新高考數(shù)學(xué)一輪復(fù)習(xí)百題刷過(guò)關(guān)專(zhuān)題13 數(shù)列的性質(zhì)必刷小題100題(原卷版)

專(zhuān)題13數(shù)列的性質(zhì)必刷小題100題任務(wù)一:善良模式(基礎(chǔ))1-30題一、單選題1．已知SKIPIF1<0為等差數(shù)列SKIPIF1<0的前n項(xiàng)和，且滿足SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知SKIPIF1<0為等比數(shù)列，SKIPIF1<0是它的前n項(xiàng)和．若SKIPIF1<0，且SKIPIF1<0與SKIPIF1<0的等差中項(xiàng)為SKIPIF1<0，則SKIPIF1<0（）A．29 B．31 C．33 D．353．已知數(shù)列SKIPIF1<0的通項(xiàng)公式是SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．3027 D．30284．在等比數(shù)列SKIPIF1<0中，已知SKIPIF1<0，SKIPIF1<0SKIPIF1<0，則SKIPIF1<0（）A．63 B．SKIPIF1<0 C．2 D．SKIPIF1<05．記SKIPIF1<0為正項(xiàng)等比數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的值為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．等差數(shù)列{an}的首項(xiàng)為1，公差不為0.若a2，a3，a6成等比數(shù)列，則{an}前6項(xiàng)的和為（）A．－24 B．－3C．3 D．87．已知數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．10 D．SKIPIF1<08．若SKIPIF1<0為數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，且SKIPIF1<0，則SKIPIF1<0等于（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．在公差大于0的等差數(shù)列SKIPIF1<0中，SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0成等比數(shù)列，則數(shù)列SKIPIF1<0的前21項(xiàng)和為（）A．12 B．21 C．11 D．3110．在等差數(shù)列SKIPIF1<0中，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）A．165 B．160 C．155 D．14511．記等比數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，若SKIPIF1<0則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<012．已知SKIPIF1<0為等比數(shù)列SKIPIF1<0的前n項(xiàng)和，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）．A．30 B．SKIPIF1<0 C．SKIPIF1<0 D．30或SKIPIF1<013．已知數(shù)列SKIPIF1<0為等差數(shù)列，其前n項(xiàng)和為SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）A．110 B．55 C．50 D．4514．?dāng)?shù)列SKIPIF1<0中的前n項(xiàng)和SKIPIF1<0，數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，則SKIPIF1<0（）.A．190 B．192 C．180 D．18215．已知數(shù)列SKIPIF1<0的前n項(xiàng)積為SKIPIF1<0，且滿足SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0為（）.A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<016．在等比數(shù)列SKIPIF1<0中，公比為SKIPIF1<0，前6項(xiàng)的和為SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題17．已知數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，下列說(shuō)法正確的是（）A．若點(diǎn)SKIPIF1<0在函數(shù)SKIPIF1<0為常數(shù)SKIPIF1<0的圖象上，則SKIPIF1<0為等差數(shù)列B．若SKIPIF1<0為等差數(shù)列，則SKIPIF1<0為等比數(shù)列C．若SKIPIF1<0為等差數(shù)列，SKIPIF1<0，SKIPIF1<0，則當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0最大D．若SKIPIF1<0，則SKIPIF1<0為等比數(shù)列18．已知等差數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，若SKIPIF1<0且SKIPIF1<0，則下列說(shuō)法正確的有（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<019．?dāng)?shù)列{an}的前n項(xiàng)和為Sn，SKIPIF1<0，則有（）A．Sn＝3n－1 B．{Sn}為等比數(shù)列C．a(chǎn)n＝2·3n－1 D．SKIPIF1<020．記等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，已知SKIPIF1<0，SKIPIF1<0，則有（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<021．已知Sn為等差數(shù)列{an}的前n項(xiàng)和，a3＋S5＝－18，a6＝－a3，則（）A．a(chǎn)n＝2n－9 B．a(chǎn)n＝2n－7C．Sn＝n2－8n D．Sn＝n2－6n22．設(shè)等比數(shù)列SKIPIF1<0的各項(xiàng)都為正數(shù)，其前n項(xiàng)和為SKIPIF1<0，已知SKIPIF1<0，且存在兩項(xiàng)SKIPIF1<0，使得SKIPIF1<0，則下列結(jié)論正確的是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<023．