2021年安徽省黃山市高考數(shù)學(xué)第二次(二模)質(zhì)檢試卷(理科)

2021年安徽省黃山高考數(shù)學(xué)第次質(zhì)檢試（理科）（模）一選題共12小題）A{13}{x0}BA{23}

B{13}C{12}D{13}AA

Bsinx+B

CC

DD022020020220200202所位數(shù)出概（A

B

C

Dxm

yfmm+1]A[23]

B2

C23]y4xll3|QF

QPFC

n52021302021n52021302021A3

B4

C

D2

20K

kkXYA1

B2

C3

D{}3+4aA22020

B22021

C2022

DlnAbaBcCaDcba10ABCABacsinsinCsinA+3CA30

B120

C30150

D60114A

B

C

D12+121200a

abA+

Be2

+

C

D二填題每題5分）1314132021

a+xx

xR

12112115ABC4

16F

a0

+2a2

MFMF三解題本題5小題共70分解答寫文說、明程演步．在題的應(yīng)域題）17Cabc+2bacos+01A2a2

ABC18SABCDSADADABAD1SABSCDmm2BCEOE+FB19nnn

1122121111212121122121111212121212kk2k1n42n43n20C2

100y1

xe12Fll

CNFMkkkl21falnx+ge+bx2

x1hfx+hh2yfg01x+gex考注：在22、23題任一作，果做則按做第題分作答，請鉛筆答卡將選號的框涂[選4-4坐系參方]22φC22

2OlA1C20

||2

[選修4-5：不等選23fx|x+1|1a2x22a0fx0a

參考答案一選題每題5分）A{13}{x0}BA{23}B{13}C{12}D{123}{123}B{2}B{23}A

B

C

D

+i

CAx+2cos2

sinx+B

C]x

D22D02

2020020220200202所位數(shù)出概（A

B

C

D40910499010C

xm

yfmm+1]A[23]x

B2

C23]

D3

x2]4[yfmm2m42my4xll3|QF

QPFCA3B4

C

DPFlFQ

FFp2QFQQlFFp2D

Q|FQ|

2

20K

kkXYA1

B2

C3

D2

R20CKD

kkXY

n52021n5311202133333n52021n5311202133333C{}3+4aA22020

B22021

C2022

D{}

a3aa02aa2021

lnclogAbaBcCaaln

Dcaloglogbeb

log

1c10ABCABacsinsinCsinA+3CA30

B120

C30150

D60sinCsinAsinCABC1+32sin30

C114A

B

C

D12+1288[1

13

]1211121212

2]686

V32121200a

abA+

Be2

+

C

Df

x0+f20210x2021xfx+fx0fabbb0afe2

lne2

f1ln1

012

f100

e1002100

100e2e100

e2ab102

0202102021002021020210二填題本題4小題每題5分共20分．在題的應(yīng)域題）13022fx|2x

14132021

a+x?xxR

1132021+x++xR）x01x1+1

0

115ABC4BC

A02

20C0Py

x

x2

2

2

x2

y2

+2y

2

2[xy

]

66

121122211212122211211222112121222116Fa0+2a2

MMF1+

xAFBMFOAOFeq\o\ac(△,BF)eq\o\ac(△,)FaBF2

bFMF|

MFMBMFMF

+2b

a

ay1+

xy

x

三解題本題5小題共70分解答寫文說、明程演步．在題的應(yīng)域題）17Cabc+2bacos+01A2a2

ABC1c+2cosAB0CcoscosAcos0AC+2sincos0sinAsin0cos02a2223bcbc4ABC18SABCDSADADABAD1SABSCDmm2BCEOE+FB

BACDKSKSABmADKOAOODADSADABCDSADABCDDCBAOKADBADCOAKDAKAKDODAOKADBCAOKBCKEKEBCmKSE2ABCKEBEFCAFAFFCOEFFFBAOKADKBCKAOKBEAO14BE2

SFEeq\o\ac(△,S)SFEeq\o\ac(△,S)KAKOOEABKAAB2KBKE

OEADAD2SOADAO

OF+FEOE

ABCDSOOEFHSEKSEBCFHFHFSHSFSBCFH2?

SFSBC

19nnn

kk2k1n42n43n12

+

2kk123324k3k2kkkkkkkk144kk+43+kkkk1k3nkpk3knnknk1n2kkk1kkk1kk1n

11221211112121122111122121111212112211nnk1n+kn1+kn1+1knkkp

k20C2

100y

xe112FllCFMkkkl1b02

x1p0q02

x2l

ykxt

ykxktxkt12

112212112212My24+60t4

21falnx+ge

+bx

1hfx+hh2yfg01x+gex1xalnxxhx

x0x2++x0a0hx0x0+a080x0

0xx

hx0hx0hhx2x

xgxea+1fxxy1ax1a1+2bxx1eb

1212121212121212x+xe2xfxe11

xlnxex1e0Klnx1Kxe

0x1K0K01x+K0K1KK考注：在22、23題任一作，果做則按做第題分作答，請鉛筆答卡將選號的框涂[選4-4坐系參方]22φC22

2OlA1C20

|

+|OB