版權(quán)說(shuō)明:本文檔由用戶(hù)提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
石灰石/石膏濕法脫硫,,,,,,,,,,
1,校核煤質(zhì),,,,,,,,,
,Car=,64,%,,Nar=,1,%,,,
,Har=,5,%,,War=,8,%,,,
,Oar=,6.6,%,,Aar=,16,%,,,
,Sar=,0.4,%,,Var=,15,%,,,
,換算成干燥無(wú)灰基的元素含量,,,,,,,,,
,Cdaf=,84.21052632,%,取,Cdaf=,80,%,,,
,Hdaf=,6.578947368,%,,Hdaf=,6.1,%,,,
,Odaf=,8.684210526,%,,Odaf=,11.8,%,,,
,Sdaf=,0.526315789,%,,Sdaf=,1.6,%,,,
,,,,,,,,,,,
,"Qdaf,net=",339Cdaf+1030Hdaf-109(Odaf-Sdaf)=,,,,34.43447368,MJ/kg,,,
,,,,取,"Qdaf,net=",34.4,MJ/kg,,,
,換算成低位收到基發(fā)熱量,,,,,,,,,
,"Qar,net=","Qdaf,net*76/100=",,,,26.144,MJ/kg,,,
,,,,取,"Qar,net=",25.8,MJ/kg,,,
,,,,,,,,,,,
,全廠效率為,,38,%,含硫量為,0.4,%,,,
,燃燒計(jì)算,,,,,,,,,
,mcoal=,,,,,,,,,
,,,,,,,,,,,
,mcoal=,0.073439412,=,73.4,t/h,,,,,
2,標(biāo)準(zhǔn)狀況下理論空氣量,,,,,,,,,
,Qa’=,4.76*(1.867CY+5.56HY+0.7SY-0.7OY)=,,,,6.8043248,m3/kg,,,
,,,,取,Qa’=,6.8,m3/kg,,,
3,標(biāo)準(zhǔn)狀況下理論煙氣量(空氣含濕量為12.93g/m3),,,,,,,,,
,Qs’=,1.867(CY+0.375SY)+11.2HY+1.24WY+0.016Qa'+0.79Qa'+0.8NY,,,,,,,,
,,,,,=,7.3456805,m3/kg,,,
,,,,取,Qs’=,7.35,m3/kg,,,
4,標(biāo)準(zhǔn)狀況下實(shí)際煙氣量,,,,,,,,,
,空氣過(guò)剩系數(shù),,α=,1.3,,,,,,
,Qs=,Qs’+1.016(α-1)Qa',,,=,9.42264,m3/kg,,,
,,,,取,Qs=,9.4,m3/kg,,,
5,標(biāo)準(zhǔn)狀況下煙氣含塵濃度,,,,,,,,,
,排煙中飛灰占煤中不可燃組分的比例,,,,dsh=,16,%,,,
,C=,,=,0.002723404,kg/m3,,,,,
,,取,C=,0.002723,kg/m3,,,,,
6,標(biāo)準(zhǔn)狀況下煙氣中濃度,,,,,,,,,
,CSO2=,,=,851.0638298,mg/m3,,,,,
,,取,CSO2=,852,mg/m3,,,,,
,SO2濃度的校準(zhǔn),,,基準(zhǔn)氧含量為,,6,%,,,
,"CSO2,at4.6%=",,,,,,,,,
,"CSO2,at4.6%=",931.52,mg/m3,取,"CSO2,at4.6%=",932,mg/m3,,,
,二氧化硫排放標(biāo)準(zhǔn)(標(biāo)準(zhǔn)狀態(tài)下):,,,,200,mg/m3,,,,
,,,,"CSO2,at6%=",218.6666667,mg/m3,,,,
,,,取,"CSO2,at6%=",219,mg/m3,,,,
,除硫效率為,,76.5258216,%,,,,,,
,,取,77,%,,,,,,
7,標(biāo)準(zhǔn)狀況下SO2燃燒產(chǎn)量,,,,,,,,,
,mSO2=,,,=,0.5872,t/h,,,,
,,,取,mSO2=,0.59,t/h,,,,
