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精選優(yōu)質(zhì)文檔-----傾情為你奉上精選優(yōu)質(zhì)文檔-----傾情為你奉上專心---專注---專業(yè)專心---專注---專業(yè)精選優(yōu)質(zhì)文檔-----傾情為你奉上專心---專注---專業(yè)土地平整問(wèn)題摘要隨著山區(qū)城市的發(fā)展,向山要地開發(fā)成為了一種必然的選擇。為了更好的確定平整地的起始點(diǎn),做到節(jié)約成本的目的,我們根據(jù)幾個(gè)決定性因素利用散點(diǎn)法【1】、建立了相關(guān)的模型。主要討論如何在一片山地之中選擇合適的方位與開挖深度,從而使總的土石方量最小,使得在實(shí)際工程中達(dá)到最可靠,最節(jié)約成本。采用MATLAB軟件模擬功能,畫出了該工廠的這片土地的三維圖形與等高線圖,并對(duì)山地地形作出分析。在求解開挖位置時(shí),我們只考慮連片地的一種放置位置,并通過(guò)平移求出海拔方差最小的區(qū)域,在此區(qū)域內(nèi)用散點(diǎn)法求出最小土石方量,從而決定從什么地方,什么海拔高度平整一塊固定大小的長(zhǎng)方形連片土地,能使總的土石方量最小,使工程施工經(jīng)濟(jì)上達(dá)到最優(yōu)。關(guān)鍵詞:合理開挖土地散點(diǎn)法最優(yōu)Ⅰ問(wèn)題重述1.1問(wèn)題背景土地整理在我國(guó)是一個(gè)較新的學(xué)科領(lǐng)域,面對(duì)“21世紀(jì)誰(shuí)來(lái)養(yǎng)活中國(guó)?”的嚴(yán)峻挑戰(zhàn),積極推行土地整理,已成為解決各方土地矛盾,實(shí)現(xiàn)土地資源可持續(xù)利用和保持經(jīng)濟(jì)快速、健康發(fā)展的必然選擇【2】。但是如何在一片山地之中選擇合適的方位與開挖深度,從而使總的土石方量最小,就是一個(gè)有意義的命題了!1.2問(wèn)題提出某工廠為了在一片長(zhǎng)度為1500米,寬度為1000米的山地之中,開挖出一個(gè)800米×600米平坦連續(xù)的長(zhǎng)方形地塊作為工廠的廠房地基,前期已經(jīng)在本塊土地上測(cè)量出長(zhǎng)、寬每隔30米的網(wǎng)格的對(duì)應(yīng)網(wǎng)格點(diǎn)的海拔高度(詳細(xì)數(shù)據(jù)見附件(1))。問(wèn)題:①用附件(1)中的數(shù)據(jù)畫出工廠的這片土地的三維圖形與等高線圖;②從什么地方,什么海拔高度平整一塊800米×600米的連片土地能使總的土石方量最小?③如果允許平整出來(lái)的土地為二層的臺(tái)階狀地塊,要求各地塊的長(zhǎng)、寬不少于60米,又將從什么地方、什么海拔高度分別開挖,能使總的土石方量最小?Ⅱ問(wèn)題分析2.1問(wèn)題一分析我們可以利用MATLAB軟件直接調(diào)用surf函數(shù)和contour函數(shù)分別畫出這片土地的三維圖形和等高線圖。2.2問(wèn)題二分析考慮要平整一塊800米×600米的連片土地,且要使土石方量最小,我們需要確定這塊800米×600米的連片土地的底面投影區(qū)域,以及海拔高度,使得其土石方量最小。對(duì)于指定底面是800米×600米大小區(qū)域內(nèi),在內(nèi)平移,取海拔的高度做方差,如果方差最小,說(shuō)明這片區(qū)域比較平坦,挖土或填土的土石方量近似最小。我們可以通過(guò)這個(gè)思路求出連片地的底面投影區(qū)域,即為求出滿足海拔方差值最小的底面位置的問(wèn)題。確定連片地的底面投影區(qū)域后,再通過(guò)散點(diǎn)法在施工場(chǎng)地計(jì)算高程,挖填土方量等因素,綜合協(xié)調(diào)的處理,從而達(dá)到土方運(yùn)輸量最小。