浙江大學c程2023B試卷E

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浙江大學c程2023B試卷E

《CProgramming》TESTPAPER

Time:8:30-10:30am.June20,2023

Importantnote:youranswersmustbewrittenontheanswersheet

Section1:SingleChoice（1markforeachitem,total10marks）

1.Theprecedenceofoperator_____isthelowestone.

A．B．!=C．D．=

2._____iswrongifitisusedasanintegerconstant.

A．0xaB．010LC．10D．1.0

3.Theexpression!(x0||y0)isequivalentto_____.

A．!(x0)!(yB．!x0!y0C．!x0||!y0D．!(x0)||!(y0)

0)

4.Thevalueofexpression______isn’t0。

A．1/2B．!’\0’C．!EOFD．NULL

5.Ifxisafloatvariable,thevalueofexpression(x=10/4)is_____。

A．2.5B．2.0C．3D．2

6.Ifvariablesaredefinedandassignedcorrectly,theexpression______iswrong.

A．abB．a^bC．xD．a,b

7.Accordingtothedeclaration:inta[10],*p=a;theexpression______iswrong.

A．a[9]B．p[5]C．*p++D．a++

8.______iswrong.

A．charstr[10];str=string;B．charstr[]=string;

C．char*p=string;D．char*p;p=string;

9.Ifallvariableshavebeendefinedanddeclaredinthefollowingprogram,allthevariables

whichcanbeusedinfunctionfun()are______.

#includestdio.h

voidfun(intx)

{staticinty;

……

return;

}

intz;

voidmain()

{inta,b;

fun(a);

……

}

A．x,yB．x,y,zC．a,b,y,zD．a,b,x,y,z

10.Accordingtothedeclaration:intp[5],*a[5];theexpression______iscorrect.

A．p=aB．p[0]=aC．*(a+1)=pD．a[0]=2

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浙江大學c程2023B試卷E

Section2:Fillintheblanks（2markforeachitem,total30marks）

1.Accordingtothedeclaration:inta[2][3][4]，thenumberofelementsofarrayais___24__.

2.Writingconditionalexpression___（x0）?1:(x==0)?0:-1___tocalculatethevalueofy.1x0

y=0x=0

-1x0

3.Thevalueofexpression1105is__1___.

4.Thevalueofexpression~(101)4is___0___.

5.Thevalueofexpressionsizeof(“hello〞)is___6___.

6.Theoutputofthefollowingstatementsis__k=10,s=25___.

intk,s;

for(k=1,s=0;k10;k++){

if(k%2==0)continue;

s+=k;

}

printf(k=%ds=%d,k,s);

7.Theoutputofthefollowingstatementsis__47___.

#defineMM(x,y)(x*y)

printf(%d,MM(2+3,15));

8.Theoutputofthefollowingstatementsis__k=1s=30___.

intk=1,s=0;

switch(k){

case1:s+=10;

case2:s+=20;break;

default:s+=3;

}

printf(k=%ds=%d,k,s);

9.Theoutputofthefollowingprogramis__1#2#3#___.

#includestdio.h

intf()

{staticintk;

return++k;

}

voidmain()

{intk;

for(k=0;k3;k++)

printf(%d#,f());

}

10.Theoutputofthefollowingprogramis__5___.

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浙江大學c程2023B試卷E

f(intx)

{

if(x=1)return1;

elsereturnf(x-1)+f(x-2);

}

voidmain()

{printf(%d,f(4));

}

11.Theoutputofthefollowingstatementsis__2,1___.

intk=1,j=2,*p,*q,*t;

p=k;q=j;

t=p;p=q;q=t;

printf(%d,%d,*p,k);

12.Theoutputofthefollowingstatementsis__10#30#___.

intc[]={10,30,5};

int*pc;

for(pc=c;pcc+2;pc++)

printf(%d#,*pc);

13.Theoutputofthefollowingstatementsis___FOUR,P__.

char*st[]={ONE,TWO,FOUR,K};

printf(%s,%c\n,*(st+2),**st+1);

14.Theoutputofthefollowingprogramis__0,4___.

#includestdio.h

voidp(int*x,inty)

{++*x;

y=y+2;

}

voidmain()

{intx=0,y=3;

p(y,y);

printf(%d,%d,x,y);

}

15.Writingthedeclaration_____withtypedef,whichmakesCPasynonymforacharacter

pointerarray,10elements.typedefchar*CP[10];

Section3:Readeachofthefollowingprogramsandanswerquestions(5marksforeachitem,totalmarks:30)

1.Theoutputofthefollowingprogramis__33#366#3699#___.