,SO2的脫除量,,,,,,,,,
,"mSO2,removal=",,0.4543,t/h,,,,,,
,取,"mSO2,removal=",0.45,t/h,,,,,,
8,煙氣中水蒸氣密度,,,,,,,,,
,由理想氣體狀態(tài)方程得,,,,,,,,,
,PVwater=nwaterRT,,,,,,,,,
,,,,,,,,,,,
,,,,,,,,,,,
,,,,,,,,,,,
,ρ=,0.778501328,kg/Nm3,,,,,,,
,取,ρ=,0.78,kg/Nm3,,,,,,
9,煙氣體積流量,,,,,,,,,
,"Vfluegas,wet=mcoal.Vfluegas",,,,,,,,,
,"Vfluegas,wet=",,689960,Nm3/h,,,,,,
,取,"Vfluegas,wet=",,690000,Nm3/h,,,,,
,"Vfluegas,dry=Vfluegas,wet.(1-0.083)=",,,,632730,Nm3/h,,,,
,取,"Vfluegas,dry=",,633000,Nm3/h,,,,,
,Vwater=,57000,Nm3/h,,,,,,,
10,煙氣質(zhì)量流量,,,,,,,,,
,"mfluegas,dry=Vdry.ρfluegas,dry",,,,,,,,,
,煙氣密度(標(biāo)準(zhǔn)狀態(tài)):ρ=,,,1.34,kg/m3,,,,,
,"mfluegas,dry=",,848220,kg/h,,,,,,
,取,"mfluegas,dry=",,848000,kg/h,,,,,
,"mfluegas,wet=mfluegas,dry+mwater",,,,,,,,,
,mwater=,44460,kg/h,,,,,,,
,"mfluegas,wet=",,892460,kg/h,,,,,,
,取,"mfluegas,wet=",,892000,kg/h,,,,,
11,吸收塔飽和溫度計(jì)算,,,,,,,,,
,假定電除塵器出口溫度為,,,135,°C,,,,,
,GGH出口溫度為,,,108,°C,,,,,
,干煙氣水含量,,,,,,,,,
,,,,,,,,,,,
,x1=,0.052429245,,,,,,,,
,取,x1=,0.052,,,,,,,
,"在h,x圖上,108°C和0.052的交點(diǎn)的焓h=",,,,248,kJ/kg,,,,
,沿等焓線到飽和線可得到飽和溫度T,,,,,,,,,
,T=,48,°C,,x2=,0.077,,,,
,"mwater,vapourised=(xwater,outlet-xwater,inlet).mfluegas,dry",,,,,,,,,
,"mwater,vapourised=",,21200,kg/h,,,,,,
,,,,=,27179.48718,Nm3/h,,,,
,,取,"Vwater,saturation=",,27000,Nm3/h,,,,
12,吸收塔出口凈煙氣的計(jì)算,,,,,,,,,
,"Vwater,vapourised,cleangas=Vwater+Vwater,saturation",,,,,,,,,
,"Vwater,vapourised,cleangas=",,84000,Nm3/h,,,,,,
,"Vcleangas,wet=Vinlet,dry+Vwater,vapourised,cleangas",,,,,,,,,
,"Vcleangas,wet=",,717000,Nm3/h,,,,,,
13,吸收塔煙氣計(jì)算結(jié)果匯總,,,,,,,,,
,13.1吸收塔入口:,,,,,,,,,
,Vwet=,690000,Nm3/h,,,,,,,
,Vdry=,633000,Nm3/h,,,,,,,
,mwet=,892000,kg/h,,,,,,,
,mdry=,848000,kg/h,,,,,,,
,Vwater,57000,Nm3/h,,,,,,,
,mwatewr,44460,kg/h,,,,,,,
,T1=,108,°C,,,,,,,
,O2=,6,%(dry),,,,,,,
