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基于福田紅樹林保護區(qū)的一體化 生態(tài)系統(tǒng)模型 學(xué)校信息:華北電力大學(xué)(北京) 指導(dǎo)老師:雍雪林 隊員姓名: 陸鋒 創(chuàng)新電 1301 1131180714 劉弈卿 實踐電 1301 1131180713 董程程 實踐電 1301 1131180405 ?4X?o?Nz)?X?.e?.!?.! d?.n?.un?.?X?)?X?i!x?9 +n| NX ?.?o+(?! X!XU6 Xl?J?+?mCz?!?5! !L+(?1?z?.q)?X? X!XU6X?1?z ?| ?u)?X%?U6?K)?XEWE?.? .?.d?.J? ?.?.U?o?9?I?1 ?9?.(?T+ (?9?) )?5L?1?O(?(J d?.-5dNXxG?dNX -5dNX?c?.?c)?X-5? d?)?X-5?dl+(?! ! U6o?1?e5?+(?-5U6-5d?N xG?dNX?PSRd?.?!G?An ?c)?X?xGdL?(?I? IO?g(?I?-?yaaho?)?X ?1?73.24IOy1?/x0 1?/ x0 3nf?.?:J?Nz)?X?.oeTe ?i!x?9?1?N? ?5K?5?“L?/ ?“LJ?N?O?n?c?Cz $?.?8?AcS?Cz?Cz?1? /?)vk?%?0(CzX? dK? ?M#:Xe ?.(?5? ?15?v?uzc?+? c?Cz?zc?+?m?Cz?U?NS| PSRd?.o-5?nOl4X?)?X8c?xG- 5?1?nd cccEWE?.?.o-5?n?gPSR?. ? 8z?n 8 1KKK-3 2KKK3 3?.bbb?4 4NNNzzz)?XXX?.4 4.1? . . . . . . . . . . . . . . . . . . . . . . . . . . . . .4 4.2X . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .6 4.3U6?. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .8 5uuuBP ?.10 5.1?.?. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .10 5.2)L. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .11 5.3)(J. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .11 5.4?.?O(5?. . . . . . . . . . . . . . . . . . . . .12 6)?XXX-555dddNNNXXX13 6.1+(?-5. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .13 6.2U6?-5. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .14 7uuuPSR?.?444XXX?)?XXXdddNNNXXX16 7.14X?)?XxdI?. . . . . . . . . . . . . . . . .16 7.2I?-?( . . . . . . . . . . . . . . . . . . . . . . . . . . . . .23 7.3uPSR?.?4X?)?Xxd(J. . . . . . . . . . . .23 8NNNzzz)?XXX?.oooeee26 8.1e . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .26 8.2ue?A: . . . . . . . . . . . . . . . . . . . . . . . . . . . . .27 9?555KKK?27 9.1?|8. . . . . . . . . . . . . . . . . . . . . . . . . .27 9.2. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .28 9.3( . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .29 9.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .29 10 ?.?:30 10.1 ?.:. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .30 10.2 ?.:. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .30 11 zzz30 1K- IS?5?/)?X4X?g,?o?/ )?X?)?xyf?K8I)?Kk 1. ?Nz)?X?.oe TeU?Ny)?X?iiIATCX?)?X? iUXi(Jy?N? TeI)?X?x?8c?)?xdu? i;?=7)fmN?vkCX? D(!?f?eI? TexJn?g=U?yk?5Ac) ?Xu)x?U5? 2. ?eSK ?e4X?I?)?XK$A?.e?1) ?u5? 2K 3K-CK8?(=?Nz)?X ?.oe?eNK u1?e7LnUi!d!?i IkiIi6dNXIkA?dIdX lmIX?nU3?NL 3,X?n?nf?.?.!?.! d?.3nf?.?:?8nUuN?)?X?.o e nf?.?Xe 1: f?.(? 3 3?.b? b?CAc?e?Ag,/ b?+T+?I?X b?O?vk?U/NoN b?)?X?-?X?oo? b?5?U?/?)K?UC?/?)? 4Nz)?X?. ?.k?o(?)?X) +?)+mX?zIOL?.?4X? ?%?LEWEU|?.?)?X?U6?. d?.J?| 4.1? ?e4X?g,?od?!*?/!/?/?A |A?u?/)?X?AfX)?Up ?/)?X?U= 4.1.1y yo?!S?!?2 2:? 4.1.24X?)?X+(? u2012/4-2013/44X?o)?5i?w?e? zN?O Shannon Wiener?5 H = P pi lnpi piL38?I?i ? 4 Pielou! J = H/lnS So MargalefL?. D = (S 1)/lnN S8Nk?N )?X?+?)?G?13,14? O?)?XL1 L 1: ?)?X+?)? aO a?5HLD!P S?S?S? ja1083.075.286.040.561.731.420.280.140.69 2i511.792.544.0115.3420.2819.180.350.470.54 .461.01.212.440.941.211.440.390.310.73 202.541.303.2827.3513.3230.280.840.750.87 4.1.3?)?X? X ?)?X? XnE,)a7N? eX XL2 L 2: ?)?X? X )?!.7!2i9U?11? ? 5, 52i!?. g?1?S M?!?! !)q? n?p?S “?!Mja )?!9? 5? z?.? ?11X/aD ?C ?. SB jaA0E?U$?p? ? ?XX e C + D k1 2C(?) B + C k2 2B(?) A + B k3 2A(ja) A k4 E(jak? ABCDOj!?. S!?a?k1k2k3O?! ?. Sj?OXk4ja?k?XddX? dC dt = k1CD k2CB dB dt = k2CB k3AB dA dt = k3AB k4A (1) 5 ?dC dt = 0, dB dt = 0, dA dt = 0?|?) A = k2 k3 C, B = k4 k3 , C = k3 k2 A, D = k2k4 k1k3 (2) |?)wD?A!B!C?O?Xk2?L ?a?o|uDk3?Lja?Oa;? 3ek1,k2,k3,k4D ?k2k4 k2k1UCkv ? ?B kk4 k3?JA)? XJ)?X?.Z6LX?gN!U=m=E ,?eXTPX?(?U”N U6 4.2X 4.2.1 4X?XI34X?g,?oJS?! ?3? ?2011c?2S?+U ,?#30a?+?#18az?/(10m 10m; .+?L3 L 3: ?/?V 8 S? 2011-042012-042011-042012-042011-042012-04 (/hm2)3240032400188001880072007200 9(cm)9.40479.85467.89698.42768.65329.1939 p(m)6.156.405.505.755.856.10 I 22b31042.9700N;22b31042.2800N;22b31041.5000N; 114b00008.8000E114b00007.0500E114b00006.8300E 4.2.2?. ?)?X%;?%;C!I%;Cv!o7N% ;CL1%;CWnKk C = CV+ CL+ CW+ CS(3) )?X%;OC )?X%;O=%L?%;OCV!I%; OCL!o7N%;OCW1%;OCS?= C = CV+ CL+ CW+ CS(4) o?)?GPP?)?NPP ?)?g?)L1zEk?)o?) ?GPP?)?NPPcg?)?ko%?! 6 I)O?o?)?g?)3? ?K?I)L)OB ? ( GPP = Ra+ L + CV NPP = L + B (5) ?Ra?“?!Z?X? Ra= Rl+ Rs+ Rr p a2+ b2(6) ?