而土方工程量的計(jì)算,采用散點(diǎn)法。一般來(lái)說(shuō),只要基本按照自然地形的變化選取合適的特征點(diǎn),將自然地形在某一方向上的變化簡(jiǎn)化為相似的折線變化,再求出折線與設(shè)計(jì)線之間的面積乘以高度,即可求得體積。2.3問(wèn)題三分析對(duì)于底面是800米×600米大小的為二層的臺(tái)階狀土地,均分為兩塊,取任意一塊在內(nèi)平移,取海拔的高度做方差,如果方差最小,說(shuō)明這片區(qū)域比較平坦,挖土或填土的土石方量近似最小。在確定一塊連片地后,在其四周取另一塊連片地,并使其海拔高度方差最小。Ⅲ模型假設(shè)在平整單元內(nèi)無(wú)土方進(jìn)出;只考慮800米×600米的連片土一種放置位置(見附錄1);假設(shè)所求海拔即為連片地海拔高度的平均值;假設(shè)臺(tái)階高度沒(méi)有要求。Ⅳ符號(hào)說(shuō)明符號(hào)說(shuō)明連片土地平均高程實(shí)測(cè)的各點(diǎn)高程應(yīng)側(cè)區(qū)域的測(cè)點(diǎn)數(shù)挖方區(qū)的平均挖深填方區(qū)平均填高大于平均高程的各實(shí)測(cè)點(diǎn)的高程小于平均高程的各實(shí)測(cè)點(diǎn)的高程大于平均高程的測(cè)點(diǎn)數(shù)小于平均高程的測(cè)點(diǎn)數(shù)挖方量填方量挖方的面積填方的面積Ⅴ模型建立4.1問(wèn)題一模型1.通過(guò)MATLAB7.0編程(程序見附錄:2),畫出這片土地的三維圖如下:圖1山地三維圖2.這片土地等高線圖如下:圖2土地三維等高線圖3土地二維等高線4.2問(wèn)題二模型在山地內(nèi),指定底面是800米×600米大小的連片地(圖4),并將連片地在山地內(nèi)平移(只考慮一種放置位置),并計(jì)算海拔高度的方差,如果方差最小,說(shuō)明這片區(qū)域比較平坦,挖土或填土的土石方量近似最小。圖4連片地放置根據(jù)地形情況布置測(cè)量點(diǎn),考慮到計(jì)算的精確程度應(yīng)在的場(chǎng)地四邊的最高點(diǎn)、最低點(diǎn)、次高點(diǎn)、次低點(diǎn)以及一切能代表不同高程的各個(gè)位置上都均勻布置測(cè)點(diǎn),將測(cè)點(diǎn)高程求算術(shù)平均值,此平均值即為設(shè)計(jì)的地面平均高程,計(jì)算公式為:在平整單元無(wú)土方進(jìn)出的條件下,根據(jù)挖填平衡,可由下面的方程組【3】分別求得挖填方面積:挖方面積:填方面積:將各實(shí)測(cè)點(diǎn)高程與平均高程相比較,大于平均高程的為挖方,小于平均高程的為填方,等于平均高程的表示不挖不填。以此算出各點(diǎn)高程與平均高程的差值,并算出總挖深、總填高??偼谏睿嚎偺罡撸和诜搅浚禾罘搅浚?.3問(wèn)題三模型建立將臺(tái)階狀土地均分為兩片土地,取任意一塊在內(nèi)平移,取海拔的高度做方差,如果方差最小,說(shuō)明這片區(qū)域比較平坦,挖土或填土的土石方量近似最小。在確定一塊連片地后,在其四周取另一塊連片地,并使其海拔高度方差最小??紤]到第一塊連片地放置位置不同,對(duì)第二塊連片地的選取會(huì)有影響,所以第一塊連片地的放置有兩種情況(圖5).4004006001500100040040060015001000圖5第一塊土地兩種放置位置Ⅵ模型求解5.1問(wèn)題一模型求解通過(guò)MATLAB7.0編程(程序見附錄2),畫出這片土地的三維圖。5.2問(wèn)題二模型求解通過(guò)MATLAB7.0編程(程序見附錄3)求出在此數(shù)據(jù)區(qū)域(x=0:600,y=690:1500)內(nèi),平均海拔為12.095,海拔高度方差最小為8.4913,即:所挖填的土石方量最小。