設(shè)SKIPIF1<0是數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，SKIPIF1<0，SKIPIF1<0，則下列說(shuō)法正確的有（）A．?dāng)?shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0B．?dāng)?shù)列SKIPIF1<0為遞增數(shù)列C．?dāng)?shù)列SKIPIF1<0的通項(xiàng)公式為SKIPIF1<0D．?dāng)?shù)列SKIPIF1<0的最大項(xiàng)為SKIPIF1<0第II卷（非選擇題）三、填空題24．已知等比數(shù)列SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0_________．25．已知數(shù)列SKIPIF1<0的各項(xiàng)均為正數(shù)，其前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且滿足SKIPIF1<0，則滿足SKIPIF1<0的最大的正整數(shù)SKIPIF1<0等于_________．26．已知數(shù)列SKIPIF1<0的首項(xiàng)SKIPIF1<0，滿足SKIPIF1<0，則SKIPIF1<0__________.27．九連環(huán)是中國(guó)的一種古老智力游戲，它用九個(gè)圓環(huán)相連成串，環(huán)環(huán)相扣，以解開(kāi)為勝，趣味無(wú)窮．中國(guó)的末代皇帝溥儀SKIPIF1<0也曾有一個(gè)精美的由九個(gè)翡翠繯相連的銀制的九連環(huán)（如圖）．現(xiàn)假設(shè)有SKIPIF1<0個(gè)圓環(huán)，用SKIPIF1<0表示按照某種規(guī)則解下SKIPIF1<0個(gè)圓環(huán)所需的銀和翠玉制九連環(huán)最少移動(dòng)次數(shù)，且數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0_______．28．已知SKIPIF1<0為數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，數(shù)列SKIPIF1<0是等差數(shù)列，若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0___________.29．正項(xiàng)等差數(shù)列SKIPIF1<0的前SKIPIF1<0和為SKIPIF1<0，已知SKIPIF1<0，則SKIPIF1<0=__________.30．已知等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0________________．任務(wù)二:中立模式(中檔)1-40題一、單選題1．設(shè)數(shù)列SKIPIF1<0滿足SKIPIF1<0，則數(shù)列SKIPIF1<0的前n項(xiàng)和SKIPIF1<0為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知等差數(shù)列SKIPIF1<0且SKIPIF1<0，則數(shù)列SKIPIF1<0的前13項(xiàng)之和為（）A．26 B．39 C．104 D．523．已知公比不等于SKIPIF1<0的等比數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)乘積為SKIPIF1<0，若SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．設(shè)數(shù)列SKIPIF1<0和SKIPIF1<0的前SKIPIF1<0項(xiàng)和分別為SKIPIF1<0，SKIPIF1<0，已知數(shù)列SKIPIF1<0的等差數(shù)列，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．?dāng)?shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0，則（）A．?dāng)?shù)列SKIPIF1<0是公比為2的等比數(shù)列 B．SKIPIF1<0C．SKIPIF1<0既無(wú)最大值也無(wú)最小值 D．SKIPIF1<06．已知數(shù)列SKIPIF1<0滿足：SKIPIF1<0，SKIPIF1<0SKIPIF1<0，則SKIPIF1<0()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0（SKIPIF1<0且SKIPIF1<0），數(shù)列SKIPIF1<0的前n項(xiàng)和為Sn，則（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<08．已知等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）A．15 B．23 C．28 D．309．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<010．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，設(shè)SKIPIF1<0，若數(shù)列SKIPIF1<0是單調(diào)遞減數(shù)列，則實(shí)數(shù)SKIPIF1<0的取值范圍是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<011．在數(shù)列SKIPIF1<0中，SKIPIF1<0，則SKIPIF1<0（）A．25 B．32 C．62 D．7212．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0=（）A．-1 B．SKIPIF1<0C．1 D．213．記首項(xiàng)為1的數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且SKIPIF1<0時(shí)，SKIPIF1<0，則SKIPIF1<0的值為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<014．設(shè)SKIPIF1<0為數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，SKIPIF1<0，且SKIPIF1<0.