%;OCV ?%;OGPP?RaI)L CV= GPP Ra L(7) 1%;OCS 1%;OS?%En?%Ex1)? Rh?Me? CS= En+ Ex Rh Me(8) I%;OCL %I)L%)D)D! H! ?I?S?%EnKk CL= L D H I En(9) (9)?4X?)?X%? 4.2.3?.?) 2011-2012c?e4X?%9OL4?.) ? L 4: 2011-2012ce4X?%9O ? ? S? 2011-42012-42011-42012-42011-42012-4 ?%CV226.2267239.511594.7031104.065840.233445407 I%CL19.234621.74520.52350.52430.10230.1140 o7%CW2.80932.819513,155813.04942.00651.9091 1%CN426.1060430.3850176.1760176.8960188.2110188.0190 X%C674.3766694.4612284.5584294.5355230.5528234.5828 ?OCV13.28489.36274.3077 IOCL2.51060.00080.0117 o7OCW0.0102-0.1064-0.0974 1OCS4.2790.72-0.192 XOC20.08469.97714.03 ?“?.LSPSSO?L5dx4X? %?X3 7 L 5: 4X?% 8S? ? o?)?(GPP)35.924219.90168.6771 ?)?(NPP)23.838214.74336.4751 ?(Ra) “?4.84542.25940.9670 Z?6.15782.72841.1677 X?1.07280.17050.0673 O12.07605.15832.1674 I)(L)10.55345.38062.1674 ?%;O(CV)13.28489.36274.3077 I? I)(L)10.55345.38062.1674 D)(D)+ 5.27075.03322.0376 (H)+?(I) IN1?%(En)2.77210.34660.1181 I%;O(CL)2.51060.00080.0117 1? S?%(En)2.65440.27810.0619 ?!(Ex)3.32001.15220.2640 1)?(Rh)1.60920.40250.2494 ?(Mc)0.08620.30780.2685 1%;O(Cs)4.2790.72-0.192 3: 4X?%? 4.3U6?. 4.3.1uEWE?.?U6 EWE?. EWE?.3?)?XdX?k)?U|group box| ?U|)k”?!2i)!a!a?,c#|a)? A5X? ?!?,c#|?kU|U ?CXT)?XU6?L3?Lb?)?X?U|? 8 -?=LT)?X?oo?eL Q = P + R + U(10) QP)?R?Uz? 9?nuzU|? Pi= Yi+ B2iMi+ Ei+ BAi+ Pi(1 EEi)(11) PiU|i?o)?YiU|i ?oMM2iU|io? k?EiU|i ?(- )BAiU|?) EEiU|i?)?E?=z?M0i“LU|i?k? LU|?)?)?U|)? )3 )M? |?L Bi ( P B )i n X j=1 Bj(Q B )j DCji ( P B )i (1 EEi) Yi Ei BAi= 0(12) Bi ( P B )i EEi n X j=1 Bj(Q B )j DCji Yi Ei BAi= 0(13) EWE?.?.I?kBi!(P B)i!Q( Q B)j!EEi!DCji Eic4 ?knL3?.g1$? L5)U/U3)?XU|m?69 U|?)0 ?)3 ?6?1)? XE?m?p?1 4.3.2?.?N) ?.)ckI4X?)?XU|?1NyIOXe 1. 3zEWE?.U|?yL?I”?| 2. l)?)? q?+y?U|?D ?)a?5y 3. y?U|U?CX)?XU6?Lc 3U|U? ?K?54X?/)?Xy15 U|=s!6c) !20c) !_! !N!?a!fa!.!2i!2i!ja” ? EWE?.?kI?y0 EE 1IL?.?ENk?0 X2o- 5?nT)?XU6L?C-?dXA?5 ?nG?JX?F?A?1 3 2?A nSy?p dX)?XU6?-U= = n X i=1 i|i|(19) i“L1iG?-= i= Xi n P i=1 Xi ?X?N?X-U?)?X?G? Il)?54X/?)?XU6L? Z6?K?l-O?(J5w?c4X?Xk-|Z 6?X?gN!U,(?)3XS? 7uPSR?.?4X?)?XdNX 7.14X?)?XxdI? dud(JOfX!G?fX!AfXO?DIp! 16 DIs!DIrnfX?(J?1?)