新人教版八年級(jí)上期末數(shù)學(xué)檢測(cè)卷B二

1、2013-2014學(xué)年新人教版八年級(jí)（上）期末數(shù)學(xué)檢測(cè)卷b（二）一、選擇題（每小題3分，共24分）1下列圖案中不是軸對(duì)稱(chēng)圖形的是（）abcd 顯示解析2下列運(yùn)算結(jié)果正確的是（）aa3a4=a12b（a2）3=a6c（3a）3=3a3da（a+1）=a2+1 顯示解析3下列說(shuō)法中：三條線(xiàn)段組成的圖形叫做三角形；三角形的角平分線(xiàn)是射線(xiàn)；三角形的三條高所在的直線(xiàn)相交于一點(diǎn)，這一點(diǎn)不在三角形的內(nèi)部，就在三角形的外部；三角形的三條中線(xiàn)相交于一點(diǎn)，且這點(diǎn)一定在三角形的內(nèi)部其中正確的有（）a4個(gè)b3個(gè)c2個(gè)d1個(gè) 顯示解析4下列說(shuō)法不正確的是（）a在銳角三角形中，最大的銳角x的

2、取值范圍是60°x90°b在abc中，銳角的個(gè)數(shù)最多c在abc中三個(gè)內(nèi)角：=1：3：5，這個(gè)三角形是直角三角形d一個(gè)三角形中至少有一個(gè)角是銳角 顯示解析5下列條件中，能判定abcdef的是（）aab=de，bc=ef，a=dba=d，c=f，ac=efcb=e，a=d，ac=efdb=e，a=d，ab=de 顯示解析6下列分解因式正確的是（）am3-m=m（m-1）（m+1）bx2-x-6=x（x-1）-6c2a2+ab+a=a（2a+b）dx2-y2=（x-y）2 顯示解析7對(duì)于分式2x+a3x1，當(dāng)x=-a2時(shí)，下列說(shuō)法中：分式值一定為0；

3、分式一定有意義；當(dāng)a=-23時(shí)，分式無(wú)意義其中正確的個(gè)數(shù)有（）a3個(gè)b2個(gè)c1個(gè)d0個(gè) 顯示解析8如圖，在rtabc中，ab=cb，boac，把a(bǔ)bc折疊，使ab落在ac上，點(diǎn)b與ac上的點(diǎn)e重合，展開(kāi)后，折痕ad交bo于點(diǎn)f，連接de、ef下列結(jié)論：tanadb=2；圖中有4對(duì)全等三角形；若將def沿ef折疊，則點(diǎn)d不一定落在ac上；bd=bf；s四邊形dfoe=saof，上述結(jié)論中正確的個(gè)數(shù)是（）a1個(gè)b2個(gè)c3個(gè)d4個(gè) 顯示解析二、填空題（每小題3分，共24分）9已知等腰三角形的一個(gè)內(nèi)角為40°，則這個(gè)等腰三角形的頂角為  顯示解析10化

4、簡(jiǎn)：（a2b）-2（a-1b-2）-3=  顯示解析11如圖，abc中，ab=ac，a=30°，de垂直平分ac，則bcd的度數(shù)為  顯示解析12如圖，在abc中，ab=ac，b=30°，ab的垂直平分線(xiàn)ef交ab于點(diǎn)e，交bc于點(diǎn)f，ef=2，則bc的長(zhǎng)為  顯示解析13如果（a+b）2=19，a2+b2=14，則（a-b）2=  顯示解析14如圖，在abc中，ab=a，ac=b，bac=150°，則sabc=  顯示解析15如圖，在abc中，ad為bc邊上的中線(xiàn)