記SKIPIF1<0為數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，若對(duì)任意SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的最小值為（）A．3 B．SKIPIF1<0 C．2 D．SKIPIF1<015．設(shè)等比數(shù)列SKIPIF1<0的公比為SKIPIF1<0，前SKIPIF1<0項(xiàng)和為SKIPIF1<0.若SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的值為（）A．2 B．3 C．4 D．516．設(shè)數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，已知SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（）A．510 B．511 C．512 D．51417．設(shè)等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，數(shù)列SKIPIF1<0的前SKIPIF1<0和為SKIPIF1<0，已知SKIPIF1<0，若SKIPIF1<0，則正整數(shù)SKIPIF1<0的值為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<018．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0前n項(xiàng)之和為SKIPIF1<0，則滿足不等式SKIPIF1<0的最小整數(shù)n是（）A．60 B．62 C．63 D．6519．已知函數(shù)SKIPIF1<0的圖像過(guò)點(diǎn)SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0．記數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<020．已知數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，且滿足SKIPIF1<0，數(shù)列SKIPIF1<0的通項(xiàng)SKIPIF1<0，則使得SKIPIF1<0恒成立的最小的k值最接近（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．1二、多選題21．已知等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，公差SKIPIF1<0，SKIPIF1<0，SKIPIF1<0是SKIPIF1<0與SKIPIF1<0的等比中項(xiàng)，則下列選項(xiàng)正確的是()A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0有最大值 D．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的最大值為2122．等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，公差為SKIPIF1<0，SKIPIF1<0，則下列結(jié)論正確的是（）A．若SKIPIF1<0，則SKIPIF1<0B．若SKIPIF1<0，則SKIPIF1<0最小C．SKIPIF1<0D．SKIPIF1<023．已知數(shù)列{an}滿足a1＝1，nan+1﹣（n+1）an＝1，n∈N*，其前n項(xiàng)和為Sn，則下列選項(xiàng)中正確的是（）A．?dāng)?shù)列{an}是公差為2的等差數(shù)列B．滿足Sn＜100的n的最大值是9C．Sn除以4的余數(shù)只能為0或1D．2Sn＝nan24．等差數(shù)列SKIPIF1<0與SKIPIF1<0的前SKIPIF1<0項(xiàng)和分別為SKIPIF1<0與SKIPIF1<0，且SKIPIF1<0，則（）A．SKIPIF1<0 B．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0，SKIPIF1<025．已知等比數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0是SKIPIF1<0與SKIPIF1<0的等差中項(xiàng)，數(shù)列SKIPIF1<0滿足SKIPIF1<0，數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，則下列命題正確的是（）A．?dāng)?shù)列SKIPIF1<0的通項(xiàng)公式為SKIPIF1<0B．SKIPIF1<0C．?dāng)?shù)列SKIPIF1<0的通項(xiàng)公式為SKIPIF1<0D．SKIPIF1<0的取值范圍是SKIPIF1<026．已知等差數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，且滿足SKIPIF1<0，SKIPIF1<0，則（）A．?dāng)?shù)列SKIPIF1<0是遞增數(shù)列 B．?dāng)?shù)列SKIPIF1<0是遞增數(shù)列C．SKIPIF1<0的最小值是SKIPIF1<0 D．使得SKIPIF1<0取得最小正數(shù)的SKIPIF1<027．已知SKIPIF1<0為等差數(shù)列，其前SKIPIF1<0項(xiàng)和SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0，則（）A．公差SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．當(dāng)且僅當(dāng)SKIPIF1<0時(shí)SKIPIF1<028．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，對(duì)于任意SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，不等式SKIPIF1<0恒成立，則SKIPIF1<0的取值可以是（）A．1 B．2 C．SKIPIF1<0 D．429．設(shè)等差數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，公差為SKIPIF1<0．已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（）A．?dāng)?shù)列SKIPIF1<0的最小項(xiàng)為第SKIPIF1<0項(xiàng) B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0時(shí)，SKIPIF1<0的最大值為SKIPIF1<030．