新高考數(shù)學一輪復習分層提升練習第07練 函數(shù)的基本性質(zhì)Ⅰ-單調(diào)性與最值（原卷版）

第07講函數(shù)的基本性質(zhì)Ⅰ-單調(diào)性與最值（精練）【A組

】一、單選題1．在下列四個函數(shù)中，在SKIPIF1<0上為增函數(shù)的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．設函數(shù)SKIPIF1<0，若SKIPIF1<0，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．已知SKIPIF1<0，則“SKIPIF1<0”是“函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞減”的（

）A．充分不必要條件 B．必要不充分條件C．充要條件 D．既不充分也不必要條件5．若對任意的SKIPIF1<0，SKIPIF1<0恒成立，則m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．已知函數(shù)SKIPIF1<0的最小值為a，則函數(shù)SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．若偶函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，且SKIPIF1<0，則不等式SKIPIF1<0解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0二、多選題9．已知函數(shù)SKIPIF1<0則下列結(jié)論正確的是（

）A．f(x)的定義域是SKIPIF1<0，值域是SKIPIF1<0B．f(x)的單調(diào)減區(qū)間是(1，3)C．f(x)的定義域是SKIPIF1<0，值域是SKIPIF1<0D．f(x)的單調(diào)增區(qū)間是(-∞，1)10．若二次函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上是增函數(shù)，則a可以是（

）A．SKIPIF1<0 B．0 C．1 D．211．已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0的圖象是連續(xù)不斷的，且滿足以下條件：①SKIPIF1<0，SKIPIF1<0；②SKIPIF1<0，當SKIPIF1<0時，SKIPIF1<0；③SKIPIF1<0.則下列選項成立的是（

）A．SKIPIF1<0B．若SKIPIF1<0，則SKIPIF1<0或SKIPIF1<0C．若SKIPIF1<0，則SKIPIF1<0D．SKIPIF1<0，使得SKIPIF1<0三、填空題12．函數(shù)SKIPIF1<0在SKIPIF1<0上的值域為________．13．函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間為__．14．定義在SKIPIF1<0上的函數(shù)SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則m的取值范圍是______．15．若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，則實數(shù)a的取值范圍是________.四、解答題16．函數(shù)SKIPIF1<0，SKIPIF1<0(1)判斷單調(diào)性并證明，(2)求最大值和最小值17．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，當SKIPIF1<0時，SKIPIF1<0．(1)求SKIPIF1<0．(2)求函數(shù)SKIPIF1<0的解析式．(3)若SKIPIF1<0，求實數(shù)a的取值范圍．【B組

】一、單選題1．若1≤x≤2時，不等式SKIPIF1<0恒成立，則實數(shù)m的最小值為（

）A．0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間是（）A．SKIPIF1<0 B．[2，＋∞）C．SKIPIF1<0 D．SKIPIF1<03．定義在R上的奇函數(shù)SKIPIF1<0，滿足SKIPIF1<0，且在SKIPIF1<0上單調(diào)遞減，則不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<04．函數(shù)SKIPIF1<0，SKIPIF1<0，對SKIPIF1<0，SKIPIF1<0，使SKIPIF1<0成立，則a的取值范圍是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題5．設SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，且SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，SKIPIF1<0，則（

）A．SKIPIF1<0在SKIPIF1<0上單調(diào)遞減B．SKIPIF1<0C．不等式SKIPIF1<0的解集為SKIPIF1<0D．SKIPIF1<0的圖象與SKIPIF1<0軸只有2個交點6．已知函數(shù)SKIPIF1<0，以下結(jié)論正確的是（

）A．SKIPIF1<0為奇函數(shù)B．對任意的SKIPIF1<0都有SKIPIF1<0C．對任意的SKIPIF1<0都有SKIPIF1<0D．SKIPIF1<0的值域是SKIPIF1<0三、填空題7．因函數(shù)SKIPIF1<0的圖像形狀像對勾，我們稱形如“SKIPIF1<0”的函數(shù)為“對勾函數(shù)”．該函數(shù)具有性質(zhì)：在SKIPIF1<0上是減函數(shù)，在SKIPIF1<0上是增函數(shù)，若對勾函數(shù)SKIPIF1<0對于任意的SKIPIF1<0，都有SKIPIF1<0，則實數(shù)t的最大值為__________．四、解答題9．已知函數(shù)SKIPIF1<0，其中SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的奇偶性：(2)若函數(shù)在區(qū)間SKIPIF1<0上是嚴格增函數(shù)，求實數(shù)a的取值范圍.10．已知定義域為R的函數(shù)SKIPIF1<0是奇函數(shù)．(1)求a的值；(2)判斷SKIPIF1<0的單調(diào)性，并證明；(3)若關于m的不等式SKIPIF1<0在SKIPIF1<0上有解，求實數(shù)t的取值范圍．【C組

在創(chuàng)新中考查思維】一、單選題1．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，若SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，都有SKIPIF1<0成立，則不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知奇函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，對SKIPIF1<0，關于SKIPIF1<0的不等式SKIPIF1<0在SKIPIF1<0上有解，則實數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<03．函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，且在SKIPIF1<0上是增函數(shù)，若對任意SKIPIF1<0，均有SKIPIF1<0，則實數(shù)t的最大值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．3二、多選題4．已知SKIPIF1<0是定義在區(qū)間SKIPIF1<0上的奇函數(shù)，且SKIPIF1<0，若SKIPIF1<0時，有SKIPIF1<0．若SKIPIF1<0對所有SKIPIF1<0恒成立，則實數(shù)m的取值范圍可能是（

）A．SKIPIF1<0 B．SKIPIF1<0