版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
微專題17圓錐曲線壓軸小題【秒殺總結(jié)】1、求的離心率(或離心率的取值范圍),常見有以下方法:①求出a,c,代入公式SKIPIF1<0;②只需要根據(jù)一個(gè)條件得到關(guān)于a,b,c的齊次式,結(jié)合b2=c2-a2轉(zhuǎn)化為a,c的齊次式,然后等式(不等式)兩邊分別除以a或a2轉(zhuǎn)化為關(guān)于e的方程(不等式),解方程(不等式)即可得e(e的取值范圍).③幾何法:尋找?guī)缀侮P(guān)系,將問題轉(zhuǎn)化④坐標(biāo)法:一般套路將坐標(biāo)代入曲線求解2、解析幾何中與動(dòng)點(diǎn)有關(guān)的最值問題一般的求解思路:①幾何法:利用圖形作出對(duì)應(yīng)的線段,利用幾何法求最值;②代數(shù)法:把待求量的函數(shù)表示出來,利用函數(shù)求最值.【典型例題】例1.(2023·陜西西安·??寄M預(yù)測(cè))SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,一束光線從點(diǎn)SKIPIF1<0出發(fā)射到SKIPIF1<0上的點(diǎn)SKIPIF1<0,經(jīng)SKIPIF1<0反射后,再經(jīng)SKIPIF1<0反射,落到線段SKIPIF1<0上(不含端點(diǎn)),則SKIPIF1<0的斜率的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0例2.(2023秋·內(nèi)蒙古包頭·高三統(tǒng)考期末)已知拋物線SKIPIF1<0,斜率為SKIPIF1<0的直線SKIPIF1<0與SKIPIF1<0的交點(diǎn)為E,F(xiàn),與SKIPIF1<0軸的交點(diǎn)為SKIPIF1<0.若SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0(
)A.5 B.4 C.3 D.2例3.(2023春·全國(guó)·高三競(jìng)賽)設(shè)圓SKIPIF1<0的圓心為SKIPIF1<0,點(diǎn)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0為直線SKIPIF1<0上一點(diǎn).若圓上存在兩點(diǎn)A,B,使得點(diǎn)SKIPIF1<0滿足SKIPIF1<0,則SKIPIF1<0面積的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0例4.(2023秋·廣西南寧·高三南寧二中??计谀┮阎p曲線SKIPIF1<0的左,右焦點(diǎn)分別是SKIPIF1<0,SKIPIF1<0,點(diǎn)P是雙曲線C右支上異于頂點(diǎn)的點(diǎn),點(diǎn)H在直線SKIPIF1<0上,且滿足SKIPIF1<0.若SKIPIF1<0,則雙曲線C的離心率為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0例5.(2023·全國(guó)·模擬預(yù)測(cè))已知橢圓SKIPIF1<0的左?右焦點(diǎn)分別為SKIPIF1<0,點(diǎn)SKIPIF1<0在橢圓SKIPIF1<0上,若離心率SKIPIF1<0,則橢圓SKIPIF1<0的離心率的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0例6.(2023·四川綿陽·統(tǒng)考模擬預(yù)測(cè))已知SKIPIF1<0為拋物線:SKIPIF1<0的焦點(diǎn),過直線SKIPIF1<0上任一點(diǎn)SKIPIF1<0向拋物線引切線,切點(diǎn)分別為A,SKIPIF1<0,若點(diǎn)SKIPIF1<0在直線SKIPIF1<0上的射影為SKIPIF1<0,則SKIPIF1<0的取值范圍為______.例7.