,SO2=,852,mg/m3,,,,,,,
,"SO2,6%O2=",932,mg/m3,,,,,,,
,13.2吸收塔出口:,,,,,,,,,
,Vwet=,717000,Nm3/h,,,,,,,
,Vdry=,633000,Nm3/h,,,,,,,
,mwet=,913200,kg/h,,,,,,,
,mdry=,848000,kg/h,,,,,,,
,Vwater,84000,Nm3/h,,,,,,,
,mwatewr,65520,kg/h,,,,,,,
,T1=,48,°C,,,,,,,
,O2=,,%(dry),,,,,,,
,SO2=,200,mg/m3,,,,,,,
,"SO2,6%O2=",219,mg/m3,,,,,,,
14,廢水流量的計(jì)算,,,,,,,,,
,假定煙氣中HCl的濃度CHCl,fluegas=,,,,46,mg/Nm3,HCl的去除率為,,98,%
,廢水中Cl-含量保持,,15,g/L,,,,,,
,"mCl-=0.98.CHCl,fluegasVdry",,,,,,,,,
,mCl-=,28.53564,kg/h,,,,,,,
,取,mCl-=,28.5,kg/h,,,,,,
,,,,,,,,,,,
,mwater=,1900,kg/h,,,,,,,
15,石灰石消耗量/石膏產(chǎn)量,,,,,,,,,
,SO2+CaCO3+2H2O+1/2O2→CaSO4.2H2O+CO2,,,,,,,,,
,石灰石耗量,,,,,,,,,
,0.70984375,t/h,,取,0.7,t/h,,,,
,石膏產(chǎn)量,,,,,,,,,
,1.22093125,t/h,,取,1.2,t/h,,,,
16,工藝水消耗量,,,,,,,,,
,"mwater=mwater,vapourised+mwashwater+mcrystalwater+mgypsum,moisture",,,,,,,,,
,mwater=,23484.49612,kg/h,取,mwater=,23484,kg/h,,,
,Vmater=,23.484,m3/h,,,,,,,
17,石膏脫水(石膏密度ρgypsum=,,,2.3,kg/l,水的密度ρwater=,,1,kg/l,
,假定,,,,,,,,,
,吸收塔石膏濃度Cgypsum=,,,13,%,,,,,
,旋流器底流石膏濃度Cgypsum=,,,50,%,,,,,
,真空皮帶機(jī)石膏濃度Cgypsum=,,,90,%,,,,,
,旋流器頂流石膏濃度Cgypsum=,,,3,%,,,,,
,17.1石膏漿液密度計(jì)算,,,,,,,,,
,,,,,,,,,,,
,,,,,,,,,,,
,ρs=,1.07930549,kg/l,,,,,,,
,取,ρs=,1.079,kg/l,,,,,,
,17.2旋流器底流密度計(jì)算,,,,,,,,,
,"ρs,hydrocyclone,underflow=",,,1.393939394,kg/l,,,,,
,取,"ρs,hydrocyclone,underflow=",,,1.394,kg/l,,,,
,17.3旋流器頂流密度計(jì)算,,,,,,,,,
,"ρs,hydrocyclone,overflow=",,,1.017249005,kg/l,,,,,
,取,"ρs,hydrocyclone,overflow=",,,1.017,kg/l,,,,
,17.4脫水石膏產(chǎn)量,,,,,,,,,
,mbeltfilter=,,,=,1333.333333,kg/h,,,,
,,,取,mbeltfilter=,1330,kg/h,,,,
,"mhydrocyclone,underflow=",,,,,=,2400,kg/h,,
,"Vhydrocyclone,underflow=",,,,,=,1.721664275,m3/h,,
,,,,取,"Vhydrocyclone,underflow=",,1.72,m3/h,,
,17.5吸收塔來(lái)石膏漿液計(jì)算,,,,,,,,,
,"mfrom,absorbor=mhydrocyclone,underflow+mhydeocyclone,overfloe",,,,,,,,,
