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1、實現(xiàn)DES加解密算法實驗報告一、 DES加解密算法問題簡介DES算法全稱為Data Encryption Standard,即數(shù)據(jù)加密算法,它是IBM公司于1975年研究成功并公開發(fā)表的。DES算法的入口參數(shù)有三個:Key、Data、Mode。其中Key為8個字節(jié)共64位,是DES算法的工作密鑰;Data也為8個字節(jié)64位,是要被加密或被解密的數(shù)據(jù):Mode為DES的工作方式,有兩種:加密或解密。 二、 DES加解密算法設(shè)計方法簡介DES算法把64位的明文輸入塊變?yōu)?4位的密文輸出塊,它所使用的密鑰也是64位,其功能是把輸入的64位數(shù)據(jù)塊按位重新組合,并把輸出分為L0 、R0兩部分,每部分各長
2、32位,其置換規(guī)則見下表: 58,50,12,34,26,18,10,2,60,52,44,36,28,20,12,4,62,54,46,38,30,22,14,6,64,56,48,40,32,24,16,8,57,49,41,33,25,17, 9,1,59,51,43,35,27,19,11,3,61,53,45,37,29,21,13,5,63,55,47,39,31,23,15,7,即將輸入的第58位換到第一位,第50位換到第2位,依此類推,最后一位是原來的第7位。 L0、R0則是換位輸出后的兩部分,L0是輸出的左32位,R0 是右32位,例:設(shè)置換前的輸入值為D1D2D3D64,則
3、經(jīng)過初始置換后的結(jié)果為:L0=D550D8;R0=D57D49.D7。經(jīng)過26次迭代運算后,得到L16、R16,將此作為輸入,進行逆置換,即得到密文輸出。逆置換正好是初始置的逆運算,例如,第1位經(jīng)過初始置換后,處于第40位,而通過逆置換,又將第40位換回到第1位,其逆置換規(guī)則如下表所示:40,8,48,16,56,24,64,32,39,7,47,15,55,23,63,31, 38,6,46,14,54,22,62,30,37,5,45,13,53,21,61,29, 36,4,44,12,52,20,60,28,35,3,43,11,51,19,59,27, 34,2,42,10,50,1
4、8,58 26,33,1,41, 9,49,17,57,25, 放大換位表 32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9, 8, 9, 10,11, 12,13,12,13,14,15,16,17,16,17,18,19,20,21,20,21, 22,23,24,25,24,25,26,27,28,29,28,29,30,31,32, 1, 單純換位表 16,7,20,21,29,12,28,17, 1,15,23,26, 5,18,31,10, 2,8,24,14,32,27, 3, 9,19,13,30, 6,22,11, 4,25, 在f(Ri,Ki)算法描述
5、圖中,S1,S2.S8為選擇函數(shù),其功能是把6bit數(shù)據(jù)變?yōu)?bit數(shù)據(jù)。下面給出選擇函數(shù)Si(i=1,2.8)的功能表: 選擇函數(shù)Si S1: 14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7, 0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8, 4,1,14,8,13,6,2,11,15,12,9,7,3,10,5,0, 15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13, S2: 15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10, 3,13,4,7,15,2,8,14,12,0,1,10
6、,6,9,11,5, 0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15, 13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9, S3: 10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8, 13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1, 13,6,4,9,8,15,3,0,11,1,2,12,5,10,14,7, 1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12, S4: 7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15, 13,8,11,
7、5,6,15,0,3,4,7,2,12,1,10,14,9, 10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4, 3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14, S5:2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9, 14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6, 4,2,1,11,10,13,7,8,15,9,12,5,6,3,0,14, 11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3, S6: 12,1,10,15,9,2,6,8,0,13,3,4,
8、14,7,5,11, 10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8, 9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6, 4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13, S7: 4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1, 13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6, 1,4,11,13,12,3,7,14,10,15,6,8,0,5,9,2, 6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12, S8: 13,2,8,4
9、,6,15,11,1,10,9,3,14,5,0,12,7, 1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2, 7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8, 2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11, 子密鑰Ki(48bit)的生成算法初始Key值為64位,但DES算法規(guī)定,其中第8、16、.64位是奇偶校驗位,不參與DES運算。故Key 實際可用位數(shù)便只有56位。即:經(jīng)過縮小選擇換位表1的變換后,Key 的位數(shù)由64 位變成了56位,此56位分為C0、D0兩部分,各28位,然后分別進行第1次循環(huán)左移
10、,得到C1、D1,將C1(28位)、D1(28位)合并得到56位,再經(jīng)過縮小選擇換位2,從而便得到了密鑰K0(48位)。依此類推,便可得到K1、K2、.、K15,不過需要注意的是,16次循環(huán)左移對應(yīng)的左移位數(shù)要依據(jù)下述規(guī)則進行: 循環(huán)左移位數(shù)1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1 以上介紹了DES算法的加密過程。 DES算法的解密過程是一樣的,區(qū)別僅僅在于第一次迭代時用子密鑰K15,第二次K14、,最后一次用K0,算法本身并沒有任何變化。三、 程序代碼#include "memory.h"#include "stdio.h"enu
11、m encrypt,decrypt;/ENCRYPT:加密,DECRYPT:解密void des_run(char out8,char in8,bool type=encrypt);/設(shè)置密鑰void des_setkey(const char key8);static void f_func(bool in32,const bool ki48);/f函數(shù)static void s_func(bool out32,const bool in48);/s盒代替/變換static void transform(bool *out, bool *in, const char *table, int
12、len);static void xor(bool *ina, const bool *inb, int len);/異或static void rotatel(bool *in, int len, int loop);/循環(huán)左移 /字節(jié)組轉(zhuǎn)換成位組static void bytetobit(bool *out,const char *in, int bits);/位組轉(zhuǎn)換成字節(jié)組static void bittobyte(char *out, const bool *in, int bits);/置換IP表const static char ip_table64=58,50,42,34,26
13、,18,10,2,60,52,44,36,28,20,12,4,62,54,46,38,30,22,14,6,64,56,48,40,32,24,16,8,57,49,41,33,25,17,9,1,59,51,43,35,27,19,11,3,61,53,45,37,29,21,13,5,63,55,47,39,31,23,15,7;/逆置換IP-1表const static char ipr_table64=40,8,48,16,56,24,64,32,39,7,47,15,55,23,63,31,38,6,46,14,54,22,62,30,37,5,45,13,53,21,61,29,
