C語言版井字棋

1、十五、井字棋【問題描述】設(shè)計(jì)一個(gè)井字棋的游戲程序【基本要求】游戲規(guī)則是：從一個(gè)空的棋盤開始，人為x一方，計(jì)算機(jī)為o一方，人機(jī)雙方輪流放置棋子，人下的時(shí)候，字符x將被放入棋盤中指定的位置，輪到計(jì)算機(jī)下時(shí)，程序?qū)呙杵灞P，并將字符o放入掃描到的第一個(gè)空格，某一方有3枚棋子占據(jù)了一橫行、一豎行或一對(duì)角線則獲勝，若整個(gè)棋盤被占滿還沒有一方獲勝則為和局。截圖：代碼：/author GXU-pengcheng#include<stdio.h>#include<windows.h>#include<conio.h>void Help();/幫助int Play(char

2、player,int choice);/對(duì)弈void Init();/初始化棋盤void Display();/打印棋盤void Black(int choice);/黑棋void White(int choice);/白棋void Block(int choice);/添加選擇框void Clear(int choice);/清空之前的選擇框int Judge(int choice,char symbol);/判斷輸贏 返回值0為無結(jié)果,1為獲勝,2為平局int Funcx(int choice);/將標(biāo)號(hào)轉(zhuǎn)換為行號(hào)int Funcy(int choice);/將標(biāo)號(hào)轉(zhuǎn)換為列號(hào)void En

3、d(char symbol);/結(jié)束int Found();/返回第一個(gè)沒有棋子的位置的編號(hào)char a3164;/用數(shù)組存放棋盤和棋子，a行列int b=0;/棋子個(gè)數(shù)int main()char player;int choice; system("title 井字棋");/設(shè)置標(biāo)題system("mode con cols=64 lines=35");/設(shè)置窗口大小system("color 70");/設(shè)置顏色while(1)printf("nnnnnnttt井t字t棋");printf("nnn

4、nnnnnttt1. 玩 家 先 手nnttt2. 電 腦 先 手nnttt3. 幫 助nnttt4. 退 出nnnnntt請(qǐng)輸入: ");player=getch();if(player='1')Init();Block(5);choice=5;Play(player,choice);else if(player='2')Init();Play(player,choice);else if(player='3')Help();getch();system("cls");continue;else if(player

5、='4')return 0;elseprintf("nntt 輸入錯(cuò)誤請(qǐng)重新輸入！");Sleep(1000);system("cls");continue;return 0;void Help()system("cls");printf("nnnnnnnnnttt 幫助nnn");printf("t 'W'上移, 'S'下移, 'A'左移, 'D'右移 nn");printf("tt 游戲中按'4

6、'退出");printf("nnnntt 按任意鍵退出");int Play(char player,int choice)/對(duì)弈char get;char symbol;int c=0;/Judge得出的結(jié)果while(1)system("cls");/每次循環(huán)清屏一次Display();if(player='1')/玩家下棋while(1)/確定要下的位置if(get=getch()!=' ')if(get='4')system("cls");return 0;el

7、se if( (get='w'|get='W') &&choice-3>=1)Clear(choice);choice =choice-3;else if(get='s'|get='S')&&choice+3<=9)Clear(choice);choice = choice+3;else if(get='a'|get='A')&&(choice+2)/3=(choice+1)/3)Clear(choice);choice -= 1;else

8、 if(get='d'|get='D')&&(choice-1)/3=choice/3)Clear(choice);choice += 1;elsecontinue;Block(choice);system("cls");Display();elseif(a(choice-1)/3)*10+2(choice-1)%3)*21+4!=' ')printf("該位置已有其他棋子！");continue;elseClear(choice);break;/while結(jié)束b+;Black(choice

9、);player='0'symbol='#'/if結(jié)束else/電腦下棋choice=Found();Block(choice);b+;White(choice);player='1'symbol='*'if(c=Judge(choice,symbol)!=0)/判斷輸贏if(c=2)symbol='='c=0;End(symbol);break;return 0;void Init()/初始化棋盤int x=0,y=0;int i='1'for(x=0;x<31;x+)for(y=0;y&l

