深圳辦理調(diào)檔函要多久拿到

1、河南省北大附中河南分校2014屆高三最后一次沖刺（猜題卷）文科數(shù)學(xué)試題一、選擇題：本大題共12小題,每小題5分 共60分1定義集合運(yùn)算：ab=zz=xy（x+y），xa，yb，設(shè)集合a=0，1，b=2，3，則集合ab的所有元素之和為（）a0b6c12d182已知復(fù)數(shù)z(cosi)(2sini)是純虛數(shù)，0,2)，則( )a. b. c. d.3已知集合，,若“”是“”的充分非必要條件，則的取值范圍是（ ）（a） （b） （c） （d）4下圖為某算法的程序框圖，則程序運(yùn)行后輸出的結(jié)果是( )a 3 b 4 c 5 d 65一個(gè)幾何體的三視圖如圖所示，其中正視圖和側(cè)視圖是腰長(zhǎng)為4的兩個(gè)全等的等腰直

2、角三角形若該幾何體的體積為v，并且可以用n這樣的幾何體拼成一個(gè)棱長(zhǎng)為4的正方體，則v，n的值是（ ） a bc d 6在abc中，內(nèi)角a，b，c所對(duì)的邊分別是a，b，c.已知8b5c，c2b，則cos c() a. b c± d.7下列命題正確的個(gè)數(shù)是 命題“”的否定是“”； “函數(shù)的最小正周期為”是“”的必要不充分條件； 在上恒成立在上恒成立； “平面向量與的夾角是鈍角”的充分必要條件是“”.a1 b2 c3 d48已知函數(shù)的圖象在點(diǎn)處的切線與直線平行，若數(shù)列的前n項(xiàng)和為，則的值為（ ）a、b、c、d、9、如圖，在棱長(zhǎng)為1的正方體abcd-a1b1c1d1中，p是棱上的點(diǎn)， 則滿足

3、的點(diǎn)p的個(gè)數(shù)有（ ）a4b6 c8 d1210在集合中任取一個(gè)偶數(shù)a和一個(gè)奇數(shù)b構(gòu)成以原點(diǎn)為起點(diǎn)的向量，從所有得到的以原點(diǎn)為起點(diǎn)的向量中任取兩個(gè)向量為鄰邊作平行四邊形，記所有作成的平行四邊形的個(gè)數(shù)為，在區(qū)間1，和2，4分別各取一個(gè)數(shù)，記為m和n，則方程1表示焦點(diǎn)在x軸上的橢圓的概率是 （ ）a b. c. d. 11已知是內(nèi)一點(diǎn),且若、的面積分別為、, 則的最小值是（ ） a9 b. 16 c. 18 d. 2012已知函數(shù) 函數(shù)，若存在，使得成立，則實(shí)數(shù)的取值范圍是a. b. c. d.二、填空題：本大題共4小題，每小題5分，共20分。 40 50 60 70 80 90 體重(kg)0.0

4、050.0100.0200.0300.0350.0150.02513從某地高中男生中隨機(jī)抽取100名同學(xué)，將他們的體重（單位：kg）數(shù)據(jù)繪制成頻率分布直方圖（如圖）由圖中數(shù)據(jù)可知體重的平均值為kg；若要從身高在 60 , 70），70 ，80) , 80 , 90三組內(nèi)的男生中，用分層抽樣的方法選取12人參加一項(xiàng)活動(dòng)，再?gòu)倪@12人選兩人當(dāng)正負(fù)隊(duì)長(zhǎng)，則這兩人身高不在同一組內(nèi)的概率為 （2個(gè)數(shù)據(jù)錯(cuò)一個(gè)不得分）14非零向量滿足，則與的夾 角大小為 15已知函數(shù)為r上的奇函數(shù)，的導(dǎo)數(shù)為，且當(dāng)時(shí)，不等式 成立，若對(duì)一切恒成立，則實(shí)數(shù)的取值 范圍是 。16.已知下列命題：函數(shù)的單調(diào)增區(qū)間是.要得到函數(shù)的圖

