數(shù)值計(jì)算方法上機(jī)題

1、第二章插值法計(jì)算公Lagrange插值多項(xiàng)Newton 向前插值計(jì)算公式Newton 向后插值公第二章插值法計(jì)算公Lagrange插值多項(xiàng)Newton 向前插值計(jì)算公式Newton 向后插值公式解線性代數(shù)方程組的迭代cout輸入各點(diǎn)的坐標(biāo)值1.1Lagrangecout輸入要計(jì)算的點(diǎn)的橫坐標(biāo)li=(xr-xj)/(xi-coutx 對(duì)應(yīng)的函數(shù)值為: constvoid main()double double xr;cout輸入插值點(diǎn)的個(gè)數(shù)1.2 Newton 向前插值計(jì)算公輸出所求點(diǎn)的y for(j=0;jn-rij=ri-1j+1-ri-for(j=0;jn-rij=ri-1j+1-ri-否

2、插值公式累double pp=1; 是constvoid main()double double double xr;double double t=1.0;cout輸入各點(diǎn)的坐標(biāo)值cout輸入要計(jì)算的點(diǎn)的橫坐標(biāo):cout=0;j-rij=ri-1j-ri-1j-double pp=1; 否插值公式累是for(j=n-1;j=0;j-rij=ri-1j-ri-1j-double pp=1; 否插值公式累是constvoid main()double double double xr;double double t=1;cout coutx 對(duì)應(yīng)的函數(shù)值為/輸出x6.1 void main()d

3、ouble double 坐cout輸入系數(shù)方陣的維數(shù)輸出所求點(diǎn)的y double sum=0; double sum=0; 否是量/輸出x迭代格式通用const N=30; void main()double double cout輸入迭代次數(shù)x(k+1,i)=(b(i)-cout輸入迭代次數(shù)double sum=0; cout輸入迭代次數(shù)double sum=0; 否是/輸出x方法迭代格式通用程x(k+1,i)=(b(i)-否是double sum=0; 否是double sum=0; xk+1i=xki+w*(bi-const N=20; void main()doubledouble/

4、x 雅各比方法計(jì)算實(shí)x(k+1,i)=x(k,i)+(b(i)-否是否是double sum=0; double sumdx=0; constvoid main()doubledoublex(k+1,i)=(b(i)-temp=temp+a(i,j)*x2221112221112221112221112cout迭代結(jié)束輸入系數(shù)矩陣4-0-00-4-0-00-400-004-0-0-4-0-46輸入初始迭代向量系數(shù)矩陣為114-0-00-4-0-00-400-004-00-0-4-00-0-42221112222111222111222111222111222111222111222111222

5、1121222122211212222121212Pressanykeyto否是constN=200; const c=200; void main()double x(i)=(b(i)-輸入系數(shù)矩陣4-0-輸入系數(shù)矩陣4-0-00-4-0-00-400-004-0-0-4-0-46輸入初始迭代向量double sum=0; double sumdx=0; 系數(shù)矩陣為114-0-00-4-0-00-400-004-00-0-4-00-0-4222222Pressanykeyto6.6 方法迭代格式計(jì)算實(shí)否否是double sum=0; for(k=0; abs(xk+1-xk+1 =xk +w*(bi-sum)/aii; /xconst N=20; void main()double double xN x(k+1,i)=x(k,i)+(b(i)-輸入系數(shù)矩陣4-0-00-4-0-00-400-004-輸入系數(shù)矩陣4-0-00-4-0-00-400-004