C++實現(xiàn)復數(shù)四則運算.docx

#include /using namespace std;class Complexpublic:Complex()real=0;imag=0;Complex(double r,double i):real(r),imag(i)friend istream& operator(istream&,Complex&);/友元函數(shù)，用來輸入復數(shù)friend ostream& operator(istream &input,Complex &c)coutc.real;coutc.imag;return input;ostream & operator(ostream &output,Complex &c)if(c.real=0&c.imag=0) output0;else if(c.real=0&c.imag!=0) outputc.imagi; else if(c.real!=0&c.imag=0) outputc.real; else if(c.imag=1) outputc.real+i; else if(c.imag=-1) outputc.real0) outputc.real+c.imagi; else if(c.imag0) outputc.realc.imagi; return output;Complex operator +(Complex &c1,Complex &c2)return Complex(c1.real+c2.real,c1.imag+c2.imag);Complex operator-(Complex &c1,Complex &c2)return Complex(c1.real-c2.real,c1.imag-c2.imag);Complex operator*(Complex &c1,Complex &c2)return Complex(c1.real*c2.real-c1.imag*c2.imag,c1.real*c2.imag+c1.imag*c2.real);Complex operator/(Complex &c1,Complex &c2)return Complex(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag),(c2.real*c1.imag-c1.real*c2.imag)/(c2.real*c2.real +c2.imag*c2.imag);void suan(Complex &c1,Complex &c2,Complex &c3)int flag=1;char c; cout菜單:endl; cout1.輸入復數(shù)1endl; cout2.輸入復數(shù)2endl; cout+.進行復數(shù)相加運算endl; cout-.進行復數(shù)相減運算endl; cout*.進行復數(shù)相乘運算endl; cout/.進行復數(shù)相除運算endl; cout0.退出endl;while(flag) cout請選擇操作:c; switch (c) case 1:cinc1;cout您輸入的復數(shù)是:c1c2;cout您輸入的復數(shù)是:c2endl;break; case +:c3=c1+c2;cout(c1)+(c2)=c3endl;break; case -:c3=c1-c2;cout(c1)-(c2)=c3endl;break; case *:c3=c1*c2;cout(c1)*(c2)=c3endl;break; case /:c3=c1/c2;cout(c1)/(c2)=c3endl;break; case 0:flag=0;