相位干涉儀測(cè)向

相位干涉儀測(cè)向0708311507083119一、題目要求使用Simulink模擬構(gòu)建一個(gè)相位測(cè)向系統(tǒng)，構(gòu)造兩個(gè)有時(shí)延的到來信號(hào)，對(duì)其進(jìn)行捕獲，分別在時(shí)域和頻域上對(duì)接收的信號(hào)進(jìn)行方向估計(jì)，并評(píng)估側(cè)向效果。二、實(shí)驗(yàn)方案及公式推導(dǎo)A.公式推導(dǎo)圖1信號(hào)為s(r)=Ecos(2兀ft)，則如圖1所示天線長(zhǎng)為d,信號(hào)方向與參考方向夾角為00設(shè)2點(diǎn)的接收信號(hào)為r2(t)=5(t)=Ecos(2兀ft)則1點(diǎn)的接收信號(hào)為r(t)=s(t-t)=Ecos(2兀ft-2KdSin0)0人其中X=C為信號(hào)波長(zhǎng)f0①時(shí)域測(cè)向?qū)_(t),r(t)改寫為復(fù)數(shù)形式得r(t)=Eej偵f0tr(t)=Eej2兀f0t-wi2兀dsin0X對(duì)(3)式取共軛得,r*(t)=Ee-j2兀f0t⑷式與(5)式相乘得,r(t)r*(t)=E2e-帥⑴⑵⑶⑷⑸(6)對(duì)(6)式求相角，乘以-^得，sin0=墾2兀d2兀d取反正弦，乘以竺P，求出0兀②頻域測(cè)向?qū)?3)、(4)作FFT得，R1(w)=E8(f—fo)e-帥由公式求出同①，可求出0B.方案論述0=arctanR(k)

—IRQ(k)中=arctanF-arctan"Rq(k)Rq(k)⑺⑻⑼(10)一、伯努利二進(jìn)制碼流經(jīng)BPSK產(chǎn)生r(t)二、產(chǎn)生r(t)=r(t)e-帥三、①時(shí)域法：r(t)r*(t)取出甲②頻域法：對(duì)r(t),r(t)作FFT,求出相位差甲1四、根據(jù)甲的值對(duì)應(yīng)求出0三、Simulink框圖說明及參數(shù)設(shè)計(jì)：依據(jù)方案的設(shè)計(jì)，建立Simulink仿真模型A.框圖模塊說明：口-二/相乘器相加器ElErnc-uHi曰in口ryBErncuHiBinnry-二進(jìn)制數(shù)據(jù)流AWGMAWGMChannel高斯白噪聲信道FIT?」1&i實(shí)現(xiàn)快速傅立葉變換L實(shí)現(xiàn)運(yùn)算功能時(shí)}—~爐|}in[u)——GompiestoResl-lmsg求信號(hào)實(shí)部虛部Real-1magtoI-1由實(shí)部虛部合成信號(hào)Buffer緩存—?-?―*■star'CorrplextoTrigMCEFtriE：rOV求信號(hào)相角作arctan運(yùn)算B.模型框圖:EuT?r其中Subsystem如圖3日efn^ulliBinary^EFWKGenerHicrModulatofSssE-bsnd1Subsysteml如圖4tsp-Dn-entis11tsp-Dn-entis11圖4四、仿真數(shù)據(jù)處理，圖表及得出相關(guān)結(jié)論參數(shù)設(shè)計(jì)：Frotabilityofazero:|o.=Initialeeed:leLSanpletizie-:|i/lc:cccccc|Bernoulli模塊參數(shù)圖52兀dsin。義曰［人由于^=〈兀得,d2兀dsin。義曰［人由于^=〈兀得,d〈一,人2SubsystemlGain的參數(shù)一=-pi/1.5Gain:|-tJ-=WiLltiplication:|Elea&nt-Tize；E.8u)Sazirletime(_1forinJie-Tite-d}zF3X108==3m，可取d=1m貝。1X108同理Gainl，Gain4的參數(shù)為-^—=-1.5/pi2兀dGain:/二yuLtipliL：ation:|Element-TriEG；K.Su)Sampletzizie-(1forinJieilte-d}z假設(shè)。=60。10=4502實(shí)驗(yàn)結(jié)果:Disp-luyDisplay1Disp-luyDisplay1圖8由圖得時(shí)域測(cè)向結(jié)果01=59.85062=44.91045o—44.910=0.2%450600—59.8545o—44.910=0.2%450測(cè)向誤差￡==0.25%1600由圖得頻域測(cè)向結(jié)果61=59.26062