單片機(jī)原理與應(yīng)用第四章作業(yè)答案

4－9試計(jì)算片內(nèi)RAM區(qū)40H~47H單元中8個(gè)數(shù)據(jù)的平均值，結(jié)果存放在4Ah中;說明：先對8個(gè)數(shù)求和，結(jié)果放在30h，31h；然后用右移3次求平均。ORG0000HSJMPMAINORG0030HMIAN:MOVR0,#40HMOVR1,#30HMOV30H,#00HMOV31H,#00HMOVR2,#8CLRCL1:MOVA,@R1ADDCA,@R0MOV@R1,AINCR0INCR1MOVA,@R1ADDCA,#00HMOV@R1,ADECR1DJNZR2,L1INCR1L2:MOVR2,#03HMOVA,@R1RRCAMOV@R1,AINCR1MOVA,@R1RRCAMOV@R1,ADECR1DJNZR2,L2DECR1MOV4AH,@R1SJMP$4－10在起始地址為2100H,長度為64H的數(shù)表中查找ASCII碼’F’,如果有,將其值送到1000H單元,如果沒有,將0FFH送1000H單元.ORG0000HSJMPMAINORG0030HMAIN:MOVR2,#64MOVDPTR,#2100HL2:MOVXA,@DPTRCJNEA,#’F’,L1MOVDPTR,#1000HMOVA,#00HMOVX@DPTR,ASJMPLASTL1:INCDPTRDJNZR2,L2MOVA,#0FFHMOVX@DPTR,ALAST:SJMP$4－11試編寫將片內(nèi)40H~60H單元中的內(nèi)容傳送到外部RAM以2000h為首地址的存放區(qū)域中，并將原數(shù)據(jù)全部清零。ORG0000HSJMPMAINORG0030HMIAN:MOVR0,#40HMOVDPTR,#2000HMOVR1,#20HL1:MOVA,@R0MOVX@DPTR,AMOV@R0,#00HINCR0INCDPTRDJNZR1,L1SJMP$4－12編寫，內(nèi)部RAM50H‐59H10個(gè)單元內(nèi)容的平均值，并存放在5AH單元。ORG0000HSJMPMAINORG0030HMIAN:MOVR1,#50HMOV30H,#00HMOV31H,#00HMOVR2,#0AHMOV5AH,#00HL1:MOVA,@R1ADDA,@R1MOV30H,AMOVA,#00HADDCA,31HMOV31H,AINCR1DJNZR2,L1MOVR3，31HMOVR2，30HMOVR4，#10ACALLDIV16_8MOV5AH,R5SJMP$;*********************************;除法子程序中;被除數(shù)（R3,R2),除數(shù)（R4），結(jié)果（R6,R5);*********************************DIV16_8:CLRAMOVR5,AMOVR6,ACLRPSW.5GAOWDIV:CLRCMOVA,R3SUBBA,R4JCLOOP2MOVR3,AINCR6SJMPGAOWDIV;MOVA,R6;ADDCA,#00H;MOVR6,ALOOP2:MOVR7,#08HDIWDIV:CLRC;MOVA,R5;RLCA;MOVR5,AMOVA,R2RLCAMOVR2,AMOVA,R3RLCAMOVR3,AMOVPSW.5,CCLRCSUBBA,R4JBPSW.5,DIWDIV1JCDIWDIV2DIWDIV1:MOVR3,AINCR2DIWDIV2:DJNZR7,DIWDIVMOVA,R2MOVR5,ACLRPSW.5RET;********************************4－14試編寫內(nèi)部RAM40H為首地址的連續(xù)20個(gè)單元的內(nèi)容按降序排列，并存放到外部RAM2000H為首地址的存儲區(qū)中。