《電路分析基礎》習題參考答案

1、電路分析基礎各章習題參考答案第 1 章 習題參考答案1- 1(1) 50W ; (2) 300 V、25V, 200V、75 V ;(3)巳=12.5 Q Ra=100Q, R4=37.5 Q1- 2VA=8.5V， Vm=8.5V， VB=0.5V， VC=-12V， VD=-19V， VI=21.5V， UAB=8V， UBC=12.5，UDA=-27.5V1- 3U=204 V, E=205 V1- 4(1) VA=100V, VB=99V, VC=97V, VD=7V, VE=5V, VF=1V, UAF=99V, UCE=92V,UBE=94V, UBF=98V, UCA=-3 V；

2、 (2) VC=90V, VB=92V, VA=93V, VE=-2V, VF=-6V, VG=-7V, UAF=99V, UCE=92V, UBE=94V, UBF=98V , UCA=-3 V1- 5R=806.7 Q, I=0.27A1- 6I=4A,I1=11A, I2=19A1- 7(a) U=6V, (b) U=24 V, (c) R=5Q, (d) I=23.5A1- 8(1) i6=-1A ; (2) U4=10V , U6=3 V ;(3) Pi =-2W 發(fā)出，P2 =6W 吸收，P3 =16W 吸收，P4 =-10W 發(fā)出，P5 =-7W 發(fā)出， P6 =-3W 發(fā)出1-

3、 9 I=1A, US=134V, R=7.8Q1- 10 S 斷開：Uab=-4.8V , Uao =-12V , Ubo=-7.2V ; S 閉合：12 V , 12 V, 0 V1- 12 UAB=11V， I2=0.5A，I3=4.5A， R3=2.4Q1- 13 R1=19.88k Q，R2=20 kQ1-14 RP1=11.11 Q，RP2=100Q第 2 章 習題參考答案2- 12.4 Q，5A2- 2(1) 4V，2V，1V； (2) 40mA ，20mA，10mA2- 31.5 Q，2A，1/3A2-46Q， 36Q2- 5 2A， 1A2- 6 1A2- 7 2A2- 81

4、0A2- 9I1=1.4A，I2=1.6A，I3=0.2A2- 10 I1=0A，I2=-3A，P1=0W，P2=-18W2- 11 I1 =-1A，I2=-2A，E3=10V2- 12 I1 =6A，I2=-3A，I3=3A2- 13 I1 =2A，I2=1A，I3=1A，I4 =2A，I5=1A2-14 URL=30V ，I1 =2.5A ，I 2=-35A，IL=7.5A2-15 Uab=6V，I1=1.5A，I2=-1A，I3=0.5A2-16 Ii =6A, l2=-3A , l3=3A2-17 Ii =4/5A , l2=-3/4A , I 3=2A , “=31/20A , l5

5、=-11/4A2-18 l1 =0.5A , l2=-0.25A2-19 l3=1A2-20 l5=-1A2-21(1) l5=0A , Uab=OV ; (2) l5=1A , Uab=11V。2-22 Il=2A2-23 l s=35/3A , Ro=2 Q2-2418Q, -2Q, 12Q2-25 U = 5V2-26 I=1A2-27 U = 5V2-28 I=1A2-2910V, 180 Q2- 30 U0=9V, R0=6V, U=15V第3章習題參考答案3- 150Hz, 314rad/s, 0.02s, 141V, 100V , 1203- 2200V, 141.4V3- 3u

6、=14.1sin (314t-60 )V3- 4(1) J1-麗2= 120, (2)獻=-90 )收=-210 3-53- 6(1) i1=14.1 si n (cot 50)A; (2) U2=300 sin ( 3 60)V3- 8(1) R; (2) L; C; L3- 9i=2.82 sin ( o 30A , Q=19.88 var3- 10 u=44.9sin (314t 135) V, Q=3.18 var3- 11(1) I=20A ; (2) P=4.4kW3- 12 I=1.4A, l =1.430 A ; Q=308 var, P=0W3- 13I=9.67A ; l

7、=9.67/150 A ；Q=2127.4 var, P=0W; lc=0A3- 14 I=2A ; C=20.3 疔；Il = 0.25A, lc= 16A第4章習題參考答案4- 1(a) Z =536.87 驗,Y =0.2 乂 -36.87 s ； (b) Z = 2.5 2 45, Y =0.2 7236.87 5S4- 2Y=(0.06-j0.08) S , R=16.67 Q L=0.04 Q4-3 U S =111.34 . 59.53 V4-4 I =236. 874-5 Z =8 6 . .3 17 91】I =1.16 . -79.99 A , U R =17.38. -7

