新高考數(shù)學(xué)一輪復(fù)習(xí)第2章 第06講 對(duì)數(shù)與對(duì)數(shù)函數(shù) 精講+精練（學(xué)生版）

第06講對(duì)數(shù)與對(duì)數(shù)函數(shù)(精講+精練）目錄第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶第二部分：課前自我評(píng)估測(cè)試第三部分：典型例題剖析高頻考點(diǎn)一：對(duì)數(shù)的運(yùn)算；高頻考點(diǎn)二：換底公式高頻考點(diǎn)三：對(duì)數(shù)函數(shù)的概念；高頻考點(diǎn)四：對(duì)數(shù)函數(shù)的定義域高頻考點(diǎn)五：對(duì)數(shù)函數(shù)的值域①求對(duì)數(shù)函數(shù)在區(qū)間上的值域；②求對(duì)數(shù)型復(fù)合函數(shù)的值域③根據(jù)對(duì)數(shù)函數(shù)的值域求參數(shù)值或范圍高頻考點(diǎn)六：對(duì)數(shù)函數(shù)的圖象①判斷對(duì)數(shù)（型）函數(shù)的圖象②根據(jù)對(duì)數(shù)（型）函數(shù)的圖象判斷參數(shù)③對(duì)數(shù)（型）函數(shù)圖象過(guò)定點(diǎn)問(wèn)題高頻考點(diǎn)七：對(duì)數(shù)函數(shù)的單調(diào)性①對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性②由對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性求參數(shù)③由對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性解不等式④對(duì)數(shù)（指數(shù)）綜合比較大小高頻考點(diǎn)八：對(duì)數(shù)函數(shù)的最值①求對(duì)數(shù)（型）函數(shù)的最值②根據(jù)對(duì)數(shù)（型）函數(shù)的最值求參數(shù)③對(duì)數(shù)（型）函數(shù)的最值與不等式綜合應(yīng)用第四部分：高考真題感悟第五部分：第06講對(duì)數(shù)與對(duì)數(shù)函數(shù)（精練）第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶1、對(duì)數(shù)的概念（1）對(duì)數(shù)：一般地，如果SKIPIF1<0SKIPIF1<0，那么數(shù)SKIPIF1<0叫做以SKIPIF1<0為底SKIPIF1<0的對(duì)數(shù)，記作SKIPIF1<0，其中SKIPIF1<0叫做對(duì)數(shù)的底數(shù)，SKIPIF1<0叫做真數(shù).（2）牢記兩個(gè)重要對(duì)數(shù)：常用對(duì)數(shù)，以10為底的對(duì)數(shù)SKIPIF1<0；自然對(duì)數(shù)，以無(wú)理數(shù)e=2.71828…為底數(shù)的對(duì)數(shù)SKIPIF1<0.（3）對(duì)數(shù)式與指數(shù)式的互化：SKIPIF1<0.2、對(duì)數(shù)的性質(zhì)、運(yùn)算性質(zhì)與換底公式（1）對(duì)數(shù)的性質(zhì)根據(jù)對(duì)數(shù)的概念，知對(duì)數(shù)SKIPIF1<0具有以下性質(zhì)：①負(fù)數(shù)和零沒(méi)有對(duì)數(shù)，即SKIPIF1<0；②1的對(duì)數(shù)等于0，即SKIPIF1<0；③底數(shù)的對(duì)數(shù)等于1，即SKIPIF1<0；④對(duì)數(shù)恒等式SKIPIF1<0.（2）對(duì)數(shù)的運(yùn)算性質(zhì)如果SKIPIF1<0，那么：①SKIPIF1<0；②SKIPIF1<0；③SKIPIF1<0.（3）對(duì)數(shù)的換底公式對(duì)數(shù)的換底公式：SKIPIF1<0.換底公式將底數(shù)不同的對(duì)數(shù)轉(zhuǎn)化為底數(shù)相同的對(duì)數(shù)，進(jìn)而進(jìn)行化簡(jiǎn)、計(jì)算或證明.換底公式應(yīng)用時(shí)究竟換成什么為底，由已知條件來(lái)確定，一般換成以10為底的常用對(duì)數(shù)或以SKIPIF1<0為底的自然對(duì)數(shù).換底公式的變形及推廣：①SKIPIF1<0；②SKIPIF1<0；③SKIPIF1<0(其中SKIPIF1<0，SKIPIF1<0，SKIPIF1<0均大于0且不等于1，SKIPIF1<0).3、對(duì)數(shù)函數(shù)及其性質(zhì)（1）對(duì)數(shù)函數(shù)的定義形如SKIPIF1<0(SKIPIF1<0，且SKIPIF1<0)的函數(shù)叫做對(duì)數(shù)函數(shù)，其中SKIPIF1<0是自變量，函數(shù)的定義域是SKIPIF1<0．（2）對(duì)數(shù)函數(shù)的圖象與性質(zhì)SKIPIF1<0SKIPIF1<0圖象性質(zhì)定義域：SKIPIF1<0值域：SKIPIF1<0過(guò)點(diǎn)SKIPIF1<0，即當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0在SKIPIF1<0上是單調(diào)增函數(shù)在SKIPIF1<0上是單調(diào)減函數(shù)第二部分：課前自我評(píng)估測(cè)試第二部分：課前自我評(píng)估測(cè)試一、判斷題1．（2022·江西·貴溪市實(shí)驗(yàn)中學(xué)高二期末）已知SKIPIF1<0，則不等式SKIPIF1<0成立