匯編程序：Sizeequ20；數(shù)據(jù)個(gè)數(shù)Arrayequ40h；數(shù)據(jù)起始地址Changebit0；交換標(biāo)志ORG0000HSJMPSortORG0030HSort:MOVR0，#ArrayMOVR7，#Size-1CLRChangeGoon:MOVA，@R0MOVR2，AINCR0MOVB，@R0CJNEA，B，NotEqualSJMPNextNotEqual:JCNext；前小后大，不交換SETBChange；前大后小，設(shè)交換標(biāo)志XCHA，@R0；交換DECR0XCHA，@R0INCR0Next:DJNZR7，GoonJBChange，SortMOVR0，#ArrayMOVR7，#SizeMOVDPTR,#2000HL1:MOVA,@R0MOVX@DPTR,AINCROINCDPTRDJNZR7,L1LJMP$4－15試編寫一查表程序，從首地址為2000H,長度為16的數(shù)據(jù)快中找出ASCII碼D，將其地址送到20A0H~20A1H單元中。ORG0000HSJMPMIANORG0030HMAIN:MOVDPTR,#4000HMOVR0,#16-1L1:MOVA,R0MOVCA,@A+DPTRCJNEA,#43H,L2SJMPL3L2:DJNZR0,L1SJMPLASTL3:ADDA,DPLMOV30H,A;結(jié)果暫存在31h，30hMOVA,#00HADDCA,DPHMOV31H,AMOVDPTR,#20A0H;結(jié)果存入到片外20A1h，20A0hMOVA,30HMOVX@DPTR,AINCDPTRMOVA,31HMOVX@DPTR,ALAST:SJMP$ORG2000HDB30H,31H,32H,33H,34H,35H,36H,37H,38H,39H,40H,41H,42H,43H,44H,45H4－16試編寫表程序，將存放在內(nèi)部RAM起始地址為30h的20個(gè)十六進(jìn)制數(shù)分別轉(zhuǎn)換為相應(yīng)的ASCII碼，結(jié)果存入內(nèi)部RAM起始地址為50h的連續(xù)單元中。ORG0000HSJMPMAINORG0030HMAIN:MOVR0,#30HMOVR1,#50HMOVR2,#20LOOP:MOVA,@R0MOVDPTR,#TABMOVCA,@A+DPTRMOV@R1,AINCR1INCR0DJNZR2,LOOPSJMP$TAB:DB30H,31H,32H,33H,34H,35H,36H,37H,38H,39H,40H,41H,42H,43H,44H,45H程序，將存放在內(nèi)部RAM起始地址為40H的N個(gè)ASCII碼分別轉(zhuǎn)化為相應(yīng)的十六進(jìn)制數(shù)，結(jié)果存入內(nèi)部RAM起始地址為60H的連續(xù)單元中。解答：NEQU20HORG0000HSJMPMAINORG0030HMAIN:MOVR0,#40HMOVR1,#60HMOVR2，#NBCD1:MOVA,@R0ACALLHBCDMOV@R1,50HINCR0INCR1DJNZR2,BCD1SJMP$HBCD:CJNEA,#30H,L1L1：JCLASTCJNEA,#40H,L2L2：JCL3CJNEA,#46H,L4L4：JCL5SJMPNONUML5：CLRCSUBBA,#36HMOV50H,ASJMPLASTL3：CLRCSUBBA,#30HMOV50H,ASJMPLASTNONUM:MOV50H,#0FFHLAST:RET4－18設(shè)在外部RAM2000h~2014h單元中，存放有5個(gè)壓縮BCD碼，試編寫程序?qū)⑺鼈冝D(zhuǎn)換成ASCII碼，存放在以2005H單元為首地址的存儲區(qū)中。ORG0000HSJMPMAINORG0030HMAIN:MOVR0,#40H；壓縮BCD碼變成非壓縮BCD碼MOVR1,#5MOVDPTR,#2000HL1:MOVXA,@DPTRMOV30H,AANLA,#0FHMOV@R0,AINCR0MOVA,30HSWAPAANLA,#0FHMOV@R0,AINCR0INCDPTRDJNZR1,L1MOVR0,#40H;40H存儲區(qū)的非壓縮BCD碼轉(zhuǎn)換成ASCII碼，存放在以40H單元為首地址的存儲區(qū)中。MOVR1,#0AHMOVDPTR,#TABL2:MOVA,@R0MOVCA,@A+DPTRMOV@R0INCR0DJ