DL∕T 5040-2006 英文版 輸電線路對無線電臺影響防護設(shè)計規(guī)程

1、ICS 29.020F 21Record No.: J5402006Electric Power Industry Standard of the People's Republic of ChinaPDL / T 5040 2006To replace DL 5040 1995Code for Designing of Radio Stations against Effects from Power Transmission LinesIssue Date: September 14, 2006ImpIementation Date: March 1, 2007Issued by

2、the NationaI DeveIopment and Reform Commission of the PeopIe's RepubIic of ChinaElectric Power Industry Standard of the People's Republic of ChinaPDL / T 5040 2006To replace DL 5040 1995Code for Designing of Radio Stations against Effects from Power Transmission LinesTranslation sponsored by

3、: China Electric Power Planning & Engineering Association Translated by: SUNTHER Consulting Co., Ltd.Reviewed by: Southwest Electric Power Design InstituteCHINA ELECTRIC POWER PRESS BEIJING, 2012圖書在版編目（CIP）數(shù)據(jù)DL/T 50402006 輸電線路對無線電臺影響防護設(shè)計規(guī)程： 代 替 DL/T 50401995=Code for designing of radio stations

4、against effects from power transmission lines：英文 / 中華人民共和國國家發(fā)展和改革委員會發(fā)布. 北京：中國電力出版社，2013.5ISBN 978-7-5123-3975-0. D . 中 . 輸電線路-影響-無線電臺-防護措施-標準-中國-英文 . TN924-65中國版本圖書館CIP 數(shù)據(jù)核字（2013）第 009449 號中國電力出版社出版（北京市東城區(qū)北京站西街 19 號 100005 ） 北京博圖彩色印刷有限公司印刷*2013 年 5 月第一版2013 年 5 月北京第一次印刷850 毫米×1168 毫米 32 開本 0.75

5、 印張 15 千字敬 告 讀 者本書封底貼有防偽標簽，刮開涂層可查詢真?zhèn)伪緯缬杏⊙b質(zhì)量問題，我社發(fā)行部負責(zé)退換版 權(quán) 專 有翻 印 必 究DL / T 5040 2006ContentsForeword1 Scope12 Terms and Definitions23 Protecting Distance34 Protective Measures55 Calculation of Protecting Distance7IDL / T 5040 2006ForewordThis code is a revision of the Code for Designing of Radio S

6、tations against Effects from High-Voltage Power Transmission Lines (DL/T 50401995) in accordance with the requirements of the Notice on Issuance of Plan for Supplementing Electric Power Industry Standard in 2003 issued by the General Office of National Development and Reform Commission (FGBGY 2003 8

7、73).This code contains the following major changes compared with DL/T 50401995:1. The protecting distance of VHF/UHF aeronautical radio communication station is revised;2. The requirements for the protecting distance of air traffic control radar station are added;3. The requirements of protecting di

8、stance of radio telemetry seismic network are added;4. The protection requirements for mobile-phone base station are added;5. The requirements for values of atmospheric noise are changed.This code supersedes DL/T 50401995 upon its issuance. This code is proposed by the China Electricity Council.This

9、 code is interpreted and managed by the Technical Committee on Electric Power Planning and Engineering of Standardization Administration of Power Industry.Main drafting organization: Southwest Electric Power Design Institute.IIDL / T 5040 2006The participants involved in preparation: China Power Eng

10、ineering Consulting Group Corporation, East China Electric Power Design Institute, Zhejiang Electric Power Design Institute and Shandong Electric Power Engineering Consulting Institute Corp., Ltd.The leading authors of this code: Wei Dejun, Wang Qiang, Wang Yonggang, Wang Jin, Li Li, Liu Zhongquan,

11、Miao Guiliang, Gao Zhilin, Wang Yi, and Han Yanming.This code was first issued on July 13, 1995.This code is translated by SUNTHER Translation & Solutions under the authority of China Electric Power Planning & Engineering Association.IIIDL / T 5040 20061ScopeThis code specifies the protectin