()2．（2021·江西·貴溪市實(shí)驗(yàn)中學(xué)高二階段練習(xí)）SKIPIF1<0()3．（2021·江西·貴溪市實(shí)驗(yàn)中學(xué)高三階段練習(xí)）SKIPIF1<0.()4．（2021·江西·貴溪市實(shí)驗(yàn)中學(xué)高二階段練習(xí)）若SKIPIF1<0則SKIPIF1<0SKIPIF1<0

()二、單選題1．（2022·北京·一模）下列函數(shù)中，定義域與值域均為R的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·海南·模擬預(yù)測(cè)）已知SKIPIF1<0，則a，b，c的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·湖南師大附中高一階段練習(xí)）不等式SKIPIF1<0成立的一個(gè)充分不必要條件是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·陜西西安·高一期末）函數(shù)SKIPIF1<0的圖像大致為（

）A． B．C． D．5．（2022·吉林·農(nóng)安縣教師進(jìn)修學(xué)校高一期末）函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0第三部分：典型例題剖析第三部分：典型例題剖析高頻考點(diǎn)一：對(duì)數(shù)的運(yùn)算1．（2022·甘肅平?jīng)觥ざ＃ㄎ模㏒KIPIF1<0______．2．（2022·北京師大附中高一期末）SKIPIF1<0______________．3．（2022·浙江·杭州市富陽(yáng)區(qū)第二中學(xué)高一階段練習(xí)）計(jì)算SKIPIF1<0______.4．（2022·湖南·高一課時(shí)練習(xí)）計(jì)算：(1)SKIPIF1<0；(2)SKIPIF1<0；(3)SKIPIF1<0．高頻考點(diǎn)二：換底公式1．（2022·貴州遵義·高三開學(xué)考試（理））已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·安徽·安慶市教育教學(xué)研究室高一期末）已知SKIPIF1<0，SKIPIF1<0，用SKIPIF1<0，SKIPIF1<0表示SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·山東濟(jì)南·二模）已知SKIPIF1<0，SKIPIF1<0，那么SKIPIF1<0用含a、b的代數(shù)式表示為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·湖南·高一課時(shí)練習(xí)）計(jì)算：SKIPIF1<0________.高頻考點(diǎn)三：對(duì)數(shù)函數(shù)的概念1．（2021·河南·洛寧縣第一高級(jí)中學(xué)高一階段練習(xí)）已知函數(shù)SKIPIF1<0滿足①定義域?yàn)镾KIPIF1<0；②值域?yàn)镾KIPIF1<0；③SKIPIF1<0.寫出一個(gè)滿足上述條件的函數(shù)：SKIPIF1<0___________.2．（2021·江蘇·高一專題練習(xí)）對(duì)數(shù)函數(shù)f（x）的圖象過(guò)點(diǎn)(3，－2），則f(SKIPIF1<0)＝________.3．（2021·江蘇南通·高三期中）寫出滿足條件“函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，且SKIPIF1<0”的一個(gè)函數(shù)SKIPIF1<0___________.4．（2021·全國(guó)·高一專題練習(xí)）若函數(shù)f(x)=(a2+a-5)logax是對(duì)數(shù)函數(shù)，則a=________.高頻考點(diǎn)四：對(duì)數(shù)函數(shù)的定義域1．