高考數(shù)學(xué)(文數(shù))二輪復(fù)習(xí)查漏補(bǔ)缺練習(xí)：第15講《導(dǎo)數(shù)與函數(shù)的極值、最值》(學(xué)生版)

1、課時(shí)作業(yè)(十五)第15講導(dǎo)數(shù)與函數(shù)的極值、最值時(shí)間 / 45分鐘分值 / 100分基礎(chǔ)熱身1.設(shè)函數(shù)f(x)=ln x+1x,則()A.x=1為f(x)的極大值點(diǎn)B.x=1為f(x)的極小值點(diǎn)C.x=e為f(x)的極大值點(diǎn)D.x=e為f(x)的極小值點(diǎn)2.當(dāng)函數(shù)y=x·3x取得極小值時(shí),x=()A.1ln3B.-1ln3C.ln 3D.-ln 33.當(dāng)x-1,2時(shí),函數(shù)f(x)=ex-x的最小值為()A.1B.-1C.0D.-e4.函數(shù)f(x)=2xsin x在區(qū)間0,2上的最大值是()A.3B.4C.D.25.函數(shù)f(x)=x3-3x的極小值點(diǎn)為. 能力提升6.若函數(shù)f(

2、x)=13x3-x+m的極大值為1,則函數(shù)f(x)的極小值為()A.-13B.-1C.13D.17.若函數(shù)y=ax3+bx2取得極大值和極小值時(shí)的x的值分別為0和13,則()A.a-2b=0B.2a-b=0C.2a+b=0D.a+2b=08.設(shè)函數(shù)f(x)在R上可導(dǎo),其導(dǎo)函數(shù)為f'(x),若函數(shù)f(x)僅在x=-2處取得極小值,則函數(shù)y=xf'(x)的圖像可能是()9.已知x=x0是函數(shù)f(x)=ex-ln x的極值點(diǎn),若a(0,x0),b(x0,+),則()A.f'(a)<0,f'(b)>0B.f'(a)>0,f'(b)<

3、;0C.f'(a)>0,f'(b)>0D.f'(a)<0,f'(b)<010.已知函數(shù)f(x)=ex(x2-x+1)-m,若函數(shù)f(x)有三個(gè)不同的零點(diǎn),則實(shí)數(shù)m的取值范圍是()A.(-,1)B.(1,e3)C.1,3eD.(-,1)(e3,+)11.若x=1是函數(shù)f(x)=(ex+a)ln x的極值點(diǎn),則實(shí)數(shù)a=. 12.已知三次函數(shù)f(x)=ax3+bx2+cx+d的圖像如圖K15-2所示,則f'(0)f'(1)=. 13.若函數(shù)f(x)=x3-6bx+3b在(0,1)內(nèi)有極小值,則實(shí)數(shù)b的取值范圍是. 14.已知函數(shù)f(x)=(x-k)ex.(1)求f(x)的單調(diào)區(qū)間;(2)求f(x)在區(qū)間0,1上的最小值.15.已知函數(shù)f(x)=ex+ax+1(aR),x=0是f(x)的極值點(diǎn).(1)求a,并求f(x)在-2,1上的最小值;(2)若不等式kf'(x)<xex+1對(duì)任意x>0都成立,其中k為整數(shù),f'(x)為f(x)的導(dǎo)函數(shù),求k的最大值.難點(diǎn)突破16.設(shè)函數(shù)f(x)=-x3+3bx,當(dāng)x0,1時(shí),f(x)的值域?yàn)?,1,則b的值是()A.12B.22C.322D.34217. 已知函數(shù)f(x)=exx+k(ln x