高考數(shù)學(xué)二輪復(fù)習(xí)核心專題講練：函數(shù)與導(dǎo)數(shù)第3講 利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性、極值、最值原卷版

第3講利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性、極值、最值目錄第一部分：知識強化第二部分：重難點題型突破突破一：導(dǎo)數(shù)的幾何意義突破二：利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性角度1：利用導(dǎo)數(shù)求函數(shù)的單調(diào)區(qū)間（不含參）角度2：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)角度3：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間角度4：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)角度5：已知函數(shù)SKIPIF1<0有三個單調(diào)區(qū)間突破三：利用導(dǎo)數(shù)研究函數(shù)的極值與最值角度1：求已知函數(shù)的極值（點）、最值角度2：根據(jù)函數(shù)的極值（點）、最值，求參數(shù)突破四：含參問題討論單調(diào)性角度1：導(dǎo)函數(shù)有效部分是一次型（或可化為一次型）角度2:導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且可因式分解型角度3:導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且不可因式分解型第三部分：沖刺重難點特訓(xùn)第一部分：知識強化1、導(dǎo)數(shù)的幾何意義函數(shù)SKIPIF1<0在點SKIPIF1<0處的導(dǎo)數(shù)的幾何意義，就是曲線SKIPIF1<0在點SKIPIF1<0處的切線的斜率SKIPIF1<0，即SKIPIF1<0，相應(yīng)的切線方程為SKIPIF1<0.（1）在型求切線方程已知：函數(shù)SKIPIF1<0的解析式.計算：函數(shù)SKIPIF1<0在SKIPIF1<0或者SKIPIF1<0處的切線方程.步驟：第一步：計算切點的縱坐標SKIPIF1<0（方法：把SKIPIF1<0代入原函數(shù)SKIPIF1<0中），切點SKIPIF1<0.第二步：計算切線斜率SKIPIF1<0.第三步：計算切線方程.切線過切點SKIPIF1<0，切線斜率SKIPIF1<0。根據(jù)直線的點斜式方程得到切線方程：SKIPIF1<0.（2）過型求切線方程已知：函數(shù)SKIPIF1<0的解析式.計算：過點SKIPIF1<0（無論該點是否在SKIPIF1<0上）的切線方程.步驟：第一步：設(shè)切點SKIPIF1<0第二步：計算切線斜率SKIPIF1<0；計算切線斜率SKIPIF1<0；第三步：令：SKIPIF1<0，解出SKIPIF1<0，代入SKIPIF1<0求斜率第三步：計算切線方程.根據(jù)直線的點斜式方程得到切線方程：SKIPIF1<0.2、利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性（1）求已知函數(shù)（不含參）的單調(diào)區(qū)間①求SKIPIF1<0的定義域②求SKIPIF1<0③令SKIPIF1<0，解不等式，求單調(diào)增區(qū)間④令SKIPIF1<0，解不等式，求單調(diào)減區(qū)間注：求單調(diào)區(qū)間時，令SKIPIF1<0（或SKIPIF1<0）不跟等號.