（2022·甘肅·甘南藏族自治州合作第一中學(xué)高一期末）函數(shù)f（x）=SKIPIF1<0的定義域?yàn)椋ǎ〢．（2，+∞） B．（0，2） C．（-∞，2） D．（0，SKIPIF1<0）2．（2022·四川·模擬預(yù)測(cè)（文））函數(shù)SKIPIF1<0的定義域?yàn)開__________.3．（2022·四川宜賓·高一期末）函數(shù)SKIPIF1<0的定義域?yàn)開_______.4．（2022·上海市控江中學(xué)高一期末）函數(shù)SKIPIF1<0定義域?yàn)镽，則實(shí)數(shù)k的取值范圍為______.5．（2022·上海浦東新·高一期末）函數(shù)SKIPIF1<0的定義域?yàn)開____________．高頻考點(diǎn)五：對(duì)數(shù)函數(shù)的值域①求對(duì)數(shù)函數(shù)在區(qū)間上的值域1．（2022·全國(guó)·高三專題練習(xí)）函數(shù)SKIPIF1<0在SKIPIF1<0上的值域?yàn)開______________________．2．（2022·全國(guó)·池州市第一中學(xué)高一開學(xué)考試）已知函數(shù)SKIPIF1<0．(1)求SKIPIF1<0在區(qū)間SKIPIF1<0上的值域；3．（2022·全國(guó)·高一課時(shí)練習(xí)）求函數(shù)SKIPIF1<0的值域.②求對(duì)數(shù)型復(fù)合函數(shù)的值域1．（2022·貴州·畢節(jié)市第一中學(xué)高一階段練習(xí)）函數(shù)y＝2＋log2(x2＋3)(x≥1)的值域?yàn)椋?/p>

）A．(2，＋∞) B．(－∞，2)C．[4，＋∞) D．[3，＋∞)2．（2022·青?！ご笸ɑ刈逋磷遄灾慰h教學(xué)研究室高一期末）函數(shù)SKIPIF1<0的值域是________．3．（2022·河南焦作·高一期末）已知函數(shù)SKIPIF1<0（a>0且a≠1）的圖象過(guò)點(diǎn)SKIPIF1<0.(1)求a的值及SKIPIF1<0的定義域；(2)求SKIPIF1<0在SKIPIF1<0上的最小值.4．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0.當(dāng)SKIPIF1<0時(shí)，求該函數(shù)的值域；③根據(jù)對(duì)數(shù)函數(shù)的值域求參數(shù)值或范圍1．（2022·河南信陽(yáng)·高一期末）已知函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0，則實(shí)數(shù)m的值為（

）A．2 B．3 C．9 D．272．（2022·陜西咸陽(yáng)·高一期末）函數(shù)SKIPIF1<0在[1，3]上的值域?yàn)閇1，3]，則實(shí)數(shù)a的值是___________.3．（2022·全國(guó)·高一階段練習(xí)）函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0，則實(shí)數(shù)SKIPIF1<0的取值范圍為______．4．（2022·河南·林州一中高一開學(xué)考試）若函數(shù)SKIPIF1<0有最小值，則a的取值范圍為______．5．（2022·山西省長(zhǎng)治市第二中學(xué)校高一期末）已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí)，求函數(shù)SKIPIF1<0的值域；(2)若函數(shù)SKIPIF1<0的值域?yàn)镽，求實(shí)數(shù)SKIPIF1<0取值范圍.高頻考點(diǎn)六：對(duì)數(shù)函數(shù)的圖象①判斷對(duì)數(shù)（型）函數(shù)的圖象1．（2022·廣東汕尾·高一期末）當(dāng)SKIPIF1<0時(shí)，在同一平面直角坐標(biāo)系中，SKIPIF1<0與SKIPIF1<0的圖象是（