(2023·全國(guó)·高三專題練習(xí))雙曲線SKIPIF1<0的左右焦點(diǎn)分別為SKIPIF1<0,SKIPIF1<0,以實(shí)軸為直徑作圓SKIPIF1<0,過圓SKIPIF1<0上一點(diǎn)SKIPIF1<0作圓SKIPIF1<0的切線交雙曲線的漸近線于SKIPIF1<0,SKIPIF1<0兩點(diǎn)(SKIPIF1<0在第一象限),若SKIPIF1<0,SKIPIF1<0與一條漸近線垂直,則雙曲線離心率為______.例8.(2023·全國(guó)·高三專題練習(xí))已知雙曲線SKIPIF1<0的左、右焦點(diǎn)分別為SKIPIF1<0、SKIPIF1<0,點(diǎn)SKIPIF1<0在雙曲線SKIPIF1<0上,點(diǎn)SKIPIF1<0在直線SKIPIF1<0上,且滿足SKIPIF1<0.若存在實(shí)數(shù)SKIPIF1<0使得SKIPIF1<0,則雙曲線SKIPIF1<0的離心率為_____________例9.(2023秋·浙江杭州·高三浙江省桐廬中學(xué)期末)已知橢圓C:SKIPIF1<0,經(jīng)過原點(diǎn)O的直線交C于A,B兩點(diǎn).P是C上一點(diǎn)(異于點(diǎn)A,B),直線BP交x軸于點(diǎn)D.若直線AB,AP的斜率之積為SKIPIF1<0,且SKIPIF1<0,則橢圓C的離心率為______.例10.(2023秋·吉林長(zhǎng)春·高三校考階段練習(xí))已知雙曲線SKIPIF1<0的左、右焦點(diǎn)分別為SKIPIF1<0,若在右支上存在一點(diǎn)SKIPIF1<0,使得點(diǎn)SKIPIF1<0到直線SKIPIF1<0的距離為SKIPIF1<0,則雙曲線的離心率SKIPIF1<0的取值范圍是_____.例11.(2023秋·河南安陽·高三??计谀┻^拋物線SKIPIF1<0的焦點(diǎn)的直線與SKIPIF1<0交于SKIPIF1<0兩點(diǎn).設(shè)SKIPIF1<0為線段SKIPIF1<0的中點(diǎn),SKIPIF1<0,點(diǎn)SKIPIF1<0,若直線SKIPIF1<0軸,且SKIPIF1<0,則SKIPIF1<0__________.例12.(2023·全國(guó)·高三專題練習(xí))已知橢圓SKIPIF1<0與雙曲線SKIPIF1<0的離心率互為倒數(shù),且它們有共同的焦點(diǎn)SKIPIF1<0、SKIPIF1<0,P是SKIPIF1<0與SKIPIF1<0在第一象限的交點(diǎn),當(dāng)SKIPIF1<0時(shí),雙曲線SKIPIF1<0的離心率等于______.例13.(2023·全國(guó)·高三專題練習(xí))已知橢圓SKIPIF1<0:SKIPIF1<0的左、右焦點(diǎn)分別是SKIPIF1<0,SKIPIF1<0,斜率為SKIPIF1<0的直線SKIPIF1<0經(jīng)過左焦點(diǎn)SKIPIF1<0且交C于A,B兩點(diǎn)(點(diǎn)A在第一象限),設(shè)SKIPIF1<0的內(nèi)切圓半徑為SKIPIF1<0,SKIPIF1<0的內(nèi)切圓半徑為SKIPIF1<0,若SKIPIF1<0,則橢圓的離心率SKIPIF1<0___________.例14.(2023·全國(guó)·高三專題練習(xí))已知橢圓SKIPIF1<0的左焦點(diǎn)為SKIPIF1<0,過SKIPIF1<0斜率為SKIPIF1<0的直線SKIPIF1<0與橢圓SKIPIF1<0相交于SKIPIF1<0、SKIPIF1<0兩點(diǎn),若SKIPIF1<0,則橢圓SKIPIF1<0的離心率SKIPIF1<0______.【過關(guān)測(cè)試】一、單選題1.(2023秋·山東濰坊·高三統(tǒng)考期末)已知SKIPIF1<0為坐標(biāo)原點(diǎn),SKIPIF1<0是拋物線SKIPIF1<0上的動(dòng)點(diǎn),且SKIPIF1<0,過點(diǎn)SKIPIF1<0作SKIPIF1<0,垂足為SKIPIF1<0,下列各點(diǎn)中到點(diǎn)SKIPIF1<0的距離為定值的是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.