?Xn?DdI fXd?z=?pLG?4zfXeq?e ZdIx!fXIm?XXe10 10: x!fXdI?X )?X?n?Dz ?)?X?xGy x!x!x9xox?yIO5I?)? XxdNX66 L 10: ?xGy ?D 8060 D 8035 D 60D 35 ?xxxx duINXI?a.E,I?jdIk 55IdI?1IOz?n?n?zIA XA?0-1 ?p?xG? 7.1.1fXdI? 5I?-%-A?6? IOIy9?O?a.L11 L 11: a.?yIO #?O -% - a./km2? 10002352318.81.1 2p83,4,5501-10003414327.35.4 386401-5001245710.03.0 4$87,8201-4002610220.99.7 5L9,10101-2001775114.213.0 6D1151-10065435.29.4 17 7D1226-5022761.86.5 84D13,14,152-2520991.730.9 9160-1930.121.0 w,?p)?X?L11d? XXe L 12: d 1000 (/km2)25501002004005001000 00.10.20.30.40.50.60.81 LuY GDP 2014c?GDPo23560.94? ?I13?GDP I?O: S1= 1 0.4G G0 (20) G2014c?e?GDPoG02014 c?GDP o o? ?O2014c1-10?e/?o?5189.76 ? ? I13?o?I?O S2= 1 0.4V V0 (21) V?e2014c1-10?o?V02014 c1-10 ?o? / / /API5i?A/z? Vg5/?L?/GuL? GCz/?/k!o2!2 2 !?z?!?z1!?z%!?!u5kz? /5?/?A?AUSl0.970.611.000.680.690.490.590.410.000.00 ?0.531.000.450.600.380.250.160.570.890.54 d0.440.720.690.000.410.050.150.121.000.27 0.220.440.470.280.090.010.011.000.960.72 0.170.200.140.330.190.020.030.420.9070.57 ?0.000000.310.380.000.000.000.260.880.39 4X1.000.600.120.850.410.420.850.000.291.00 px0.780.450.501.000.780.900.900.890.460.99 A0.780.370.000.530.130.311.000.890.460.99 H?0.780.370.210.680.530.280.190.890.460.99 ?0.780.370.300.910.661.000.280.890.460.99 M0.810.190.250.270.470.370.160.890.460.99 0.440.220.140.180.440.200.110.580.250.16 0.530.670.240.850.660.870.430.610.410.33 )G)G?oS?)?G3? ?5IIO 19 5)?5dIO6?IO)?5yo? ?XL16 L 16: )?5?IO ?)?5G pBI 60pLAk)?XL? 30 BI 60?LAk?/)?5pL 20 BI 30?Ak)?5oNY $BI 20yAk)?54$ )?5d)L!)+L!Ak5! %?L!?5?NOXe dI?O 1. )L)+L )L)+LORvRpLO)? )+? 2. Ak5 Ak5UeO ED= NEV 635 + NEP 3662 2 (22) EDLAk5 NEVL?dSIAk?)? NEPL?dSIAk?)+? 635L)? 3662L)+? 3. %?L %?LUeO Rr= Nrv 635 + Nrp 3662 2 (23) RrL%?L NrvL?dS%?)? NrpL?dS%?)+? 4. ?5 ?5)?5?5?5UeO Ei= Ni NV+ NP (24) EiL?5 NiL?dS?5 NVL?dS)? NPL?dS)+? 20 ?dI?8z?n8z?dI=8zc?dI8 zX8zX= 100 AmaxAmax ?OI8z?nc? I?L17 L 17: dI?9?- dI?- )+L36620.25 )L6350.25 Ak50.30700.25 %?L0.15720.125 ?50.14410.125 nI?-dI?-L17 o)?5O)?5UeO BI = Rv. 0.2 + RP. 0.2 + DE. 0.2 + ED. 0.2 + Rr. 0.1 + (100 EI.) 0.1 BIL)?5 Rv. L8z?)L RP.L8z?)+L DE.L8z?)?Xa.?5 ED.L8z?Ak5 Rr.L8z?%?L EI.L8z?5 G Y 5uT-S? ?