浙大C語言答案(全)

浙大春季C語言程序編程目錄第2周(M2)220011求華氏溫度100°F對應(yīng)的攝氏溫度。220012求華氏溫度150ヤ對應(yīng)的攝氏溫度。320013求攝氏溫度26。(3對應(yīng)的華氏溫度。320015當n為152時,分別求出n的個位數(shù)字(digiti)、卜位數(shù)字(digit2)和百位數(shù)字(digit3)的值。320026輸入2個整數(shù)num!和num2,計算并輸出它們的和、差、積、商與余數(shù)。4第3周(M3)520031求1+2+3+......+100(調(diào)試示例error02_5)520032求m+(m+l)+(m+2)+......+100520033求l/m+l/(m+l)+l/(m+2)+......+l/n620034求1+1/3+1/5+......的前n項和?20035求1-1/4+1/7ーレ10+ 的前n項之和720036輸出華氏ー攝氏溫度轉(zhuǎn)換表(改錯題error02_6)820038求x的n次裏920041生成3的乘方表1020044求100Ao.5+101ハ0.5+ +1000Ao.51020053計算物體自由下落的距離1120056計算分段函數(shù)1120061階梯電價1220062求m*m+l/m+(m+l)*(m+l)+l/(m+l)+(m+2)*(m+2)+l/(m+2)+ +n*n+ 1/n1320063求1-2/3+3/5-4/7+5/9-6/11+ 1420064求2A1+2A2+2A3+ +2An15第4周(M4)1510007顯示圖案(復習prin氓)的字符串輸出)1520042生成階乘表1620043使用函數(shù)求n!/(m!*(n-m)!)1620054求平均值1720057求1+1/2+1/3+......+l/n1820065求0!+1!+2!+ +n!1840015求最小值!940018求a+aa+aaa+aa...a20第5周(M5)2130001求一元二次方程的根2130002求分段函數(shù)的值2330003分類統(tǒng)計字符2330004顯示五級記分制成績所對應(yīng)的百分制成績區(qū)間(使用switch)2430005顯示水果的價格(使用switch)2530007求三角形的面積和周長2730008計算個人所得稅2830051判斷閏年2930052統(tǒng)計學生平均成績與及格人數(shù)3030053分段計算水費（使用嵌套的i任else語句）31第6周（M6）3240011求最小公倍數(shù)和最大公約數(shù)（調(diào)試示例error04_l）3240012求1-1/4+1/7-1/10+1/13-1/16+ 3340014求整數(shù)的位數(shù)3440023換硬幣3540024找出各位數(shù)字的立方和等于它本身的數(shù)3640025找完數(shù)（改錯題error04_2）3840027從高位開始逐位輸出ー個整數(shù)的各位數(shù)字（選作）3940052判斷素數(shù)4040053逆序輸出整數(shù)4140054輸出斐波那契序列42第7周（M7）4250002使用函數(shù)判斷數(shù)的符號4250003使用函數(shù)求奇數(shù)和4350005使用函數(shù)統(tǒng)計素數(shù)并求和4450006使用函數(shù)統(tǒng)計ー個整數(shù)中數(shù)字的個數(shù)4550007使用函數(shù)找水仙花數(shù)4650009使用函數(shù)求余弦函數(shù)的近似值4850052使用函數(shù)找最大值4950062使用函數(shù)輸出指定范圍內(nèi)的Fibonacci數(shù)5050063使用函數(shù)找出指定范圍內(nèi)的完數(shù)51第8周（M8）5240013求奇數(shù)和5240062求x+x*x/2!+x*x*x/3!+x*x*x*x/4!+ 的值5350004使用函數(shù)計算兩點間的距離5450061使用函數(shù)求2+22+222+22-25560002整數(shù)的十進制、ハ進制和十六進制表現(xiàn)形式5660003分類統(tǒng)計字符5760006驗證歌德巴赫猜想5860007使用函數(shù)輸出整數(shù)的逆序數(shù)5960009統(tǒng)計單詞6060062簡單計算器61第2周（M2）20011求華氏溫度100叩對應(yīng)的攝氏溫度。計算公式如ド,c=5*（f-32）/9,式中:c表示攝氏溫度,f表示華氏溫度。（源程序error02」.cpp）輸入輸出示例:fahr=100,celsius=37#include<stdio.h>intmain(void)intCelsius,fahr;fahr=100;celsius=5*(fahr-32)/9;printf(Mfahr=%d,Celsius=%d\nM,fahr,Celsius);return0;}20012求華氏溫度150°F對應(yīng)的攝氏溫度。計算公式:C=5*F/9-5*32/9.式中:C表示攝氏溫度,F表示華氏溫度。輸入輸出示例：fahr=150,celsius=66#include<stdio.h>intmain(void){intCelsius,fahr;fahr=150;celsius=5*fahr/9-5*32/9;printf(nfahr=%d,Celsius=%d\nn,fahr,Celsius);return0;}20013求攝氏溫度26℃對應(yīng)的華氏溫度。計算公式如下,六9*c/5+32,式中：c表示攝氏溫度,f表示華氏溫度。輸入輸出示例：celsius=26,fahr=78#include<stdio.h>intmain(void){intCelsius,fahr;celsius=26;fahr=9*celsius/5+32;printff'celsius=%d,fahr=%d\n”,Celsius,fahr);return0;}20015當n為152時,分別求出n的個位數(shù)字(digiti)、十位數(shù)字(digit2)和百位數(shù)字(digit3)的值。輸入輸出示例：整數(shù)152的個位數(shù)字是2,十位數(shù)字是5,百位數(shù)字是1#includc<stdio.h>intmain(void){intn,digitI,digit2,digit3;n=152;digitl=n;digit2=(n/10);digit3=n/100;printf("整數(shù)％d的個位數(shù)字是%d,卜位數(shù)字是％d,百位數(shù)字是％d\n”,n,digiti,digit2,digit3);return0;)20026輸入2個整數(shù)num!和num2,計算并輸出它們的和、差、積、商與余數(shù)。輸出兩個整數(shù)的余數(shù)可以用printf("%d%%%d=%d\n",numl,num2,numl%num2);輸入輸出示例:括號內(nèi)是說明輸入53(numl=5,num2=3)輸出5+3=85-3=25*3=155/3=15%3=2#include<stdio.h>intmain(void){intnuml,num2;scanff%d%d”,&numl,&num2);printff'%d+%d=%d\nH,num1,num2,num1+num2);printf("％d?%d=%d\nM,num1,num2,num1-num2);printff%d*%d=%d\nM,num1,num2,num1*num2);printf(n%d/%d=%d\nM,numl,num2,numl/num2);printff'%d%%%d=%d\n",num1,num2,num1%num2);return0;第3周(M3)20031求1+2+3+ +100(調(diào)試示例error02_5)計算表達式1+2+3+......