組進(jìn)行運(yùn)動(dòng)分析。見(jiàn)表3.3。（4）求各構(gòu)件的質(zhì)心7、8、9、10點(diǎn)及礦石破碎阻力

22、作用點(diǎn)11點(diǎn)的運(yùn)動(dòng)參數(shù)。見(jiàn)表4.1表4.5。表4.1 7點(diǎn)運(yùn)動(dòng)參數(shù)形式參數(shù)n1n2n3kr1r2gamtwepvpap實(shí)值20720.0r270.0twepvpap表4.2 8點(diǎn)運(yùn)動(dòng)參數(shù)形式參數(shù)n1n2n3kr1r2gamtwepvpap實(shí)值40830.0r480.0twepvpap表4.3 9點(diǎn)運(yùn)動(dòng)參數(shù)形式參數(shù)n1n2n3kr1r2gamtwepvpap實(shí)值30940.0r390.0twepvpap表4.4 10點(diǎn)運(yùn)動(dòng)參數(shù)形式參數(shù)n1n2n3kr1r2gamtwepvpap實(shí)值601050.0r6100.0twepvpap表4.5 11點(diǎn)運(yùn)動(dòng)參數(shù)形式參數(shù)n1n2n3kr1r2gamtwepv

23、pap實(shí)值601150.0r6110.0twepvpap（5）調(diào)用rrrf對(duì)由桿組成的RRR桿組進(jìn)行靜力分析。見(jiàn)表4.6。表4.6形式參數(shù)n1n2n3ns1ns2nn1nn2nexfk1k2pvpaptwefr實(shí)值3659100111145pvpaptwefr（6）調(diào)用rrrf對(duì)由桿組成的RRR桿組進(jìn)行靜力分析。見(jiàn)表4.7。表4.7形式參數(shù)n1n2n3ns1ns2nn1nn2nexfk1k2pvpaptwefr實(shí)值4238730032pvpaptwefr（7）調(diào)用barf對(duì)主動(dòng)件進(jìn)行靜力分析。見(jiàn)表4.8。表4.8形式參數(shù)n1ns1nn1k1papefrtb實(shí)值1121papefr&tb程序清單

24、#include graphics.h#include subk.c#include subf.c#include draw.cmain() static double p202,vp202,ap202,del; static double t10,w10,e10; static double sita1370,fr1draw370,sita2370,fr2draw370,sita3370,fr3draw370,tbdraw370,tb1draw370; static double fr202,fe202; static int ic; double r12,r23,r34,r35,r56;

25、double r27,r48,r39,r610,r611; int i; double pi,dr; double fr1,bt1,fr4,bt4,fr6,bt6,we1,we2,we3,we4,we5,tb,tb1; FILE*fp; sm1=0.0;sm2=500.0;sm3=200.0;sm4=200.0;sm5=900.0; sj1=0.0;sj2=25.5;sj3=9.0;sj4=9.0;sj5=50.0; r12=0.1; r23=1.25; r34=1.0; r35=1.15;r56=1.96; r27=r23/2; r48=r34/2; r39=r35/2; r610=r56/

26、2; r611=0.6; pi=4.0*atan(1.0); dr=pi/180.0; w1=-170*2*pi/60; e1=0.0; del=15; p11=0.0; p12=0.0; p41=0.94; p42=-1.0; p61=-1.0; p62=0.85; printf(n The Kineto-static Analysis of a Six-bar Linkasen);printf( NO THETA1 FR1 BT1 FR4 BT4 FR6 BT6 TB TB1n);printf( (deg.) (N) (deg.) (N) (deg.) (N) (deg.) (N.m) (

27、N.m) n); if(fp=fopen(六桿受力8888888.doc,w)=NULL) printf(Cant open this file./n); exit(0); fprintf(fp,n The Kineto-static Analysis of a Six-bar Linkasen);fprintf(fp, NO THETA1 FR1 BT1 FR4 BT4 FR6 BT6 TB TB1n );fprintf(fp,(deg.) (N) (deg.) (N) (deg.) (N) (deg.) (N.m) (N.m) n ); ic=(int)(360.0/del); for(i