/YYYd6?IO7) ?Y5aza?NIXL18 L 18: YYdIO IaIIaIIIaIVa zI?COD2345 ?N0.20.30.40.5 Hg0.000050.000050.00020.00005 6Cd0.0010.0050.010.01 YPd0.0010.0050.010.05 ?As0.020.030.050.05 Cu0.0050.010.050.05 Zn0.020.050.10.5 u50.0050.0050.010.05 ?0.0150.030.030.045 1 5?/1d6?dIO?I5 1?1? ?1pH !k!o?!o?!o%5 fdI? ?.d;*KX(df?- 21 dudImy5d|?18z?n(c J(+.1k!o?!o?!o%? I(x) I(x) = 1.0,X X2; 0.9(X X1) X2 X1 ,X1 X X2; 0.1,X X1. (25) (S?I1?IO2(1k!?!? ?!?%?=:X1!X2?I=:X1!X2?L19 L 19: 1?I-=:? dIk(g/kg)o?(g/kg)o?(g/kg)o%(g/kg) X160.50.410 X2402.02.050 ?pH I1UX)?kZd? .?e1pH ?L (x) = 1,b1 x b2 x a1 b1 b2 ,a x b a2 x a2 b2 ,b2 x a2 0,x a1x a2 (26) pH d?.a1!a2!a3!a4?z1IO3O? 4.5!8.5!6.5!7.81?nI$L IFI = X Wi Ii(27) IFI 1?nI?0 1 m?pL1? Wi!IiOLdI?- df?-XWidX(dfm?X LSPSS19.0?OdImX?kIX o?-=?dI?-XL20 L 20: dI?X?-X dIXrea)?-Xrea/ P rea) pH0.65560.2355 o?0.61480.2208 o?0.50460.1813 o%0.66420.2385 k0.34480.1239 du1?IFI0?1m?d?IFI 1? 22 7.1.3AfXdI? ?o?O Ig,?oa.?Oy?K?n? L 21: ?o?OdIO ?o?OI? 10.60.2 ?o? ?o?N?-)?+nYdIz L 22: ?o?dIO ?p9e 10.70.3 ?oc ?ocTKT = M NM“L?SN “Lc IO L 23: ?ocdIO ?ocIO?20050-20050e 10.650.2 D 1. D?o?r!(”!?aLu 2?S/!OI?/?!E?/? K 1 2. 3D?m?D?k?K ?k?AU?U?/?o? 0.7 3. m?E?D?Kk?S? J 0.4 4. =k?Dw?K0.1 7.2I?-?( ?gI?-?1Dyaahp OI? -?(JXL24 7.3uPSR?.?4X?)?Xxd(J 7.3.1fXd(J 2013?eOc?e5282/km2?LdI O?K?0.1 23 L 24: )?XxdI OK?I?- 0.2297 0.04590.0459 LuY 0.0460 o?0.0230 GDP0.0230 /G 0.169 /0.1033 c4U0.0344 G? 0.6483 G 0.1616?50.1616 ?G 0.3882 ?0.0520 ?a0.1489 ?90.0487 ?p0.0480 ?CX0.0906 G 0.1050 c0.0204 cY0.0204 Y0.0611 A 0.1220 ?o?O0.0642 ?A 0.1220 ?o?0.0145 ?oc0.0312 D0.0122 LuY GDP #L?#?2014c?eGDPo16001.98?GDP ? S1= 1 0.4 16001.98 23560.94 = 0.7284 o? du?e2014c1-10?o?I1?TS2= 1 0.4 = 0.6 /G / ?u?52014c?I-:/16 2014 c?e? /?33?/0I?1 c4U 2013?e?eI?*?c4p35.1e y38?12Fpp 35eU1 U?c4$6.7ey312 ?19 F$ 5eF0 UdIOTI1 7.3.2G?fXd(J ?GL144X?!?a!?p! ?9!?CX8z?O0.12!0.41!0.42!0.85!0.85? AI?0.12!0.41!0.42!0.85!0.85 24 ?5K8?O?)+L!) L!Ak5!%?L!?5I?O 83.41!85.21!89.93!97.04!90.31?Bi? Bi= 0.25 83.41 + 0.25 85.21 + 0.25 89.93 + 0.125 97.04 + 0.125 90.31 = 88.07 d?5I?0.8807 G Y N?J?L2012c4X?/Yoi:Y!qu
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