高等數(shù)學(xué)I(上)學(xué)習(xí)通超星期末考試答案章節(jié)答案2024年

高等數(shù)學(xué)I(上)學(xué)習(xí)通超星期末考試章節(jié)答案2024年/star3/origin/3b5c5bea5437dfad0e0a37b415ad2298.png

答案:原式=(3分)=-3(3分)/star3/origin/a1e05cf7dc487e49489b37f160de71bf.png

答案:要使,(3分)只要,即要,取,當(dāng)時(shí),有,從而.(4分)/star3/origin/f377017de27d82e5f9397062d7d3c256.png

答案:原式(3分)(3分)/star3/origin/8a2cc302f3aac4f81f0c4bcaec6d74bc.png

答案:原式(3分)(3分)/star3/origin/e1279228da6dba7f08e63c532a8e3f18.png

答案:原式=(3分)(3分)/star3/origin/8868e120448473f3a3bc2dc551154c8c.png

答案:原式=(3分)=0(3分)/star3/origin/1a5673bd59cdef13976b54585097bc90.png

答案:原式(2分)(2分)(3分)(3分)發(fā)散數(shù)列是無界的;

答案:錯(cuò)/star3/origin/efd54f292ec58102484b203b7ae055d9.png

答案:錯(cuò)/star3/origin/201863814f906307bbf73d934d2b18d3.png

答案:錯(cuò)/star3/origin/5c75db793df901c1eeea5c5a3c1c6114.png

答案:錯(cuò)/star3/origin/3eec7cfe633fe161c8bf43d3cd151c46.png

答案:對(duì)/star3/origin/ab8dfa84b2abeac471874a60b4c37049.png

答案:以1為極限/star3/origin/0064bdb27e97e14cd380ead7038abb16.png

答案:先給定后再確定/star3/origin/5cefb6795097dc7fa23db1eb450100b7.png

答案:因?yàn)?,=(4分)若存在,即:=(4分)所以.(2分)/star3/origin/b2eaf683513e9847d1bcc0c23a5a7576.png

