c語言程序代碼

-.z.要求在屏幕上輸出下一行信息。Thisisacprogram.程序:#include<stdio.h>intmain(){printf("thisisacprogram.\n〞);return0;}求兩個整數(shù)之和。程序：#include<stdio.h>intmain(){inta,b,sum;a=122;b=234;sum=a+b;printf("sumis%d\n〞,sum);return0;}求兩個整數(shù)之間的較大者。程序：#include<stdio.h>intmain(){intma*(int*,inty);inta,b,c;scanf("%d,%d",&a,&b);c=ma*(a,b);printf("ma*=%d\n",c);return0;}intma*(int*,inty){intz;if(*>y)z=*;elsez=y;return(z);}有人用溫度計測量出華氏發(fā)表示的溫度〔如69°F〕，今要求把她轉(zhuǎn)換成以攝氏法表示的溫度〔如20℃〕。公式：c=5〔f-32〕/9.其中f代表華氏溫度，c代表攝氏溫度。程序：#include<stdio.h>intmain(){floatf,c;f=64.0;c=(5.0/9)*(f-32);printf("f=%f\nc=%f\n",f,c);return0;}計算存款利息。有1000元，想存一年。有一下三種方法可選：〔1〕活期：年利率為r1；〔2〕一年定期：年利率為r2；〔3〕存兩次半年定期：年利率為r3。分別計算一年后按三種方法所得到的本息和。程序：#include<stdio.h>intmain(){floatp0=1000,r1=0.0036,r2=0.0225,r3=0.0198,p1,p2,p3;p1=p0*(1+r1);p2=p0*(1+r2);p3=p0*(1+r3/2)*(1+r3/2);printf("p1=%f\np2=%f\np3=%f\n",p1,p2,p3);return0;}給定一個大寫字母，要求以小寫字母輸出。程序：#include<stdio.h>intmain(){charc1,c2;c1=’A’;c2=c1+32;printf("%c\n〞,c2);printf("%d\n〞,c2);return0;}給出三角形的三邊長，求三角形的面積。公式：假設(shè)給定三角形的三邊長，且任意兩邊之長大于第三邊。則：area=QUOTE其中s=(a+b+C)/2.程序：#include<stdio.h>#include<math.h>intmain(){doublea,b,c,area;a=3.67;b=5.43;c=6.21;s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c));printf("a=%f\tb=%f\tc=%f\n〞,a,b,c);printf("area=%f\n〞,area);return0;}求a*2+b*+c=0方程的根。a,b,c由鍵盤輸入，設(shè)b2-4ac>0.程序：#include<stdio.h>#include<math.h>intmain(){doublea,b,c,disc,*1,*2,p,q;scanf("%lf%lf%lf〞,&a,&b,&c);disc=b*b-4*a*c;if(disc<0)printf("Thisquestionhasnorealroots\n〞);else{p=-b/(2.0*a);q=sqrt(disc)/(2.0*a);*1=p+q;*2=p-q;printf("*1=%7.2f\n*2=%7.2f\n〞,*1,*2);}return0;}先后輸出BOY三個字符。程序：#include<stdio.h>intmain(){chara=’B’,b=’O’,c=’Y’;putchar(a);putchar(b);putchar(c);putchar(‘\n’);return0;}用三個getchar函數(shù)先后向計算機輸入BOY三個字符，然后用putchar函數(shù)輸出。程序：#include<stdio.h>intmain(){chara,b,c;a=getchar();b=getchar();c=getchar();putchar(a);putchar(b);putchar(c);putchar(‘\n’);return0;}或#include<stdio.h>intmain(){putchar(getchar());putchar(getchar());putchar(getchar());putchar(‘\n’);return0;}用getchar函數(shù)從鍵盤讀入一個大寫字母，把它轉(zhuǎn)換成小寫字母，然后用getchar函數(shù)輸出對應(yīng)的小寫字母。程序：#include<stdio.h>intmain(){charc1,c2;c1=getchar();c2=c1+32;putchar(c2);putchar(‘\n’);return0;}輸入兩個實數(shù)，按代數(shù)值由小到大的順序輸出這兩個數(shù)?！矃⒄諏蓚€杯子中的水互換，必須借助第三個杯子〕。程序：#include<stdio.h>intmain(){floata,b,t;scanf("%f,%f〞,&a,&b);if(a>b){t=a;a=b;b=t;}printf("%5.2f,%5.2f\n〞,a,b);return0;}輸入a，b，c三個數(shù)，要求由小到大的順序輸出。程序：#include<stdio.h>intmain(){ floata,b,c,t; scanf("%f,%f,%f",&a,&b,&c); if(a>b); { t=a; a=b; b=t; } if(a>c) { t=a; a=c; c=t; } if(b>c) { t=b; b=c; c=t; } printf("%5.2f,%5.2f,%5.2f\n",a,b,c); return0;}14．輸入一個字符，判斷它是否為大寫字母，如果是，將它轉(zhuǎn)換成小寫字母，如果不是，不轉(zhuǎn)換。然后輸出最后得到的字符。程序：#include<stdio.h>intmain(){charch;scanf("%c〞,&ch);ch=(ch>=’A’&&ch<=’Z’)"(ch+32):ch;printf("%c\n〞,ch);return0;}或#include<stdio.h>intmain(){ charch; scanf("%c",&ch); if(ch>='A'&&ch<='Z') printf("%c\n",ch+32); else printf("%c\n",ch); return0;}15.有一個函數(shù):y=QUOTE編一程序。