TZOIA 3003-2024 硅光電倍增管可靠性評估方法

IC

31.080

CC

L54

ZOI

c ? ? ? + k Y ‰=

TZ/OI3A0023202

.{ ?+k C ?1× %M–

Reliabilityevaluationmethodf

? ? ?0o ?

2024.2

X ? yO? ??? & èB' 6 ?. F?,′-( ￡ C Y

202-042-04 9 202-042-04?

c ? ? ?+k Y P9… P

T/ZOIA30032024

PAGE\*ROMAN

II

-$ !W

}@.0 II

1 93$1

2 ?93WE+X.?& 1

3 _B ….?y 1

4 08\?–"r 2

5 B4?–"r 3

63?)^7

? @6

\·&9'—GB/T1.122020é7?F?,I 1\1G6?7?F·&,′5′?C§9y??Iê,′??êC§9y?

\·&+aGüFT+eW–*?

\·&+a]￡?y+e×J?J??

\·&C§9y…}?GüFT+eW–?]-0–L’z,?.D0|p?KQ]T|+e€9L€?(?:#§6?

?k+?0°6?-9L€?( ?

\·&k?±C§9yê?GMN?H91?)1~?HL|'f?71*Z?~A???"?7??P>?)?#??1AE1?N_?PF?+8￡)a?)?? ?

T/ZOIA30032024

PAGE

1

.{ +k C 1%M ]A?#f

1 99*

\?&+|??.uy+e=?1S?iliconPhotomultiplier,SiPM ˉ,·_B ??y? MWA?,·08\?–"r…BP…?# ?

\?&F2+X.uy+e=?1,· MWA‘¨? 2??,·M Y&?2 ??99]K+^‰,

’>|

;G?&],·?FJE?],·?93WE+X6<·@\?&?= A,·!n??]#¨ O,·E+

?B O)?,·(x\F2+X\?&=# O,·E+X?&¨?0(x\?5 p9,· iˉ

&?

GB/T4937.4-2012 z,.

GB/T4937.13-2012 z,.

&j…"DIBP….1\?4#G

6j—FO0c1$fl’BHPA…STˉ?&j…"DIBP….1\?1#3G 6-M.

GB/T11499-2001 z,60?&?1V’GB/T19001-2016CXG1*63+?–"r

GB/T21194-2007FJ A7+X,·y+e&,· MWFJ+X?–"rGB/T33768-2017FJ +Xy+e& MWBP…?#

3 eB#′—

GB/T11499-2001 …GB/T33768-2017+|?,· ?;G_B ??yF2+X\?&?

3.1

B mspecimen

+X MWBP…,·#{.uy+e=?1g??

3.2

G10+kre`versebreakdownvoltage

VBR

˙)?;¨FJEB g,·A+e#qP’f?—)?,·+e??

3.3

E`overvoltageVov

Q A+0fl+e? :,·+e??

3.4

?+k#wdarkcurrentID

y’?XB gT1 —??,·A5+e?&¨FJEB g,·+e#q?

3.5

?A?)‰darkcountrateDCR

˙)?;¨}&L$+O,·M Y?&?

3.6

%Mre]liability

B gX??&;???,·&L$…@??ˇ7-,·7-??

3.7

%M]BrePl′iabilitytest

)B gF>| MWB3 ?6…A’,·0/{!¨juL6?T?_VE‘77?–

??3.8

3.9

g~failure

B gX??&;???,·&L$Wa??ˇ7-,·7-?&¨0 jax?

g~Zfailure? criteria

T?B gax,·??4 68b??"x

4.1 BP′2–`

BP…2??5

4.2 BP′A=

y+e('WBP…?jBP…?)?BP…?

BP…A7,·5$?Q…B3?1GVB/T819001,·-(￡? ??4.3 BP′)?

LM 9??¨p9BP…?X;G7W"D&,·)?]F>|a) $Y??15 35 ×

b) -()$ˉ??45% 75%×

c) W"D???86kPa 106kPa?

#?9 9??êèXBP??z:#>BP?)?3‘&?

5 ?+k]73#?B?#

5.1 í+k#w

#{B?*6.?? .1?

0c?$à

μ#{.uy+e=?1?