答案:原式=(4分)(4分)(2分)/star3/origin/374c4e5f7f30204107b9122ea2239a01.png

答案:原式=(4分)=(4分)(2分)/star3/origin/f3a5ad5e6df23e48c168b7f5834fdbe4.png

答案:原式(4分)(4分)(2分)/star3/origin/da783709ed17a73cd48d7f875ce66159.png

答案:錯(cuò)/star3/750_1024/d0e0f59a82792c2e4a309a1985fc2417.jpg

答案:錯(cuò)/star3/origin/f91b88ab5b5562505a74f084098fab0b.png

答案:對(duì)/star3/origin/d971e5f3c6c239bea93450c3c7a3a474.png

答案:錯(cuò)/star3/origin/2960fac0de81b40e38acf682beec728a.png

答案:1/star3/origin/9f6c58c09796587b5789caada4911440.png

答案:0/star3/origin/c92a41821e3ab6ee0a0d077d0bd63268.png

答案:-1/star3/origin/0f5c1edf0cf1e8c3c873835ea6faf40a.png

答案:0/star3/origin/c34c19dd4158bbaf82a623b60fb0d6e3.png

答案:1/star3/origin/fe038239b32ca2b387312492d255a113.png

答案:不存在/star3/origin/5f117e485576cd7effc5b72c4971fdf8.png

答案:不存在/star3/origin/1f293b62f6ac0eee6247fb5b2ef5ca8a.png

答案:(10分)/star3/origin/91fe19d442d5335a8da37e3e0794a5bf.png

答案:(10分)/star3/origin/c321d56bea4cffa725a836616363a8ca.png

答案:(10分)/star3/origin/8ac3e9308aed892ecebb015eb5e1fc47.png

答案:因?yàn)?5分)且.(5分)/star3/origin/48f6674499b575db65c27c9f241955fd.png

答案:錯(cuò)/star3/origin/78b6c31d92440d5f7c126cce8713b0bc.png

答案:對(duì)/star3/origin/769a66350ccf4ba1d28479fc761624b5.png

答案:對(duì)/star3/origin/cff99f9182bcf01634f3d06fb6e1a2e9.png

答案:錯(cuò)/star3/origin/b02389e0826a3be77d7327e42db3341a.png

答案:錯(cuò)/star3/origin/b60e3259d4cb7365a7a86e23aed7d33e.png

答案:對(duì)/star3/origin/9a4c79be15f9b5a008e3f7aed85b0ed6.png

答案:6/star3/origin/8057b85aaf590ea3bcc54e84087e7aae.png

答案:3/star3/origin/1a3356e9f996733b2932ad0a063c1125.png

答案:1/star3/origin/8478c4397a8e68854bdd34aadbd9859f.png

答案:1/2/star3/origin/e3e07ee23fc08bfb55c8ef1795d11421.png

答案:1/star3/origin/5ea8f9d042ca92290790dafd75bf7b1d.png

答案:1/star3/origin/3870e98e5a88b87ad3ec9235d888c8ad.png

答案:,,(4分)令(4分)得(2分)/star3/origin/342da2b28e842fcbae5dccc514dd4b3c.png

答案:令(3分)因?yàn)樵趨^(qū)間上連續(xù),且(4分)故由零點(diǎn)定理,在區(qū)間內(nèi)至少存在一點(diǎn),使得,即方程在區(qū)間內(nèi)至少有一個(gè)根.(2分)/star3/origin/23b8df6ff65f3a0e95b58ef943b4b259.png

答案:因?yàn)楫?dāng)時(shí),(2分)(8分)/star3/origin/dda4fc259f01b99a8033e4e2e047e882.png

答案:因當(dāng)時(shí),,故=(3分)=(3分)==(4分)/star3/origin/08ce174e6d29ef3e070f4b057f1821e1.png

答案:錯(cuò)/star3/origin/dfb343db15ab3b68042e5e11d620bb98.png

答案:對(duì)/star3/origin/9745454cc44bccb2c8fda4ad6ed1a9a1.png

答案:錯(cuò)/star3/origin/925b677f22ce7f6f8b608c43926ee57a.png

答案:1初等函數(shù)在其定義區(qū)間內(nèi)()

答案:連續(xù)/star3/origin/abfe501f913886e5c4da4d5caac10b97.png

答案:跳躍間斷點(diǎn)/star3/origin/37758f32b17d1c776138b41c68c1a0cb.png

答案:連續(xù)點(diǎn)/star3/origin/33db24f9f0e3ccd9bb84b3d1d8c5bdeb.png

答案:2/star3/origin/946570b3fcded59e575e92e04162855a.png

答案:0/star3/origin/e658149bb1c0fe280333aa5415134d61.png

答案:同階無窮小,但不等價(jià)/star3/origin/4f8b41f9583a9080554919f84fe5d3af.png

答案:由得原方程兩邊對(duì)求導(dǎo),得(2分)將及代入上式,得(2分)所求切線方程為(2分)法線方程為(2分)/star3/origin/b5236e15417d27ad9c25f20cf118f0a8.png

答案:原方程兩邊對(duì)求導(dǎo),得(4分)化簡(jiǎn)得(4分)/star3/origin/9023aec32b49e0cc5567cb7748a29d2b.png

答案:(4分)(4分)/star3/origin/a13555980dc846262656acc96159660b.png

答案:兩邊同時(shí)取對(duì)數(shù)(2分)上式兩邊對(duì)求導(dǎo)(3分)(3分)/star3/origin/f2247a07d07ad0bacca569a63e4b5bf5.png