12、g distance between high voltage AC overhead power transmission lines (abbreviated as transmission lines) and various types of radio stations, and proposes protective measures for cases where the protecting distance cannot be met, and provides methods for calculating protecting distances.This code ap

13、plies to the protection design of 110kV-500kV three-phase AC overhead transmission lines for radio stations which comply with applicable standards.1DL / T 5040 20062Terms and DefinitionsThe following terms and definitions are applicable to this code:Protecting distanceThe minimum distance between th

14、e edge of radio station antennas and transmission lines, which is specified to ensure the normal operation of radio stations.2DL / T 5040 20063 Protecting Distance3.0.1 1The protecting distance between transmission lines and various radio stations shall comply with the requirements given in Table 3.

15、0.1.Table 3. 0. 1 Protecting distance between power transmission lines and radio stationsmNo.Names of Radio StationsVoltage Level of Transmission Line kV110220-3305001Amplitude modulation broadcasting radio stationClass 180010001200Class 2500700900Class 33004005002Amplitude modulation broadcasting m

16、onitoring stationClass 1140016002000Class 26008001000Class 33004005003Short-wave radio receiving stationClass 1100013001800Class 26008001100Class 35006007004Short-wave radio direction-finding station1000160020005TV transposer station and rebroadcasting stationVHF (I)300400500VHF (III)1502503506VHF/U

17、HF aeronautical radio communication station2002503007Air defense surveillance radar station(80-300)MHz1000120016003DL / T 5040 2006Table 3. 0. 1 (continued)No.Names of Radio StationsVoltage Level of Transmission Line kV110220-3305007Air defense surveillance radar station(300-3000)MHz70080010008Air t

18、raffic control radar station4509Medium-wave navigation station50010Ultrashort-wave direction-finding station70011Marine radio navigation station4003.0.2 2 Where there is difficulty in fulfilling the protecting distance specified in Table 3.0.1, proper protective measures may be applied based on the

19、actual situation of transmission lines and radio stations after calculation (see Chapter 5) and test.4DL / T 5040 20064 Protective Measures4.1 1Transmission Line4.1.1 1 The cross-section of conductors, number of bundles and arrangement shall be properly determined based on the radio interference lev

20、el to control the electric field intensity around the conductor surface and reduce the radio interference field intensity.4.1.2 2 The insulation level of the transmission line section adjacent to radio stations shall be enhanced to prevent the insulator hardware from generating spark disturbance and

21、 prevent the connections between spacers and conductors from loosening.4.1.3 3 When selecting routes, the lines should run along the non-receiving direction of radio receiving stations and take advantage of the shielding effect of terrain in the adjacent section of lines and stations.4.1.4 4 Tension

22、 wire laying and other new techniques should be adopted for line erection to protect conductors against wear.4.1.5 5 Operation and maintenance should be enhanced as necessary to control and reduce the radio interference level.4.1.6 6 Line routes should be relocated as appropriate to maintain reasona

23、ble distance.4.2 2Radio Station4.2.1 1Antennas with strong directivity and high gains are recommended.4.2.2 2The location of antennas should be moved as necessary.5DL / T 5040 20064.2.3 3Higher transmitting power is recommended to improve the receiving signal-to-noise ratio.4.2.4 4Signal wave forms

24、and signal transmission modes with high anti-jamming capability should be adopted.4.2.5 5Radio stations should be relocated as necessary.6DL / T 5040 20065 Calculation of Protecting Distance5.1 1Calculating the Protecting Distance with Signal-To-Noise Ratio5.1.1 1Calculation of Protecting Distance1

25、When E0-13.98k + Ew + Ef < Nmin, the protecting distance is calculated according to Formula (5.1.1-1): E0 +Ef +Ew - Nmin +1.320kWhere:Dmin = 10(5.1.1-1)Dmin protecting distance, m;E0 reference radio interference field intensity of transmission lines, dB (mV/m);Ef correction value of radio interfe

