新高考數(shù)學(xué)二輪提升練專題11 三角函數(shù)的圖象與性質(zhì)（ω的取值范圍）（原卷版）

專題11三角函數(shù)的圖象與性質(zhì)（ω的取值范圍）三角函數(shù)的圖象與性質(zhì)一直是高考的必考內(nèi)容，也是高考熱點(diǎn)內(nèi)容，在三角函數(shù)圖象中，SKIPIF1<0對(duì)整個(gè)圖象的性質(zhì)影響巨大。因此近年高考中對(duì)ω的取值范圍的考察就是高考的熱門考點(diǎn)之一，這部分考題呈現(xiàn)出綜合性較強(qiáng)，對(duì)學(xué)生的邏輯推理，直觀想象素養(yǎng)要求較高，所以對(duì)SKIPIF1<0的取值范圍的系統(tǒng)研究，找到解題的通性通法對(duì)提高學(xué)生的整體數(shù)學(xué)素養(yǎng)有巨大的幫助。一、熱點(diǎn)題型歸納題型1、與函數(shù)平移相關(guān)的ω取值范圍問題題型2、與函數(shù)單調(diào)性相關(guān)的ω取值范圍問題題型3、與函數(shù)零點(diǎn)相關(guān)的ω取值范圍問題題型4、與函數(shù)最值相關(guān)的ω取值范圍問題題型5、與函數(shù)極值相關(guān)的ω取值范圍問題題型6、與函數(shù)對(duì)稱性相關(guān)的ω取值范圍問題題型7、與零點(diǎn)、單調(diào)性、對(duì)稱性等相關(guān)的綜合性問題二、最新模考題組練三、十年高考真題練【題型1】與函數(shù)平移相關(guān)的ω取值范圍問題【解題技巧】1、平移后與原圖象重合：1）平移長(zhǎng)度即為原函數(shù)周期的整倍數(shù)；2）平移前的函數(shù)SKIPIF1<0=平移后的函數(shù)SKIPIF1<0.2、平移后與新圖象重合：平移后的函數(shù)SKIPIF1<0=新的函數(shù)SKIPIF1<0.3、平移后的函數(shù)與原圖象關(guān)于SKIPIF1<0軸對(duì)稱：平移后的函數(shù)為偶函數(shù)；4、平移后的函數(shù)與原函數(shù)關(guān)于SKIPIF1<0軸對(duì)稱：平移前的函數(shù)SKIPIF1<0=平移后的函數(shù)-SKIPIF1<0；5、平移后過定點(diǎn)：將定點(diǎn)坐標(biāo)代入平移后的函數(shù)中。【典例分析】1.（2022.遼寧高三模擬）已知函數(shù)SKIPIF1<0，將SKIPIF1<0的圖像向右平移SKIPIF1<0個(gè)單位長(zhǎng)度后，若所得圖像與原圖像重合，則SKIPIF1<0的最小值等于（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<02．（2022·全國(guó)·統(tǒng)考高考真題（甲））將函數(shù)SKIPIF1<0的圖像向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到曲線C，若C關(guān)于y軸對(duì)稱，則SKIPIF1<0的最小值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·河南·模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0的最小正周期為SKIPIF1<0，若SKIPIF1<0，把SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到奇函數(shù)SKIPIF1<0的圖象，則SKIPIF1<0（

