云南師大附中2022屆高考數(shù)學(xué)適應(yīng)性月考卷（二）（掃描版）文新人教A版

云南師大附中2022屆高考適應(yīng)性月考卷（二）文科數(shù)學(xué)參照答案第Ⅰ卷（選擇題，共60分）一、選擇題（本大題共12小題，每題5分，共60分）題號(hào)123456789101112答案BCBADBABCAAC【剖析】1．S∪T{1,3,5,6}，則US∪T＝{2,4,7,8}．應(yīng)選B．2．由sin0知是第三象限角或位于軸非正半軸上或第四象限角，由tan0知是第一象限角或第三象限角，依題意知是第三象限角．應(yīng)選C．3．3x22xx≥1x1．應(yīng)選B．4．若直線xay50與直線a2x2y4a0垂直，則a22a0,即a0或a2．應(yīng)選A．5由T2ππ，2.由f032sin3,sin3ππ.，．應(yīng)選D．2236．△ABC是直角三角形，BC是斜邊，且BC222222,則球心在平面ABC上的射影為BC的中點(diǎn)，因此球的半徑R12223，球的體積V4πR343π.應(yīng)選B．37．依題意得cos4π0,則4πkππkZ,kπ5πkZ，因此的最小值是π3326。選Ａ68．設(shè)公差為d，則(1d)21(14d)∵d≠0，解得d＝2，∴S10＝100．應(yīng)選B．9．PAQC1,SAPQC1SAA1CCS△AAC，VBAPQCVBAACVAABC1V.應(yīng)選C．2111133basinB，得3sinAsinB，sinB0，sinA3Aπ，π2π10．由2sinB，又0A或A，2233應(yīng)選A．11．設(shè)點(diǎn)x0,y0為曲線y1324xc上任意一點(diǎn)，則該點(diǎn)處的切線斜率為y|xx022bx04.由xbxx03已知條件得x022bx04≥0對(duì)任意的x0R恒成立，4b216≤0，解得2≤b≤2．應(yīng)選A．12．由圖形的對(duì)稱性可知，F(xiàn)2MN,F2NM必然為銳角，只需使MF2N也為銳角，即MF2F145，MF1F1F2，即b22c，b22ac，c2a22ac．22e10，解得12e12，又aee1，1e12．選C．90第Ⅱ卷（非選擇題，共分）二、填空題（本大題共4小題，每題5分，共20分）題號(hào)13141516答案243115125【剖析】1，1，13．sincossincos21sin2sin2245252514．過C作CDAB，D為垂足，連結(jié)C1D，則C1DAB，C1DC60，CD3，則C1D3，點(diǎn)C12到直線AB的距離為315．Sna1ddn，S10S8d108d2,n221082S1111211110211216．拋物線y1x2的焦點(diǎn)為F0,1，記點(diǎn)P在拋物線的準(zhǔn)線l:y1上的投影為P，則4PPPFPPPAPFPA≥AF22125PAPMminPAPP1min516701710f0a2fπ1a3b1334422ab25fx2cos2x2sinxcosx1cos2xsin2x2sin2xπ1,4xππ2xππ5π.44424sin2xπ21,fx021.104212:an12an1nNan112anan1112,an1an12a112,an12nan2n1.bnanan1bnnnnn22142,nnn141421242n12.Sn1412331912A1AABC，BCABC

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