已知SKIPIF1<0，且SKIPIF1<0，則下列結(jié)論正確的是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0第II卷（非選擇題）三、填空題31．已知等差數(shù)列SKIPIF1<0，SKIPIF1<0的前SKIPIF1<0項(xiàng)和分別為SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0______．32．已知SKIPIF1<0是數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，求數(shù)列SKIPIF1<0的通項(xiàng)公式___________.33．已知數(shù)列SKIPIF1<0滿足：SKIPIF1<0，SKIPIF1<0（SKIPIF1<0，SKIPIF1<0），則SKIPIF1<0___________.34．?dāng)?shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和SKIPIF1<0，SKIPIF1<0.設(shè)SKIPIF1<0，則數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和SKIPIF1<0___________.35．?dāng)?shù)列SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0_______.36．已知數(shù)列SKIPIF1<0，SKIPIF1<0均為等比數(shù)列，前SKIPIF1<0項(xiàng)和分別為SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0___________.37．已知數(shù)列SKIPIF1<0為等差數(shù)列，公差SKIPIF1<0，且滿足SKIPIF1<0，則SKIPIF1<0___________.38．設(shè)數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，數(shù)列前n項(xiàng)和為SKIPIF1<0，且SKIPIF1<0（SKIPIF1<0且SKIPIF1<0），若SKIPIF1<0表示不超過(guò)x的最大整數(shù)，SKIPIF1<0數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，則SKIPIF1<0_____________．39．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，設(shè)SKIPIF1<0，SKIPIF1<0為數(shù)列SKIPIF1<0的前n項(xiàng)和．若SKIPIF1<0對(duì)任意SKIPIF1<0恒成立，則實(shí)數(shù)SKIPIF1<0的最小值為_(kāi)_______40．設(shè)SKIPIF1<0為數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和，SKIPIF1<0，則數(shù)列SKIPIF1<0的前7項(xiàng)和為_(kāi)_______.任務(wù)三:邪惡模式(困難)1-30題一、單選題1．?dāng)?shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，若數(shù)列SKIPIF1<0為單調(diào)遞增數(shù)列，則SKIPIF1<0的取值范圍為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知正項(xiàng)數(shù)列SKIPIF1<0中，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則使不等式SKIPIF1<0成立的最小整數(shù)n為（）A．3 B．4 C．5 D．63．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，記數(shù)列SKIPIF1<0前SKIPIF1<0項(xiàng)和為SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0．記SKIPIF1<0為數(shù)列SKIPIF1<0的前n項(xiàng)和，則（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．英國(guó)著名物理學(xué)家牛頓用“作切線”的方法求函數(shù)零點(diǎn)時(shí)，給出的“牛頓數(shù)列”在航空航天中應(yīng)用廣泛，若數(shù)列SKIPIF1<0滿足SKIPIF1<0，則稱(chēng)數(shù)列SKIPIF1<0為牛頓數(shù)列.如果函數(shù)SKIPIF1<0，數(shù)列SKIPIF1<0為牛頓數(shù)列，設(shè)SKIPIF1<0且SKIPIF1<0，SKIPIF1<0，數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．在數(shù)列{an}中．a(chǎn)1＝4，a2＝6，且當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，若Tn是數(shù)列{bn}的前n項(xiàng)和，bn＝SKIPIF1<0，則當(dāng)SKIPIF1<0為整數(shù)時(shí)，λn＝（）A．6 B．12 C．20 D．247．已知等比數(shù)列SKIPIF1<0的公比為3，前SKIPIF1<0項(xiàng)和為SKIPIF1<0，若關(guān)于SKIPIF1<0的不等式SKIPIF1<0有且僅有兩個(gè)不同的整數(shù)解，則SKIPIF1<0的取值范圍為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<08．已知數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和為SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<09．已知無(wú)窮遞減實(shí)數(shù)列SKIPIF1<0滿足SKIPIF1<0，則下列可作為SKIPIF1<0遞推公式SKIPIF1<0的是（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<010．已知SKIPIF1<0，若數(shù)列SKIPIF1<0的前SKIPIF1<0項(xiàng)和是SKIPIF1<0，設(shè)SKIPIF1<0，設(shè)SKIPIF1<0，當(dāng)且僅當(dāng)SKIPIF1<0時(shí)，不等式SKIPIF1<0成立，則實(shí)數(shù)SKIPIF1<0的范圍為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．