再通過(guò)Excel和散點(diǎn)法求得最小的土石方量為:。5.3問(wèn)題三模型求解通過(guò)MATLAB7.0編程(程序見附錄4)求出在此區(qū)域(x=210:810,y=750:1150)內(nèi),平均海拔為5.095,海拔高度方差最小為5.6813,最小挖土量為:。再確定第一塊連片地后,只需在A、B處(圖6)分別計(jì)算第二塊連片的海拔方差,取最小值即可。A處海拔方差:7.6070B處海拔方差:10.8042A處海拔方差小于B處海拔方差,取A處為第二塊連片地位置,此處最小挖土量為:.8。圖6第一塊連片地位置600600400AB圖7AB位置Ⅶ模型評(píng)價(jià)與改進(jìn)模型的優(yōu)點(diǎn)在于對(duì)原始數(shù)據(jù)進(jìn)行整合時(shí),使用MATLAB軟件描述山地的三維圖形和等高線圖形,在此基礎(chǔ)上可以得到具有很高的擬合度和適度性。對(duì)模型的進(jìn)一步討論便可以得到一系列可靠而實(shí)用的信息,所得結(jié)論與客觀事實(shí)很好地吻合,從而進(jìn)一步說(shuō)明模型是合理的。在解決合理開挖土地的問(wèn)題中,通過(guò)土石方量費(fèi)用最小的原則,確定平整土地的開挖位置和開挖高度。模型的缺點(diǎn)在于在建立模型時(shí),只考慮了連片地的一種位置,偶然性較大,且不能得到大規(guī)模推廣。在確定開挖位置時(shí)可以采用枚舉法,具體思路如下:將平整塊區(qū)域投影到底面(XOY平面),確定開挖方向,即要確定平整塊的底面位置。顯然底面是800米×600米的矩形,假設(shè)矩形的四個(gè)頂點(diǎn)分別為A、B、C、D。山地是長(zhǎng)度為1500米,寬度為900米的矩形區(qū)域,因此平整塊底面投影矩形ABCD可以在1500×900的區(qū)域范圍內(nèi)任意移動(dòng),四個(gè)頂點(diǎn)不能超出這個(gè)范圍我們要取遍所有可能的位置,必須枚舉所有的可能值。參考文獻(xiàn)[1]劉富民,土地整治中土方量測(cè)量及計(jì)算方法比較研究,科技信息,2012年3期,2012。[2]馮忠江,張艷東,張磊,淺談土地整理項(xiàng)目中的土地平整問(wèn)題,河北:資源與產(chǎn)業(yè),2005.5。[3]江平,周連,何申泰,卓犖,土地整理中土地平整工程中的若干方法討論,國(guó)土資源管理,2007年5期,2007。附錄附錄1:附錄2:x=0:30:1500;y=0:30:900;[x1,y1]=meshgrid(x,y)z=[1.291.291.471.691.861.942.052.312.6833.123.183.363.673.873.723.342.982.822.853.023.223.263.012.592.131.751.471.320.921.031.231.491.812.112.282.262.121.991.982.092.342.612.712.572.352.232.192.11.881.621.291.291.471.691.861.942.052.312.6833.123.183.363.673.873.723.342.982.822.853.023.223.263.012.592.131.751.471.320.921.031.231.491.812.112.282.262.121.991.982.092.342.612.712.572.352.232.192.11.881.621.291.291.471.691.861.942.052.312.6833.123.183.363.673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