廣東省中考數(shù)學(xué)模擬試卷

1、2014年廣東省中考數(shù)學(xué)模擬試卷一、選擇題（本大題10小題，每小題3分，共30分）在每小題列出的四個選項中，只有一個是正確的.1-6的絕對值是（）a-6b6c6d16顯示解析2下列各圖中，經(jīng)過折疊能圍成一個立方體的是（）abcd顯示解析3中國航母遼寧艦是中國人民海軍第一艘可以搭載固定翼飛機(jī)的航空母艦，滿載排水量為67500噸，這個數(shù)據(jù)用科學(xué)記數(shù)法表示為（）a6.75104噸b6.75103噸c6.75105噸d6.7510-4噸顯示解析4若m-n=-1，則（m-n）2-2m+2n的值為（）a-1b1c2d3顯示解析5一組數(shù)據(jù)2，4，x，2，4，7的眾數(shù)是2，則這組數(shù)據(jù)的平均數(shù)、中位數(shù)分別為（）

2、a3.5，3b3，4c3，3.5d4，3顯示解析6如圖，直線l1l2，若1=140，2=70，則3的度數(shù)是（）a60b65c70d80顯示解析7如果ab0，那么下列判斷正確的是（）aa0，b0ba0，b0ca0，b0da0，b0或a0，b0顯示解析8不等式組2x12x17的解集在數(shù)軸上表示正確的是（）abcd顯示解析9下列標(biāo)志中，可以看作是中心對稱圖形的是（）abcd顯示解析10二次函數(shù)y=ax2+bx+c的圖象如圖所示，則一次函數(shù)y=ax+b與反比例函數(shù)y=cx在同一平面直角坐標(biāo)系中的大致圖象為（）abcd顯示解析二、填空題（本大題6小題，每小題4分，共24分）請將下列各題的正確答案填寫在答

3、題卡相應(yīng)的位置上11分解因式：2x2-4x=顯示解析12已知a1+|a+b+1|0，則ab=顯示解析13=80，則的補(bǔ)角為顯示解析14如圖，在小山的東側(cè)a點有一個熱氣球，由于受西風(fēng)的影響，以30米/分的速度沿與地面成75角的方向飛行，25分鐘后到達(dá)c處，此時熱氣球上的人測得小山西側(cè)b點的俯角為30，則小山東西兩側(cè)a、b兩點間的距離為米顯示解析15如圖，在abc中，debc，ad=1，ab=3，de=2，則bc=顯示解析16如圖，ab是半圓o的直徑，且ab=8，點c為半圓上的一點將此半圓沿bc所在的直線折疊，若圓弧bc恰好過圓心o，則圖中陰影部分的面積是（結(jié)果保留）顯示解析三、解答題（一）（本大

4、題3小題，每小題5分，共15分）17解方程：12x+2(54x+1)8+x顯示解析18先化簡，再求值：(3xx2xx+2)x24x，再選擇一個使原式有意義的x代入求值顯示解析19如圖，已知線段ab（1）用尺規(guī)作圖的方法作出線段ab的垂直平分線l（保留作圖痕跡，不要求寫出作法）；（2）在（1）中所作的直線l上任意取兩點m，n（線段ab的上方）連結(jié)am，an，bm，bn求證：man=mbn顯示解析四、解答題（二）（本大題3小題，每小題8分，共24分）20某商場以每件280元的價格購進(jìn)一批商品，當(dāng)每件商品售價為360元時，每月可售出60件，為了擴(kuò)大銷售，商場決定采取適當(dāng)降價的方式促銷，經(jīng)調(diào)查發(fā)現(xiàn)，如

5、果每件商品降價1元，那么商場每月就可以多售出5件（1）降價前商場每月銷售該商品的利潤是多少元？（2）要使商場每月銷售這種商品的利潤達(dá)到7200元，且更有利于減少庫存，則每件商品應(yīng)降價多少元？顯示解析21保障房建設(shè)是民心工程，廣東省某市從2009年開始加快保障房建設(shè)進(jìn)程，現(xiàn)統(tǒng)計了該市2009年到2013年這5年新建保障房情況，繪制成如圖所示的折線統(tǒng)計圖和不完整的條形統(tǒng)計圖（1）小麗看了統(tǒng)計圖后說：“該市2012年新建保障房的套數(shù)比2011年少了”你認(rèn)為小麗說法正確嗎？請說明理由（2）求補(bǔ)全條形統(tǒng)計圖（3）求這5年平均每年新建保障房的套數(shù)顯示解析22如圖點a、b、c、d在o上，acbd于點e，過點

6、o作ofbc于f，求證：（1）aebofc；（2）ad=2fo顯示解析五、解答題（三）（本大題3小題，每小題9分，共27分）23如圖，拋物線y=ax2+bx（a0）經(jīng)過原點o和點a（2，0）（1）寫出拋物線的對稱軸與x軸的交點坐標(biāo)；（2）點（x1，y1），（x2，y2）在拋物線上，若x1x21，比較y1，y2的大??；（3）點b（-1，2）在該拋物線上，點c與點b關(guān)于拋物線的對稱軸對稱，求直線ac的函數(shù)關(guān)系式顯示解析24已知直線pd垂直平分o的半徑oa于點b，pd交o于點c、d，pe是o的切線，e為切點，連結(jié)ae，交cd于點f（1）若o的半徑為8，求cd的長；（2）證明：pe=pf；（3）若pf

7、=13，sina=513，求ef的長顯示解析25已知：如圖，在平行四邊形abcd中，ab=12，bc=6，adbd以ad為斜邊在平行四邊形abcd的內(nèi)部作rtaed，ead=30，aed=90（1）求aed的周長；（2）若aed以每秒2個單位長度的速度沿dc向右平行移動，得到a0e0d0，當(dāng)a0d0與bc重合時停止移動，設(shè)運(yùn)動時間為t秒，a0e0d0與bdc重疊的面積為s，請直接寫出s與t之間的函數(shù)關(guān)系式，并寫出t的取值范圍；（3）如圖，在（2）中，當(dāng)aed停止移動后得到bec，將bec繞點c按順時針方向旋轉(zhuǎn)（0180），在旋轉(zhuǎn)過程中，b的對應(yīng)點為b1，e的對應(yīng)點為e1，設(shè)直線b1e1與直線b

8、e交于點p、與直線cb交于點q是否存在這樣的，使bpq為等腰三角形？若存在，求出的度數(shù)；若不存在，請說明理由xqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawg

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