數(shù)字電路習(xí)題參杭電原版

第一

mv(t)vetm

tlntw0.9tw0.1

us= 0.105usus 2.303

tw0.5

us 0.6930

v(t

(1et/r)充t1

v(t)ve(tt1)/m0.5vmm

t1

ln2rln2502ln25ln2112t-XY11X2tY--1X2tY(1) (2) (3) (4) )8421 (8B)H(10001101100)EX-3 1. = [94] = = BIN= OCT [97](1) (2) 第二（3）F=（5）FACD略B

Z

BD

XYXZWY(AB)(BC)B

(XZ)(YZ

(BD)(B

(YZ)(WX)(XYAB

WZWX

XY①CADBDAB②CABAD*注：卡諾圖化簡所得的結(jié)果并不是唯一AC(a)= (b)= (c)= (d)=F=Σm(2,4,5,6)F=ПM(0,1,3,7)F=Σm(0,1,3,7)F F=Σm(0,4,6,7)FPBCEABDEACDEBCDEACDEABCE第三

t

O-

tOtOtOt（a（b）P1X1X2Y1Y

P2Y1Y2X1X

P3ABC(DTTLP1F(ABC)F(ABCDP2(ABEFJ)D(ABEFJ

P2

P1P2FAB

P2

P2CAB

（C第四(a)PA⊙BPAB(c)PA QP(A(d)P(AQ(e)P[A(CQ(BC)(f)PA BA2401234567&1&&0101311F01233120131F10123312 123123123F013101311F123123 0F0000C

Z(2)F1m(0,1,5,10,14,15，F(xiàn)2的MUX實(shí)現(xiàn)與F1AA11012345673G2018

1F1 A （1）FAB (2)FAB00131123123F1注（1）FABC001311123123FFDF1123123F013111

DF00131123123F1DFABCDF00000000110010000111010000101101101011101000010011101011011011001110101110111110FABDACDBCDBCDACDABCDF00001000100010000110010000101101100011101000010010101011011011000110101110011111FABCDABCDABCDW,Z,Y,XX,W,Z,Y第五HLHLHLLLRQQt(c)（d）nDi0X0000X11110X0011X11IIIIiQn1i

JQnKQn

ENQn

(QnQn)可得：J KENDI=ABBCQCA1111Q1QHL置L置tQHL翻L翻翻JtHLL 第六[Q1Q2]n+1=01；[Q1Q2]n+2=t置數(shù)t置數(shù)右移移持移置數(shù)左移RM1RM11 =&< <1011011060110110011001001910010010200100100401001000810000001000000001111100011001110101101111100000000890S=13狀態(tài)僅為665P0P01231213 PQ2、Q3、P波765765432100000000676700 電SQ30SQ300200100000M＝06；M＝13210545632105456 10(a)

波形圖如下 1&1&01002200

0000020(a)先用兩片74LS197構(gòu)成16×16＝256模的計(jì)數(shù)器，再用反饋置數(shù)法（或反饋0.5個(gè)數(shù)的Q7端為低電平，向上49個(gè)數(shù)（含128）的Q7端為高電平。故置數(shù)端的輸入數(shù)據(jù)DI＝79＝[ 1111110298＝7×1498分頻器。同理要求占空比為0.5，所以模14計(jì)數(shù)器的狀態(tài)應(yīng)采用0001～1110，用1111來產(chǎn)生異步置數(shù)信號。Q6端作為分頻信號輸出。11&10100000CT{Q1220002200& 98＝7×7×274LS9777222計(jì)數(shù)器不能用前兩塊74LS97中的模2計(jì)數(shù)器，因?yàn)榉答伓耸峭瑫r(shí)對74LS97中的模2，模811111Q622002200&2200&

M=38*16 X=0: M=8X=1 M=分頻后應(yīng)取Q20087162534

((D1=D0=X+Q1Q0Z=Q1Q0X

XXX01----

XX----Z1Z11RXD&(1)

A

C<<A（00B（01D1=Q1X+Q1Q0XD0=Q0X+Q1XZ=A（00B（01D1=Q1X+Q0XD0=Q0X+Q1Q0XZ=Q1Q0X(2 Z(t)=

A

D第七3<=>00 &13<=0 13<=>00 MM0B2B2MB0&1133030?0DD0~0100010F3<=0 0011133030∑0第八

共了11個(gè)1（編程簡圖見下頁F0=∑m(5,7,10,11F1=∑m(5,7,14,15F3=∑m(0,2,8F4=∑m(0,2,5,13F5=∑m(5,13,10,14（）（）字12248線9位線 m1 m6m7 11與1地1 & & & WXYZF1=WX+(W?X)Z=F2=WXZ+WXZ+WXZ+F3=(X+Y)?W=WX+WX+WY+F4=WX+F5=W?X?Y?Z=WXYZ+WXYZ+WXZ+WXZ+YZ+0

4

910

12

14WW與Z1111或陣 P2 與111BC(Q0(10010102010011301110041001015101111711100161100010000001D0=Q2Q0+D1=Q1Q0+Q2Q1Q0D2=Q1Q