+100的值。輸出示例:sum=5050#include<stdio.h>intmain(void)(inti,sum;sum=0;fbr(i=l;i<=100;i++)sum=sum+i;printftnsum=%d\nM,sum);20032求m+(m+1)+(m+2)+ +100輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入ー個正整數(shù)m(0<=m<=100)?計算表達式m+(m+1)+(m+2)+ +100的值。輸入輸出示例:括號內(nèi)為說明輸入3(repeat=3)0(計算0+1+2+...+100)10(計算10+11+12+...+100)50(計算50+51+52+…+100)輸出sum=5050sum=5005sum=3825#include<stdio.h>intmain(void){inti,m,sum;intrepeat,ri;scanグ％d”,&repeat);fbr(ri=1;ri<=repeat;ri++){scanR"％d”,&m);sum=0;fbr(i=m;i<=100;i++)sum=sum+i;printff'sum=%d\n",sum);20033求l/m+l/(m+l)+l/(m+2)+......+l/n輸入ー個正整數(shù)repeat(0<repeat<10).做repeat次下列運算:輸入2個正整數(shù)m和n(m<=n).計算表達式l/m+l/(m+l)+l/(m+2)+ + 1/n的值,輸出時保留3位小數(shù)。輸入輸出示例:括號內(nèi)為說明輸入3(repeat=3)515(計算1/5+1/6+1/7+...+1/15)1020(計算1/10+1/11+1/12+...+1/20)3(計算1+1/2+1/3)輸出sum=1.235sum=0.769sum=1.833#include<stdio.h>intmain(void)(inti,m,n;intrepeat,ri;doublesum;scanff'%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanff'%d%d"，&m,&n);sum=0;for(i=m;i<=n;i++)sum=sum+1.0/i;printff'sum=%.3f\nH,sum);20034求1+1/3+1/5+......的前n項和輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入ー個正整數(shù)n,計算表達式1+1/3+1/5+......的前n項之和,輸出時保留6位小數(shù)。輸入輸出示例:括號內(nèi)為說明輸入(repeat=2)5(計算1+1/3+1/5+1/7+1/9)23(計算1+1/3+1/5+...+1/45)輸出sum=1.787302sum=2.549541//include<stdio.h>intmain(void)(inti,n;intdenominator;intrepeat,ri;doublesum;scanff%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanff%d”,&n);sum=0;denominator=l;fbr(i=l;i<=n;i-H-)(sum=sum+1.0/denominator;denominator=denominator+2;}printfV'sum=%.6f\nH,sum);20035求1-1/4+1/7-1ハ0+ 的前n項之和輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:讀入ー個正整數(shù)n,計算1-1/4+1/7ーレ10+……的前n項之和,輸出時保留3位小數(shù)。輸入輸出示例:括號內(nèi)是說明輸入(repeat=2)10輸出sum=0.893sum=0.819#include<stdio.h>intmain(void){intflag,i,n,t;intrepeat,ri;doubleitem,sum;scanfi("％d"，&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanR"％d”,&n);sum=0;flag=l;t=l；fbr(i=l；i<=n；i++){item=flag*1.0/t;sum=sum+item;flag=-flag;t=t+3;}printf(Hsum=%.3f\n",sum);20036輸出華氏?攝氏溫度轉(zhuǎn)換表(改錯題error02_6)輸入ー個正整數(shù)repeat(0<rcpcat<10)?做repeat次下列運算:讀入2個整數(shù)lower和upper,輸出ー張華氏ー攝氏溫度轉(zhuǎn)換表,華氏溫度的取值范圍是[lower,upper]?每次增加2F。計算公式:c=5*(f-32)/9,其中:c表示攝氏溫度,f表示華氏溫度。輸出請使用語句printf("％3.0f%6.lf\n"，fahr,Celsius);輸入輸出示例:括號內(nèi)是說明輸入2(repeat=2)3235(lower=32,upper=35)4030(lower=40,upper=30)輸出fahrCelsius320.0341.1fahrCelsius#include<stdio.h>intmain(void)intlower,upper;intrepeat,ri;doubleCelsius,fahr;scanff'%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanfi("％d%d"，&lower,&upper);printf(Mfahrcelsius\n");fbr(fahr=lower;fahr<=upper;fahr-H-,fahri-+)(celsius=5*(fahr-32)/9;printf(H%3.0f%6.1f\nM,fahr,Celsius);20038求x的n次累輸入ー個正整數(shù)repeat(0<repeat〈10),做repeat次下列運算:讀入1個實數(shù)x和正整數(shù)n(n<=50),計算并輸出x的n次壽(保留2位小數(shù)),不允許調(diào)用pow函數(shù)求事。輸入輸出示例:括號內(nèi)是說明輸入2(repeat=2)1.52(x=1.5,n=2)7(x=2,n=7)輸出2.25128.00#include<stdio.h>intmain(void)(inti,n;intrepeat,ri;doublemypow,x;scanfi("％d"，&repeat);fbr(ri=1;ri<=repeat;ri++){scanf「％lf%d”,&x,&n);mypow=l;fbr(i=l;i<=n;i-H")mypow=mypow*x;printff%.2f\n“，mypow);20041生成3的乘方表輸入ー個正整數(shù)n,生成一張3的乘方表,輸出3ハ〇?3八n的值,可調(diào)用基函數(shù)計算3的乘方。輸出使用語句prin氓"pow(3,%d)=%.Of\n",i,mypow);輸入輸出示例:括號內(nèi)是說明輸入3(n=3)輸出pow(3,0)=1pow(3,l)=3pow(3,2)=9pow(3,3)=27#include<stdio.h>#include<math.h>intmain(void)|inti,n;doublemypow;scanff%d”,&n);fbr(i=O;i<=n;i-H-){mypow=pow(3,i)；printffpow(3,%d)=%.0f\n\i,mypow);20044求100ハ0.5+101ハ0.5+ +1000A0.5計算100八0.5+101八0.5+……+1000八0.5的值(保留2位小數(shù)),可調(diào)用sqi!