5、象，需把函數(shù)的圖象上所有點(diǎn)向左平行移動(dòng)個(gè)單位長(zhǎng)度.已知函數(shù)，當(dāng)時(shí)，函數(shù)的最小值為在0,1上至少出現(xiàn)了100次最小值，則.其中正確命題的序號(hào)是_ 三、解答題：解答應(yīng)寫(xiě)出文字說(shuō)明、證明過(guò)程或演算步驟。17.（本小題滿分12分）數(shù)列各項(xiàng)均為正數(shù)，其前項(xiàng)和為，且滿足.（1）求數(shù)列的通項(xiàng)公式；（2）設(shè)， 求數(shù)列的前n項(xiàng)和，并求使 對(duì)所有的 都成立的最大正整數(shù)m的值18（本小題滿分12分）某班50名學(xué)生在一次百米測(cè)試中，成績(jī)?nèi)拷橛?3秒與18秒之間，將測(cè)試結(jié)果按如下方式分成五組：第一組，第二組，第五組右圖是按上述分組方法得到的頻率分布直方圖. （1）若成績(jī)大于或等于14秒且小于16秒認(rèn)為良好， 求該班在

6、這次百米測(cè)試中成績(jī)良好的人數(shù)； （2）設(shè)表示該班某兩位同學(xué)的百米測(cè)試成績(jī)，且已知cbagdef19（本小題滿分12分）如圖，四邊形為矩形，四邊形為梯形，且平面平面，點(diǎn)為的中點(diǎn) （1）求證：平面； （2）求三棱錐的體積； 20（本小題滿分12分）如圖9-13，p是拋物線c：y=x2上點(diǎn)，直線l過(guò)點(diǎn)p且與拋物線c交于另一點(diǎn)q (1)若直線l與過(guò)點(diǎn)p的切線垂直，求線段pq中點(diǎn) m的軌跡方程； ()若直線l不過(guò)原點(diǎn)且與x軸交于點(diǎn)s，與y軸交于點(diǎn)t，試求的取值范圍21（本小題滿分12分）已知函數(shù)是定義在上的奇函數(shù),當(dāng)時(shí), (其中e是自然界對(duì)數(shù)的底, )（） 求的解析式;（）設(shè)求證：當(dāng)，時(shí)，；（）是否存在

7、負(fù)數(shù)，使得當(dāng)時(shí)，的最小值是3 ？如果存在，求出實(shí)數(shù)的值；如果不存在，請(qǐng)說(shuō)明理由。請(qǐng)考生在第（22）、（23）、（24）三題中任選一題做答，如果多做，則按所做的第一題記分。做答時(shí)用2b鉛筆在答題卡上把所選題目對(duì)應(yīng)題號(hào)下方的方框涂黑。22.如圖，o的半徑ob垂直于直徑ac，m為ao上一點(diǎn)，bm的延長(zhǎng)線交o于n，過(guò)n點(diǎn)的切線交ca的延長(zhǎng)線于p(1) 求證：；（2）若o的半徑為，求mn的長(zhǎng)23已知橢圓c的極坐標(biāo)方程為，點(diǎn)f1、f2為其左，右焦點(diǎn)，直線的參數(shù)方程為(t為參數(shù)，tr) （）求直線和曲線c的普通方程； （）求點(diǎn)f1、f2到直線的距離之和.24（本小題滿分10分）選修45：不等式選講 已知函數(shù)

