新高考數(shù)學(xué)一輪復(fù)習(xí)函數(shù)重難點(diǎn)專題21指對(duì)冪函數(shù)（原卷版）

專題21指對(duì)冪函數(shù)一、單選題1．（2022·北京·高考真題）己知函數(shù)SKIPIF1<0，則對(duì)任意實(shí)數(shù)x，有（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·上海·高考真題）下列冪函數(shù)中，定義域?yàn)镾KIPIF1<0的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·北京·高考真題）在北京冬奧會(huì)上，國(guó)家速滑館“冰絲帶”使用高效環(huán)保的二氧化碳跨臨界直冷制冰技術(shù)，為實(shí)現(xiàn)綠色冬奧作出了貢獻(xiàn)．如圖描述了一定條件下二氧化碳所處的狀態(tài)與T和SKIPIF1<0的關(guān)系，其中T表示溫度，單位是K；P表示壓強(qiáng)，單位是SKIPIF1<0．下列結(jié)論中正確的是（

）A．當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，二氧化碳處于液態(tài)B．當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，二氧化碳處于氣態(tài)C．當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，二氧化碳處于超臨界狀態(tài)D．當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，二氧化碳處于超臨界狀態(tài)4．（2022·浙江·高考真題）已知SKIPIF1<0，則SKIPIF1<0（

）A．25 B．5 C．SKIPIF1<0 D．SKIPIF1<05．（2022·全國(guó)·高考真題（文））已知SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·全國(guó)·高考真題）設(shè)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2021·湖南·高考真題）函數(shù)SKIPIF1<0的定義域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2021·全國(guó)·高考真題（文））青少年視力是社會(huì)普遍關(guān)注的問題，視力情況可借助視力表測(cè)量．通常用五分記錄法和小數(shù)記錄法記錄視力數(shù)據(jù)，五分記錄法的數(shù)據(jù)L和小數(shù)記錄表的數(shù)據(jù)V的滿足SKIPIF1<0．已知某同學(xué)視力的五分記錄法的數(shù)據(jù)為4.9，則其視力的小數(shù)記錄法的數(shù)據(jù)為（

）（SKIPIF1<0）A．1.5 B．1.2 C．0.8 D．0.69．（2021·天津·高考真題）若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．SKIPIF1<010．（2021·天津·高考真題）設(shè)SKIPIF1<0，則a，b，c的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<011．（2021·天津·高考真題）函數(shù)SKIPIF1<0的圖像大致為（

）A．B．C． D．12．（2021·全國(guó)·高考真題）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則下列判斷正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<013．（2021·全國(guó)·高考真題（文））下列函數(shù)中最小值為4的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<014．（2021·全國(guó)·高考真題（理））設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0．則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<015．（2020·山東·高考真題）函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<016．（2020·山東·高考真題）已知函數(shù)SKIPIF1<0是偶函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則該函數(shù)在SKIPIF1<0上的圖像大致是（

）A．B．C． D．17．（2020·海南·高考真題）已知函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<018．（2020·天津·高考真題）設(shè)SKIPIF1<0，則SKIPIF1<0的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<019．（2020·全國(guó)·高考真題（文））設(shè)SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<020．（2020·全國(guó)·高考真題（理））若SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<021．（2020·全國(guó)·高考真題（文））設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<022．（2020·全國(guó)·高考真題（文））Logistic模型是常用數(shù)學(xué)模型之一，可應(yīng)用于流行病學(xué)領(lǐng)域．有學(xué)者根據(jù)公布數(shù)據(jù)建立了某地區(qū)新冠肺炎累計(jì)確診病例數(shù)I(t)(t的單位：天)的Logistic模型：SKIPIF1<0，其中K為最大確診病例數(shù)．當(dāng)I(SKIPIF1<0)=0.95K時(shí)，標(biāo)志著已初步遏制疫情，則SKIPIF1<0約為（

）（ln19≈3）A．60 B．63 C．66 D．6923．（2020·全國(guó)·高考真題（理））設(shè)函數(shù)SKIPIF1<0，則f(x)（

）A．是偶函數(shù)，且在SKIPIF1<0單調(diào)遞增 B．是奇函數(shù)，且在SKIPIF1<0單調(diào)遞減C．是偶函數(shù)，且在SKIPIF1<0單調(diào)遞增 D．是奇函數(shù)，且在SKIPIF1<0單調(diào)遞減24．（2020·全國(guó)·高考真題（理））已知55<84，134<85．設(shè)a=log53，b=log85，c=log138，則（

）A．a(chǎn)<b<c B．b<a<c C．b<c<a D．c<a<b二、填空題25．（2022·上?！じ呖颊骖}）已知函數(shù)SKIPIF1<0的反函數(shù)為SKIPIF1<0，則SKIPIF1<0________26．（2020·山東·高考真題）若SKIPIF1<0，則實(shí)數(shù)SKIPIF1<0的值是______.27．（2020·北京·高考真題）函數(shù)SKIPIF1<0的定義域是____________．28．（2020·江蘇·高考真題）已知y=f(x)是奇函數(shù)，當(dāng)x≥0時(shí)，SKIPIF1<0，則f(-8)的值是____.三、雙空題29．（