c語言程序代碼

要求在屏幕上輸出下一行信息。Thisisacprogram.程序:#include<stdio.h>intmain(){printf(“thisisacprogram.\n”);return0;}求兩個(gè)整數(shù)之和。程序：#include<stdio.h>intmain(){inta,b,sum;a=122;b=234;sum=a+b;printf(“sumis%d\n”,sum);return0;}求兩個(gè)整數(shù)之間的較大者。程序：#include<stdio.h>intmain(){intmax(intx,inty);inta,b,c;scanf("%d,%d",&a,&b);c=max(a,b);printf("max=%d\n",c);return0;}intmax(intx,inty){intz;if(x>y)z=x;elsez=y;return(z);}有人用溫度計(jì)測量出華氏發(fā)表示的溫度(如69°F),今要求把她轉(zhuǎn)換成以攝氏法表示的溫度(如20。0。公式：c=5(f-32)/9.其中f代表華氏溫度，c代表攝氏溫度。程序：#include<stdio.h>intmain(){floatf,c;f=64.0;c=(5.0/9)*(f-32);printf("f=%f\nc=%f\n",f,c);return0;}計(jì)算存款利息。有1000元，想存一年。有一下三種方法可選(1)活期：年利率為r1；(2)一年定期：年利率為r2；(3)存兩次半年定期：年利率為r3。分別計(jì)算一年后按三種方法所得到的本息和。程序：#include<stdio.h>intmain(){floatp0=1000,r1=0.0036,r2=0.0225,r3=0.0198,p1,p2,p3;p1=p0*(1+r1);p2=p0*(1+r2);p3=p0*(1+r3/2)*(1+r3/2);printf("p1=%f\np2=%f\np3=%f\n",p1,p2,p3);return0;}給定一個(gè)大寫字母，要求以小寫字母輸出。程序：#include<stdio.h>intmain(){charc1,c2;c1='A';c2=c1+32;printf(“%c\n”,c2);printf(“%d\n”,c2);return0;}給出三角形的三邊長，求三角形的面積。公式：若給定三角形的三邊長，且任意兩邊之長大于第三邊則：area二Js(s—a)(s—b)(s—c)其中s=(a+b+C)/2.程序：#include<stdio.h>#include<stdio.h>#include<stdio.h>#include<stdio.h>#include<math.h>intmain(){doublea,b,c,area;a=3.67;b=5.43;c=6.21;s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c));printf(“a=%f\tb=%f\tc=%f\n”,a,b,c);printf(“area=%f\n”,area);return0;}8.求ax2+bx+c二0方程的根。a,b,c由鍵盤輸入，設(shè)b2-4ac>0.程序：#include<stdio.h>#include<math.h>intmain(){doublea,b,c,disc,x1,x2,p,q;scanf(“%lf%lf%lf”,&a,&b,&c);disc=b*b-4*a*c;if(disc<0)printf(“Thisquestionhasnorealroots\n”);else{p=-b/(2.0*a);q=sqrt(disc)/(2.0*a);x1=p+q;x2=p-q;printf(“x1=%7.2f\nx2=%7.2f\n”,x1,x2);}return0;}9.先后輸出BOY三個(gè)字符。程序：#include<stdio.h>intmain(){chara='B',b='O',c='Y';putchar(a);putchar(b);putchar(c);putchar(‘\n');return0;}10.用三個(gè)getchar函數(shù)先后向計(jì)算機(jī)輸入BOY三個(gè)字符，然后用putchar函數(shù)輸出。程序：#include<stdio.h>intmain(){chara,b,c;a=getchar();b=getchar();c=getchar();putchar(a);putchar(b);putchar(c);putchar(‘\n');return0;}或#include<stdio.h>intmain(){putchar(getchar());putchar(getchar());putchar(getchar());putchar(‘\n');return0;}用getchar函數(shù)從鍵盤讀入一個(gè)大寫字母，把它轉(zhuǎn)換成小寫字母，然后用getchar函數(shù)輸出對應(yīng)的小寫字母。程序：#include<stdio.h>intmain(){charc1,c2;c1=getchar();c2=c1+32;putchar(c2);putchar(‘\n');return0;}輸入兩個(gè)實(shí)數(shù)，按代數(shù)值由小到大的順序輸出這兩個(gè)數(shù)(參照將兩個(gè)杯子中的水互換，必須借助第三個(gè)杯子）。程序：#include<stdio.h>intmain(){floata,b,t;scanf(“%f,%f”,&a,&b);if(a>b){t=a;a=b;b=t;}printf(“%5.2f,%5.2f\n”,a,b);return0;}13.輸入a,b,c三個(gè)數(shù)，要求由小到大的順序輸出。程序：#include<stdio.h>intmain(){floata,b,c,t;scanf("%f,%f,%f",&a,&b,&c);if(a>b);{t=a;a=b;b=t;}if(a>c){t=a;a=c;c=t;}if(b>c){t=b;b=c;c=t;}printf("%5.2f,%5.2f,%5.2f\n",a,b,c);return0;}14．輸入一個(gè)字符，判斷它是否為大寫字母，如果是，將它轉(zhuǎn)換成小寫字母，如果不是，不轉(zhuǎn)換。然后輸出最后得到的字符。程序：#include<stdio.h>intmain(){charch;scanf(“%c”,&ch);ch=(ch>='A'&&ch<='Z')?(ch+32):ch;printf(“%c\n”,ch);return0;}或#include<stdio.h>intmain(){charch;scanf("%c",&ch);if(ch>='A'&&ch<='Z')printf("%c\n",ch+32);elseprintf("%c\n",ch);return0;-1(x<0)15.