,"mfrom,absorbor.Cgypsum=mhydrocyclone,underflow.Cgypsum,underflow+mhydeocyclone,overfloe.Cgypsum,overflow",,,,,,,,,
,聯(lián)立以上方程組解得,,,,,,,,,
,"mfrom,absorbor=",,11280,kg/h,,,,,,
,"mgypsum=mfrom,absorbor.Cgypsum",,,,,,,,,
,mgypsum=,1466.4,kg/h,,取,mgypsum=,1466,kg/h,,
,"mwater=mfrom,absorbor-mgypsum=",,,9814,kg/h,,,,,
,"Vfrom,absorbor=",,,,=,10.45412419,m3/h,,,
,,,取,"Vfrom,absorbor=",,10.45,m3/h,,,
18,石灰石漿液供給,,,,,,,,,
,石灰石耗量mCaCO3=,,0.7,t/h,,,,,,
,假定石灰石漿液濃度CCaCO3=,,,30,%,,,,,
,石灰石固體密度ρCaCO3=,,,2.8,kg/l,,,,,
,18.1石灰石漿液質(zhì)量流量,,,,,,,,,
,msuspension=,,,=,2.333333333,t/h,,,,
,,取,msuspension=,,2.33,t/h,,,,
,18.2石灰石漿液密度,,,,,,,,,
,,,,,,,,,,,
,,,,,,,,,,,
,ρsuspension=,,1.238938053,kg/l,,,,,,
,取,ρsuspension=,,1.24,kg/l,,,,,
,18.3石灰石漿液體積流量,,,,,,,,,
,Vsuspension=,,,=,1.879032258,m3/h,,,,
,,,取,Vsuspension=,1.88,m3/h,,,,
19,漿液池尺寸,,,,,,,,,
,假定漿液停留時(shí)間△t=,,,2,h,,,,,
,漿液罐體積,,,,,,,,,
,Vtank=Vsuspension.△t=,,3.76,m3,,,,,,
,D=(0.89.Vtank)1/3=,,1.495750938,m,,,,,,
,取,D=,1.5,m,,,,,,
,H=1.5×D=,,2.25,m,,,,,,
20,濾池箱尺寸計(jì)算,,,,,,,,,
,"假定濾布沖洗水量mwater,beltfilter=",,,5,t/h,,,,,
,以,50,%,的石膏質(zhì)量流量作為石膏沖洗水量,,,,,,
,20.1濾液量,,,,,,,,,
,"mwater,filtrate=mwater,beltfilter+mwater,wash",,,,,,,,,
,"mwater,filtrate=",,5.6,t/h,,,,,,
,"Vwater,filtrate≈",,5.6,m3/h,,,,,,
,假定濾液箱停留時(shí)間△t=,,,1,h,,,,,
,20.2濾液箱容積,,,,,,,,,
,"Vtank=Vwater,filtrate.△t=",,,5.6,m3,,,,,
,D=(0.89.Vtank)1/3=,,1.708150023,m,,,,,,
,取,D=,1.7,m,,,,,,
,H=1.5×D=,,2.55,m,,,,,,
21,吸收塔尺寸的設(shè)計(jì),,,,,,,,,
,21.1循環(huán)漿液流量,,,,,,,,,
,煙氣流量Vwet=,,690000,Nm3/h,,,,,,
,二氧化硫濃度CSO2=,,932,mg/m3,,,,,,
,二氧化硫脫除率,,77,%,,,,,,
,假定液氣比L/G=,,12,l/Nm3,,,,,,
,吸收塔出口凈煙氣溫度T2=,,,48,°C,,,,,
,"Vwet,actual=",,,,,,,,,
,"Vwet,actual=",,842996.7051,Nm3/h,,,,,,
,取,"Vwet,actual=",,843000,Nm3/h,=,234.1666667,Nm3/s,,