5、已知ac=5，ad=4，則ab的取值范圍是  顯示解析16關(guān)于x的分式方程mx1+31x1的解為正數(shù)，則m的取值范圍是  顯示解析三、解答題（其中17，18題各9分，19，21，22，24，26題各10分，20題12分，23題8分，25題14分，共102分）17已知2x+y=4，求代數(shù)式（x+y）2-（x-y）2-2y（x-12y）÷4y的值 顯示解析18（1）計(jì)算：a1a÷（a-2a1a）（2）解方程：23+x3x1=19x3 顯示解析19有公路l1同側(cè)、l2異側(cè)的兩個(gè)城鎮(zhèn)a，b，如下圖電信部門(mén)要修建一座信號(hào)發(fā)射

6、塔，按照設(shè)計(jì)要求，發(fā)射塔到兩個(gè)城鎮(zhèn)a，b的距離必須相等，到兩條公路l1，l2的距離也必須相等，發(fā)射塔c應(yīng)修建在什么位置？請(qǐng)用尺規(guī)作圖找出所有符合條件的點(diǎn)，注明點(diǎn)c的位置（保留作圖痕跡，不要求寫(xiě)出畫(huà)法） 顯示解析20如圖，在abc中，ab=ac，點(diǎn)d、e、f分別在邊ab、bc、ac上，且bd=ce，def=b圖中是否存在和bde全等的三角形？說(shuō)明理由 顯示解析21甲、乙兩人準(zhǔn)備整理一批新到的實(shí)驗(yàn)器材若甲單獨(dú)整理需要40分鐘完工：若甲、乙 共同整理20分鐘后，乙需再單獨(dú)整理20分鐘才能完工（1）問(wèn)乙單獨(dú)整理多少分鐘完工？（2）若乙因工作需要，他的整理時(shí)間不超過(guò)30分鐘

7、，則甲至少整理多少分鐘才能完工？ 顯示解析22如圖，已知點(diǎn)d為等腰直角abc內(nèi)一點(diǎn)，cad=cbd=15°，e為ad延長(zhǎng)線(xiàn)上的一點(diǎn)，且ce=ca（1）求證：de平分bdc；（2）若點(diǎn)m在de上，且dc=dm，求證：me=bd 顯示解析23某種產(chǎn)品的原料降價(jià)，因而廠(chǎng)家決定對(duì)產(chǎn)品進(jìn)行降價(jià)現(xiàn)有兩種方案：方案1：第一次降價(jià)p%，第二次降價(jià)q%方案2：第一、二次降價(jià)均為p+q2%其中p，q是不相等且使此情境有意義的正數(shù)，兩種方案哪種降價(jià)最多？ 顯示解析24一塊原邊長(zhǎng)分別為a，b（a1，b1）的長(zhǎng)方形，一邊增加1，另一邊減少1（1）當(dāng)a=b時(shí)，變化后的面積是增加還是

8、減少？（2）當(dāng)ab時(shí)，有兩種方案，第一種方案如圖1，第二種方案如圖2請(qǐng)你比較這兩種方案，確定哪一種方案變化后的面積比較大 顯示解析25如圖1，在正方形abcd中，點(diǎn)m、n分別在ad、cd上，若mbn=45°，易證mn=am+cn（1）如圖2，在梯形abcd中，bcad，ab=bc=cd，點(diǎn)m、n分別在ad、cd上，若mbn=12abc，試探究線(xiàn)段mn、am、cn有怎樣的數(shù)量關(guān)系？請(qǐng)寫(xiě)出猜想，并給予證明（2）如圖3，在四邊形abcd中，ab=bc，abc+adc=180°，點(diǎn)m、n分別在da、cd的延長(zhǎng)線(xiàn)上，若mbn=12abc，試探究線(xiàn)段mn、am、cn又有怎樣的

9、數(shù)量關(guān)系？請(qǐng)直接寫(xiě)出猜想，不需證明 顯示解析26在abc中，a=90°，點(diǎn)d在線(xiàn)段bc上，edb=12c，bede，垂足為點(diǎn)e，de與ab相交于點(diǎn)f當(dāng)ab=ac時(shí)（如圖所示）（1）ebf= （2）探究線(xiàn)段be與fd的數(shù)量關(guān)系，并加以證明v7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtw

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