+e#q>?

??

41í+k#w#?B?*<4

5.1.1 #?B!?Pú#{B!?P?2;?

a) 9.1F?#{B3+5×

b) A?5?íDXBgT1,′yA?5?+e???93$è|Aà…+e#qlè￡j?+e#q?

?úD—,?

-(￡·&8#A???ê 2;‘& ?

)?3#{B$Y?×

yA?5?+e??5.2 íA×|)?

#{B?*6.??. 2?

˙

0c?$

B g

nW+eD

/j#

5.2.1 #B!P

#{B!P?;

a) 9.2F?#{B3+5×

42 ?A?)‰#B *<4

B3820c?$àèXBgT1íD??êyA?5?+e?×

#{B&L$T0μQ???êL8l,′79aA? Nd×

9???1??`BgX??êyA?5?+e?;,′? A?)·DCR?

&%4L?Z

í,

?1?

?úD—,?

-(￡·&8#A???ê 2;‘& ?

)?3#{B$Y?×

yA?5?+e?×

??êL8l08\j0.5pe?photonequivalent?è￡1Zy€EMY79au?,′ 0.5=?6B4ü?·"x

6.1 ?+k(ˉ] BP?6.1.1 ?+k]73#?B

BP?-$,o

.?êX??ê,′?+e?>$Y?;Bg_V%C???ê,′y+eW7-77?

A?=

BP?A?7??±"r2;?

a) +e?+e#q>??y$à?>???/j#??y?)·A??B+*+eD1y×

b) BP?‘&;7-O-??BP?$Y??+e??+e#q?E?*#’,′>?5?×

c) 7-ˉBgE*19M?,′y+eF?,′y+e×?|1>?’??

BP?—,

BP?‘&2; ?

a) )?3$Y??15 35 ×

b) -()$ˉ??25% 75%×

"D??86kPa 106kPa×

#{B)?3??y#{G??.??,′ jà_??M‰+e?+e.?1y￠×

e) #{B3+5?±9C?O#{G?N′'&L$èBg,′?Gy+eò?X'￡>‘;F>|×

f) #{G?3+5??`8??è A?#{G?5ì,′?.?W×

g) #{B??§9y?;m‘&èFˉ})?3y)BgW7-,′?y?

BP?!?PúBP?!?P?2;?

a) ]*#{B3+5è|6[íDp??ê,′?5?+e?×

b) ?BgE?`??ê,′BP?$Y?>F>|?+e#q??A?,′y+eW7-#{BèAà…)?,′$Y???5?

+e?úy+eW7-#{B ??

?#?

y+eW7-#{Bé#9'—\· &5.1-5.2??ê,′‘ &??±"r?

g~Z¤

Bg?/?7?.uy+e=?1?,′y+eW7-#{B5ìè*)à;G??{0Tjax?

?+e#q=??1μ

?A?)·?DG?W?1ZG?4×?

LG-$?

BP?-$,o

e#{1>?,′Bg,′8aCXG?è? +X?eP?XBP?E÷0;]7-EC§,′??è+X?)"BgBP?}

>,′FGe?

A?=

§98F2nW=|§9E3W????j,′y–??

BP?—,

BP?‘&2;?

a) ?&>?M’?G÷+X1.5= 10=nTK?×

b) ?&?14?G÷+X10= 1000=nTK?×

|?G÷+X5= 1000=nTK??

6.2.4 ?#?

X1.5= 10=,′nTK?;)Bg>?M’F>|eè?&?14?X 10= 1000=,′nTK?;eè

|FGe?X 5= 1000=,′nTK?;F>| ?

6.2.5 g~Z¤

axT?,′???GB/T33768-20175.1.3.6?

p?BP?

p?è1

BP?-$,o

?&Xˉ+X?FE?1yE÷0;]=Fˉ}``a+?.à?1yjàa+?+XèBBP?+XA?`BgXB?+X;,′5′??7-,′ˉ7-??0cêW?

A?=

BP?A?7,′???GB/T33768-20175.2.1.2?

BP?—,

BP?‘&,′???GB/T33768-20175.2.1.3?

BP?!?Pú

BP?!?P?,′???GB/T33768-20175.2.1.4?