已知數(shù)列SKIPIF1<0的各項(xiàng)均不為零，SKIPIF1<0，它的前n項(xiàng)和為SKIPIF1<0．且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0（SKIPIF1<0）成等比數(shù)列，記SKIPIF1<0，則（）A．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0 B．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0C．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0 D．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<012．已知數(shù)列{an}滿足3a1＝1，n2an+1﹣an2＝n2an（n∈N*），則下列選項(xiàng)正確的是（）A．{an}是遞減數(shù)列B．{an}是遞增數(shù)列，且存在n∈N*使得an＞1C．SKIPIF1<0D．SKIPIF1<013．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0，則下列說(shuō)法中錯(cuò)誤的是（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<014．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，則下列選項(xiàng)正確的是（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<015．已知數(shù)列SKIPIF1<0滿足SKIPIF1<0.記數(shù)列SKIPIF1<0的前n項(xiàng)和為SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<016．已知數(shù)列SKIPIF1<0與SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，下列正確的是（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0是等差數(shù)列 D．SKIPIF1<0是等比數(shù)列二、多選題17．設(shè)SKIPIF1<0是無(wú)窮數(shù)列，若存在正整數(shù)k，使得對(duì)任意SKIPIF1<0，均有SKIPIF1<0，則稱(chēng)SKIPIF1<0是間隔遞增數(shù)列，k是SKIPIF1<0的間隔數(shù).則下列說(shuō)法正確的是（）A．公比大于1的等比數(shù)列一定是間隔遞增數(shù)列B．已知SKIPIF1<0，則SKIPIF1<0是間隔遞增數(shù)列C．已知SKIPIF1<0，則SKIPIF1<0是間隔遞增數(shù)列且最小間隔數(shù)是2D．已知SKIPIF1<0，若SKIPIF1<0是間隔遞增數(shù)列且最小間隔數(shù)是3，則SKIPIF1<018．我國(guó)明代音樂(lè)理論家和數(shù)學(xué)家朱載堉在所著的《律學(xué)新說(shuō)》一書(shū)中提出了“十二平均率”的音樂(lè)理論，該理論后被意大利傳教士利瑪竇帶到西方，對(duì)西方的音樂(lè)產(chǎn)生了深遠(yuǎn)的影響.以鋼琴為首的眾多鍵盤(pán)樂(lè)器就是基于“十二平均率”的理論指導(dǎo)設(shè)計(jì)的.圖中鋼琴上的每12個(gè)琴鍵（7個(gè)白鍵5個(gè)黑鍵）構(gòu)成一個(gè)“八度”，每個(gè)“八度”各音階的音高都是前一個(gè)“八度”對(duì)應(yīng)音階的兩倍，如圖中所示的琴鍵的音高SKIPIF1<0（SKIPIF1<0稱(chēng)為“中央C”）.將每個(gè)“八度”（如SKIPIF1<0與SKIPIF1<0之間的音高變化）按等比數(shù)列十二等份，得到鋼琴上88個(gè)琴鍵的音階.當(dāng)鋼琴的SKIPIF1<0鍵調(diào)為標(biāo)準(zhǔn)音440Hz時(shí)，下列選項(xiàng)中的哪些頻率（單位：Hz）的音可以是此時(shí)的鋼琴發(fā)出的音（）（參考數(shù)據(jù)：SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0）A．110 B．233 C．505 D．124419．在數(shù)列SKIPIF1<0中，其前SKIPIF1<0的和是SKIPIF1<0，下面正確的是（）A．若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0B．若SKIPIF1<0，則SKIPIF1<0C．若SKIPIF1<0，則SKIPIF1<0D．若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<020．?dāng)?shù)學(xué)中有各式各樣富含詩(shī)意的曲線，螺旋線就是其中比較特別的一類(lèi).螺旋線這個(gè)名詞來(lái)源于希臘文，它的原意是“旋卷”或“纏卷”.小明對(duì)螺旋線有著濃厚的興趣，連接嵌套的各個(gè)正方形的頂點(diǎn)就得到了近似于螺旋線的美麗圖案，其具體作法是：在邊長(zhǎng)為1的正方形SKIPIF1<0中，作它的內(nèi)接正方形SKIPIF1<0，且使得SKIPIF1<0；再作正方形SKIPIF1<0的內(nèi)接正方形SKIPIF1<0，且使得SKIPIF1<0；類(lèi)似地，依次進(jìn)行下去，就形成了陰影部分的圖案，如圖所示.設(shè)第n個(gè)正方形的邊長(zhǎng)為SKIPIF1<0(其中第1個(gè)正方形SKIPIF1<0的邊長(zhǎng)為SKIPIF1<0，第2個(gè)正方形SKIPIF1<0的邊長(zhǎng)為SKIPIF1<0，…)，第n個(gè)直角三角形(陰影部分)的面積為SKIPIF1<0(其中第1個(gè)直角三角形SKIPIF1<0的面積為SKIPIF1<0，第2個(gè)直角三角形SKIPIF1<0的面積為SKIPIF1<0，…)，則（）A．?dāng)?shù)列SKIPIF1<0是公比為SKIPIF1<0的等比數(shù)列 B．SKIPIF1<0C．?dāng)?shù)列SKIPIF1<0是公比為SKIPIF1<0的等比數(shù)列 D．?dāng)?shù)列SKIPIF1<0的前n項(xiàng)和SKIPIF1<021．斐波那契螺旋線，也稱(chēng)“黃金螺旋”，是根據(jù)斐波那契數(shù)列畫(huà)出來(lái)的螺