微機原理編程題.doc

微機原理編程題1. 分支程序設(shè)計.編寫一段程序，已知BUF1單元中有一帶符號字節(jié)數(shù)據(jù)X，BUF2中有一帶符號字節(jié)數(shù)據(jù)Y，根據(jù)以下函數(shù)關(guān)系編寫程序求Z的值，結(jié)果存入RESULT 單元。Z=|X-Y|；DATA SEGMENTBUF1 DB 05HBUF2 DB 02HRESULT DB ?DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX MOV AL,BUF1 MOV BL,BUF2 SUB AL,BL JNC GREAT NEG ALGREAT:MOV RESULT,ALEXIT: MOV AH,4CH INT 21H CODE ENDS END START .編寫一段程序，已知BUF單元中有一無符號字節(jié)數(shù)據(jù)X，假設(shè)為8，根據(jù)以下函數(shù)關(guān)系編寫程序求Y的值，結(jié)果存入RESULT 單元。Z=5X X=10;DATA SEGMENTBUF DB 8RESULT DB ?DATA ENDSCODE SEGMENTASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX MOV AL,BUF CMP AL,10 JAE GRE MOV BL,AL ADD AL,AL ADD AL,AL ADD AL,BL JMP DONEGRE: SUB AL,5DONE: MOV RESULT,AL MOV AH,4CH INT 21H CODE ENDS END START.在內(nèi)存單元BUF中存放一個帶符號字節(jié)數(shù)據(jù)X，假定為-2，試根據(jù)以下函數(shù)關(guān)系編寫程序求Y的值，結(jié)果存入RESULT 單元。Y=1 X0,0 X=0,-1 X0;DATA SEGMENTBUF DB -2RESULT DB ?DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART: MOV AX,DATA MOV DS,AX MOV AL,BUF CMP AL,0 JGE L1 MOV AL,-1 JMP L3L1:JZ L2 MOV AL,1 JMP L3L2:MOV AL,0L3:MOV RESULT,AL MOV AH,4CH INT 21HCODE ENDS END START 2. N個數(shù)中求最大值、最小值.假定N=10,已知原始數(shù)據(jù)存放在BUF開始的內(nèi)存單元中，將結(jié)果存入MAX，MIN內(nèi)存單元中。DATA SEGMENTBUF DB 3,5,7,8,5,3,9,7,13,1COUNT EQU $-BUFMAX DB ?MIN DB ? DATA ENDSCODE SEGMENTASSUME CS:CODE,DS:DATASTART: MOV AX,DATA MOV DS,AX MOV CX,COUNT-1 MOV AL,BUF MOV MAX,AL MOV MIN,AL LEA SI,BUFAGAIN: MOV AL,SI+1CMP AL,MINJGE S1MOV MIN,ALS1:CMP AL,MAXJLE S2MOV MAX,ALS2: INC SI LOOP AGAIN MOV AH,4CH INT 21HCODE ENDS END START 3. 編寫程序求1+2+3+N100時最大的N值，將N值送NUM單元中，同時將1+2+3+N的和送到SUM單元中。DATA SEGMENTNUM DB ?SUM DB ?DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX MOV AL,0 MOV BL,0AGAIN:INC BL ADD AL,BL CMP AL,100 JB AGAIN SUB AL,BL DEC BL MOV NUM,BL MOV SUM,AL MOV AH,4CH INT 21H CODE ENDS END START 4. 統(tǒng)計字符，正數(shù)，負(fù)數(shù)，零的個數(shù)。若自STRING單元開始存放一個字符串，以$結(jié)尾，試編寫程序，統(tǒng)計字符串的長度，并將結(jié)果存入COUNT單元。DATA SEGMENTSTRING DB abcdefg$COUNT DW ?DATA ENDSCODE SEGMENTASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX LEA SI,STRING MOV CX,0NEXT: MOV AL,SI CMP AL,$ JZ DONE INC CX INC SI JMP NEXTDONE: MOV COUNT,CX MOV AH,4CH INT 21H CODE ENDS END START .自BUF單元開始存放10個帶符號字節(jié)數(shù)據(jù)，將其中的正數(shù)、負(fù)數(shù)和零選出來，并統(tǒng)計其個數(shù)，分別存入PLUS、MINUS和ZERO單元中。DATA SEGMENTBUF DB 5,-2,0,-1,4,0,-4,8,0,-7PLUS DB ?MINUS DB ?ZERO DB ?DATA ENDSCODE SEGMENTASSUME CS:DATA,DS:DATASTART:MOV AX,DATA MOV DS,AX LEA SI,BUF MOV CX,10AGAIN:MOV AL,BX INC BX AND AL,AL JS M1 JZ M2 INC PLUS JMP NEXTM1: INC MINUS JMP NEXTM2: INC ZERO JMP NEXTNEXT: LOOP AGAIN MOV AH,4CH INT 21H CODE ENDS END START 5. 求壓縮BCD碼的和。已知從BUF1和BUF2單元開始，存放兩個各為10個字節(jié)的BCD數(shù)，求這兩個數(shù)的和，并將結(jié)果存入BUF3單元中。DATA SEGMENTBUF1 DB 01H,01H,01H,01H,01H,01H,01H,01H,01H,01HBUF2 DB 03H,03H,03H,03H,03H,03H,03H,03H,03H,03HBUF3 DB 11 DUP(?) DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART: MOV AX,DATA MOV DS,AX MOV CX,10 LEA SI,BUF1 LEA DI,BUF2 LEA BX,BUF3AGAIN: MOV AL,SI ADC AL,DI DAA MOV BX,AL INC SI INC DI INC BX LOOP AGAIN ADC AH,0 MOV BX,AH MOV AH,4CH INT 21HCODE ENDSEND START6. 8255編程題：(課后實驗) 8255工作于方式0，此時PA、PB、PC均為可獨立輸入/輸出的并行口。8255的各寄存器對應(yīng)的口地址為：PA口：200H，PB口：202H，PC口：204H，控制口：206H。要求8255工作于方式0，PA口設(shè)置為輸入，PC口設(shè)置為輸出。DATA SEGMENTC8255 EQU 206HP8255A EQU 200HP8255C EQU 204HDATA ENDSCODE SEGMENTASSUME