?#?e#{!?P?2;?

a) BP?5?>è9'—\·& 6.2?@-e×

b) 9'—\·& 5.1-5.2??ê,′‘&??±"r?@y+eW7-#{B?

g~Z¤

?*)à\·& ?6.2.5],′+???&??jax?

N?eT

BP?-$,o

.?êX??êNá)·93$μ_?)Bg,′?y?

A?=

BP?A?7??±"r2;?

7-×+O??êj??pM0?Ná,′_?>?5?×

b) +e?+e#q>??y$à?>???/j#??y?)·A??#{B+eDˉ?nTK?1y?

BP?—,

BP?‘&,′???GB/T33768-20175.2.2.3?

BP?!?Pú

BP?!?P?,′???GB/T33768-20175.2.2.4?

?#?!?Púe#{!?P?2;?

a) BP?5?>è9'—\·& 6.2?@-e×

b) 9'—\·& 5.1-5.2??ê,′‘&??±"r?@y+eW7-#{B ?

g~Z¤

?*)à\·& ?6.2.5],′+???&??jax?

)?1BP?

$_üà)?

BP?-$,o

.?êBgˉQ$Y?~$Y,′7-?èúQ$Y?~$Y?/F) .uy+e=?1?,′?yèA??&1>?

?8?(wKˉO0cêW?

A?=

BP?A?7,′???GB/T33768-20175.3.3?

BP?—,

BP?‘&2;?

a) ú)?$Y??-40 +125 ×

b) ú)?!Q 9GB/T33768-20175.3.3?F?j 500!Q?M?×)?3?èF 100!Q?×)?3? ,

|],′ GB/T33768-2017j??93WE+X,′·& ×

c) wL}$YFO)·9GB/T33768-20175.3.3?F?=?? 10 /6J?è|],′ GB/T33768-2017

j??93WE+X,′·& ×

Q~$Y1&L$?=A?106J??

BP?!?Pú

BP?!?P?,′???GB/T33768-20175.3?

?#?e#{!?P?2;?

a) BP?5?>è9'—\·& 6.2?@-e×

b) 9'—\·& 5.1-5.2??ê,′‘&??±"r?@y+eW7-#{B?

g~Z¤

?*)à\·& ?6.2.5],′+???&??jax?

p?FU0i7$μ'#BP?

BP?-$,o

A?`Bgˉ$Y??$ˉ????1y??,′7-?èA??&1>??8?(wKˉO0cêW?

A?=

7-F5 1??ê,′$Y??-()$ˉ?,′??é?è<&?+eF?èBP?&5?&íD??ê,′?5?‘

&?

BP?—,

BP?‘&,′???GB/T4937.4-20124.1?

BP?!?PúBP?!?P?2;?

BP?}X??ê,′$Y?;?@Bgy+e(?W#{B×

b) |‰BP?!?P?,′???GB/T4937.4-20125?

?#?e#{!?P?2;?

a) BP?5?>è9'—\·& 6.2?@-e×

b) 9'—\·& 5.1-5.2??ê,′‘&??±"r?@y+eW7-#{B ?

g~Z¤

?*)à\·& ?6.2.5],′+???&??jax?

6.4.3 -M4

BP?-$,o

\BP?_j?Q#§%W"D)Bg?y,′0ZDFO,′BP??7€<°BP??

A=

1-M.w063,·BP…1?¨D9*?B g,·>?5?BP…1?=>-M. +O+X?

BP′,

BP…&?;

$Y??35 f3 ×

b) BP?&L$9GB/T4937.13-20124.2?F?j24f2?&è|],′ GB/T4937.13-2012j??93WE+X,′·&×

c) -"1#eFO)·?20 50g/(m2gd)?

BP?!?PúBP?!?P?2;?

BP?}?@Bgy+e(?W#{B×

b) |‰BP?!?P?,′??? GB/T4937.13-20124?

?#?e#{!?P?2;?

a) BP?5?>è?0?￡+X#q?,′?/?€"d?"d$Y=CμE÷38 ?8#Aa#GBg56J?è?L”?Bg>?M’"1#e,′-è'f>+X0a"DFW"D?i￠×

b