8、 （）當(dāng)時(shí)，求不等式的解集； （）若不等式對(duì)任意實(shí)數(shù)恒成立，求的取值范圍 北大附中河南分校高考預(yù)測(cè) 若時(shí)，有6種情況7分若分別在和內(nèi)時(shí)，共有12種情況. 9分 abcdxxaxbxcxdyyaybycydzzazbzc zd 在中，af=fe， afe=60º， 是正三角形 aef=60º，由ef/ad知ead=60º， en=aesin60º=12分20解法：(1)設(shè)p(x1，y1)、q(x2，y2)、m (x0，y0)，依題意x10，yl>0，y2>0由y=x2，得y'=x. 過(guò)點(diǎn)p的切線的斜率k切=x1, x1=0不合題意， x

9、10 直線l的斜率k1=,直線l的方程為y-x21=(x-x1)方法一：聯(lián)立消去y，得x2+-x21-2=0 由消去x，得y2-2(k2+b)y+b2=0則方法一： y1、y2可取一切不相等的正數(shù)， 的取值范圍是(2，+)方法二：當(dāng)b>0時(shí)，=|b|+2>2；當(dāng)b<0時(shí), =-b又由方程有兩個(gè)相異實(shí)根，得=4(k2+b) 2-4b2= 4k2(k2+2b)>0于是k2+2b>0，即k2>-2b 所以當(dāng)b>0時(shí)，可取一切正數(shù)，的取值范圍是(2+)方法三：由p、q、t三點(diǎn)共線得ktq=ktp,即則x1y2-bx1=x2y1-bx2，即b(x2-x1)=(x

10、2y1-x1y2)于是b=可取一切不等于l的正數(shù)，的取值范圍是(2，+)21（）設(shè)，則，所以又因?yàn)槭嵌x在上的奇函數(shù)，所以 故函數(shù)的解析式為 （）證明：當(dāng)且時(shí)，設(shè) 因?yàn)?，所以?dāng)時(shí)，此時(shí)單調(diào)遞減；當(dāng)時(shí)，此時(shí)單調(diào)遞增，所以 又因?yàn)?，所以?dāng)時(shí)，此時(shí)單調(diào)遞減，所以所以當(dāng)時(shí)，即 （）解：假設(shè)存在負(fù)數(shù)，使得當(dāng)時(shí)，有最小值是3，則當(dāng)，由于，則，故函數(shù) 是上的增函數(shù)所以，解得（舍去）當(dāng)時(shí)，則當(dāng)時(shí)，此時(shí)函數(shù)是減函數(shù)；當(dāng)時(shí)，此時(shí)函數(shù)是增函數(shù)所以，解得滿足題意。綜上可知，存在負(fù)數(shù)，使得當(dāng)時(shí)，有最小值22（1）連接on，因?yàn)閜n切o于n，所以，所以，因?yàn)閛b=on，所以因?yàn)橛?，所?故，所以.（2）因?yàn)?，所?23(

11、) 直線普通方程為 ； 曲線的普通方程為 () ,，點(diǎn)到直線的距離 點(diǎn)到直線的距離 24解：（）當(dāng)時(shí)，即，當(dāng)時(shí)，得，即，所以；當(dāng)時(shí)，得成立，所以；當(dāng)時(shí)，得，即，所以.故不等式的解集為.（），由題意得，則或，解得或,故的取值范9jwkffwvg#tym*jg&6a*cz7h$dq8kqqfhvzfedswsyxty#&qa9wkxfyeq!djs#xuyup2knxprwxma&ue9aqgn8xp$r#&#849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tng

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26、eh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz

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28、wpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwc

29、vr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am

30、p;qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am

31、p;qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#

32、kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ks

33、v*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89

34、amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$

35、vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&

36、;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%madnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvk

37、um&gtxrm6x4ngpp$vstt#&ksv*adnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy

38、7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&am

39、p;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue

40、%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpaza

41、dnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk

42、!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6

43、ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&g

44、txrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amy

45、wpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gx

46、gjqv3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849g

47、xgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6

48、ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mzadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gx

49、gjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk

50、!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&g

51、txrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvk

52、um&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk

53、8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp

54、$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&am

55、p;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd

56、6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wew

57、z#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&

58、amp;qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv

59、*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!

60、z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am