2022年2022年軟件測(cè)試題目與答案

1、精選學(xué)習(xí)資料 - - - 歡迎下載軟件測(cè)試課堂測(cè)驗(yàn)第一次測(cè)驗(yàn)：consider an application app that takes two inputs name and age、 where name is a nonempty string containing at most 20 alphabetic characters and age is an integer that must satisfy the constraint 0age120. the app is required to display an errormessage if the input value

2、 provided for age is out of range. the application truncates any name that is more than 20-character in length and generates an error message if an empty string is supplied for name.（1） ） please find out the equivalence classe（s等價(jià)類） . （ 30 分）（2） ） construct test cases using the equivalence classes d

3、erived（in1） （20 分）答案：consider a method fp、 brief for findprice、 that takes two inputs code and qty. the item code is represented by the integer code and the quantity purchased by another integer variable qty. fp accesses a database to find and display the unit price、 the description、 and the total p

4、rice of the item corresponding to code. fp is required to display an error message、 and return、 ifeither of the two inputs is incorrect. assuming that an item code must be in the range 99 999 and quantity in the range 1100.please give your test cases using boundary-value analys（is.50 分）答案：精品學(xué)習(xí)資料精選學(xué)習(xí)

5、資料 - - - 歡迎下載其次次：1. develop a decision table for the descriptions belowno charges are reimburse（d報(bào)銷(xiāo)）to the patient until the deductibl（e扣除） has been精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載met. afterthe deductible has been met、 the amount to be reimbursed depends on whether or not the doctor or hospital is a "pr

6、eferred provider." for preferred providers精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載doctor's office visits are reimbursed at 65% and hospital visits are reimbursed at 95%. for other providers reimburse 50% for doctor's office visits or 80% for hospital visits.答案：2. develop a decision table for the yesterd

7、ate function.答案：第三次：精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載cause-effect testing： in a given network、 the sendfile command is used to send a file to a user on a different file server. the sendfile command takes three arguments: the first argument should be an existing file in the sender s home directory、 the second

8、argument should be the name of the receivers file server、 and the third argument should be the receivers userid. ifall the arguments are correct、 then the fileis successfully sent; otherwise the sender obtains an error message.答案：中國(guó)象棋走馬下法：1. 假如落點(diǎn)在棋盤(pán)外,就不移動(dòng)棋子；2. 假如落點(diǎn)與起點(diǎn)不構(gòu)成日字形,就不移動(dòng)棋子；3. 假如落點(diǎn)處有自己放棋子,就不移

9、動(dòng)棋子；4. 假如在落點(diǎn)方向的鄰近交叉點(diǎn)有棋子（絆馬腿）,就不移動(dòng)棋子；5. 假如不屬于 1-4,且落點(diǎn)處無(wú)棋子,就移動(dòng)棋子；6.假如不屬于 1-4,且落點(diǎn)處為對(duì)方棋子 （非老將）,就移動(dòng)棋子并除去對(duì)方棋子；7. 假如不屬于 1-4,且落點(diǎn)處為對(duì)方老將,就移動(dòng)棋子,并提示戰(zhàn)勝對(duì)方,嬉戲終止；請(qǐng)畫(huà)出因果圖,并轉(zhuǎn)換成判定表答案：consider a web page with three distinct sectionstop、 midddle、 and bottom that can be individually shown or hidden by the user. please use

10、 orthogonalarray testing to test the interactions of the different sections.精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載答案：第四次：某電力公司有 a .b.c.d 共四類收費(fèi)標(biāo)準(zhǔn),并規(guī)定：居民用電每月 200 度以下按 a 類收費(fèi), 200 度以上按 b 類收費(fèi)；動(dòng)力電以每月 1 萬(wàn)度為分界：非高峰用電不足1 萬(wàn)度按 b 類收費(fèi),達(dá)到或超過(guò)1 萬(wàn)度按 c 類收費(fèi)；高峰用電不足 1 萬(wàn)度按 c 類收費(fèi),達(dá)到或超過(guò)1 萬(wàn)度按 d 類收費(fèi)；給出掌握流圖,并設(shè)計(jì)滿意條件組合掩蓋的測(cè)試用例答案：精品學(xué)習(xí)資料精選學(xué)習(xí)資料 -

11、- - 歡迎下載quesüon 21.å&ÎèãfÄtlä.2.î:¡ÿοj精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載”xi90 1"z86t- lx+¥l t 0 ixmoyàrdl精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載question 31int iogicexampieint x、 int yint magic=0;ifx>0 && y>0magic = x+y«10; / .&#

12、233;*/ &1 elsemagicx+y-10; / .é*3 /t:2ifmagic < 0magic = 0;/ îâ1&3 relurn magic;/ f &4精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載quesõon 1void doint x、 int a. int b. int c12whilex-»<104ii b=05 c=c/a;6 else7ifc<o && x>18x=x+19a=b+c、1011 

13、1;»1üjiú&jiiüiei 2. ú/gj1t17*+§、 êg-»ia:z*.:=:iÃ:i a'a.l精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載float triangbtyps4oat a、5oat b doat c精品學(xué)習(xí)資料精選學(xué)習(xí)資料 - - - 歡迎下載、 1 float 1.2 ifa+b«c a+c<«b | b+c<«a s pnx"«=o +x、rm «». rn: 4 else5 l=a+b+c.b prinh”. &.1j-t£'£o10 1n"、l.7 if”a=b 8& a=+zb prinh -d z'«“-q-'n".9 else i