）A．SKIPIF1<0 B．2 C．SKIPIF1<0 D．SKIPIF1<0【變式演練】1.（2022.綿陽(yáng)市高三校考期中）將函數(shù)SKIPIF1<0（SKIPIF1<0）的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，所得圖象經(jīng)過點(diǎn)SKIPIF1<0，則SKIPIF1<0的最小值是（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<02.（2022.江西高三期末）若將函數(shù)SKIPIF1<0的圖像向右平移SKIPIF1<0個(gè)單位長(zhǎng)度后，與函數(shù)SKIPIF1<0的圖像重合，則SKIPIF1<0的最小值為（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<03．（2022·北京·人大附中校考模擬預(yù)測(cè)）將函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到函數(shù)SKIPIF1<0的圖象，則SKIPIF1<0______；若SKIPIF1<0為偶函數(shù)，則SKIPIF1<0的最小值是______.【題型2】與函數(shù)單調(diào)性相關(guān)的ω取值范圍問題【解題技巧】已知函數(shù)y=Asin(ωx+φ)在給定區(qū)間上的單調(diào)性，求ω的取值范圍已知函數(shù)y=Asin(ωx+φ)(A>0,ω>0)，在[x1,1）根據(jù)區(qū)間[x1,x22）以單調(diào)遞增為例，利用ωx1+φ,ω3）結(jié)合第一步求出的ω的范圍對(duì)k進(jìn)行賦值，從而求出ω（不含參數(shù)）的取值范圍.【典例分析】1．（2022·湖南·長(zhǎng)沙模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，若SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞減，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·河南·高三專題練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，則SKIPIF1<0的取值范圍為________.3．（2022·河北張家口·高三期末）已知函數(shù)SKIPIF1<0，SKIPIF1<0且函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，則SKIPIF1<0的最大值為___________.【變式演練】1.（2022·河南·汝州市模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02.（2022·廣西·高三專題練習(xí)）將函數(shù)SKIPIF1<0圖象上所有點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0倍SKIPIF1<0縱坐標(biāo)不變SKIPIF1<0，再向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，若SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022秋·陜西西安·高三?？茧A段練習(xí)）將函數(shù)SKIPIF1<0的圖像向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后，得到的圖像關(guān)于SKIPIF1<0軸對(duì)稱，且函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則函數(shù)SKIPIF1<0的最小正周期為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【題型3】與函數(shù)零點(diǎn)相關(guān)的ω取值范圍問題【解題技巧】已知三角函數(shù)的零點(diǎn)個(gè)數(shù)問題求ω的取值范圍對(duì)于區(qū)間長(zhǎng)度為定值的動(dòng)區(qū)間，若區(qū)間上至少含有k個(gè)零點(diǎn)，需要確定含有k個(gè)零點(diǎn)的區(qū)間長(zhǎng)度，一般和周期相關(guān)，若在在區(qū)間至多含有k個(gè)零點(diǎn)，需要確定包含k+1個(gè)零點(diǎn)的區(qū)間長(zhǎng)度的最小值．【典例分析】1．（2022·河南·校聯(lián)考模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上恰有50個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·安徽合肥·?？寄M預(yù)測(cè)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有且僅有4個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·四川宜賓·統(tǒng)考模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，方程SKIPIF1<0在區(qū)間SKIPIF1<0有且僅有四個(gè)根，則正數(shù)SKIPIF1<0的取值范圍是_________．【變式演練】1．（2022·河南南陽(yáng)·高一期末）設(shè)函數(shù)SKIPIF1<0，已知SKIPIF1<0在SKIPIF1<0上有且僅有SKIPIF1<0個(gè)零點(diǎn)，則下列說法錯(cuò)誤的是（

）A．SKIPIF1<0的取值范圍是SKIPIF1<0B．SKIPIF1<0的圖象與直線SKIPIF1<0在SKIPIF1<0上的交點(diǎn)恰有SKIPIF1<0個(gè)C．SKIPIF1<0的圖象與直線SKIPIF1<0在SKIPIF1<0上的交點(diǎn)可能有SKIPIF1<0個(gè)D．SKIPIF1<0在SKIPIF1<0上單調(diào)遞減2．（2022·安徽·銅陵高三階段練習(xí)）已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0在SKIPIF1<0上有且只有五個(gè)實(shí)數(shù)根，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·重慶江北·?？家荒＃┖瘮?shù)SKIPIF1<0在SKIPIF1<0上有SKIPIF1<0個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【題型4】與函數(shù)最值相關(guān)的ω取值范圍問題【典例分析】1．（2022·安徽馬鞍山·三模）函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上恰有兩個(gè)最小值點(diǎn)，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·河南·寶豐縣模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的值域?yàn)镾KIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·四川成都·模擬預(yù)測(cè)（理））已知函數(shù)SKIPIF1<0，若SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上有最大值，沒有最小值，則SKIPIF1<0的最大值為______．【變式演練】1.（2022·河南·高三期中）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)不存在最小值，則SKIPIF1<0的取值范圍是（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<02.（2022·廣東·廣州市高三階段練習(xí)）已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0（SKIPIF1<0）的最大值為SKIPIF1<0，則正實(shí)數(shù)SKIPIF1<0的取值個(gè)數(shù)最多為（）A．4 B．3 C．2 D．13．（2022春?瑤海區(qū)月考）將函數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0圖象上每點(diǎn)的橫坐標(biāo)變?yōu)樵瓉淼?倍，得到函數(shù)SKIPIF1<0，函數(shù)SKIPIF1<0的部分圖象如圖所示，且SKIPIF1<0在SKIPIF1<0，SKIPIF1<0上恰有一個(gè)最大值和一個(gè)最小值（其中最大值為1，最小值為SKIPIF1<0，則SKIPIF1<0的取值范圍是SKIPIF1<0SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【題型5】與函數(shù)極值相關(guān)的ω取值范圍問題【典例分析】1．（2022·湖北武漢·統(tǒng)考模擬預(yù)測(cè)）已知偶函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0）在SKIPIF1<0上恰有2個(gè)極大值點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<02．（2022·陜西咸陽(yáng)·統(tǒng)考一模）已知函數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0向右平移SKIPIF1<0個(gè)單位長(zhǎng)度后的圖象與原函數(shù)圖象重合，SKIPIF1<0的極大值與極小值的差大于15，則a的最小值為（