26、rence frequency, dB (mV/m);Ew radio interference increment on rainy days, dB (mV/m);Nmin the minimum protective field intensity, dB (mV/m);k transverse attenuation factor of radio interference.2 When E0 - 13.98k + Ew + Ef > Nmin, the protecting distance is calculated according to Formula (5.1.1-2

27、): E0 +Ef +Ew - Nmin +2 20kDmin = 10(5.1.1-2)5.1.2 2Calculation of Radio Interference Level of Transmission Line1 Reference radio interference field intensity of single-phase conductors. Assume the following conditions:Direct distance from the single-phase conductor: 20m;7DL / T 5040 2006Height: 2m

28、above ground; Frequency: 0.5MHz; Weather: sunny;The 50% reference radio interference field intensity can be calculated according to Formula (5.1.2-1):E0= 3.5gmax + 12r-30(5.1.2-1)Where:E0 reference radio interference field intensity of single- phase conductor, dB (V/m);gmax effective value of maximu

29、m apparent electric field intensity of conductors, kV/cm;r diameter of conductors or sub-conductors of bundles, cm.2 Reference radio interference field intensity of three-phase single-circuit transmission lines.1) Assume the following conditions:Distance between each phase conductor of three-phase s

30、ingle-circuit transmission line and the horizontal projection of side conductor: 20m;Height: 2m above ground; Whether: sunny; Frequency: 0.5MHz.The 50% reference radio interference field intensity can be calculated according to Formulas (5.1.2-2)(5.1.2-4):Eoa = 3.5 gmax(a) + 12r-30-20k lg (Da /20)(5

31、.1.2-2)Eob = 3.5 gmax(b) + 12r-30-20k lg(Db /20)(5.1.2-3)Eoc = 3.5 gmax(c) + 12r-30-20k lg(Dc /20)(5.1.2-4)Where:8Eoa、Eob and Eoc reference radio interference fieldDL / T 5040 2006intensities of A-、B- and C-phase conductors, when the distance from the horizontal projection of side conductor is 20m w

32、ith the height of 2m above the ground, dB(V/m);Da、Db and Dc direct distances of A-, B- and C-phaseconductors, when the distance from the horizontal projection of side conductor is 20m with the height of 2m above the ground, m;gmax(a)、gmax(b) and gmax(c) effective values of maximum apparentelectric f

33、ield intensities of A-, B- and C-phase conductors, kV/cm.2) The reference radio interference field intensity of three-phase single-circuit transmission lines shall be calculated according to the following method: when the difference between the reference radio interference field intensities of any t

34、wo phases is greater than 3dB (V/m), take the maximum as the reference value for this line. Otherwise, take the average of two large radio interference field intensities plus 1.5dB (V/m) as the reference value for this line.3 Reference radio interference field intensity of three-phase double-circuit

35、 transmission lines.First, E'0a, E'0b and E'0c (one circuit), as well as E''0a, E''0b and E''0c (the other circuit), the reference radio interference field intensities of individual phases of double-circuit transmission lines are calculated according to Formulas (

36、5.1.2-2)-(5.1.2-4).1) The integrated reference radio interference field intensity9DL / T 5040 2006of individual phases of three-phase double-circuit power lines can be calculated according to Formulas (5.1.2-5)- (5.1.2-7):(10 20 )E¢ 2()20 a E0¢¢a + 10 20E0¢¢a¢ = 201g(5.

37、1.2-5)(10 20 )E¢2()20 b E0¢¢b + 10 20E0¢¢b¢ = 201g(5.1.2-6)(10 20 )E¢2()20 c E0¢¢c + 10 20E0¢¢c¢ = 201g(5.1.2-7)2) Reference radio interference field intensity of three- phase double-circuit transmission lines. After the reference radio int

38、erference field intensities of individual phases of three-phase double-circuit power transmission line are obtained according to Formulas (5.1.2-5)- (5.1.2-7), the reference radio interference field intensity of three-phase double-circuit power line can be calculated according to the principle of Ar

