初一數(shù)學(xué)方案題帶答案

初一數(shù)學(xué)方案題帶答案一、整數(shù)運(yùn)算計(jì)算：(-13)+27-9。解答：(-13)+27-9=-13+18=5。計(jì)算：$(-8)\\times(-4)\\div2$。解答：$(-8)\\times(-4)\\div2=32\\div2=16$。計(jì)算：$((-10)\\times5)+(-30)$。解答：$((-10)\\times5)+(-30)=(-50)+(-30)=-80$。二、有理數(shù)的加減法計(jì)算：(-5)+6-(-2)-7。解答：(-5)+6-(-2)-7=(-5)+6+2-7=-4。計(jì)算：(-7)-(-5)+(-10)+9。解答：(-7)-(-5)+(-10)+9=(-7)+5+(-10)+9=-3。計(jì)算：(-5)-6-(-2)+7。解答：(-5)-6-(-2)+7=(-5)-6+2+7=-2。三、有理數(shù)的乘除法計(jì)算：$(-12)\\times(-3)\\div6$。解答：$(-12)\\times(-3)\\div6=36\\div6=6$。計(jì)算：$(-15)\\div3\\times(-4)$。解答：$(-15)\\div3\\times(-4)=(-5)\\times(-4)=20$。計(jì)算：$(-6)\\times8\\div(-2)$。解答：$(-6)\\times8\\div(-2)=(-48)\\div(-2)=24$。四、分?jǐn)?shù)的加減法計(jì)算：$\\frac{2}{5}-\\frac{1}{10}$。解答：$\\frac{2}{5}-\\frac{1}{10}=\\frac{4}{10}-\\frac{1}{10}=\\frac{3}{10}$。計(jì)算：$\\frac{3}{4}+\\frac{2}{3}$。解答：$\\frac{3}{4}+\\frac{2}{3}=\\frac{9}{12}+\\frac{8}{12}=\\frac{17}{12}$。計(jì)算：$\\frac{5}{6}-\\frac{1}{3}+\\frac{1}{2}$。解答：$\\frac{5}{6}-\\frac{1}{3}+\\frac{1}{2}=\\frac{10}{12}-\\frac{4}{12}+\\frac{6}{12}=\\frac{12}{12}=1$。五、分?jǐn)?shù)的乘除法計(jì)算：$\\frac{3}{4}\\times\\frac{2}{3}$。解答：$\\frac{3}{4}\\times\\frac{2}{3}=\\frac{6}{12}=\\frac{1}{2}$。計(jì)算：$\\frac{1}{2}\\div\\frac{3}{4}$。解答：$\\frac{1}{2}\\div\\frac{3}{4}=\\frac{2}{4}\\div\\frac{3}{4}=\\frac{2}{3}$。計(jì)算：$\\frac{2}{3}\\times\\frac{5}{4}\\div\\frac{1}{5}$。解答：$\\frac{2}{3}\\times\\frac{5}{4}\\div\\frac{1}{5}=\\frac{10}{12}\\di