）A．6 B．7.5 C．12 D．183．（2022·青?！ばＢ?lián)考模擬預(yù)測(cè)）若SKIPIF1<0，SKIPIF1<0分別是函數(shù)SKIPIF1<0的零點(diǎn)和極值點(diǎn)，且在區(qū)間SKIPIF1<0上，函數(shù)SKIPIF1<0存在唯一的極大值點(diǎn)SKIPIF1<0，使得SKIPIF1<0，則下列數(shù)值中，SKIPIF1<0的可能取值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【變式演練】1．（2022·遼寧丹東·統(tǒng)考二模）關(guān)于函數(shù)SKIPIF1<0，有下述四個(gè)結(jié)論：①若SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞增，則SKIPIF1<0.②若SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞減，則SKIPIF1<0.③若SKIPIF1<0在SKIPIF1<0內(nèi)有且僅有一個(gè)極大值點(diǎn)，則SKIPIF1<0.④若SKIPIF1<0在SKIPIF1<0內(nèi)有且僅有一個(gè)極小值點(diǎn)，則SKIPIF1<0.其中所有正確結(jié)論的序號(hào)是（

）A．①③ B．②③ C．①④ D．③④2．（2022·全國(guó)·高三專題練習(xí)）若函數(shù)SKIPIF1<0（SKIPIF1<0）在SKIPIF1<0上單調(diào)，且在SKIPIF1<0上存在極值點(diǎn)，則ω的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·安徽·安慶高三階段練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0不存在極值點(diǎn)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<0【題型6】與函數(shù)對(duì)稱性相關(guān)的ω取值范圍問題【解題技巧】已知一條對(duì)稱軸和一個(gè)對(duì)稱中心，由于對(duì)稱軸和對(duì)稱中心的水平距離為SKIPIF1<0，則SKIPIF1<0．【典例分析】1．（2022·四川綿陽(yáng)·?？寄M預(yù)測(cè)）若存在實(shí)數(shù)SKIPIF1<0，使得函數(shù)SKIPIF1<0的圖象的一個(gè)對(duì)稱中心為SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·重慶·高三專題練習(xí)）已知函數(shù)SKIPIF1<0SKIPIF1<0在區(qū)間SKIPIF1<0上有且僅有4條對(duì)稱軸，給出下列四個(gè)結(jié)論：①SKIPIF1<0在區(qū)間SKIPIF1<0上有且僅有3個(gè)不同的零點(diǎn)；②SKIPIF1<0的最小正周期可能是SKIPIF1<0；③SKIPIF1<0的取值范圍是SKIPIF1<0；④SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增．其中所有正確結(jié)論的序號(hào)是（