(2023秋·廣東深圳·高三統(tǒng)考期末)已知交于點(diǎn)SKIPIF1<0的直線SKIPIF1<0,SKIPIF1<0相互垂直,且均與橢圓SKIPIF1<0相切,若SKIPIF1<0為SKIPIF1<0的上頂點(diǎn),則SKIPIF1<0的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(2023·江西·校聯(lián)考一模)已知雙曲線SKIPIF1<0的左、右焦點(diǎn)分別為SKIPIF1<0,點(diǎn)SKIPIF1<0在雙曲線上,且SKIPIF1<0,SKIPIF1<0的延長(zhǎng)線交雙曲線于點(diǎn)SKIPIF1<0,若雙曲線的離心率為SKIPIF1<0,則SKIPIF1<0(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.(2023·湖南永州·統(tǒng)考二模)如圖,SKIPIF1<0為雙曲線的左右焦點(diǎn),過SKIPIF1<0的直線交雙曲線于SKIPIF1<0兩點(diǎn),且SKIPIF1<0,SKIPIF1<0為線段SKIPIF1<0的中點(diǎn),若對(duì)于線段SKIPIF1<0上的任意點(diǎn)SKIPIF1<0,都有SKIPIF1<0成立,則雙曲線的離心率是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.(2023·全國(guó)·高三專題練習(xí))已知SKIPIF1<0,SKIPIF1<0是橢圓C:SKIPIF1<0的左,右焦點(diǎn),過SKIPIF1<0且傾斜角為SKIPIF1<0的直線交橢圓C于點(diǎn)P,Q(P在第一象限),SKIPIF1<0與SKIPIF1<0的平分線分別交直線SKIPIF1<0于點(diǎn)M,N,則M,N縱坐標(biāo)比SKIPIF1<0(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.-16.(2023·全國(guó)·高三專題練習(xí))用平面截圓柱面,當(dāng)圓柱的軸與SKIPIF1<0所成角為銳角時(shí),圓柱面的截線是一個(gè)橢圓.著名數(shù)學(xué)家Dandelin創(chuàng)立的雙球?qū)嶒?yàn)證明了上述結(jié)論.如圖所示,將兩個(gè)大小相同的球嵌入圓柱內(nèi),使它們分別位于SKIPIF1<0的上方和下方,并且與圓柱面和SKIPIF1<0均相切.給出下列三個(gè)結(jié)論:①兩個(gè)球與SKIPIF1<0的切點(diǎn)是所得橢圓的兩個(gè)焦點(diǎn);②橢圓的短軸長(zhǎng)與嵌入圓柱的球的直徑相等;③當(dāng)圓柱的軸與SKIPIF1<0所成的角由小變大時(shí),所得橢圓的離心率也由小變大.其中,所有正確結(jié)論的序號(hào)是(
)A.① B.②③ C.①② D.①③7.(2023·全國(guó)·高三專題練習(xí))已知點(diǎn)SKIPIF1<0滿足SKIPIF1<0,且點(diǎn)Q恒在在以SKIPIF1<0、SKIPIF1<0為左、右焦點(diǎn)的橢圓SKIPIF1<0內(nèi),延長(zhǎng)SKIPIF1<0與橢圓交于點(diǎn)SKIPIF1<0,若SKIPIF1<0,則該橢圓離心率取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題8.(2023春·廣東韶關(guān)·高三校聯(lián)考開學(xué)考試)已知SKIPIF1<0是拋物線SKIPIF1<0的焦點(diǎn),點(diǎn)SKIPIF1<0在拋物線SKIPIF1<0上,過點(diǎn)SKIPIF1<0的兩條互相垂直的直線SKIPIF1<0,SKIPIF1<0分別與拋物線SKIPIF1<0交于SKIPIF1<0,SKIPIF1<0和SKIPIF1<0,SKIPIF1<0,過點(diǎn)SKIPIF1<0分別作SKIPIF1<0,SKIPIF1<0的垂線,垂足分別為SKIPIF1<0,SKIPIF1<0,則(