答案:(2分)=(3分)=(3分)/star3/origin/d8f8830177988ea29bc1a19e34def8e7.png

答案:錯(cuò)/star3/origin/64d68589f196c57b4c842fddb6270abc.png

答案:錯(cuò)/star3/origin/a04d4b7352cb4f14f8e18000af631c1c.png

答案:對(duì)/star3/origin/e34db3c1846eed1796f7d3faaa39ced9.png

答案:對(duì)/star3/origin/6dd5db80cc52470ad376dd4272ac498b.png

答案:0/star3/origin/75be9ec14c119137f27f160448a7d591.png

答案:連續(xù)但不可導(dǎo)/star3/origin/0bcd670055cc67e3f592237d65ef10f2.png

答案:0/star3/origin/75cb1d9971cfa2f27761e77a20e46595.png

答案:4/star3/origin/823137b5717117c1de6259bd23840b74.png

答案:錯(cuò)/star3/origin/c297c32cd2bc50d5d9b6ce9b6879a9bb.png

答案:錯(cuò)/star3/origin/04816b31e8542c3d4e323b9f0b72fb67.png

答案:錯(cuò)/star3/origin/f47e420e6c348483f989fba49d27d328.png

答案:令在上顯然滿足拉格朗日中值定理?xiàng)l件則,使得(4分)(4分)/star3/origin/e0aa8948412a96023847f0764c0a92c4.png

答案:(4分)(4分)/star3/origin/b8399a9e95b63ed31a4a40fc777167eb.png

答案:(2分)(6分)/star3/origin/d8a12403dfd72cc76a8488f7a9488159.png

答案:(4分)(4分)/star3/origin/e050badb3e97ada19f0a2ba4753e36d6.png

答案:錯(cuò)/star3/origin/9c30987d11337257dd59507e64c48abb.png

答案:錯(cuò)/star3/origin/b5f11c050351f95bf18e97966bfeb62a.png

答案:錯(cuò)(15分)要建造一個(gè)容積為8000立方米的無蓋長(zhǎng)方體蓄水池,已知池底為正方形且單位造價(jià)為側(cè)壁造價(jià)的兩倍,問蓄水池的尺寸如何設(shè)計(jì)才能使得造價(jià)最低?

答案:設(shè)底邊長(zhǎng)為,高為,則.(7分)令得唯一駐點(diǎn)故當(dāng)?shù)酌孢呴L(zhǎng)為20米,高為20米時(shí),蓄水池的造價(jià)最低.(8分)/star3/origin/f9fcf0e8da0cba4d797e3a6eeee5d2dd.png

答案:因?yàn)榱?得駐點(diǎn)(7分)故最大值,最小值(8分)/star3/origin/f509876ee6774dd49e16ff4f6331b373.png

答案:錯(cuò)/star3/origin/44d6604b85ae91e844ed08f7ccc3f0d4.png

答案:錯(cuò)/star3/origin/30c0854a3ad7d9271546668e5359fe4c.png

答案:錯(cuò)函數(shù)在開區(qū)間內(nèi)的最小值必是極小值.

答案:對(duì)函數(shù)的最大值一定是極大值.

答案:錯(cuò)/star3/origin/8bbda6cb4040aeaf02afb67f754ed42b.png

答案:20/star3/origin/dc1b07104008bce7f1576ee551771270.png

答案:0/star3/origin/3ebeb95eef4e44086487c9decbbc99e9.png

答案:令(2分)因?yàn)樵趨^(qū)間上連續(xù),且(4分)故由零點(diǎn)定理,在區(qū)間內(nèi)至少存在一點(diǎn),使得,即方程在區(qū)間內(nèi)至少有一個(gè)根.(2分)/star3/origin/9c1eda7ec2d870371d7bda9565416522.png

答案:(1)原式(3分)(1分)(2)因?yàn)?2分)且.(2分)/star3/origin/1ba4ff4c4f78fda3ea86b66d7e954d36.png

答案:(1)(4分)(2)(4分)/star3/origin/9ae74c717ed6fe51cf142caa53a1becd.png

答案:(1)(4分)(2)(4分)/star3/ori