THUSSAT中學(xué)生標(biāo)準(zhǔn)學(xué)術(shù)能力2023年11月診斷性測試答案

一項(xiàng)是符合題目要求的.12345678CABBABDD項(xiàng)符合題目要求．全部選對的得5分，部分選對但不全的得2分，有錯選的得0分.9ACABACD三、填空題：本題共4小題，每小題5分472四、解答題：本題共6小題，共70分．解答應(yīng)寫出文字說明sinCcosBsinCcosBbsinCcosB2sinsinCcosBsinB,12cosB=12,得B=············································································322222)，SESFSB=SC且==λ,：SE=SF·····················································6SBSC則AE=AF···································故ΔSEF與ΔAEF都是等腰三角形，取EF的中點(diǎn)G，則SG與AG均垂直于EF，Gλa,λa,(1?λ)h,SG=λa,λa,?λh,AG=λa,λa,(1?λ)h，平面AEF⊥平面SBC等價于SG⊥AG·················10分a2λ24λ=························12分nn:{an?2}是公比為的等比數(shù)列·······························································2分(1)n?1(1)n?1an「1(1)2(1)n?1]「(1)n]2n···························································(1)n(1)n1(1)n(1)n1:n取最小值14·················4{Cn}中最大項(xiàng)為C2,C3····································································}中最小值為λ2,:(bm)min?(Cn)max>，即λ2?λ>，:λ>·················································12分2012分）XP························································································································································2112分）=2a,:4a=4,:a=2·······························2:b=1，2(12)22222設(shè)Bx22④·····················································2④·····················································2A,F22x2: 2: 22222m:k<2，:m=:k<2，2:SΔF1BC=2BCd=2kx1?x2················································44k244k2?2x|2|4k2|=22224212242122221SF1BC···································································10分22設(shè)2k2設(shè)2k22t2t2tt66 6646644·····························································································2212分）由題意知又又:1<x2只需證x22·································((1))(2)(2)2)2)2)((1))