)A.四邊形SKIPIF1<0面積的最大值為2B.四邊形SKIPIF1<0周長(zhǎng)的最大值為SKIPIF1<0C.SKIPIF1<0為定值SKIPIF1<0D.四邊形SKIPIF1<0面積的最小值為329.(2023春·浙江·高三開學(xué)考試)已知F為雙曲線SKIPIF1<0的右焦點(diǎn),P在雙曲線C的右支上,點(diǎn)SKIPIF1<0.設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,下列判斷正確的是(
)A.SKIPIF1<0最大值為SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.存在點(diǎn)P滿足SKIPIF1<010.(2023春·廣東·高三統(tǒng)考開學(xué)考試)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0為圓SKIPIF1<0上的一個(gè)動(dòng)點(diǎn),則下列結(jié)論正確的是(
)A.以SKIPIF1<0為直徑的圓與圓SKIPIF1<0相交所得的公共弦所在直線方程為SKIPIF1<0B.若點(diǎn)SKIPIF1<0,則SKIPIF1<0的面積為SKIPIF1<0C.過點(diǎn)SKIPIF1<0且與圓SKIPIF1<0相切的圓的圓心軌跡為圓D.SKIPIF1<0的最小值為SKIPIF1<011.(2023春·江蘇常州·高三校聯(lián)考開學(xué)考試)已知雙曲線SKIPIF1<0的左?右焦點(diǎn)分別是SKIPIF1<0,點(diǎn)SKIPIF1<0在雙曲線的右支上,則(
)A.若直線SKIPIF1<0的斜率為SKIPIF1<0,則SKIPIF1<0B.使得SKIPIF1<0為等腰三角形的點(diǎn)SKIPIF1<0有且僅有四個(gè)C.點(diǎn)SKIPIF1<0到兩條漸近線的距離乘積為SKIPIF1<0D.已知點(diǎn)SKIPIF1<0,則SKIPIF1<0的最小值為512.(2023秋·江西新余·高三統(tǒng)考期末)如圖,過雙曲線SKIPIF1<0:SKIPIF1<0右支上一點(diǎn)SKIPIF1<0作雙曲線的切線SKIPIF1<0分別交兩漸近線于SKIPIF1<0,SKIPIF1<0兩點(diǎn),交SKIPIF1<0軸于點(diǎn)SKIPIF1<0,SKIPIF1<0、SKIPIF1<0分別為雙曲線的左、右焦點(diǎn),SKIPIF1<0為坐標(biāo)原點(diǎn),則下列結(jié)論錯(cuò)誤的是(
)A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.若存在點(diǎn)SKIPIF1<0,使SKIPIF1<0,且SKIPIF1<0,則雙曲線SKIPIF1<0的離心率為SKIPIF1<013.(2023春·江蘇南通·高三??奸_學(xué)考試)已知過拋物線SKIPIF1<0焦點(diǎn)SKIPIF1<0的直線SKIPIF1<0交SKIPIF1<0于SKIPIF1<0兩點(diǎn),交SKIPIF1<0的準(zhǔn)線于點(diǎn)SKIPIF1<0,其中SKIPIF1<0點(diǎn)在線段SKIPIF1<0上,SKIPIF1<0為坐標(biāo)原點(diǎn),設(shè)直線SKIPIF1<0的斜率為SKIPIF1<0,則(
)A.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0 B.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0C.存在SKIPIF1<0使得SKIPIF1<0 D.存在SKIPIF1<0使得SKIPIF1<0三、填空題14.(2023秋·河北邯鄲·高三統(tǒng)考期末)已知拋物線SKIPIF1<0的焦點(diǎn)為F,若SKIPIF1<0在拋物線C上,且滿足SKIPIF1<0,則SKIPIF1<0的最小值為______.15.(2023·四川涼山·統(tǒng)考一模)如圖,已知橢圓SKIPIF1<0,SKIPIF1<0.