28、=0;i=ic;i+) t1=(-i)*del*dr; bark(1,2,0,1,r12,0.0,0.0,t,w,e,p,vp,ap); rrrk(1,4,2,3,3,2,r34,r23,t,w,e,p,vp,ap); rrrk(1,3,6,5,4,5,r35,r56,t,w,e,p,vp,ap); bark(2,0,7,2,0.0,r27,0.0,t,w,e,p,vp,ap); bark(4,0,8,3,0.0,r48,0.0,t,w,e,p,vp,ap); bark(3,0,9,4,0.0,r39,0.0,t,w,e,p,vp,ap); bark(6,0,10,5,0.0,r610,0.0

29、,t,w,e,p,vp,ap); bark(6,0,11,5,0.0,r611,0.0,t,w,e,p,vp,ap); rrrf(3,6,5,9,10,0,11,11,4,5,p,vp,ap,t,w,e,fr); rrrf(4,2,3,8,7,3,0,0,3,2,p,vp,ap,t,w,e,fr); barf(1,1,2,1,p,ap,e,fr,&tb); fr1=sqrt(fr11*fr11+fr12*fr12); bt1=atan2(fr12,fr11); fr4=sqrt(fr41*fr41+fr42*fr42); bt4=atan2(fr42,fr41); fr6=sqrt(fr61*

30、fr61+fr62*fr62); bt6=atan2(fr62,fr61); we1=-(ap11*vp11+(ap12+9.81)*vp12)*sm1-e1*w1*sj1;we2=-(ap71*vp71+(ap72+9.81)*vp72)*sm2-e2*w2*sj2;we3=-(ap81*vp81+(ap82+9.81)*vp82)*sm3-e3*w3*sj3;we4=-(ap91*vp91+(ap92+9.81)*vp92)*sm4-e4*w4*sj4; extf(p,vp,ap,t,w,e,11,fe);we5=-(ap101*vp101+(ap102+9.81)*vp102)*sm5-

31、e5*w5*sj5+fe111*vp111+fe112*vp112; tb1=-(we1+we2+we3+we4+we5)/w1; printf(%3d %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1fn,i+1,t1/dr,fr1,bt1/dr,fr4,bt4/dr,fr6,bt6/dr,tb1,tb1);fprintf(fp,%1d %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1f %7.1fn,i+1,t1/dr,fr1,bt1/dr,fr4,bt4/dr,fr6,bt6/dr,tb1

32、,tb1); tbdrawi=tb; tb1drawi=tb1; fr1drawi=fr1;sita1i=bt1; fr2drawi=fr4;sita2i=bt4; fr3drawi=fr4;sita3i=bt4; if(i%16)=0)getch(); fclose(fp); getch(); draw2(del,tbdraw,tb1draw,ic); draw3(del,sita1,fr1draw,sita2,fr2draw,sita3,fr3draw,ic); getch();#includemath.hextf(p,vp,ap,t,w,e,nexf,fe) double p202,vp

33、202,ap202,t10,w10,e10,fe202; double pi,dr; pi=4.0*atan(1.0); dr=pi/180.0; if(w50) fenexf1=(-t1/dr-90.0)*(85000.0/182.0)*cos(-t5-pi/2); fenexf2=-(-t1/dr-90.0)*(85000.0/182.0)*sin(-t5-pi/2); elsefenexf1=0;fenexf2=0; 運(yùn)行結(jié)果： The Kineto-static Analysis of a Six-bar LinkaseNO THETA1 FR1 BT1 FR4 BT4 FR6 BT6

34、 TB TB1 (deg.) (N) (deg.) (N) (deg.) (N) (deg.) (N.m) (N.m) The Kineto-static Analysis of a Six-bar LinkaseNO THETA1 FR1 BT1 FR4 BT4 FR6 BT6 TB TB1 (deg.) (N) (deg.) (N) (deg.) (N) (deg.) (N.m) (N.m) 1 0.0 4442.5 -157.9 2351.4 10.3 1669.1 5.0 534.3 534.32 -15.0 4901.8 144.8 2892.4 7.9 899.3 17.6 103