10、t;64;y+)if(y=Funcy(1)|y=Funcy(2)|y=Funcy(3)|y=Funcy(2)+Funcy(3)if(x=Funcx(1)|x=Funcx(4)|x=Funcx(7)|x=Funcx(4)+Funcx(7)axy='+'elseaxy='|'else if(x=Funcx(1)|x=Funcx(4)|x=Funcx(7)|x=Funcx(4)+Funcx(7)axy='-'elseaxy=' '/for(x=1;x<=7;x=x+3)/在每個(gè)格子的左上角添加序號(hào)，范圍19/for(y=1;y&l

11、t;=3;y+)/a(Funcx(x)+1)(Funcy(y)+1)=i;/i+;/void Display()/打印棋盤int x=0,y=0;for(x=0;x<31;x+)for(y=0;y<64;y+)printf("%c",axy);void Block(int choice)/添加選擇框int x,y;for(x=Funcx(choice)+1;x<Funcx(choice)+10;x+)for(y=Funcy(choice)+2;y<Funcy(choice)+20;y+)if(x=Funcx(choice)+1|x=Funcx(cho

12、ice)+9)if(y=Funcy(choice)+2|y=Funcy(choice)+19)axy='+'else if(y<Funcy(choice)+7|y>Funcy(choice)+14)axy='-'else if(x<Funcx(choice)+4|x>Funcx(choice)+6)if(y=Funcy(choice)+2|y=Funcy(choice)+19)axy='|'void Clear(int choice)/清空選擇框int x,y,i;for(i=1;i<=9;i+)if(aFuncx(

13、choice)+1Funcy(choice)+2='+'&&i!=choice)for(x=Funcx(choice)+1;x<Funcx(choice)+10;x+)for(y=Funcy(choice)+2;y<Funcy(choice)+20;y+)if(x=Funcx(choice)+1|x=Funcx(choice)+9)if(y=Funcy(choice)+2|y=Funcy(choice)+19)axy=' 'else if(y<Funcy(choice)+7|y>Funcy(choice)+14)axy=&

14、#39; 'else if(x<Funcx(choice)+4|x>Funcx(choice)+6)if(y=Funcy(choice)+2|y=Funcy(choice)+19)axy=' 'void Black(choice)/添加黑棋int x,y;for(x=Funcx(choice)+2;x<Funcx(choice)+9;x+)for(y=Funcy(choice)+4;y<Funcy(choice)+18;y+)if(x=Funcx(choice)+2|x=Funcx(choice)+8)axy='#'else if

15、(y=Funcy(choice)+4|y=Funcy(choice)+17)axy='#'void White(choice)/添加白棋int x;int d=4;for(x=Funcx(choice)+2;x<=Funcx(choice)+8;x+)axFuncy(choice)+d='*'axFuncy(choice)+20-d='*'d=d+2;int Judge(int choice,char symbol)/判斷輸贏 返回值0為無結(jié)果,1為獲勝,2為平局if(aFuncx(choice)+2Funcy(choice)+4=aFun

16、cx(choice+3)+2Funcy(choice)+4&&aFuncx(choice+3)+2Funcy(choice)+4=aFuncx(choice+6)+2Funcy(choice)+4)|(aFuncx(choice)+2Funcy(choice)+4=aFuncx(choice)+2Funcy(choice+1)+4&&aFuncx(choice)+2Funcy(choice+1)+4=aFuncx(choice)+2Funcy(choice+2)+4)|aFuncx(5)+2Funcy(5)+4=symbol&&(aFuncx(1

17、)+2Funcy(1)+4=aFuncx(5)+2Funcy(5)+4&&aFuncx(5)+2Funcy(5)+4=aFuncx(9)+2Funcy(9)+4)|(aFuncx(3)+2Funcy(3)+4=aFuncx(5)+2Funcy(5)+4&&aFuncx(5)+2Funcy(5)+4=aFuncx(7)+2Funcy(7)+4)return 1;if(b=9)return 2;return 0;int Funcx(int choice)/將標(biāo)號(hào)轉(zhuǎn)換為行號(hào)return (choice-1)/3)%3)*10;int Funcy(int choice)/將標(biāo)號(hào)轉(zhuǎn)換為列號(hào)return (choice-1)%3)*21;void End(char symbol)/結(jié)束system("cls");Display();if(symbol='*')printf("ttt 電 腦 勝