若由橢圓SKIPIF1<0長(zhǎng)軸一端點(diǎn)SKIPIF1<0和短軸一端點(diǎn)SKIPIF1<0分別向橢圓SKIPIF1<0引切線SKIPIF1<0和SKIPIF1<0,若兩切線斜率之積等于SKIPIF1<0,則橢圓SKIPIF1<0的離心率SKIPIF1<0__________.16.(2023秋·吉林長(zhǎng)春·高三長(zhǎng)春市第二中學(xué)??计谀┢矫娑吻€方程的一般形式為SKIPIF1<0.已知曲線SKIPIF1<0表示中心在坐標(biāo)原點(diǎn)的橢圓,若中心為坐標(biāo)原點(diǎn)的矩形的四個(gè)頂點(diǎn)均在橢圓SKIPIF1<0上,則該矩形面積的最大值為______.17.(2023秋·湖南長(zhǎng)沙·高三湖南師大附中??茧A段練習(xí))已知F為拋物線SKIPIF1<0的焦點(diǎn),由直線SKIPIF1<0上的動(dòng)點(diǎn)P作拋物線的切線,切點(diǎn)分別是A,B,則SKIPIF1<0與SKIPIF1<0(SKIPIF1<0為坐標(biāo)原點(diǎn))的面積之和的最小值是_________.18.(2023·湖南衡陽·??寄M預(yù)測(cè))已知拋物線SKIPIF1<0的焦點(diǎn)為SKIPIF1<0,圓SKIPIF1<0與SKIPIF1<0交于SKIPIF1<0兩點(diǎn),其中點(diǎn)SKIPIF1<0在第一象限,點(diǎn)SKIPIF1<0在直線SKIPIF1<0上運(yùn)動(dòng),記SKIPIF1<0.①當(dāng)SKIPIF1<0時(shí),有SKIPIF1<0;②當(dāng)SKIPIF1<0時(shí),有SKIPIF1<0;③SKIPIF1<0可能是等腰直角三角形;其中命題中正確的有__________.19.(2023·湖北·宜昌市一中校聯(lián)考模擬預(yù)測(cè))設(shè)橢圓SKIPIF1<0的離心率SKIPIF1<0,C的左右焦點(diǎn)分別為SKIPIF1<0,點(diǎn)A在橢
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- LED廣告車2024年租賃合同范本2篇
- 2025年度鄰里社區(qū)共筑住宅項(xiàng)目綠化養(yǎng)護(hù)協(xié)議3篇
- 2025年度生態(tài)農(nóng)業(yè)地產(chǎn)合作開發(fā)合同書
- 二零二五年度出租車座套定制與品牌推廣合同3篇
- 二零二五版電力設(shè)備質(zhì)檢員招聘與職責(zé)協(xié)議書3篇
- 個(gè)性化倉儲(chǔ)解決方案服務(wù)外包協(xié)議范本版A版
- 2025年度企業(yè)員工心理健康培訓(xùn)服務(wù)合同范本8篇
- 中美洲2024年原材料供應(yīng)協(xié)議
- 養(yǎng)殖場(chǎng)動(dòng)物疫病防治服務(wù)合同(2025年度)3篇
- 2025版圍欄施工安全風(fēng)險(xiǎn)評(píng)估與應(yīng)急預(yù)案合同3篇
- 浙教版七年級(jí)上冊(cè)數(shù)學(xué)第4章代數(shù)式單元測(cè)試卷(含答案)
- 一病一品成果護(hù)理匯報(bào)
- AQ-T 1009-2021礦山救護(hù)隊(duì)標(biāo)準(zhǔn)化考核規(guī)范
- 鹽酸??颂婺崤R床療效、不良反應(yīng)與藥代動(dòng)力學(xué)的相關(guān)性分析的開題報(bào)告
- 消防設(shè)施安全檢查表
- 組合結(jié)構(gòu)設(shè)計(jì)原理 第2版 課件 第6、7章 鋼-混凝土組合梁、鋼-混凝土組合剪力墻
- 建筑公司資質(zhì)常識(shí)培訓(xùn)課件
- GB/T 26316-2023市場(chǎng)、民意和社會(huì)調(diào)查(包括洞察與數(shù)據(jù)分析)術(shù)語和服務(wù)要求
- 春節(jié)值班安全教育培訓(xùn)
- 帶狀皰疹護(hù)理查房
- 平衡計(jì)分卡-化戰(zhàn)略為行動(dòng)
評(píng)論
0/150
提交評(píng)論