#includestdio.h

voidmain()

{intk,x,s,t;

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浙江大學c程2023B試卷E

x=3;

s=0;t=x;

for(k=1;k=3;k++){

t=t*10+x;

s=s+t;

printf(%d#,s);

}

}

2.Wheninput:730303129760ENTER,theoutputis____3#-1#___.

#includestdio.h

voidmain()

{intj,k,sub,x;

inta[5];

for(j=1;j=2;j++){

for(k=0;k5;k++)

scanf(“%d〞,a[k]);

scanf(“%d〞,x);

sub=-1;

for(k=0;k5;k++)

if(a[k]==x)sub=k;

printf(%d#,sub);

}

}

3.Theoutputofthefollowingprogramis__1#0#2#3#___.

#includestdio.h

voidmain()

{longnumber,wt,x;

x=number=10230;

wt=1;

while(x!=0){

wt=wt*10;

x=x/10;

}

wt=wt/10;

while(number!=0){

printf(%d#,number/wt);

number=number%wt;

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浙江大學c程2023B試卷E

wt=wt/10;

}

}

4.Wheninput:398653712421234ENTER,theoutputis

____a[0][0]=9#a[1][2]=7#a[1][1]=4#___.

#includestdio.h

voidmain()

{intflag,i,j,k,col,n,ri,a[6][6];

for(ri=1;ri=2;ri++){

scanf(%d,n);

for(i=0;in;i++)

for(j=0;jn;j++)

scanf(%d,a[i][j]);

flag=0;

for(i=0;in;i++){

col=0;

for(j=0;jn;j++)

if(a[i][col]a[i][j])col=j;

for(k=0;kn;k++)

if(a[i][col]a[k][col])break;

if(k=n){

printf(a[%d][%d]=%d#,i,col,a[i][col]);

flag=1;

}

}

if(!flag)printf(NO#);

}

}

5.Wheninput:howareyou?ENTER,theoutputis___HowAreYou?____.

#includestdio.h

voidmain()

{intword;

charch;

word=0;

while((ch=getchar())!='?'){

if(ch=='')word=0;

elseif(word==0){

word=1;

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浙江大學c程2023B試卷E

if(ch='z'ch='a')

ch=ch-'a'+'A';

}

putchar(ch);

}

}

6.Ifthefollowingdataarestoredintextfilea.txt

one?two?1234?output?

Andthefollowingdataarestoredintextfileb.txt

one?two?1204?input?

Theoutputofthefollowingprogramis__3#0#2#___.

#includestdio.h

#includestdlib.h

voidmain()

{intcount;

charch1,ch2;

FILE*f1,*f2;

if((f1=fopen(a.txt,r))==NULL){

printf(Can'topenfile:%s\n,a.txt);

exit(0);

}

if((f2=fopen(b.txt,r))==NULL){

printf(Can'topenfile:%s\n,b.txt);

exit(0);

}

count=0;

while(!feof(f1)||!feof(f2)){

ch1=fgetc(f1);

ch2=fgetc(f2);

if(ch1!=ch2){

printf(%c#%c#,ch1,ch2);

printf(%d#,count);

break;

}

if(ch1=='?')count++;

}

fclose(f1);

fclose(f2);

}

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浙江大學c程2023B試卷E

Section4:Accordingtothespecification,completeeachprogram(2markforeachblank,total:30marks)

1．Ifinputisn(n0),calculatethevalueofs=1/1!+1/2!+1/3!+……+1/n!.

#includestdio.h

voidmain()

{intj,k,n;

floatf,s;

scanf(%d,n);

;

for(k=1;k=n;k++){

;

;j++)

;

s=s+1.0/f;

}

printf(sum=%f\,s);

}

(1)s=0

(2)f=1

(3)j=k

(4)f=f*j

2．Wheninputisn(n0),ifit’saprimenumber,printYES,otherwiseprintNO.(Primenumbers:anintegralnumbernotdivisiblewithoutaremainderbyanyintegralnumberotherthanitselfandone.Oneisn’taprimenumber,buttwoisaprimenumber)。

#includestdio.h

#includemath.h

voidmain()

{

intn;

intprime(intm);

scanf(%d,n);

)

printf(YES\n);

else

printf(NO\n);

}

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intprime(intm)

{inti,n;

if(m==1)return0;

n=sqrt(m);

for(i=2;i=n;i++)

;

;

}

(5)prime(n)

(6)m%i==0

(7)0

(8)return1

3．Thedefinitionoffunctionf2()isequivalenttothedefinitionoffunctionf1().

intf1(chars[])intf2(char*s)

{intk=0;{char*ss;

while(s[k]!='\0');

k+