）A． B． C．D．2．（2022·廣東·華南師大附中高一階段練習(xí)）函數(shù)SKIPIF1<0與SKIPIF1<0的圖象可能是（

）A． B．C． D．3．（2022·浙江·高三專題練習(xí)）已知SKIPIF1<0（SKIPIF1<0且SKIPIF1<0，SKIPIF1<0且SKIPIF1<0），則函數(shù)SKIPIF1<0與SKIPIF1<0的圖象可能是（

）A． B．C． D．②根據(jù)對(duì)數(shù)（型）函數(shù)的圖象判斷參數(shù)1．（2022·新疆巴音郭楞·高一期末）如圖是三個(gè)對(duì)數(shù)函數(shù)的圖象，則a、b、c的大小關(guān)系是（

）A．a(chǎn)＞b＞c B．c＞b＞aC．c＞a＞b D．a(chǎn)＞c＞b2．（2022·全國(guó)·高三專題練習(xí)（文））已知SKIPIF1<0，若SKIPIF1<0有兩解，則a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·湖南師大附中高一期末）已知函數(shù)SKIPIF1<0的圖象如圖所示，則SKIPIF1<0滿足的關(guān)系是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·黑龍江·雙鴨山一中高一期末）已知SKIPIF1<0，若方程SKIPIF1<0有四個(gè)根SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0的取值范圍是______.③對(duì)數(shù)（型）函數(shù)圖象過(guò)定點(diǎn)問(wèn)題1．（2022·黑龍江·雙鴨山一中高一開學(xué)考試）函數(shù)SKIPIF1<0的圖象一定過(guò)定點(diǎn)__________.2．（2022·湖北·江夏一中高一階段練習(xí)）函數(shù)y＝loga(2x－3)＋8的圖象恒過(guò)定點(diǎn)A，且點(diǎn)A在冪函數(shù)f(x)的圖象上，則f（3）＝________.3．（2022·四川南充·高一期末）函數(shù)SKIPIF1<0的圖象恒過(guò)一定點(diǎn)是___________．高頻考點(diǎn)七：對(duì)數(shù)函數(shù)的單調(diào)性①對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性1．（2022·北京房山·高一期末）下列函數(shù)中，既是奇函數(shù)又在區(qū)間SKIPIF1<0上單調(diào)遞增的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國(guó)·高一課時(shí)練習(xí)）函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·北京·高三專題練習(xí)）函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·河北張家口·高一期末）函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·河南新鄉(xiāng)·高一期末）函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·山西·懷仁市第一中學(xué)校高一期末）SKIPIF1<0的單調(diào)遞增區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0②由對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性求參數(shù)1．（2022·陜西西安·高一期末）已知SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·黑龍江·雙鴨山一中高一期末）已知函數(shù)SKIPIF1<0在[2，3]上單調(diào)遞減，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·內(nèi)蒙古赤峰·高一期末）已知函數(shù)SKIPIF1<0在SKIPIF1<0上是減函數(shù)，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·湖南岳陽(yáng)·高一期末）已知函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則實(shí)數(shù)a的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·福建泉州·高一期末）若函數(shù)SKIPIF1<0在SKIPIF1<0單調(diào)遞增，則實(shí)數(shù)a的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·重慶·高一期末）已知關(guān)于SKIPIF1<0的函數(shù)SKIPIF1<0在SKIPIF1<0上是單調(diào)遞減的函數(shù)，則SKIPIF1<0的取值范圍為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<07．（2022·河南南陽(yáng)·高一期末）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0③由對(duì)數(shù)函數(shù)（型）函數(shù)的單調(diào)性解不等式1．（2022·河南濮陽(yáng)·高三開學(xué)考試（文））不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0=SKIPIF1<0，則不等式SKIPIF1<0SKIPIF1<0的解集是（