函數(shù)計算平方根。輸入輸出示例:括號內(nèi)是說明輸出sum=20435.99#include<stdio.h>#include<math.h>intmain(void){inti;doublesum;sum=0;fbr(i=100;i<=1000;i++)sum=sum+sqrt(i);printf(Msum=%.2f\nn,sum);20053計算物體自由下落的距離ー個物體從100m的高空自由落下,編寫程序,求它在前3s內(nèi)下落的垂直距離(結(jié)果保留2位小數(shù))。設(shè)重力加速度為10米/秒A2。#include<stdio.h>intmain(void){doubleheight;height=0.5*10*3*3;printf(Hheight=%.2f\nM,height);20056計算分段函數(shù)輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:編寫程序,輸入x,計算并輸出下列分段函數(shù)f(x)的值(保留2位小數(shù)),請調(diào)用sqrt()函數(shù)求平方根,調(diào)用pow()函數(shù)求暴。當x>=0時,f(x)=xA0.5,當x小于〇時,f(x)=xA5+2x+l/Xo輸入輸出示例:括號內(nèi)是說明輸入(repeat=3)10(x=10)-0.5(x=-0.5)0(x=0)輸出f(10.00)=3.16￡(-0.50)=-3.03RO.OO)=0.00include<stdio.h>#include<math.h>intmain(void)(intrepeat,ri;doublex,y;scanR”％d”,&rcpeat);fbr(ri=1;ri<=repeat;ri-H-){scanftM%lf',&x);ifl[x>=0)y=sqrt(x);elsey=pow(x,5)+2*x+l.0/x;printfC砥％.2f)=%.2f\n",x,y);2006I階梯電價輸入ー個正整數(shù)repeat(0<rcpcat<10)?做repeat次下列運算:為了提倡居民節(jié)約用電,某省電カ公司執(zhí)行“階梯電價”,安裝ー戶ー表的居民用戶電價分為兩個”階梯”:月用電量50千瓦時以內(nèi)的,電價為0.53元ノ千瓦時;超過50千瓦時的用電量,電價上調(diào)0.05元/千瓦時。輸入用戶的月用電量e(千瓦時),計算并輸出該用戶應(yīng)支付的電費(元),結(jié)果保留2位小數(shù)。輸入輸出示例:括號內(nèi)是說明輸入(repeat=2)10(e=10)100(e=100)輸出cost=5.30cost=55.50#include<stdio.h>intmain(void)Iintrepeat,ri;doublecost,e;scanfi(”％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanfi(,,%lf,,&e);if(e<=50)cost=e*0.53;elsecost=0.53*50+(e-50)*0.58;printffcost=%.2f\nn,cost);20062求m*m+l/m+(m+l)*(m+l)+l/(m+l)+(m+2)*(m+2)+l/(m+2)+ +n*n+1/n輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入兩個正整數(shù)m和n(m<=n),求sum=m*m+1/m+(m+l)*(m+l)+l/(m+l)+(m+2)*(m+2)+l/(m+2) +n*n+l/n,結(jié)果保留6位小數(shù)。輸入輸出示例:括號內(nèi)為說明輸入(repeat=3)2(m=l,n=2)5(m=2,n=5)510(m=5,n=10)輸出sum=6.500000sum=55.283333sum=355.845635#include<stdio.h>intmain(void){inti,m,n;intrepeat,ri;doublesum;scanグ％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanf("％d%d”,&m,&n);sum=0;fbr(i=m;i<=n;i-H-)sum=sum+i*i+l.0/i;printf(Hsum=%.6f\n"，sum);20063求1-2/3+3/5—4/7+5/9641+ 輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次ド列運算:輸入ー個正整數(shù)n,計算1-2/3+3/5—4/7+5/9?6ハ1+……的前n項之和,輸出時保留3位小數(shù)。輸入輸出示例:括號內(nèi)是說明輸入(repeat=3)1(n=l)3(n=3)5(n=5)輸出sum=1.000sum=0.933sum=0.917#includc<stdio.h>intmain(void){intflag,i,n;floatdenominator;intrepeat,ri;doubleitem,sum;scanfV%d”,&rcpeat);fbr(ri=1;ri<=repeat;ri-H-){scanR"％d”,&n);sum=0;flag=l;denominator=1.0;fbr(i=l;i<=n;i卄){item=flag*i*1.0/denominator;sum=sum+item;flag=-flag;denominator=denominator+2;)printfV'sum=%.3f\nH,sum);20064求2人1+2A2+2ハ3+ +2An#include<stdio.h>#include<math.h>intmain(void){inti,n;intrepeat,ri;doublesum;scanグ%d”,&repeat);fbr(ri=1;ri<=repeat;ri-H"){scanf(M%dM,&n);sum=0;fbr(i=l;i<=n;i-H-)sum=sum+pow(2,i)；printffsum=%.0f\n”，sum);第4周（M4）10007顯示圖案（復習prints）的字符串輸出）編寫程序,在屏幕上顯示如下圖案。**********#include<stdio.h>intmain(void)(printf(H****\nM?***??*"*\nM);20042生成階乘表輸入ー個正整數(shù)n,生成一張階乘表,輸出l!~n!的值,要求定義和調(diào)用函數(shù)fact(n)計算n!,函數(shù)類型為double。輸出使用語句prin氓"％d!=%.0f\n",i,myfact);輸入輸出示例:括號內(nèi)是說明輸入3(n=3)輸出1!=12!=23!=6#include<stdio.h>intmain(void){inti,n;doublemyfact;doublefact(intn);scanfi("%d”,&n);fbr(i=l;i<=n;i-H-){myfact=fact(i);printf("％d!=%.Of\nH,i,myfact);doublefact(intn)doubleresult;intj;result=l;for(j=lij<=nij-H-)result=result*j;returnresult;20043使用函數(shù)求n!