有一個(gè)函數(shù):y={0(x=0)1(x>0)編一程序。輸入一個(gè)x的值，要求輸出相應(yīng)的y值。程序：#include<stdio.h>intmain(){intx,y;scanf("%d",&x);if(x<0)y=-1;elseif(x==0)y=0;elsey=1;printf("x=%d\ny=%d\n",x,y);return0;}16?要求按照考試成績的等級輸出百分制分?jǐn)?shù)段，A等為85分以上，B等為70-84分。C等為60-69分，D等為60分以下。成績的等級由鍵盤輸入。程序：#include<stdio.h>intmain(){chargrade;scanf("%c",grade);printf("Youscore:\n");switch(grade){case'A':printf("85~100\n");break;case'B':printf("70~84\n");break;case'C':printf("60~69\n");break;case'D':printf("<60\n");break;default:printf("enterdateerror\n");}return0;}17.寫一程序，判斷某一年是否為閏年。程序:#include<stdio.h>intmain(){intleap,year;printf("pleaseenteryear:");scanf("%d",&year);if(year%4==0){if(year%100==0){if(year%400==0)leap=1;elseleap=0;}elseleap=1;}elseleap=0;if(leap)printf("%disaleapyear\n",year);elseprintf("%disnotaleapyear\n",year);return0;}或#include<stdio.h>intmain(){intleap,year;printf("pleaseenteryear:");scanf("%d",&year);if(year%4!=0)leap=0;elseif(year%100!=0)leap=1;elseif(year%400!=0)leap=0;elseleap=1;if(leap==1)printf("%disaleapyear\n",year);elseprintf("%disnotaleapyear\n",year);return0;}或#include<stdio.h>intmain(){intleap,year;printf("pleaseenteryear:");scanf("%d",&year);if((year%4==0&&year%100!=0)||(year%400==0))leap=1;elseleap=0;if(leap==1)printf("%disaleapyear\n",year);elseprintf("%disnotaleapyear\n",year);return0;}18.求ax2+bx+c=0方程的根。a,b,c由鍵盤輸入。（完整版）程序：#include<stdio.h>#include<stdio.h>#include<math.h>intmain(){doublea,b,c,disc,x1,x2,x3,realpart,imagepart;scanf("%lf,%lf,%lf",&a,&b,&c);printf("Theequation");if(fabs(a)<=1e-6)printf("isnotaquadratic");else{disc=b*b-4*a*c;if(fabs(disc)<=1e-6)printf("hastwoequalroots%8.4f\n",-b/2*a);elseif(disc>1e-6){printf("hastwodistinctrealroots\n%8.4f,%8.4f",x1,x2);x1=(-b+sqrt(disc))/2*a;x2=(-b-sqrt(disc))/2*a;else{realpart=-b/2*a;imagepart=sqrt(-disc)/2*a;printf("hastwocomplexroots:\n");printf("%8.4f+%8.4fi\n",realpart,imagepart);printf("%8.4f-%8.4fi\n",realpart,imagepart);}}return0;}//注釋：由于b*b-4*a*c(disc)是實(shí)數(shù)，而實(shí)數(shù)在計(jì)算和存儲時(shí)會有一些微小的誤差，因此不能直接進(jìn)行如下判斷：〃“if(disc==O)",因?yàn)檫@樣可能出現(xiàn)本來是零的量，由于上述誤差而判別為不等于零而導(dǎo)致結(jié)果錯(cuò)誤，//所以采取的辦法是判別disc的絕對值(fabs(disc))是否小于一個(gè)很小的數(shù)(例如：le-6)。如果小于此數(shù)，則認(rèn)為disc=0.19.給出一個(gè)不多出5位的正整數(shù)，要求：(1)：求出它是幾位數(shù);(2)：分別輸出每一位數(shù)字；(3)：按逆序輸出各位數(shù)字，例如原數(shù)為321，輸出123。程序：#include<stdio.h>intmain(){intnum,indiv,ten,hundred,thousand,ten_thousand,place;printf("請輸入一個(gè)正整數(shù)(0~99999):")；scanf("%d",&num);if(num>9999)place=5;elseif(num>999)place=4;elseif(num>99)place=3;elseif(num>9)place=2;

elseplace=1;printf("位數(shù)為：％d\n",place)；ten_thousand=num/10000;thousand=(num-ten_thousand*10000)/1000；hundred=(num-ten_thousand*10000-thousand*1000)/100；ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10；indiv=(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10)；printf("每一個(gè)數(shù)字分別為：")；printf("%d,%d,%d,%d,%d\n",ten_thousand,thousand,hundred,ten,indiv)；switch(place){case5：printf("反序數(shù)字為：%d%d%d%d%d\n",ind