,,,,取,"Vwet,actual=",,234,Nm3/s,,
,循環(huán)漿液流量,,,,,,,,,
,,,,10116,Nm3/h,,,,,
,設(shè)計(jì)噴淋塔層數(shù)為,,3,,,,,,,
,每層循環(huán)漿液流量,,,,,,,,,
,Q單循=,,3372,Nm3/h,=,0.936666667,Nm3/s,,,
,,,,取,Q單循=,0.937,Nm3/s,,,
,21.2吸收塔直徑,,,,,,,,,
,假定吸收塔煙氣流速ω=,,,3.7,m/s,,,,,
,d=,,,=,8.973505348,m,,,,
,,,取,d=,9,m,,,,
,21.3吸收塔循環(huán)區(qū)體積,,,,,,,,,
,假定循環(huán)漿液停留時(shí)間t=,,,4.3,min,,,,,
,Vabsorbersump=,,,724.98,m3,,,,,
,取,Vabsorbersump=,,725,m3,,,,,
,21.4吸收塔總高,,,,,,,,,
,漿液池位高度,,,,,,,,,
,H1=,,,11.39627988,m,,,,,
,,取,H1=,11.4,m,,,,,
,另外考慮到因注入氧化空氣引起的吸收塔漿液液位波動(dòng),漿液液位高度增加,,,,,,,0.5,m,
,取,H1=,12,m,,,,,,
,漿液液面距入口煙道高度H2,,,,,,,,,
,考慮到漿液鼓入氧化空氣和攪拌時(shí)液位有所波動(dòng),入口煙氣溫度較高、漿液溫度較低可對(duì)進(jìn)口管,,,,,,,,,
,底部有些降溫影響,加之該區(qū)間需接近料管,H2一般定位800mm~1300mm范圍為宜,此處,,,,,,,,,
,H2取,1.2,m,,,,,,,
,進(jìn)口煙道高度H3=,,4,m,,,,,,
,進(jìn)口煙道頂部距底層噴淋層高度H4=,,,,2.5,m,,,,
,噴淋層區(qū)域高度H5,,,,,,,,,
,設(shè)計(jì)噴淋層之間的間隔為,,,2,m,噴淋層數(shù),3,層,,
,H5=,4,m,,,,,,,
,除霧區(qū)高度H6=,,4,m,,,,,,
,出口煙道高度H7=,,3,m,,,,,,
,吸收塔總高H=H1+H2+H3+H4+H5+H6+H7=,,,,30.7,m,,,,
22,噴淋層設(shè)計(jì),,,,,,,,,
,單層噴淋層漿液流量Q單循=,,,3372,Nm3/h,=,937,L/s,,
,假定噴嘴流量為,,5,L/s,,,,,,
,n=,Q單循/5=,187.4,,,,,,,
,,取整為,188,,,,,,,
,假定單管可選最大直徑Dmax=,,,0.06,m,,,,,
,噴淋管內(nèi)最大流速Vmax=,,,15,m/s,,,,,
,單噴管最大流量,,,,,,,,,
,"Qmax,s=π/4.Dmax2.Vmax=",,,42.41150082,L/s,,,,,
,,取,Qmax=,42.4,L/s,,,,,
,單噴淋層主噴管數(shù),,,,,,,,,
,,,23,,,,,,,
23,除霧器沖洗覆蓋率,,,,,,,,,
,設(shè)計(jì)噴嘴數(shù)量n=,,90,噴射擴(kuò)散角α=,,90,,,,
,除霧器有效流通面積A=,,,100,m2,,,,,
,沖洗噴嘴距除霧器表面垂直距離,,,0.8,m,,,,,
,沖洗覆蓋率=,,,,,180.9557368,%,,,
,,,,,取,181,%,,,
24,煙道尺寸設(shè)計(jì),,,,,,,,,
,24.1凈煙氣煙道直徑,,,,,,,,,
,假定煙氣出口流速ω=,,18,m/s,,,,,,
,d=,,,4.068428945,m,,,,,
,,,d=,4.1,m,,,,,
,24.2原煙氣煙道直徑,,,,,,,,,
,Vactual=,286.394838,Nm3/s,,,,,,,
,取,Vactual=,286,Nm3/s,,,,,,
,d=,,=,4.497817432,m,,,,,
,,取,d=,4.5,m,,,,,
25,增壓風(fēng)機(jī)煙氣設(shè)計(jì)流量計(jì)算,,,,,,,,,