（2）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)①已知SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增SKIPIF1<0SKIPIF1<0，SKIPIF1<0恒成立.②已知SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減SKIPIF1<0SKIPIF1<0，SKIPIF1<0恒成立.注：已知單調(diào)性，等價條件中的不等式含等號.（3）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間①已知SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)增區(qū)間SKIPIF1<0SKIPIF1<0，SKIPIF1<0有解.②已知SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)減區(qū)間SKIPIF1<0SKIPIF1<0，SKIPIF1<0有解.（4）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)SKIPIF1<0SKIPIF1<0，使得SKIPIF1<0（SKIPIF1<0是變號零點）3、函數(shù)的極值一般地，對于函數(shù)SKIPIF1<0，（1）若在點SKIPIF1<0處有SKIPIF1<0，且在點SKIPIF1<0附近的左側(cè)有SKIPIF1<0，右側(cè)有SKIPIF1<0，則稱SKIPIF1<0為SKIPIF1<0的極小值點，SKIPIF1<0叫做函數(shù)SKIPIF1<0的極小值.（2）若在點SKIPIF1<0處有SKIPIF1<0，且在點SKIPIF1<0附近的左側(cè)有SKIPIF1<0，右側(cè)有SKIPIF1<0，則稱SKIPIF1<0為SKIPIF1<0的極大值點，SKIPIF1<0叫做函數(shù)SKIPIF1<0的極大值．（3）極小值點與極大值點通稱極值點，極小值與極大值通稱極值.注：極大（小）值點，不是一個點，是一個數(shù).4、函數(shù)的最大（?。┲狄话愕兀绻趨^(qū)間SKIPIF1<0上函數(shù)SKIPIF1<0的圖象是一條連續(xù)不斷的曲線，那么它必有最大值與最小值.設(shè)函數(shù)SKIPIF1<0在SKIPIF1<0上連續(xù)，在SKIPIF1<0內(nèi)可導(dǎo)，求SKIPIF1<0在SKIPIF1<0上的最大值與最小值的步驟為：（1）求SKIPIF1<0在SKIPIF1<0內(nèi)的極值；（2）將函數(shù)SKIPIF1<0的各極值與端點處的函數(shù)值SKIPIF1<0，SKIPIF1<0比較，其中最大的一個是最大值，最小的一個是最小值.5、函數(shù)的最值與極值的關(guān)系（1）極值是對某一點附近(即局部)而言，最值是對函數(shù)的定義區(qū)間SKIPIF1<0的整體而言；（2）在函數(shù)的定義區(qū)間SKIPIF1<0內(nèi)，極大（?。┲悼赡苡卸鄠€（或者沒有），但最大（?。┲抵挥幸粋€（或者沒有）；（3）函數(shù)SKIPIF1<0的極值點不能是區(qū)間的端點，而最值點可以是區(qū)間的端點；（4）對于可導(dǎo)函數(shù)，函數(shù)的最大(小)值必在極大(小)值點或區(qū)間端點處取得.第二部分：重難點題型突破突破一：導(dǎo)數(shù)的幾何意義1．（2022·全國·模擬預(yù)測）已知函數(shù)SKIPIF1<0，則過點SKIPIF1<0可作曲線SKIPIF1<0的切線的條數(shù)為（

