新高考數(shù)學(xué)二輪復(fù)習(xí)易錯(cuò)點(diǎn)03 指數(shù)函數(shù)與對(duì)數(shù)函數(shù)及函數(shù)與方程（原卷版）

易錯(cuò)點(diǎn)03指數(shù)函數(shù)與對(duì)數(shù)函數(shù)及函數(shù)與方程易錯(cuò)題【01】研究對(duì)數(shù)型函數(shù)忽略定義域研究函數(shù)SKIPIF1<0的性質(zhì)，或求解與SKIPIF1<0有關(guān)的函數(shù)與方程及不等式問(wèn)題，不少同學(xué)常因忽略SKIPIF1<0的隱含條件出現(xiàn)錯(cuò)誤。易錯(cuò)題【02】不會(huì)利用中間量比較大小在比較數(shù)與式的大小時(shí)常利用指數(shù)函數(shù)、冪函數(shù)及對(duì)數(shù)函數(shù)單調(diào)性比較大小，若比較指數(shù)式與對(duì)數(shù)式的大小，或同是指數(shù)式(對(duì)數(shù)式)但底數(shù)不相同，這些情況下常利用中間量比較大小，常用的中間量是SKIPIF1<0，有時(shí)也可借助SKIPIF1<0等中間量來(lái)比較大小.易錯(cuò)題【03】不會(huì)構(gòu)造函數(shù)比較大小比較兩個(gè)式子的大小，若兩個(gè)式子結(jié)構(gòu)比較復(fù)雜，但結(jié)構(gòu)類似，這種情況下常式子的結(jié)構(gòu)構(gòu)造函數(shù)，然后利用函數(shù)單調(diào)性比較大小。易錯(cuò)題【04】確定函數(shù)零點(diǎn)所在區(qū)間，或零點(diǎn)個(gè)數(shù)或已知函數(shù)零點(diǎn)情況求參數(shù)滿足條件，常通過(guò)數(shù)形結(jié)合轉(zhuǎn)化為兩個(gè)函數(shù)圖象的交點(diǎn)個(gè)數(shù)問(wèn)題，故提醒同學(xué)們研究函數(shù)與方程問(wèn)題不要得“意”忘“形”。 01若SKIPIF1<0在SKIPIF1<0上是減函數(shù)，則SKIPIF1<0的取值范圍是1.函數(shù)SKIPIF1<0在SKIPIF1<0單調(diào)遞增，求a的取值范圍()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．(2021湖北武漢市第一中學(xué)高三月考)函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增，則實(shí)數(shù)SKIPIF1<0的取值范圍為()．A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0 02(2019全國(guó)Ⅰ卷理T3)已知，則()A． B． C． D．1.(2021新高考2卷T7)已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則下列判斷正確的是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.設(shè)SKIPIF1<0，則()A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<0 03(2021全國(guó)卷乙卷理T12)設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<01.(2020全國(guó)Ⅰ理T12)若SKIPIF1<0，則 ()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02.(2020全國(guó)Ⅱ理T11)若SKIPIF1<0，則 ()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0 04(2018全國(guó)卷Ⅰ)已知函數(shù)SKIPIF1<0SKIPIF1<0．若SKIPIF1<0存在2個(gè)零點(diǎn)，則SKIPIF1<0的取值范圍是A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<01.(2021河南大學(xué)附屬中學(xué)高三月考)定義在R上的奇函數(shù)SKIPIF1<0，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則關(guān)于x的函數(shù)SKIPIF1<0的所有零點(diǎn)之和為()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02.(2021天津市第四十七中學(xué)高三月考)已知函數(shù)SKIPIF1<0，SKIPIF1<0(其中e是自然對(duì)數(shù)的底數(shù))，若關(guān)于x的方程SKIPIF1<0恰有三個(gè)不等實(shí)根SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的最大值為_(kāi)__________.錯(cuò)1．(2021江蘇省泰興中學(xué)高三期中)已知a=SKIPIF1<0，SKIPIF1<0，則a，b，c的大小關(guān)系為()A．a(chǎn)＜b＜c B．b＜a＜c C．c＜a＜b D．c＜b＜a2．(2021山東煙臺(tái)高三期中)設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03.(2020江西省信豐中學(xué)高三月考)若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞增，則實(shí)數(shù)SKIPIF1<0的取值范圍為()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．(2021河南高三月考)設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05.(2021黑龍江高三期中)已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則()A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06.(2021四川攀枝花高三月考)定義在SKIPIF1<0上的函數(shù)SKIPIF1<0滿足SKIPIF1<0，且SKIPIF1<0，給出如下四個(gè)結(jié)論：①SKIPIF1<0的值域?yàn)镾KIPIF1<0；②當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0；③SKIPIF1<0圖象的對(duì)稱軸為直線SKIPIF1<0；④方程SKIPIF1<0恰有SKIPIF1<0個(gè)實(shí)數(shù)解，其中正確的結(jié)論個(gè)數(shù)是()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．(2021吉林·高三月考)已知函數(shù)SKIPIF1<0，SKIPIF1<0，若關(guān)于SKIPIF1<0的方程SKIPIF1<0恰有SKIPIF1<0個(gè)不同實(shí)數(shù)根，則實(shí)數(shù)SKIPIF1<0的取值范圍為()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．(多選題)已知函數(shù)SKIPIF1<0，SKIPIF1<0，則下列說(shuō)法正確的是()A．若函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，則實(shí)數(shù)SKIPIF1<0的取值范圍是SKIPIF1<0B．若函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0，則實(shí)數(shù)SKIPIF1<0C．若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上為增函數(shù)，則實(shí)數(shù)SKIPIF1<0的取值范圍是SKIPIF1<0D．若SKIPIF1<0，則不等式SKIPIF1<0的解集為SKIPIF1<09.(多選題)(2021重慶九龍坡高三期中)已知函數(shù)SKIPIF1<0，方程SKIPIF1<0有兩個(gè)不等實(shí)根，則下列選項(xiàng)正確的是()A．點(diǎn)SKIPIF1<0是函數(shù)SKIPIF1<0的零點(diǎn)B．SKIPIF1<0，SKIPIF1<0，使SKIPIF1<0