,"假定風(fēng)機(jī)入口煙氣溫度Tfan,in=",,,135,°C,,,,,
,100%BMCR工況下風(fēng)機(jī)入口處濕煙氣流量,,,,,,,,,
,"Qfan,in=",690000,Nm3/h,,,,,,,
,"Qfan,in,act=",,,,322.7529135,Nm3/s,,,,
,,,取,"Qfan,in,act=",323,Nm3/s,,,,
26,增壓風(fēng)機(jī)總壓損,,,,,,,,,
,假定吸收塔壓損,,10,mbar,GGH壓損,12,mbar,,,
,煙道壓損,7,mbar,考慮,20,%的裕量,,,,
,△Pd=,34.8,mbar,,,,,,,
,取,△Pd=,35,mbar,=,3500,Pa,,,
27,"電機(jī)功率Pf,d",,,,,,,,,
,假定風(fēng)機(jī)效率η1=,,85,%,電動(dòng)機(jī)效率ηd=,,80,%,,
,增壓風(fēng)機(jī)所需功率Pf=,,,,1303.921569,kW,,,,
,,,取,Pf=,1304,kW,
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶(hù)所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶(hù)上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶(hù)上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶(hù)因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- Windows Server網(wǎng)絡(luò)管理項(xiàng)目教程(Windows Server 2022)(微課版)3.7 DHCP 拓展案例(一)DHCP中繼代理的配置
- 高中語(yǔ)文第4課詞語(yǔ)萬(wàn)花筒第3節(jié)每年一部“新詞典”-新詞語(yǔ)課件新人教版選修語(yǔ)言文字應(yīng)用
- 信息技術(shù)(第2版)(拓展模塊)教案 拓展模塊5 5.3常用核心技術(shù)3
- 2024年江西省中考英語(yǔ)試題含解析
- 校園展美 課件 2024-2025學(xué)年人美版(2024)初中美術(shù)七年級(jí)上冊(cè)
- 高中物理第一章運(yùn)動(dòng)的描述2時(shí)間和位移課件新人教版必修
- 【中考考點(diǎn)基礎(chǔ)練】第10章 溫度與物態(tài)變化 2025年物理中考總復(fù)習(xí)(福建)(含答案)
- 2024至2030年中國(guó)圓柱石英晶體諧振器數(shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 2024至2030年中國(guó)發(fā)音板數(shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 2024至2030年中國(guó)八爪魚(yú)數(shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 高中語(yǔ)文表現(xiàn)手法之烘托、渲染、襯托、對(duì)比的明顯區(qū)別
- 泰達(dá)時(shí)代中心樓頂發(fā)光字施工方案
- LED燈具規(guī)格書(shū)中英文
- 固定資產(chǎn)與無(wú)形資產(chǎn)管理制度
- 液壓泵站使用說(shuō)明
- 論我國(guó)農(nóng)村集體土地所有制度的完善-
- SPC八大控制圖自動(dòng)生成表
- 國(guó)家電網(wǎng)公司用電信息采集系統(tǒng)運(yùn)行維護(hù)管理辦法
- 人民大學(xué)大眾汽車(chē)案例-4組
- 惠州市金山湖公園修建性詳細(xì)規(guī)劃
- 旅行社行政崗位職責(zé)
評(píng)論
0/150
提交評(píng)論