/(m!*(n-m)!)輸入ー個正整數(shù)repeat(0<repcat<10)?做repeat次ド列運算:輸入2個正整數(shù)m和n(m<=n),計算n!/(m!*(n-m)!)〇要求定義并調(diào)用函數(shù)fact(n)計算n的階乘,其中n的類型是int,函數(shù)類型是double。例:括號內(nèi)是說明輸入:2(repeat=2)27(m=2,n=7)512(m=5,n=12)輸出:result=21result=792#include"stdio.h"intmain(void){intm,n;intrepeat,ri;doubles;doublefact(intn);scanff%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanfifH%d%dn,&m,&n);fact(n);fact(m);fact(n-m);s=l;s=s*fact(n)/(fact(m)*fact(n-m));printf("result=%.0f\n"，s);doublefact(intn)(doubleresult;inti;result=l;fbr(i=l；i<=n；i++)result=result*i;returnresult;20054求平均值編寫程序,輸入3個整數(shù),計算并輸出它們的平均值(結(jié)果保留2位小數(shù))。輸入輸出示例:輸入123輸出average=2.00#include<stdio.h>intmain(void)(inta,b,c;doubleaverage;scanグ％d%d%d”,&a,&b,&c);average=(a+b+c)/3.0;printff'average=%.2f\nn,average);20057求!+1/2+1/3+……+l/n輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:編寫程序,輸入ー個正整數(shù)n,求1+1/2+1/3+……的前n項之和,輸出時保留6位小數(shù)。輸入輸出示例:括號內(nèi)為說明輸入(repeat=2)6(計算1+1/2+1/3+1/4+1/5+1/6)2(計算1+1/2)輸出sum=2.450000sum=1.500000#include<stdio.h>intmain(void){inti,n;intrepeat,ri;doublesum;scanff%d"，&repeat);fbr(ri=1;ri<=repeat;ri++){scanff%d”,&n);sum=0;for(i=l;i<=n;i++)sum=sum+1.0/i;printff'sum=%.6f\n",sum);20065求0!+l!+2!+ +n!輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:編寫ー個程序,輸入ー個正整數(shù)n,計算e=0!+l!+2!+……+n!,要求定義和調(diào)用函數(shù)fhct(n)計算n!?函數(shù)類型是double〇例:括號內(nèi)是說明輸入(repeat=3)124輸出sum=2sum=4sum=34#include<stdio.h>intmain(void)|inti,n;intrepeat,ri;doublesum;doublefact(intn);scanR"％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanf("％d”，&n);sum=1;fbr(i=1;i<=n;i-H-){fact(i);sum=sum+fact(i);}printffsum=%.Of\nH,sum);doublefact(intn)(doubleresult;intj;result=l;fbr(j=lj<=nj-H-)result=result*j;returnresult;40015求最小值輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入ー個正整數(shù)n,再輸入n個整數(shù),輸出最小值。輸入輸出示例:括號內(nèi)是說明輸入3(repeat=3)4-2-12310004-9-11-83531輸出min=-123min=-9min=1#include<stdio.h>intmain(void)(inti,min,n,x;intrepeat,ri;scanf("％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanグ％d”,&n);scanf("％d”，&x);min=x;fbr(i=l;i<n;i-H-){scanff%d”，&x);ifi[min>x)min=x;}printffmin=%d\nM,min);40018求a+aa+aaa+aa…a提示:第i項通項:tn=a+a*10+a*100...+a*10A(n-1)=t(n-l)+a*10A(n-l)#include<stdio.h>#include<math.h>intmain(void){inta,i,n,sn,tn;intri,repeat;scanff%d"，&repeat);fbr(ri=1;ri<=repeat;ri++){scanff%ld%d”，&a,&n);sn=0;tn=O;fbr(i=0;i<n;i++){tn=tn+a*pow(10,i);sn=sn+tn;}printf("suni=%d\n",sn);第5周(M5)3000I求一元二次方程的根輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入?yún)?shù)a,b,c,求一元二次方程a*x*x+b*x+c=0的根,結(jié)果保留2位小數(shù)。輸出使用以下語句:printff參數(shù)都為零,方程無意義!\n");printf(Ha和b為〇,c不為0?方程不成立\n")；printff'x=%0.2f\nn,-c/b);printff'xl=%0.2f\nM,(-b+sqrt(d))/(2*a));printf(Mx2=%0.2f\nM,(-b-sqrt(d))/(2*a));printf(Mxl=%0.2fF%0.2fi\nM,-b/(2*a),sqrt(-d)/(2*a));printf(Mx2=%0.2l%0.2fi\n”,?b/(2*a),sqrt(-d)/(2*a));輸入輸出示例:括號內(nèi)為說明輸入:5(repeat=5)000(a=O,b=O,c=O)001(a=O,b=O,c=l)024(a=0,b=2,c=4)2.18.93.5(a=2.1,b=8.9,c=3.5)123(a=l,b=2,c=3)輸出:參數(shù)都為零,方程無意義!a和b為〇,c不為〇,方程不成立x=-2.00xl=-0.44x2=-3.80xl=-1.00+1.41ix2=-1.00-1.41i//include<stdio.h>#include<math.h>intmain(void)(intrepeat,ri;doublea,b,c,d;scanf("％d"，&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanff%lf%lf%lF,&a,&b,&c);d=b*b-4*a*c;if(a=O){if(b=O){if(c=O){printff參數(shù)都為零,方程無意義!