）A．①④ B．②③ C．②④ D．②③④【變式演練】1．（2022·四川遂寧·校考模擬預(yù)測(cè)）將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)周期后，所得圖象恰有SKIPIF1<0個(gè)對(duì)稱中心在區(qū)間SKIPIF1<0內(nèi)，則SKIPIF1<0的取值范圍為______.2.（2022·福建龍巖·模擬預(yù)測(cè)）若存在唯一的實(shí)數(shù)SKIPIF1<0，使得曲線SKIPIF1<0關(guān)于直線SKIPIF1<0對(duì)稱，則SKIPIF1<0的取值范圍是（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<03.（2022·山東·模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，在SKIPIF1<0上恰有3條對(duì)稱軸，3個(gè)對(duì)稱中心，則SKIPIF1<0的取值范圍是（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<0【題型7】與零點(diǎn)、單調(diào)性、對(duì)稱性等相關(guān)的綜合性問題【典例分析】1．（2022·新疆·統(tǒng)考一模）已知函數(shù)SKIPIF1<0在SKIPIF1<0上是增函數(shù)，且在SKIPIF1<0上恰有一個(gè)極大值點(diǎn)與一個(gè)極小值點(diǎn)，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022?成都高三期末）已知SKIPIF1<0，SKIPIF1<0，在函數(shù)SKIPIF1<0，SKIPIF1<0的圖象的交點(diǎn)中，相鄰兩個(gè)交點(diǎn)的橫坐標(biāo)之差的絕對(duì)值為SKIPIF1<0，當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，函數(shù)SKIPIF1<0的圖象恒在SKIPIF1<0軸的上方，則SKIPIF1<0的取值范圍是SKIPIF1<0SKIPIF1<0A．SKIPIF1<0，SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·陜西西安·二模（理））已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)為SKIPIF1<0．其圖像的一條對(duì)稱軸為直線SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上單調(diào)，則SKIPIF1<0的最大值為（

）A．2 B．6 C．10 D．14【變式演練】1．（2022·貴州貴陽(yáng)·模擬預(yù)測(cè)（理））若函數(shù)SKIPIF1<0在SKIPIF1<0上有且僅有3個(gè)零點(diǎn)和2個(gè)極小值點(diǎn)，則SKIPIF1<0的取值范圍為______．2．（2022秋?溫州期末）若函數(shù)SKIPIF1<0能夠在某個(gè)長(zhǎng)度為3的閉區(qū)間上至少三次出現(xiàn)最大值3，且在SKIPIF1<0上是單調(diào)函數(shù)，則整數(shù)SKIPIF1<0的值是SKIPIF1<0SKIPIF1<0A．4 B．5 C．6 D．73．（2022?浙江模擬）已知函數(shù)SKIPIF1<0，SKIPIF1<0在SKIPIF1<0，SKIPIF1<0上單調(diào)，其圖象經(jīng)過點(diǎn)SKIPIF1<0，SKIPIF1<0，且有一條對(duì)稱軸為直線SKIPIF1<0，則SKIPIF1<0的最大值是．【方法總結(jié)】求ω取值范圍的基本解題思路1、依托于三角函數(shù)的周期性：因?yàn)閒(x)=Asin(ωx+φ)的最小正周期是T=2πω，所以ω=2π2、利用三角函數(shù)的對(duì)稱性（1）三角函數(shù)兩條相鄰對(duì)稱軸或兩個(gè)相鄰對(duì)稱中心之間的“水平間隔”為T2，相鄰的對(duì)稱軸和對(duì)稱中心之間的“水平間隔”為T4，也就是說，我們可以根據(jù)三角函數(shù)的對(duì)稱性來研究其周期性，進(jìn)而可以研究（2）三角函數(shù)的對(duì)稱軸比經(jīng)過圖象的最高點(diǎn)或最低點(diǎn)，函數(shù)的對(duì)稱中心就是其圖象與x軸的交點(diǎn)（零點(diǎn)），也就是說我們可以利用函數(shù)的最值、零點(diǎn)之間的“差距”來確定其周期，進(jìn)而可以確定ω的取值.3、結(jié)合三角函數(shù)的單調(diào)性函數(shù)fx=Asin(ωx+φ)的每一“完整”單調(diào)區(qū)間的長(zhǎng)度（即兩相鄰對(duì)稱軸的間距）恰好等于T2，據(jù)此可用來求ω1．（2022·四川成都·雙流中學(xué)校考模擬預(yù)測(cè)）設(shè)SKIPIF1<0，若函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后與函數(shù)SKIPIF1<0的圖象重合，則SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·四川·校聯(lián)考模擬預(yù)測(cè)）將函數(shù)SKIPIF1<0圖象上所有點(diǎn)的橫坐標(biāo)伸長(zhǎng)到原來的2倍，再向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，若SKIPIF1<0為奇函數(shù)，則ω的最小值為（