）A．0 B．1 C．2 D．32．（2022·河南河南·模擬預(yù)測（理））已知SKIPIF1<0是奇函數(shù)，則過點SKIPIF1<0向曲線SKIPIF1<0可作的切線條數(shù)是（

）A．1 B．2 C．3 D．不確定3．（2022·江蘇南通·模擬預(yù)測）已知過點SKIPIF1<0作曲線SKIPIF1<0的切線有且僅有SKIPIF1<0條，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<04．（2022·河南省淮陽中學(xué)模擬預(yù)測（理））已知SKIPIF1<0，過原點作曲線SKIPIF1<0的切線，則切點的橫坐標為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·安徽·合肥一六八中學(xué)模擬預(yù)測（文））若直線SKIPIF1<0是曲線SKIPIF1<0的切線，也是曲線SKIPIF1<0的切線，則SKIPIF1<0__________.6．（2022·福建省漳州第一中學(xué)模擬預(yù)測）已知直線SKIPIF1<0是曲線SKIPIF1<0的切線，則SKIPIF1<0___________.7．（2022·山東師范大學(xué)附中模擬預(yù)測）已知函數(shù)SKIPIF1<0，若存在一條直線同時與兩個函數(shù)圖象相切，則實數(shù)a的取值范圍__________．8．（2022·廣東佛山·模擬預(yù)測）已知函數(shù)SKIPIF1<0，函數(shù)在SKIPIF1<0處的切線方程為____________．若該切線與SKIPIF1<0的圖象有三個公共點，則SKIPIF1<0的取值范圍是____________．突破二：利用導(dǎo)數(shù)研究函數(shù)的單調(diào)性角度1：利用導(dǎo)數(shù)求函數(shù)的單調(diào)區(qū)間（不含參）1．（2022·福建·莆田一中高二期中）若函數(shù)SKIPIF1<0，則SKIPIF1<0的一個單調(diào)遞增區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（多選）（2022·湖北黃岡·高三階段練習(xí)）下列區(qū)間中能使函數(shù)SKIPIF1<0單調(diào)遞增的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·遼寧省實驗中學(xué)東戴河分校高三階段練習(xí)）已知函數(shù)SKIPIF1<0，則SKIPIF1<0的單調(diào)減區(qū)間為______.4．（2022·全國·高二單元測試）已知函數(shù)SKIPIF1<0的單調(diào)減區(qū)間為SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0的最大值為______．角度2：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)1．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國·高二課時練習(xí)）已知函數(shù)SKIPIF1<0在SKIPIF1<0上為增函數(shù)，則實數(shù)SKIPIF1<0的取值范圍是SKIPIF1<0SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高二學(xué)業(yè)考試）函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·重慶市朝陽中學(xué)高二階段練習(xí)）已知函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增,則實數(shù)SKIPIF1<0的取值范圍是_____.5．（2022·江蘇·常熟外國語學(xué)校高二階段練習(xí)）若函數(shù)SKIPIF1<0的單調(diào)減區(qū)間是SKIPIF1<0,則實數(shù)SKIPIF1<0的值為__________．6．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則實數(shù)SKIPIF1<0的取值范圍是______角度3：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間1．（2022·河南信陽·高二期中（理））已知函數(shù)SKIPIF1<0，在其定義域內(nèi)的子區(qū)間SKIPIF1<0上不單調(diào)，則實數(shù)m的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·河南·溫縣第一高級中學(xué)高二階段練習(xí)（理））已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0存在單調(diào)遞減區(qū)間,則SKIPIF1<0的取值范圍是A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0角度4：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)1．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不是單調(diào)函數(shù)，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（多選）（2022·全國·高二單元測試）已知函數(shù)SKIPIF1<0，則SKIPIF1<0在SKIPIF1<0上不單調(diào)的一個充分不必要條件有（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·天津市武清區(qū)楊村第三中學(xué)高三階段練習(xí)）函數(shù)SKIPIF1<0在SKIPIF1<0上不單調(diào)，則實數(shù)a的取值范圍是_____．角度5：已知函數(shù)SKIPIF1<0有三個單調(diào)區(qū)間1．（2023·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0存在三個單調(diào)區(qū)間，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·江西省信豐中學(xué)高二階段練習(xí)（文））若函數(shù)SKIPIF1<0在定義域SKIPIF1<0上恰有三個單調(diào)區(qū)間，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0突破三：利用導(dǎo)數(shù)研究函數(shù)的極值與最值角度1：求已知函數(shù)的極值（點）、最值1．（2022·廣西河池·模擬預(yù)測（理））已知函數(shù)SKIPIF1<0有兩個極值點SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的極大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·青?！ご笸ɑ刈逋磷遄灾慰h教學(xué)研究室二模（理））設(shè)函數(shù)SKIPIF1<0，則下列不是函數(shù)SKIPIF1<0極大值點的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·江西南昌·一模（理））已知函數(shù)SKIPIF1<0，若不等式SKIPIF1<0的解集為SKIPIF1<0，且SKIPIF1<0，則函數(shù)SKIPIF1<0的極大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．SKIPIF1<04．（2022·四川省綿陽南山中學(xué)模擬預(yù)測（理））已知函數(shù)SKIPIF1<0的零點為SKIPIF1<0，SKIPIF1<0零點為SKIPIF1<0，則SKIPIF1<0的最大值為（