8、9.99 V , U L =145 10.01 V ,U C =46.4169.99 V4-64-74-84-94-104-114-124-134-144-154-16第55-35-45-55-65-75-95-105-115-125-135-14第66-16-36-46-56-66-76-86-96-106-116-13丫 -0.32 51.34 S , U =6.25/_51.34 V , IR =1.25 /51.34 A , I L =0.31 / _141.34 A , IC -1.88 . 38.66 AI -10 J245 A , U S =100 . 90 V 30V ; (b

9、) 2.24A ; (c) 14.49V 10V ; (b) 10A ; (c) 10VUs=15.65VX1=10 Q, X2=20 Q, X3=30 Q1u 2 1，” 0RCU1 3I1=5A, I2=4AI=(2+j)A , s =(40-j20)V Af0=649.7kHz , p=1224.7 Q Q=40.82; I=0.833 A Ur=25 叮，UL=Uc=1.02mVw0=10kHz, p=0.02 Q, Q=250; U=5V , Ir=1A,Il=Ic=250A章習題參考答案M=35.5mHW01 =1000 rad/s , 302=2236 rad/sZ1 = j31

10、.4 Q Z2=j6.28 QZr=3+7.5 QM=130mHU1=44.8VM =20mH , I1=4AU2=220V , l1=4An=1.9N2=254 匝,N3=72 匝n=10 , P2=31.25mW章習題參考答案(1) A相燈泡電壓為零，B、C相各位為220VIL = |p=4.4A，Up=220V，Ul=380V，P=2.3kW(2) Ip=7.62A，Il=13.2AA、C相各為2.2A，B相為3.8AU l=404VU A N =202 .-47 Vcos 護0.961 , Q=5.75kvarZ=33.4 三28.4 門(1) Ip=11.26A , Z=19.53

11、Z42.3 Q (2) Ip= li=11.26A , P=5.5kWUi=391VUv=160V6- 14(1) Up=220V, Ia=20A , Ib=10A , Ic=10A , In=10A ; (2) 170V , 198.3V , 198.3V ; (3) 0V ,380V, 380V, 10 3A; (4) 126.7 V , 253.3V , 11.5A, 11.5A6- 15L=110mH, C=91.9mF第7章習題參考答案7- 1P=240W , Q=360var, S=375V A7- 2P=10.84W7-3iR (t) = 11.430.0789 sin( ，t

12、-7.28 )0.016 sin(2 ，t -14.8 ) 1aUR(t)-160 1.105 sin( 4-7.28 ) 0.223 sin(2 t 14.8 )V7-4 I =3.93A , U=27.6V , P=92.67WOM U mnCOL.r227-5 u2(t) sin( ，tarctan =)V , z R. L1)z2R7-7 約為 8% , (R=1 Q, L=11.4mH , L 12.33mH)7-8Rt = R2 = R - L/C7-96 =9.39 薩，C2 =75.13 薩7-10 L1=1H, L2=66.7mH7- 11C1 = 10F C2=1.25 j

13、iF第8章習題參考答案8- 6iL(0+) = 1.5mA, ul(0+) = -15V8- 7h(0+) = 4A, i2(0+) = 1A, Ul(0+) = 2V, i*g)= 3A, i?()= 0 , Ul()= 08-8i1(0+) = 3/40A , i2(0+) = 3/40A, i3(0+) = 0 , ul1(0+) = 0 , u_2(0+) = 9/4V8-9 ic(t) =2ei6tA8-10 uL(t) =6e 蟲V8-11 UC(t) =10(1-eA1*)V , iC(t) =5e106tA8-12 uC(t) =115 e 0t sin(866 60 ) V10 t10 t8-13 UL(t)=12eV, L (t) =2(1 e )A1RCt38-14 UR(t) 7se 2 V , Ur(3.) 7se V8-15(1) t= 0.1s , (2) uC(t) =10eA0tV , (3) t = 0.1s2.t8-16 uC(t) =6e 3 V8-1750t50tiC (t) =_7.5 e 一 mA , uC(t)=30e V8-183000 ti (t) -2 e - A , i (1ms)-0.1A8-19t=0.051ms8-20(1) t= 0.05s, (2) iL(0.03 )= 4.5A , (3) t=,