理論力學(xué)(自制)

1、計算題一平面任意力系（考固定端約束）BCCAACBFAxFAyMACyFCxFFCxFCy FBFAxFAy FB01, 005 . 012, 0)(0, 0 qFFFqFMFFBCyyBCCxxFkN5 . 1, 0,kN5 . 0 CyCxBFFF025 . 11, 0)(01, 00, 0 CyAACyAyyCxAxxFqMMMqFFFFFFFmkN4kN,5 . 3, 0 AAyAxMFF若不求若不求C處的力則可處的力則可選整體為研究對象選整體為研究對象PFBxFByFCyFCxBCByFFAyPBxFFAxAB) 3(0, 0)2(0, 0) 1 (02, 0)( CxBxxCyBy

2、yByCFFFPFFFaFPaMFPFFCyBy5 . 0 0, 0022, 0)(0, 0 BxAxxAyAxBByAyyFFFPaaFaFMPFFFFPFPFPFBxAyAx ,5 . 1,PFCx PPABCDCD022, 0)(0, 00, 0 aFaFMMFFFFFFCyCxDDCyDyyCxDxxFPaMPFPFDDyDx 5 . 0CxFCyFPFBxFByFCyFCxBCByFFAyPBxFFAxABPPABCDBCDEDABCDEHFNBFAxFAyFCxFCyFNBDxFDyFFDxFDyFNEH解：解：(1) 取取DE桿為研究對象桿為研究對象kN110, 0322, 0)

3、( DXDxHFqFMMF(2) 取取BDC桿為研究對象桿為研究對象kN3110, 031, 0)( NBNBDxCFFFMF(3) 取整體為研究對象取整體為研究對象0326, 0)(02, 00, 0 qFMMMqFFFFFNBAAAyyNBAxxF0,100kNkN,3110 AAyAxMFF解得：解得：例題例題3 已知：已知：q=50kN/m, M=80kNm,求求:A、B的約束反力。的約束反力。計算題二運(yùn)動學(xué)（速度合成、加速度合成）reavvv coscos0aelvvvD retanaaaaa enatasincosaaa )sincos(200e lareavvv sinsiner

4、vvv aeaanratrarnrteaaaaa nrea cossinaaa 3222asin cot)sin cos( sin1RvaRvaa 計算題三運(yùn)動學(xué)（剛體的定軸轉(zhuǎn)動+平動基點法求速度）計算題三運(yùn)動學(xué)（剛體的定軸轉(zhuǎn)動+平動基點法求速度）計算題三運(yùn)動學(xué)（剛體的定軸轉(zhuǎn)動+平動基點法求速度）AO1OB3203vAvB0 OAvAAB03rOBvABB AO1OB20215ratB nAatAanBatBanAatAanBAatBAanBAtBAtAnABnBaaaaaa t200203,rraratAnA 2022rABaABnBA 201223rBOvaBnB nBAnAtAnBtBa

5、aaaa 60cos30cos30cos60cos計算題四動量矩定理（ 動量矩定理+質(zhì)心運(yùn)動定理）lglmgml23,2312 OyOxFmglmFlm 20224, 0mgFFOyOx OABC260sin12160sin60cos2)()(lFmlJmaFmgFmaFFACcyAeyCxAex 2, 0laatCAnCAnCAtCAAC aaaa230sin,30coslaaaaACyAcx BAC60aAaCAaAACB.132,1318,1332galgmgFAA 計算題五動能定理（ 速度合成+質(zhì)心運(yùn)動定理）AO30CxAO30COvAO30COvOv iiWTT122222212121CCOmvJmvT mgllmgWii41)30sin1 (2 lvlvvvvvvOOCAOCAOC214160cos2222222 OOvmlmlmvT41612222 mglvmlmlmvTTOO41416122212 0)60cos2( lvmmvOOlvO81 lg2934 AO30CxAO30COvAO30COvOv iiWTT122222212121CCOmvJmvT mgllmgWii41)30sin1 (2 lvlvvvvvvOOCAOCAOC214160cos2222222 OOvmlmlmvT41612222 mglvmlm