）A．1 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·四川省南充高級中學(xué)模擬預(yù)測（文））已知函數(shù)SKIPIF1<0，方程SKIPIF1<0恰有兩個不同的實數(shù)根SKIPIF1<0、SKIPIF1<0，則SKIPIF1<0的最小值與最大值的和（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．（2022·河南·南陽中學(xué)模擬預(yù)測（文））已知函數(shù)SKIPIF1<0存在兩個極值點SKIPIF1<0.(1)求SKIPIF1<0的取值范圍；(2)求SKIPIF1<0的最小值.7．（2022·四川成都·模擬預(yù)測（理））SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)．(1)當SKIPIF1<0時，求經(jīng)過SKIPIF1<0且與曲線SKIPIF1<0相切的直線；(2)記SKIPIF1<0的極小值為SKIPIF1<0，求SKIPIF1<0的最大值．8．（2022·湖南省臨澧縣第一中學(xué)二模）已知函數(shù)SKIPIF1<0.(1)當SKIPIF1<0時，若SKIPIF1<0在SKIPIF1<0上存在最大值，求m的取值范圍；(2)討論SKIPIF1<0極值點的個數(shù).9．（2022·全國·模擬預(yù)測）設(shè)函數(shù)SKIPIF1<0，SKIPIF1<0.(1)當SKIPIF1<0時，證明：SKIPIF1<0在SKIPIF1<0上無極值；(2)設(shè)SKIPIF1<0，SKIPIF1<0，證明：SKIPIF1<0在SKIPIF1<0上只有一個極大值點.角度2：根據(jù)函數(shù)的極值（點）、最值，求參數(shù)1．（2022·陜西·蒲城縣蒲城中學(xué)高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0有三個極值點，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·江西贛州·高三期中（理））已知函數(shù)SKIPIF1<0存在唯一的極值點，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·江西贛州·高三階段練習(xí)（文））等比數(shù)列SKIPIF1<0中的項SKIPIF1<0，SKIPIF1<0是函數(shù)SKIPIF1<0的極值點，則SKIPIF1<0（

）A．3 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·江西·萍鄉(xiāng)市第二中學(xué)高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0在SKIPIF1<0上的最小值為SKIPIF1<0，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·天津市瑞景中學(xué)高三期中）當SKIPIF1<0時，函數(shù)SKIPIF1<0取得最大值SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．2 D．46．（2022·河南·高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)求SKIPIF1<0在SKIPIF1<0上的極小值點；(2)若SKIPIF1<0的最大值大于SKIPIF1<0的最大值，求SKIPIF1<0的取值范圍．7．（2022·河南·高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0.(1)當SKIPIF1<0時，求SKIPIF1<0的單調(diào)區(qū)間；(2)若SKIPIF1<0在區(qū)間SKIPIF1<0上存在極值點，求實數(shù)a的取值范圍.SKIPIF1<08．（2022·北京海淀·高三期中）已知函數(shù)SKIPIF1<0．①當SKIPIF1<0時，SKIPIF1<0的極值點個數(shù)為__________；②若SKIPIF1<0恰有兩個極值點，則SKIPIF1<0的取值范圍是__________．突破四：含參問題討論單調(diào)性角度1：導(dǎo)函數(shù)有效部分是一次型（或可化為一次型）1．（2022·遼寧實驗中學(xué)模擬預(yù)測）已知函數(shù)SKIPIF1<0(1)請討論函數(shù)SKIPIF1<0的單調(diào)性2．（2022·河南河南·一模（文））已知函數(shù)SKIPIF1<0.(1)討論SKIPIF1<0的單調(diào)性；3．（2022·吉林·長春市實驗中學(xué)二模）已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性；4．（2022·黑龍江·哈爾濱市第一二二中學(xué)校模擬預(yù)測（文））已知函數(shù)SKIPIF1<0(1)若SKIPIF1<0，求SKIPIF1<0的極小值(2)討論函數(shù)SKIPIF1<0的單調(diào)性；角度2:導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且可因式分解型1．（2022·四川綿陽·一模（理））已知函數(shù)SKIPIF1<0（SKIPIF1<0）．(1)討論函數(shù)SKIPIF1<0的單調(diào)性；2．（2022·天津·南開中學(xué)模擬預(yù)測）已知函數(shù)SKIPIF1<0，SKIPIF1<0為函數(shù)SKIPIF1<0的導(dǎo)函數(shù)．(1)討論SKIPIF1<0的單調(diào)性；3．（2022·天津·二模）已知函數(shù)SKIPIF1<0．(1)當SKIPIF1<0時，求曲線SKIPIF1<0在SKIPIF1<0處的切線方程；(2)求函數(shù)SKIPIF1<0的單調(diào)區(qū)間；角度3:導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且不可因式分解型1．（2022·福建泉州·模擬預(yù)測）已知函數(shù)SKIPIF1<0(1)討論SKIPIF1<0的單調(diào)性；2．（2022·江西·模擬預(yù)測（理））已知函數(shù)SKIPIF1<0，(1)討論SKIPIF1<0的單調(diào)性；第三部分：沖刺重難點特訓(xùn)一、單選題1．（2022·全國·高二專題練習(xí)）SKIPIF1<0，SKIPIF1<0在SKIPIF1<0處切線方程為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·福建·高三階段練習(xí)）已知SKIPIF1<0，SKIPIF1<0，直線SKIPIF1<0與曲線SKIPIF1<0相切，則SKIPIF1<0的最小值是（