39、ticle 5.1.2, Clause 2, Item 3 Calculation of Apparent Electric Field Intensity of Conductor Surface1 The apparent electric field intensity of a conductor can be calculated according to Formula (5.1.3-1):gav= 1q(5.1.3-1)Where:n 2e0ggav average apparent electric field intensity of conductor su

40、rface, kV/cm;q apparent charge of unit length of conductor, 103C/m;10DL / T 5040 20060 free-space dielectric coefficient, F/m, 0=1;36 ´109n number of sub-conductors of bundled conductor;r diameter of sub-conductor, cm.2 The apparent charge of a unit length of conductor can be calculated accordi

41、ng to Formula (5.1.3-2):q = p-1×U(5.1.3-2)Where:qa q b q q= q= abc(5.1.3-3) c qq w q wv v paapabpacpawpav ppppp babbbcbwbv ppp= ppppp =abcabc-wv(5.1.3-4) cacbcccwcv pppwapwbpwcpwwpwv wv-abcwv ppppp vavbvcvwvv Ua U Ua aU b a UU= U = a2U = abc(5.1.3-5) c ww U a UU wv U U v vWhere:a= - 1 + j 1 322

42、q column matrix of apparent charges of unit length of conductor; the suffixes a, b and c respectively represent A-,11DL / T 5040 2006B- and C-phase conductor; and the suffixes w and v represent two shield wires;p-1 inverse matrix of the potential-coefficient matrix p;U column matrix of conductor vol

43、tage.3 Potential CoefficientThe self-potential coefficient can be calculated according to Formula (5.1.3-6):p =1 1n 2hi(5.1.3-6)Where:ii2e0reqipii self-potential coefficient;hi average height of the ith phase conductor above the ground, m;reqi equivalent diameter of ith phase conductor, m.n nr RIf t

44、he ith phase conductor is a bundled conductor, its equivalent diameter can be calculated according to Formula (5.1.3-7):Where:reqi = R´10-2(5.1.3-7)Rdiameter of bundled conductor, cm.The mutual potential coefficient can be calculated according to Formula (5.1.3-8):p =11n Di¢j(5.1.3-8)Where

45、:ij2 ´ e0Dijpij mutual potential coefficient;Dij distance between ith phase conductor and jth phase conductor, m;12DL / T 5040 2006ijD¢ distance between the ground image of ith phase conductorand the ground image of jth phase conductor, m.4 Order Reducing of Potential CoefficientWhen the s

46、hield wire of a power transmission line is earthed, the potential of shield wire Vw=0V, Vv=0V. The potential coefficient may be reduced by two orders and calculated according to Formula (5.1.3-9):p¢ = p-p´p-1 ´ p(5.1.3-9)abcabcabc-wvwvwv-abc pawpav p= pp (5.1.3-10)abc- wv bwbv pcwpcv

47、p= pwapwbpwc (5.1.3-11)wv-abc ppp Where: vavbvc pa¢bc potential coefficient matrix of phase conductor when the effect of earthed shield wire is considered;pabc potential coefficient matrix of phase conductor;pabc-wvmatrix of mutual potential coefficient between phase conductor and shield wire;w

48、vp-1 inverse matrix of pwv, matrix of shield wire potentialcoefficient;pwv-abc matrix of mutual potential coefficient between the shield wire and phase conductor.5 The effective value of maximum apparent electric field intensity of conductor can be calculated according to Formula (5.1.3-12):g= 1 + (

49、n -1)r g（5.1.3-12）maxR av13DL / T 5040 20065.1.4 4Corrected Value of Radio Interference Frequency.fThe radio interference frequency of power transmission lines shall be corrected based on the reference of 0.5MHz; when the frequency ranges from 0.15 to 4MHz, the corrected value can be calculated according to Formula (5.1.4-1):Where:E = 51 - 2lg(10 f )2(5.1.4)Ef corrected value of radio interference frequency, dB (mv/m);f frequency, MHz.5.1.5 5Corrected Value of Radio Interference Distance.When the distance D < 100m, the corrected value of radio interference distance