\n”)；}else(printf(Ha和b為〇,c不為0,方程不成立\n")；else{printffx=%0.2f\n",-c/b);else{if(d>=0){printf(Mxl=%0.2f\nM,(-b+sqrt(d))/(2*a));printf(nx2=%0.2f\nH,(-b-sqrt(d))/(2*a));}else{printf(Mxl=%0.2件％0.2fi\n”,?b/(2*a),sqrt(-d)/(2*a));printf(nx2=%0.2f-%0.2fi\nH,-b/(2*a),sqrt(-d)/(2*a));30002求分段函數(shù)的值輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入ー個整數(shù)x?計算并輸出下列分段函數(shù)sign(x)的值。-1x<0y=sign(x)=0x=01x>0輸入輸出示例:括號內(nèi)是說明輸入3(repeat=3)10(x=10)0(x=0)-98(x=-98)輸出sign(10)=1(x=10時y=1)sign(0)=0(x=0時y=0)sign(-98)=-1(x=-98時y=-1)#include<stdio.h>intmain(void){intrepeat,ri;intx,y;scanf("％d"，&repeat);fbr(ri=1;ri<=repeat;ri++){scanf("％d”，&x);if(x==O)y=0;elseif(x>0)y=l;elsey="l;printf(Msign(%d)=%d\n"，x,y);30003分類統(tǒng)計字符輸入10個字符,統(tǒng)計其中英文字母、空格或回車、數(shù)字字符和其他字符的個數(shù)。輸入輸出示例:括號內(nèi)是說明輸入Rcold123?輸出letter=5,blank=1,digit=3,other=1#include<stdio.h>intmain(void){charc;intblank,digit,i,letter,other;blank=digit=letter=other=0;for(i=l；i<=10；i++){c=getchar();if(e=='')blankelseifi[(c>=,a'&&c<=,z,)||(c>=,A'&&c<=,Z,))letter++;elseifi(c>=,0,&&c<=,9,)digit++;elseother-H-;*printff'letter=%d,blank=%d,digit=%d,other=%d\n",letter,blank,digit,other);}30004顯示五級記分制成績所對應(yīng)的百分制成績區(qū)間(使用switch)輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入五級制成績(A—E),輸出相應(yīng)的百分制成績(0—100)區(qū)間,要求使用switch語句。五級制成績對應(yīng)的百分制成績區(qū)間為:A(90?100)、B(80?89)、C(70-79)>D(60?69)和E(0?59),如果輸入不正確的成績,顯示"Invalidinput"〇輸出使用以下語句:printf("90-100\n");prmtf(M80-89\nM);printf(M70-79\nM);printf(H60-69\nH);printf(M0-59\nM);printf(HInvalidinput\nM);輸入輸出示例:括號內(nèi)是說明輸入6ABCDEj(repeat=6,輸入的五級成績分別為A、B、C、D、E和無效的字符j)輸出90-10080-8970-7960-690-59Invalidinput(輸入數(shù)據(jù)不合法)#include<stdio.h>intmain(void){charch;intrepeat,ri;scanff%d"，&repeat);fbr(ri=1;ri<=repeat;ri++){ch=getchar();switch(ch){case'A*:printff90-100\n")；break;case'B1:printff80-89\n)break;case'C1:printfT70-79\n”)；break;case'D*:printf(M60-69\nM);break;case'E*:printf("0?59\n”)；break;default:printff'Invalidinput\n")；break;return0;}30005顯示水果的價格(使用switch)查詢水果的單價。有4種水果,蘋果(apples)、梨(pears)、桔子(oranges)和葡萄(grapes),單價分別是3.00元/公斤,2.50元/公斤，4.10元/公斤和10.20元/公斤。在屏幕上顯示以下菜單(編號和選項)，用戶可以連續(xù)查詢水果的單價，當查詢次數(shù)超過5次時，自動退出查詢:不到5次時,用戶可以選擇退出。當用戶輸入編號1?4,顯示相應(yīng)水果的單價(保留1位小數(shù)):輸入〇,退出查詢;輸入其他編號,顯示價格為〇。輸入輸出示例:括號內(nèi)是說明輸入3(oranges的編號)0(退出查詢)輸出[1]applespearsorangesgrapes[0]Exitprice=4.1applespearsorangesgrapes[0]Exit#include<stdio.h>intmain(void){intchoice,i;doubleprice;fbr(i=l;i<=5;i++){printfHl]applesW”)；printf(M[2]pears\nH);printf(M[3]oranges\nM);printf(H[4]grapes");printf(M[O]Exit\n°);scanf("％d”,&choice);iRchoice=0)break;else{switch(choice){price=3.00;break;price=2.50;break;pricc=4.10;break;price=10.20;break;}printffprice=%0.1f\nH,price);30007求三角形的面積和周長輸入ー個正整數(shù)repeat(0<repcat<10)?做repeat次下列運算:輸入三角形的3條邊a,b,c?如果能構(gòu)成一個三角形,輸出面積area和周長perimeter(保留2位小數(shù));否則,輸出"Thesesidesdonotcorrespondtoavalidtriangle"〇在ー個三角形中,任意兩邊之和大于第三邊。三角形面積計算公式:area=(s(s-a)(s-b)(s-c))A0.5,其中s=(a+b+e)/2輸出使用以下語句:printff'area=%.21perimeter=%.2f\n",area,perimeter);printff'Thesesidesdonotcorrespondtoavalidtriangle\n");輸入輸出示例：括號內(nèi)是說明輸入2(repeat=2)553(a=5,b=5,c=3)141(a=l,b=4,c=l)輸出area=7.15,perimeter=13.00Thesesidesdonotcorrespondtoavalidtriangle#include<stdio.h>#include<math.h>intmain(void)inta,b,c;intrepeat,ri;doublearea,perimeter,s;scanfi("％d"，&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanf(M%d%d%d",&a,&b,&c);if((a+b>c)&&(a+c>b)&&(b+c>a)){perimeter=a+b+c;s=(a+b+c)/2.0〇;area=sqrt(s*(s-a)*(s-b)*(s-c));printff'area=%.2f,perimeter=%.2f\nH,area,perimeter);}elseprintff'Thesesidesdonotcorrespondtoavalidtriangle\nn);30008計算個人所得稅輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入ー個職エ的月薪salary?