）A．（﹣2，1） B．（0，1）C．（﹣∞，﹣2）∪（1，+∞） D．（1，+∞）3．（2022·北京房山·高一期末）設(shè)函數(shù)SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·四川綿陽(yáng)·一模（理））設(shè)函數(shù)SKIPIF1<0則滿足SKIPIF1<0的SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·江西贛州·一模（文））設(shè)函數(shù)SKIPIF1<0則滿足SKIPIF1<0的SKIPIF1<0取值范圍是A．[-1,2] B．[0,2] C．[1,+SKIPIF1<0） D．[0,+SKIPIF1<0）④對(duì)數(shù)（指數(shù)）綜合比較大小1．（2022·廣東中山·高一期末）設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·江西·南昌十五中高二階段練習(xí)（理））設(shè)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·福建·廈門雙十中學(xué)高二階段練習(xí)）設(shè)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·江西·九江一中高二階段練習(xí)（理））已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則a，b，c的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·江蘇·南京市第一中學(xué)高三開學(xué)考試）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0高頻考點(diǎn)八：對(duì)數(shù)函數(shù)的最值①求對(duì)數(shù)（型）函數(shù)的最值1．（2021·江蘇·沭陽(yáng)縣修遠(yuǎn)中學(xué)高一階段練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為7，則SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為（

）A．0 B．1 C．2 D．42．（2021·天津市實(shí)驗(yàn)中學(xué)濱海學(xué)校高三期中（理））已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0有最小值，且最小值為-2B．SKIPIF1<0有最小值，且最小值為-1C．SKIPIF1<0有最大值，且最大值為-2D．SKIPIF1<0有最大值，且最大值為-13．（2022·上海金山·高一期末）函數(shù)SKIPIF1<0，SKIPIF1<0的最大值為______.4．（2021·山東·嘉祥縣第一中學(xué)高三階段練習(xí)）函數(shù)SKIPIF1<0的最小值為___________.5．（2021·全國(guó)·高一課時(shí)練習(xí)）函數(shù)SKIPIF1<0的最大值是_______．②根據(jù)對(duì)數(shù)（型）函數(shù)的最值求參數(shù)1．（2022·河南平頂山·高一期末）已知函數(shù)SKIPIF1<0的最大值與最小值的差為2，則SKIPIF1<0（

）A．4 B．3 C．2 D．SKIPIF1<02．（2022·貴州·六盤水市第一中學(xué)模擬預(yù)測(cè)）若函數(shù)SKIPIF1<0有最小值，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·貴州畢節(jié)·高一期末）已知函數(shù)SKIPIF1<0若SKIPIF1<0存在最小值，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國(guó)·高三專題練習(xí)）若函數(shù)SKIPIF1<0SKIPIF1<0沒(méi)有最小值，則SKIPIF1<0的取值范圍是____________.5．（2022·甘肅省會(huì)寧縣第一中學(xué)高一期末）已知函數(shù)SKIPIF1<0（SKIPIF1<0且SKIPIF1<0），SKIPIF1<0在SKIPIF1<0上的最大值為SKIPIF1<0.(1)求SKIPIF1<0的值；(2)當(dāng)函數(shù)SKIPIF1<0在定義域內(nèi)是增函數(shù)時(shí)，令SKIPIF1<0，判斷函數(shù)SKIPIF1<0的奇偶性，并證明，并求出SKIPIF1<0的值域.6．（2022·河南信陽(yáng)·高一期末）已知函數(shù)SKIPIF1<0（SKIPIF1<0，且SKIPIF1<0）.(1)求函數(shù)SKIPIF1<0的定義域；(2)是否存在實(shí)數(shù)a，使函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減，并且最大值為1？若存在，求出a的值；若不存在，請(qǐng)說(shuō)明理由.7．（2022·天津河北·高一期末）已知函數(shù)SKIPIF1<0（SKIPIF1<0，且SKIPIF1<0）(1)求SKIPIF1<0的值及函數(shù)SKIPIF1<0的定義域；(2)若函數(shù)SKIPIF1<0在SKIPIF1<0上的最大值與最小值之差為3，求實(shí)數(shù)SKIPIF1<0的值．③對(duì)數(shù)（型）函數(shù)的最值與不等式綜合應(yīng)用1．（2022·湖北·武漢中學(xué)高一階段練習(xí)）已知函數(shù)SKIPIF1<0，若對(duì)任意的SKIPIF1<0使得SKIPIF1<0成立，則實(shí)數(shù)SKIPIF1<0的取值范圍為A．SKIPIF1<0

SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·吉林·長(zhǎng)春市第二中學(xué)高一期末）已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí)，求該函數(shù)的值域；(2)若SKIPIF1<0，對(duì)于SKIPIF1<0恒成立，求實(shí)數(shù)m的取值范圍.3．（2022·陜西安康·高三期末（文））已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0，求a的值；(2)若對(duì)任意的SKIPIF1<0，SKIPIF1<0恒成立，求SKIPIF1<0的取值范圍.4．（2022·江蘇·無(wú)錫市第一中學(xué)高一期末）設(shè)函數(shù)SKIPIF1<0，其中SKIPIF1<0為常數(shù).（1）當(dāng)SKIPIF1<0時(shí)，求SKIPIF1<0的定義域；（2）若對(duì)任意SKIPIF1<0，關(guān)于SKIPIF1<0的不等式SKIPIF1<0恒成立，求實(shí)數(shù)SKIPIF1<0的取值范圍.第四部分：高考真題感悟第四部分：高考真題感悟1．（2021·湖南·高考真題）函數(shù)SKIPIF1<0的定義域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2021·天津·高考真題）若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．SKIPIF1<03．（2021·天津·高考真題）設(shè)SKIPIF1<0，則a，b，c的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2021·全國(guó)·高考真題）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則下列判斷正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2021·全國(guó)·高考真題（文））青少年視力是社會(huì)普遍關(guān)注的問(wèn)題，視力情況可借助視力表測(cè)量．通常用五分記錄法和小數(shù)記錄法記錄視力數(shù)據(jù)，五分記錄法的數(shù)據(jù)L和小數(shù)記錄表的數(shù)據(jù)V的滿足SKIPIF1<0．已知某同學(xué)視力的五分記錄法的數(shù)據(jù)為4.9，則其視力的小數(shù)記錄法的數(shù)據(jù)為（

）（SKIPIF1<0）A．1.5 B．1.2 C．0.8 D．0.6第五部分：第06講對(duì)數(shù)與對(duì)數(shù)函數(shù)（精練）第五部分：第06講對(duì)數(shù)與對(duì)數(shù)函數(shù)（精練）一、單選題1．（2021·江蘇·高一專題練習(xí)）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的大小關(guān)系是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2021·江蘇·高一專題練習(xí)）SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2021·江蘇·高一專題練習(xí)）已知SKIPIF1<0，那么SKIPIF1<0用SKIPIF1<0表示是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2021·浙江·高一期中）已知SKIPIF1<0是SKIPIF1<0上的減函數(shù)，那么SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2021·新疆·石河子第二中學(xué)高一階段練習(xí)）已知SKIPIF1<0的值域?yàn)镽，且SKIPIF1<0在SKIPIF1<0上是增函數(shù)，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<06．（2021·陜西·武功縣教育局教育教學(xué)研究室高一期中）函數(shù)SKIPIF1<0的最小值是（

）．A．10 B．1 C．11 D．SKIPIF1<07．（2021·重慶市第七中學(xué)校高一階段練習(xí)）函數(shù)SKIPIF1<0的圖象大致為（