作業(yè)tcp實(shí)驗(yàn)報(bào)告gaia.cs umass edu的TCP端口為

WhatistheIPaddressandTCPportnumberusedbythecomputer(source)thatistransferringthefileto?Toanswerthisquestion,it’sprobablyeasiesttoselectanHTTPmessageandexplorethedetailsoftheTCPpacketusedtocarrythisHTTPmessage,usingthe“detailsoftheselectedpacketheaderwindow”(refertoFigure2inthe“GettingStartedwithWireshark”Labifyou’reuncertainabouttheWiresharkwindows.客戶(hù)端的IP客戶(hù)端的TCP端口為WhatistheIP?OnwhatportnumberisitsendingandreceivingTCPsegmentsforthisconnection?IP2TCP80WhatistheIPaddressandTCPportnumberusedbyyourcomputer(source)totransferthefileto?我的客戶(hù)端的IP我的客戶(hù)端的TCP端口為WhatisthesequencenumberoftheTCPSYNsegmentthatisusedtoinitiatetheTCPconnectionbetweenthecomputerand?WhatisitinthesegmentthatidentifiesthesegmentasaSYNsegment?theseqofSYNusedtoinitiateisflagslastsecondbitidentifiesthatitisaSYNWhatisthesequencenumberoftheSYNACKsegmentsentbytothecomputerinreplytotheSYN?WhatisthevalueoftheACKnowledgementfieldintheSYNACKsegment?Howdiddeterminethatvalue?WhatisitinthesegmentthatidentifiesthesegmentasaSYNACKsegment?sequenceno.ofSYNACKisthevalueofACKnowledgementisflagslastfifthandlastsecondbitsidentifyitisaSYNACKWhatisthesequencenumberoftheTCPsegmentcontainingtheHTTPPOSTcommand?NotethatinordertofindthePOSTcommand,you’llneedtodigintothepacketcontentfieldatthebottomoftheWiresharkwindow,lookingforasegmentwitha“POST”withinitsDATAfield.seqno.isConsidertheTCPsegmentcontainingtheHTTPPOSTasthefirstsegmentintheTCPconnection.WhatarethesequencenumbersofthefirstsixsegmentsintheTCPconnection(includingthesegmentcontainingtheHTTPPOST)?Atwhattimewaseachsegmentsent?WhenwastheACKforeachsegmentreceived?GiventhedifferencewheneachTCPsegmentwassent,andwhenitsacknowledgementwasreceived,whatistheRTTvalueforeachofthesixsegments?WhatistheEstimatedRTTvalue(seepage249intext)afterthereceiptofeachACK?AssumethatthevalueoftheEstimatedRTTisequaltothemeasuredRTTforthefirstsegment,andtheniscomputedusingtheEstimatedRTTequationonpage249forallsubsequentsegments.Note:WiresharkhasanicefeaturethatallowsyoutoplottheRTTforeachoftheTCPsegmentssent.SelectaTCPsegmentinthe“l(fā)istingofcapturedpackets”windowthatisbeingsentfromthetotheserver.Thenselect:Statistics->TCPStreamGraph->RoundTripTimeGraph.seq分別是 發(fā)送時(shí) 0.026477（連接建立后收到窗口大小是5840，一開(kāi)始發(fā)送 0.041737（發(fā)完第一個(gè)以后，接收窗口剩余夠1514，發(fā)送（接收到第一個(gè)的確認(rèn) 0.054026（被通知窗口6780后發(fā)送 0.054690（上一個(gè)發(fā)送了1514長(zhǎng)度，剩余夠1514，發(fā)送（接收到第二個(gè)的確認(rèn) 0.077405（被通知窗口8760后發(fā)送 0.078157（發(fā)送完上一個(gè)以后，剩余窗口仍夠1514，發(fā)送RTT0.053937-0.077294-0.124885-0.169118-0.217299-0.267802-0.078157=0.1ERTT=7/8*ERTT+ERTT WhatisthelengthofeachofthefirstsixTCPWhatistheminimumamountofavailablebufferspaceadvertisedatthereceivedfortheentiretrace?Doesthelackofreceiverbufferspaceeverthrottlethesender? ……發(fā)送方突然減少了發(fā)送的長(zhǎng)Arethereanyretransmittedsegmentsinthetracefile?Whatdidyoucheckfor(inthetrace)inordertoanswerthisquestion?HowmuchdatadoesthereceivertypicallyacknowledgeinanACK?CanyouidentifycaseswherethereceiverisACKingeveryotherreceivedsegment(seeTable3.2onpage257inthetext).Whatisthethroughput(bytestransferredperunittime)fortheTCPconnection?Exinhowyoucalculatedthisvalue.5.455830-0.0264775.4294秒164090/5.4294=30.222KB/sUsetheTime-Sequence-Graph(Stevens)plottingtooltoviewsequencenumberversustimeplotofsegmentsbeingsentfromthetotheserver.CanyouidentifywhereTCP’sslowstartphasebeginsandends,andwherecongestionavoidancetakesover?CommentonwaysinwhichthemeasureddatadiffersfromtheidealizedbehaviorofTCPthatwe’vestu