）A．16 B．12 C．8 D．43．（2022·河南·濮陽油田實驗學(xué)校高三階段練習(xí)（文））“過點SKIPIF1<0可以作兩條與曲線SKIPIF1<0相切的直線”的充要條件是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·上海市行知中學(xué)高三階段練習(xí)）“SKIPIF1<0”是“函數(shù)SKIPIF1<0在SKIPIF1<0上是嚴格增函數(shù)”的（

）A．充分不必要條件 B．必要不充分條件C．充要條件 D．既不充分也不必要條件5．（2022·海南昌茂花園學(xué)校高三階段練習(xí)）若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·江蘇·常州市第一中學(xué)高三開學(xué)考試）已知函數(shù)SKIPIF1<0，若SKIPIF1<0在區(qū)間上SKIPIF1<0單調(diào)遞增，則實數(shù)的a的范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<07．（2022·河南·高三階段練習(xí)（文））已知函數(shù)SKIPIF1<0在SKIPIF1<0處有極值，則SKIPIF1<0的最小值為（

）A．2 B．SKIPIF1<0 C．SKIPIF1<0 D．48．（2022·四川省成都市新都一中高三階段練習(xí)（文））函數(shù)SKIPIF1<0，SKIPIF1<0的極值點為SKIPIF1<0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．（2022·貴州·盤州市聚道高中有限責(zé)任公司高三階段練習(xí)（文））已知函數(shù)SKIPIF1<0，若對任意的SKIPIF1<0，都有SKIPIF1<0，則實數(shù)a的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．（2022·內(nèi)蒙古·赤峰二中高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0是定義域為SKIPIF1<0的奇函數(shù)，且當SKIPIF1<0時，SKIPIF1<0．若函數(shù)SKIPIF1<0在SKIPIF1<0上的最小值為3，則實數(shù)a的值為（

）A．1 B．2 C．3 D．4二、多選題11．（2022·重慶八中高三階段練習(xí)）已知函數(shù)SKIPIF1<0有兩個極值點SKIPIF1<0與SKIPIF1<0，且SKIPIF1<0，則下列結(jié)論正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（2022·浙江·高二階段練習(xí)）已知函數(shù)SKIPIF1<0，則下列判斷正確的是（

）A．直線SKIPIF1<0與曲線SKIPIF1<0相切B．函數(shù)SKIPIF1<0