輸出應(yīng)交的個人所得稅tax(保留2位小數(shù))。計算公式:tax=rate*(salary-850)當salary<850時,rate=0當850<salary<1350時,rate=5%當1350<salary<2850時,rate=10%當2850<salary<5850時，rate=15%當5850<salary時，rate=20%輸入輸出示例:括號內(nèi)是說明輸入5(repeat=5)1010.87(salary=1010.87)32098.76(salary=32098.76)800(salary=800)4010(salary=4010)2850(salary=2850)輸出tax=8.04tax=6249.75tax=0.00tax=474.00tax=200.00intmain(){intri,repeat;doublerate,salary,tax;scanff%d"，&repeat);fbr(ri=l;ri<=repeat;ri-H-){scanf(M%lf',&salary);if(salary<=850){rate=0;tax=rate*(salary-850);}elseif(salary<=1350){rate=0.05;tax=rate*(salary-850);}elseif(salary<=2850)(rate=0.10;tax=rate*(salary-850);}elseif(salary<=5850){rate=0.15;tax=rate*(salary-850);else(rate=0.20;tax=rate*(salary-850);}printfftax=%0.2f\nH,tax);30051判斷閏年輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入年year,判斷該年是否為閏年。判斷閏年的條件是:能被4整除但不能被100整除,或者能被400整除。輸出使用以下語句:printfi(H%disaleapyear.\nH,year);printf(H%disn*taleapyear.\nM,year);輸入輸出示例:括號內(nèi)是說明輸入3(repeat=3)2000(year=2000)2010(year=2010)2011(year=2011)輸出2000isaleapyear.2010isn*taleapyear.2011isn'taleapyea匚#includc<stdio.h>intmain(void)(intrepeat,ri;intyear;seanfT%d”，&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanグ％d”,&year);if((year%4==0&&year0!=0)||(year@0==0))printff'%disaleapyear.\n",year);elseprintff'%disn'taleapyear.\n",year);30052統(tǒng)計學生平均成績與及格人數(shù)輸入ー個正整數(shù)n,再輸入n個學生的成績,計算平均分(結(jié)果保留1位小數(shù)),并統(tǒng)計所有及格的人數(shù)。輸入輸出示例：括號內(nèi)是說明輸入5(n=5)7754927360輸出average=71.2count=4intmain(void){intcount,i,n;doubleaverage,grade,total;scanf("％d”,&n);total=0;count=0;fbr(i=l;i<=n;i-H-){scanfC%lf',&grade);total=total+gradc;ifi(grade>=60){count++;}}average=1.00*total/n;printff'average=%.lf\n"，average);\printff'count=%d\n",count);}30053分段計算水費(使用嵌套的iAelse語句)輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:為鼓勵居民節(jié)約用水,自來水公司采取按月用水量分段計費的辦法,居民應(yīng)交水費y(元)與月用水量x(噸)的函數(shù)關(guān)系式如下。輸入用戶的月用水量x(噸),計算并輸岀該用戶應(yīng)支付的水費y(元X保留2位小數(shù))。要求用嵌套的if-else語句。0(x<0)y=f(x)=4x/3(0<=x<=15)2.5x-10.5(x>15)輸入輸出示例:括號內(nèi)是說明輸入3(repeat=3)-0.5(x=-0.5)9.5(x=9.5)21.3(x=21.3)輸出戈?0.50)=0.00ロ9.50)=12.67f(21.30)=42.75#include<stdio.h>intmain(void)intrepeat,ri;doublex,y;scanグ％d”,&repeat);fbr(ri=l;ri<=repeat;ri++){scanf(M%lP,,&x);if(x<0)y=0;elseif<x>=0&&x<=15)y=4.0*x/3;elsey=2.5*x-10.5;printfCf(%.2f)=%.2f\n",x,y);第6周(M6)40011求最小公倍數(shù)和最大公約數(shù)(調(diào)試示例error04_l)輸入ー個正整數(shù)repeat(0<r叩eat<10),做repeat次下列運算:輸入兩個正整數(shù)m和n,輸出它們的最小公倍數(shù)和最大公約數(shù)。輸入輸出示例:括號內(nèi)為說明輸入:3(repeat=3)37(m=3,n=7)244(m=24,n=4)2418(m=24,n=18)輸出:21istheleastcommonmultipleof3and7,1isthegreatestcommondivisorof3and7.24istheleastcommonmultipleof24and4,4isthegreatestcommondivisorof24and4.72istheleastcommonmultipleof24and18,6isthegreatestcommondivisorof24and18.#include<stdio.h>intmain(void){intgcd,1cm,m,n,c;intrepeat,ri;scanf(”％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanf(”％d”,&m);scanf(M%dM,&n);ifi(m<=n)c=m;elsec=n;fbr(Icm=l;;lcm-H-){ifi(lcm%m==0&&lcm%n=0)break;fbr(gcd=c;;gcd-){if(m%gcd==O&&n%gcd=O)break;printfi(H%distheleastcommonmultipleof%dand%d,%disthegreatestcommondivisorof%dand%d.