輸入一個*的值，要求輸出相應(yīng)的y值。程序：#include<stdio.h>intmain(){ int*,y; scanf("%d",&*); if(*<0) y=-1; elseif(*==0) y=0; else y=1; printf("*=%d\ny=%d\n",*,y); return0;}16.要求按照考試成績的等級輸出百分制分數(shù)段，A等為85分以上，B等為70-84分。C等為60-69分，D等為60分以下。成績的等級由鍵盤輸入。程序：#include<stdio.h>intmain(){ chargrade; scanf("%c",grade); printf("Youscore:\n"); switch(grade) { case'A':printf("85~100\n");break; case'B':printf("70~84\n");break; case'C':printf("60~69\n");break; case'D':printf("<60\n");break; default:printf("enterdateerror\n"); } return0;}17.寫一程序，判斷*一年是否為閏年。程序:#include<stdio.h>intmain(){ intleap,year; printf("pleaseenteryear:"); scanf("%d",&year); if(year%4==0) { if (year%100==0) { if(year%400==0) leap=1; else leap=0; } else leap=1; } elseleap=0; if(leap) printf("%disaleapyear\n",year); else printf("%disnotaleapyear\n",year); return0;}或#include<stdio.h>intmain(){ intleap,year; printf("pleaseenteryear:"); scanf("%d",&year); if(year%4!=0) leap=0; elseif(year%100!=0) leap=1; elseif(year%400!=0) leap=0; else leap=1; if(leap==1) printf("%disaleapyear\n",year); else printf("%disnotaleapyear\n",year); return0;}或#include<stdio.h>intmain(){ intleap,year; printf("pleaseenteryear:"); scanf("%d",&year); if((year%4==0&&year%100!=0)||(year%400==0)) leap=1; else leap=0; if(leap==1) printf("%disaleapyear\n",year); else printf("%disnotaleapyear\n",year); return0;}18.求a*2+b*+c=0方程的根。a,b,c由鍵盤輸入?！餐暾妗吵绦颍?include<stdio.h>#include<math.h>intmain(){ doublea,b,c,disc,*1,*2,*3,realpart,imagepart; scanf("%lf,%lf,%lf",&a,&b,&c); printf("Theequation"); if(fabs(a)<=1e-6) printf("isnotaquadratic"); else { disc=b*b-4*a*c; if(fabs(disc)<=1e-6)printf("hastwoequalroots%8.4f\n",-b/2*a); else if(disc>1e-6) { printf("hastwodistinctrealroots\n%8.4f,%8.4f",*1,*2); *1=(-b+sqrt(disc))/2*a; *2=(-b-sqrt(disc))/2*a; } else { realpart=-b/2*a; imagepart=sqrt(-disc)/2*a; printf("hastwople*roots:\n"); printf("%8.4f+%8.4fi\n",realpart,imagepart); printf("%8.4f-%8.4fi\n",realpart,imagepart); } } return0;}//注釋：由于b*b-4*a*c〔disc〕是實數(shù)，而實數(shù)在計算和存儲時會有一些微小的誤差，因此不能直接進展如下判斷：//"if〔disc==0〕",因為這樣可能出現(xiàn)本來是零的量，由于上述誤差而判別為不等于零而導致結(jié)果錯誤，//所以采取的方法是判別disc的絕對值〔fabs〔disc〕〕是否小于一個很小的數(shù)〔例如：1e-6〕。如果小于此數(shù)，則認為disc=0.19.給出一個不多出5位的正整數(shù)，要求：〔1〕：求出它是幾位數(shù);〔2〕：分別輸出每一位數(shù)字；〔3〕：按逆序輸出各位數(shù)字，例如原數(shù)為321，輸出123。程序：#include<stdio.h>intmain(){ intnum,indiv,ten,hundred,thousand,ten_thousand,place; printf("請輸入一個正整數(shù)(0~99999)："); scanf("%d",&num); if(num>9999) place=5; elseif(num>999) place=4; elseif(num>99) place=3; elseif(num>9) place=2; else place=1; printf("位數(shù)為:%d\n",place); ten_thousand=num/10000; thousand=(num-ten_thousand*10000)/1000; hundred=(num-ten_thousand*10000-thousand*1000)/100; ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10; indiv=(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10); printf("每一個數(shù)字分別為："); printf("%d,%d,%d,%d,%d\n",ten_thousand,thousand,hundred,ten,indiv); switch(place) { case5:printf("反