）A．4 B．3 C．2 D．13．（2022·內(nèi)蒙古赤峰·模擬預(yù)測(cè)）函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到函數(shù)SKIPIF1<0的圖象，SKIPIF1<0的零點(diǎn)到SKIPIF1<0軸的最近距離小于SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<04．（2022·陜西榆林·三模（理））已知SKIPIF1<0，函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，且對(duì)任意SKIPIF1<0，都有SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·廣東·三模）已知函數(shù)SKIPIF1<0，且f（x）在[0，SKIPIF1<0]有且僅有3個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍是（

）A．[SKIPIF1<0，SKIPIF1<0） B．[SKIPIF1<0，SKIPIF1<0） C．[SKIPIF1<0，SKIPIF1<0） D．[SKIPIF1<0，SKIPIF1<0）6．（2022·山東省濰坊高三開學(xué)考試）函數(shù)SKIPIF1<0在SKIPIF1<0有且僅有3個(gè)零點(diǎn)，則下列說法正確的是（

）A．在SKIPIF1<0不存在SKIPIF1<0，SKIPIF1<0使得SKIPIF1<0B．函數(shù)SKIPIF1<0在SKIPIF1<0僅有1個(gè)最大值點(diǎn)C．函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)進(jìn)增D．實(shí)數(shù)SKIPIF1<0的取值范圍是SKIPIF1<07．（2022·河南·校聯(lián)考模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0的圖象與直線SKIPIF1<0有兩個(gè)相鄰的交點(diǎn)P，Q，SKIPIF1<0的圖象在P，Q之間有一個(gè)極大值點(diǎn)A，若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2022·重慶八中高三階段練習(xí)）函數(shù)SKIPIF1<0在SKIPIF1<0上的值域是SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．（2022·陜西·武功縣高三階段練習(xí)）函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)恰有兩個(gè)最小值點(diǎn)，則SKIPIF1<0的范圍是（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<010.（2022?儋州高三期中）將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，向下平移SKIPIF1<0個(gè)單位長(zhǎng)度后，得到SKIPIF1<0的圖象，如果對(duì)于區(qū)間SKIPIF1<0上任意的實(shí)數(shù)SKIPIF1<0，都有SKIPIF1<0，則正數(shù)SKIPIF1<0的最大值為（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<011．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上無極值，則SKIPIF1<0的取值范圍是（

）A．（0，5]B．（0，5）C．（0，SKIPIF1<0）D．（0，SKIPIF1<0]12．（2022·湖北武漢·模擬預(yù)測(cè)）已知偶函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0）在SKIPIF1<0上恰有2個(gè)極大值點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<013.若存在實(shí)數(shù)SKIPIF1<0，使得函數(shù)SKIPIF1<0的圖象的一個(gè)對(duì)稱中心為SKIPIF1<0，則SKIPIF1<0的取值范圍為（）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<014．（2022·安徽·高三階段練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間[0，SKIPIF1<0]上有且僅有3條對(duì)稱軸，則SKIPIF1<0的取值范圍是（

）A．（SKIPIF1<0，SKIPIF1<0] B．（SKIPIF1<0，SKIPIF1<0] C．[SKIPIF1<0，SKIPIF1<0） D．[SKIPIF1<0，SKIPIF1<0）15．（2022·遼寧·大連高三期中）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上是增函數(shù)，若函數(shù)SKIPIF1<0在SKIPIF1<0上的圖像與直線SKIPIF1<0有且僅有一個(gè)交點(diǎn)，則SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．116．（2022春?湖北期中）已知SKIPIF1<0．給出下列判斷：①若SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0；②若SKIPIF1<0在SKIPIF1<0，SKIPIF1<0上恰有9個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍為SKIPIF1<0；③存在SKIPIF1<0，使得SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到的圖象關(guān)于SKIPIF1<0軸對(duì)稱；④若SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0的取值范圍為SKIPIF1<0．其中，判斷正確的個(gè)數(shù)為SKIPIF1<0SKIPIF1<0A．1 B．2 C．3 D．417.（2022?福建高三模擬）已知函數(shù)f（x）=cos（ωx+φ）（ω＞0，|φ|≤SKIPIF1