\n"，1cm,m,n,gcd,m,n);}return0;}參考方法2：#include<stdio.h>intmain(void){intgcd,1cm,m,n,i;intrepeat,ri;scanf(”％d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanグ％d”,&m);scanff%d”，&n);ififm<=0||n<=0)pHntf("m<=0orn<=〇");else(i=l；while(i<=(m+n)/2)(if((m%i=0)&&(n%i==0))gcd=i;i++；}lcm=m*n/gcd;printf("%distheleastcommonmultipleof%dand%d,%disthegreatestcommondivisorof%dand%d.\n",1cm,m,n,gcd,m,n);40012求1-1/4+1/7-1/10+1/13-1/16+ 輸入ー個正整數(shù)repeat(0<repeat<10).做repeat次下列運算:讀入I個正實數(shù)eps,計算并輸出下式的值,精確到最后一項的絕對值小于eps(保留6位小數(shù))。請使用while語句實現(xiàn)循環(huán)。計算:1—1/4+1/7—1/10+1/13—1/16+ 輸入輸出示例:括號內(nèi)是說明輸入2(repeat^)2E-4(eps=2E-4)0.02(eps=0.02)輸出sum=0.835549sum=0.826310#include<stdio.h>#includc<math.h>intmain(void){intdenominator,flag;intrepeat,ri;doubleeps,item,sum;scanfi("％d“，&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanグ％le”,&eps);sum=0;denominator1;flag=l;item=1.0;while(fabs(item)>=eps){item=flag*1.0/denominator;sum=sum+item;flag=-flag;denominator=denominator+3;}printf("sum=%.6f\n",sum);}return0;40014求整數(shù)的位數(shù)輸入ー個正整數(shù)repeat(0<repeat<10).做repeat次下列運算:輸入ー個整數(shù)in,求它的位數(shù)。例如123的位數(shù)是3。請使用do-while語句實現(xiàn)循環(huán)。輸入輸出示例:括號內(nèi)是說明輸入4(repeat=4)12345(in=12345)-100(in=-100)-1(in=-l)1290(in=1290)輸出count=5(12345的位數(shù)是5)count=3(-100的位數(shù)是3)count=1(-1的位數(shù)是1)count=4(99的位數(shù)是2)#includc<stdio.h>intmain(void){intcount,in;intrepeat,ri;scanflfM%dM,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanR"％d",&in);count=0;ifi(in<0)in=-in;do(count";in=in/10;}while(in!=0);printff'count=%d\n",count);}return0;40023換硬幣輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:將一筆零錢(大于8分,小于1元,精確到分)換成5分、2分和1分的硬幣。輸入金額,問有兒種換法?針對每利換法,每種硬幣至少有一枚,請輸出各種面額硬幣的數(shù)量和硬幣的總數(shù)量。要求:硬幣面值按5分、2分、1分順序,各類硬幣數(shù)量依次從大到小的順序,輸出各種換法。輸出使用語句:printfi("fen5:%d,fen2:%d,fenl:%d,total:%d\n,,,fen5,fen2,fenl,fen5+fen2+fenl);輸入輸出示例:括號內(nèi)為說明輸入:2(repeat=2)10(money=10分)13(money=13分)輸出:fen5:l,fen2:2,fenl:1,total:4fen5:1,fen2:1,fen1:3,total:5count=2(10分有2種換法)fen5:2,fen2:l,fenl:1,total:4fen5:1,fen2:3,fenl:2,total:6fen5:1,fen2:2,fenl:4,total:7fen5:l,fen2:l,fenl:6,total:8count=4(13分有4種換法)#include"stdio.h"intmain(void)(intcount,fenl,fen2,fen5,money;intrepeat,ri;scanff%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanff%d”,&money);count=0;fbr(fen5=money/5;fen5>=l;fen5—)fbr(fen2=money/2;fen2>=l;fen2—)fbr(fen1=money/l;fen1>=1;fen1—)if(fen5*5+fen2*2+fenl*l==money){printf(Hfen5:%d,fen2:%d,fenl:%d,total:%d\n,,,fen5,fen2,fenl,fen5+fen2+fenl);count++;}printff'count=%d\n",count);}return0;40024找出各位數(shù)字的立方和等于它本身的數(shù)輸入ー個正整數(shù)r叩eat(0<repeat<10),做repeat次下列運算:輸入兩個正整數(shù)m和n(lv=m,nv=1000),輸出m至りn之間的所有滿足各位數(shù)字的立方和等于它本身的數(shù)。例如153的各位數(shù)字的立方和是1人3+5ハ3+3ハ3=153,這里aハb表示a的b次方。輸出使用語句:printf(',%d\nM,i);輸入輸出示例：括號內(nèi)為說明輸入:2(repeat=2)100400(m=100,n=400)1100(m=l,n=100)輸出:result:153(1*1*1+5*5*5+3*3*3=153)370(3*3*3+7*7*7=370)371(3*3*3+7*7*7+1*1*1=371)result:(1*1*1=1)#includc"stdio.hnintmain(void){inti,digit,m,n,a,b,c,sum;intrepeat,ri;scanff'%d”,&repeat);fbr(ri=1;ri<=repeat;ri++){scanfi("％d%d”,&m,&n);printf("result:\n");fbr(i=m;i<=n;i++){digit=i;a=digit;digit=digit/10;b=digit;digit=digit/10;c=digit;sum=a*a*a+b*b*b+c*c*c;if(sum=i)printff%d\n”，i);}}return0;}參考2：include"stdio.hMintmain(void)(inti,digit,m,n,number,sum;intrepeat,ri;scanfi(H%d,,,&repeat);fbr(ri=1;ri<=repeat;ri++){scanff%d%d”，&m,&n);printf(Mresult:\nM);fbr(i=m;i<=n;i++){number=i;sum=O;while(number>0){digit=number;sum=sum+digit*digit*digit;number=number/l0;}if(sum=i)printf(w%d\nM,i);40025找完數(shù)(改錯題error04_2)輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入兩個正整數(shù)m和n(l<=m,n<=1000),輸出m至リn之間的所有完數(shù),并輸出其因子。