35、8.1 1038.13 -30.0 8299.6 117.0 3106.8 5.1 488.2 138.1 1434.5 1434.54 -45.0 12072.4 106.5 3110.5 1.6 1814.6 171.7 1547.8 1547.85 -60.0 15119.0 101.3 3165.4 -1.1 3120.1 178.1 1271.0 1271.06 -75.0 16826.9 97.9 3539.8 -0.3 4005.1 -179.3 644.2 644.27 -90.0 16909.1 94.8 4392.1 3.7 4247.2 -178.5 -144.6 -14

36、4.68 -105.0 3361.2 89.9 12148.1 14.6 9873.8 109.0 -883.8 -883.89 -120.0 11111.1 -79.8 19692.7 16.5 18718.3 95.0 -1407.8 -1407.810 -135.0 25758.8 -80.7 26713.5 16.8 27580.9 89.3 -1626.3 -1626.311 -150.0 40085.4 -81.1 33069.4 16.2 36047.5 86.2 -1559.2 -1559.212 -165.0 53732.5 -81.7 38768.2 15.3 43999.

37、9 84.4 -1292.9 -1292.913 -180.0 66530.2 -82.5 43954.6 14.1 51469.2 83.3 -931.2 -931.214 -195.0 78457.1 -83.7 48874.0 12.8 58577.5 82.9 -565.2 -565.215 -210.0 89592.8 -85.1 53826.3 11.6 65486.0 82.7 -261.0 -261.016 -225.0 100079.8 -86.7 59118.9 10.5 72355.8 82.8 -57.6 -57.617 -240.0 110102.7 -88.4 65

38、024.0 9.6 79329.5 83.0 32.3 32.318 -255.0 119876.8 -90.2 71745.8 9.1 86530.5 83.1 24.0 24.019 -270.0 129642.7 -91.9 79401.0 8.8 94074.1 83.2 -39.8 -39.820 -285.0 15509.2 -94.2 433.6 137.6 1276.2 -1.6 -205.3 -205.321 -300.0 14401.7 -99.0 487.5 149.1 1486.1 -2.4 -338.7 -338.722 -315.0 12555.3 -104.5 2

39、61.9 102.2 1767.2 -2.6 -361.5 -361.523 -330.0 10038.5 -111.8 716.5 25.1 1994.9 -1.8 -227.6 -227.624 -345.0 7059.0 -125.0 1556.8 13.9 2011.8 0.5 80.8 80.825 -360.0 4442.5 -157.9 2351.4 10.3 1669.1 5.0 534.3 534.3圖4.1 六桿機(jī)構(gòu)曲柄上的平衡力矩的變化規(guī)律五.飛輪設(shè)計(jì)0-15-30-45-60-75-90-105-120-135534.31038.11434.51547.81271.06

40、44.2-144.6-883.8-1407.8-1626.3由于圖解法采用計(jì)算機(jī)繪圖（Solidworks），所以誤差較小。與解析法求得相接近。用Excel繪制力矩圖，求功計(jì)算最大盈虧功。C點(diǎn)的角速度與角加速度和曲柄的轉(zhuǎn)動(dòng)角度的關(guān)系數(shù)據(jù)表：-150-165-180-195-210-225-240-255-270-285-1559.2-1292.9-931.2-565.2-261.0-57.632.224.0-39.8-205.3-300-315-330-345-360250260270280290-338.7-361.5-227.680.8534.3-956.9-461.527.3-475.3933.6300310320330340350360-1310.6-1561.6-1658.2-1596.8-1393.7-1081.5-706.6根據(jù)盈虧功的原理，求得各盈虧功值，并作能量指示圖。以曲柄的平均驅(qū)動(dòng)力矩為分界線，求出各區(qū)段的盈虧功值如下：W1=1867.25Nm W2=-2010.03Nm W3=104.90Nm W4=-18