14、36,4,44,12,52,20,60,28,35,3,43,11, 51,19,59,27,34,2,42,10,50,18,58,26,33,1,41,9,49,17,57,25;/E 位選擇表static const char e_table48=32,1, 2, 3, 4, 5,4, 5, 6, 7, 8, 9,8, 9, 10,11,12,13,12,13,14,15,16,17,16,17,18,19,20,21,20,21,22,23,24,25,24,25,26,27,28,29,28,29,30,31,32,1;/P換位表const static char p_table32
15、=16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,30,6,22,11,4,25;/pc1選位表const static char pc1_table56= 57,49,41,33,25,17,9,1, 58,50,42,34,26,18,10,2, 59,51,43,35,27,19,11,3, 60,52,44,36,63,55,47,39, 31,23,15,7,62,54,46,38, 30,22,14,6,61,53,45,37, 29,21,13,5,28,20,12,4;/pc2選位表c
16、onst static char pc2_table48= 14,17,11,24,1,5,3,28, 15,6,21,10,23,19,12,4, 26,8,16,7,27,20,13,2, 41,52,31,37,47,55,30,40, 51,45,33,48,44,49,39,56, 34,53,46,42,50,36,29,32;/左移位數(shù)表const static char loop_table16=1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1;/S盒const static char s_box8416= /s1 14, 4, 13, 1, 2, 15, 11,
17、 8, 3, 10, 6, 12, 5, 9, 0, 7, 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8, 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0, 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13, /s2 15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10, 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11,
18、 5, 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15, 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9, /s3 10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8, 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1, 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7, 1, 10, 13, 0, 6, 9, 8,
19、 7, 4, 15, 14, 3, 11, 5, 2, 12, /s4 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15, 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9, 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4, 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14, /s5 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13,
20、0, 14, 9, 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6, 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14, 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3, /s6 12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11, 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8, 9, 14, 15, 5, 2,
21、 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6, 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13, /s7 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1, 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6, 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2, 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14
22、, 2, 3, 12, /s8 13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7, 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2, 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8, 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11;static bool subkey1648;/16圈子密鑰void des_run(char out8,char in8, bool t
23、ype) static bool m64,tmp32,*li=&m0, *ri=&m32; bytetobit(m,in,64); transform(m,m,ip_table,64); if(type=encrypt) for(int i=0;i<16;i+) memcpy(tmp,ri,32); f_func(ri,subkeyi); xor(ri,li,32); memcpy(li,tmp,32); else for(int i=15;i>=0;i-) memcpy(tmp,li,32); f_func(li,subkeyi); xor(li,ri,32);
24、memcpy(ri,tmp,32); transform(m,m,ipr_table,64); bittobyte(out,m,64);void des_setkey(const char key8) static bool k64, *kl=&k0, *kr=&k28; bytetobit(k,key,64); transform(k,k,pc1_table,56); for(int i=0;i<16;i+) rotatel(kl,28,loop_tablei); rotatel(kr,28,loop_tablei); transform(subkeyi,k,pc2_t
25、able,48); void f_func(bool in32,const bool ki48) static bool mr48; transform(mr,in,e_table,48); xor(mr,ki,48); s_func(in,mr); transform(in,in,p_table,32);void s_func(bool out32,const bool in48) for(char i=0,j,k;i<8;i+,in+=6,out+=4) j=(in0<<1)+in5; k=(in1<<3)+(in2<<2)+(in3<<
26、;1)+in4; bytetobit(out,&s_boxijk,4); void transform(bool *out,bool *in,const char *table,int len) static bool tmp256; for(int i=0;i<len;i+) tmpi=intablei-1; memcpy(out,tmp,len);void xor(bool *ina,const bool *inb,int len) for(int i=0;i<len;i+) inai=inbi;void rotatel(bool *in,int len,int loo
27、p) static bool tmp256; memcpy(tmp,in,loop); memcpy(in,in+loop,len-loop); memcpy(in+len-loop,tmp,loop);void bytetobit(bool *out,const char *in,int bits) for(int i=0;i<bits;i+) outi=(ini/8>>(i%8) &1;void bittobyte(char *out,const bool *in,int bits) memset(out,0,(bits+7)/8); for(int i=0;i<bits;i+) outi/8|=ini<<(i%8);void main() char key8='p','r','o','g','r',
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