ー個數(shù)如恰好等于它的因子之和,這個數(shù)稱為完數(shù),例如,6=1+2+3,其中1、2、3為因子,6為因子和。輸出使用以下語句:printf(M%d=ド,number);printfT+%d”，factor);pr血ff\n”)；輸入輸出示例：括號內(nèi)為說明輸入:(repeat=2)130(m=l,n=30)400500(m=400,n=500)輸出result:1=16=1+2+328=1+2+4+7+14result:496=1+2+4+8+16+31+62+124+248#include<stdio.h>intmain(void){intfactor,m,n,number,sum;intrepeat,ri;scanff%d”,&repeat);fbr(ri=1;ri<=repeat;ri-H-){seanff%d%d”，&m,&n);printf("result:\n”)；for(number=m;number<=n;number-H-){sum=l;for(factor=2;factor<=number/2;factor-H-)if(numberctor=0)sum=sum+factor;if(sum==number){printf(M%d=じnumber);for(factor=2;factor<number;factor++)if(numberctor==0)printfif*+%dM,factor);pr血f("\n")；printf(w\nM);40027從髙位開始逐位輸出一個整數(shù)的各位數(shù)字(選作)輸入ー個正整數(shù)repeat(0<rcpeat<10)?做repeat次ド列運算:輸入ー個整數(shù)in,從髙位開始逐位分割并輸出它的各位數(shù)字。輸出使用語句:printf("%-2dH,digit);輸入輸出示例:括號內(nèi)為說明輸入3(repeat=3)23456(in=23456)-600(in=-600)8(in=8)輸出234566008#include<stdio.h>intmain(void)(intdigit,in,power,temp,k;intrepeat,ri;scanfi("％d”，&repeat);for(ri=1;ri<=repeat;ri-H-){scanf(M%dM,&in);ififinvO)in=-in;power=in;temp=0;k=1;while(power>0){power=power/l0;temp++;k=k*10;)power=in;while(temp>0)(temp—;k=k/10;digit=power/k;power=power%k;printff%?2d”,digit);}printf("\n");)return0;)40052判斷素數(shù)輸入ー個正整數(shù)n,再輸入n個正整數(shù),判斷它們是否為素數(shù)。素數(shù)就是只能被1和自身整除的正整數(shù),1不是素數(shù),2是素數(shù)。輸出使用以下語句:printf("%disaprime\n",m);printf("%dis'ntaprime\n",m);輸入輸出示例:括號內(nèi)為說明輸入4(n=4)12917輸出is'ntaprimeisaprimeis'ntaprime17isaprime#include<stdio.h>#include<math.h>intmain(void)intflag,i,j,k,m,n;scanff%d”,&n);fbr(i=l;i<=n;i-H-){scanfi[M%dM,&m);if(m==l)printf(H%dis'ntaprime\nM,m);else{k=sqrt(m);fbr(j=2Jv=kj++)ifi(m%j==O){printfi(M%dis*ntaprime\n",m);break;}if(j>k)printfi("%disaprime\nM,m);}}return0;40053逆序輸出整數(shù)輸入ー個正整數(shù)repeat(0<repeat<10)?做repeat次下列運算:輸入ー個整數(shù)in,將其逆序輸出。假設(shè)正數(shù)和負數(shù)逆序輸出的結(jié)果ー樣。輸出使用語句printf("％d”,digit);輸入輸出示例:括號內(nèi)為說明輸入2(repeat=2)200(in=200)-12345(in=-12345)輸出00254321include<stdio.h>intmain(void){intdigit,x;intrepeat,ri;scanf(M%dn,&repeat);fbr(ri=1;ri<=repeat;ri-H-){scanf(H%d",&x);if(x<0)x=-x;while(x!=0){digit=x;printR"％d”,digit);x=x/10;}prin氓"\n");40054輸出斐波那契序列輸入ー個正整數(shù)n(l<n<20),輸出菲波那契(Fibonacci)序列112358…的前n項。輸出使用語句:printf("%d",x);輸入輸出示例:輸入10輸出11235813213455#include<stdio.h>intmain(void){inti,n,xl,x2,x;scanfi("％d”,&n);xl=1;x2=1;printf(”％d%dn,xl,x2);fbr(i=1;i<=n-2;i++){x=xl+x2;printf(M%dx);xl=x2;x2=x;}return0;第フ周(M7)50002使用函數(shù)判斷數(shù)的符號輸入ー個正整數(shù)repeat(0<repeat<10),做repeat次下列運算:輸入1個整數(shù)x,若x大于〇,sign(x)=1;若x等于〇,sign(x)=0;否則,sign(x)=-l,最后輸出sign(x)的值。要求定義和調(diào)用函數(shù)sign(x)實現(xiàn)該分段函數(shù),函數(shù)形參x的類型是int,函數(shù)類型是into輸入輸出示例:括號內(nèi)是說明輸入3(repeat=3)10(x=10)-5(x=-5)0(x=0)輸出sign(10)=1(x=10時sign(x)的值為1)sign(-5)=-l(x=-5時sign(x)的值為-1)sign(O)=0(x=0時sign(x)的值為0)①//include<stdio.h>intsign(intx);intmain(void)(intx,y;intrepeat,ri;scanff%d”，&repeat);fbr(ri=1;ri<=repeat;ri++){scanグ％d”,&x);y=sign(x);printfl["sign(%d)=%d\n",x,y);)}intsign(intx){intt=O;if(x<0)t=-l;elseif(x=O)t=O;elset=l;returnt;50003使用函數(shù)求奇數(shù)和輸入ー個正整數(shù)repeat(OvrepeatvlO),做repeat次下列運算:輸入ー批正整數(shù)(以零或負數(shù)為結(jié)束標志),求其中的奇數(shù)和。要求定義和調(diào)用函數(shù)even(n)判斷數(shù)的奇偶性,當n為偶數(shù)時返回1,否則返回。,函數(shù)形參n的類型是int,函數(shù)類型是int。輸入輸出示例:括號內(nèi)是說明輸入2(repeat=2)12971831120011861721019-1輸出Thesumoftheoddnumbersis30.Thesumoft