C語言程序設(shè)計(何欽銘)課后習題作業(yè)

1、精選優(yōu)質(zhì)文檔-傾情為你奉上第一章習題1、對C語言來說，下列標示符中哪些是合法的，哪些是不合法的 Total, _debug, LargeTall, Counter1, begin_ 答：合法的：_debug、Counter1、begin_。 不合法的：Total、LargeTall。2、改寫節(jié)中的流程圖，求1100中能被6整除的所有整數(shù)的和。Sum=0,i=1I<=100I能被6整除sum=sum+ii=i+1真假打印sum3、改寫節(jié)中的程序，求1100中能被6整除的所有整數(shù)的和，并在編程環(huán)境中驗證該程序的運行結(jié)果。 答：程序為：#include<>int main(void

2、)int i,sum=0;for(i=1;i<=100;i+)if(i%6=0)sum=sum+i;printf("sum=%dn",sum);return 0;4、對于給定的整數(shù)n（n>1），請設(shè)計一個流程圖判別n是否為一個素數(shù)（只能被1和自己整除的整數(shù)），并分析該流程圖中哪些是順序結(jié)構(gòu)、哪些是分支結(jié)構(gòu)和循環(huán)結(jié)構(gòu)。開始結(jié)束輸入ni=2r=n/i的余數(shù)r=0i=i+1i>=(n-1)輸出n“是素數(shù)”輸出n“不是素數(shù)”假真真假開始結(jié)束輸入ni=2r=n/i的余數(shù)r=0i=i+1i>=(n-1)輸出n“是素數(shù)”輸出n“不是素數(shù)”假真真假第二章作業(yè)1編寫程

3、序，輸入兩個整數(shù)num和num2，計算并輸出她們的和、差、積、商。答：程序：#include<> void main()int num1,num2,y1,y2,y3,y5;double y4;printf("請輸入兩個數(shù)：num1,num2n");scanf("%d%d",&num1,&num2);y1=num1+num2;y2=num1-num2;y3=num1*num2;y4=num1*num2;y5=num1%num2;printf("num1,num2和y1=%dnnum1,num2差y2=%dnnum1,n

4、um2積y3=%dnnum1,num2商y4=%lfnnum1,num2余y5=%dn",y1,y2,y3,y4,y5); 2為了倡導居民節(jié)約用電，某省電力公司執(zhí)行“階梯電價”，安裝一戶一表的居民用戶電價分為兩個“階梯”：月用電量50千瓦時以內(nèi)的，電價為元/千瓦時；超出50千瓦時的用電量，電價上調(diào)元/千瓦時。編寫程序，輸入用戶的月用電量（千瓦時），計算并輸出該用戶應支付的電費（元）。答：程序：#include<> void main()double x,y;printf("請輸入月用電量：xn");scanf("%lf",&

5、x);if(x<=50)y=*x;printf("電費y=%lfn",y);else y=*x;printf("應支付電費y=%lfn",y); 3編寫程序，輸入實數(shù)x和正整數(shù)n，計算xn,不允許調(diào)用pow（）函數(shù)求冪。答：程序：#include<> void main() double x,power; int i,n;printf("請輸入：x,nn");scanf("%lf%d",&x,&n);power=;for(i=1;i<=n;i+)power=power*x;p

6、rintf("power（x,n）=%lfn",power);4編寫程序，輸入兩個正整數(shù)m和n，求（i2+1/i）（i從m到n。）答：程序：#include<>void main()int i,m,n;double sum;sum=0;printf("input:m,nn");scanf("%d%d",&m,&n);for(i=m;i<=n;i+)sum=sum+(i*i+i);printf("sum=%lfn",sum);5編寫程序，輸入一個正整數(shù)n，計算1-2/3+3/5-4/

7、7+5/9-6/11+的前n項之和。答：程序：#include<>void main()int i,n;double sum,item,flag;flag=1;sum=0;printf("input:nn");scanf("%d",&n);for(i=1;i<=n;i+)item=(flag*i)/(2*i-1);flag=-flag;sum=sum+item;printf("sum=%lfn",sum);6某用戶為購房辦理商業(yè)貸款，選擇了按月等額本息還款法，計算公式如下，在貸款本金（loan）和月利率（ra

8、te）一定的情況下，住房貸款的月還款（money）取決于還款月數(shù)（month）?？蛻舸蛩阍?30年的范圍內(nèi)選擇還清貸款的年限，想得到一張“還款年限月還款額表”以供參考。編寫程序，輸入貸款本金loan和月利率rate，輸出“還款年限月還款額表”，還款年限的范圍是530年，輸出時分別精確到年和元。Money=loan*rate(1+rate)month/(1+rate)month-1答：程序：#include<>#include<>void main()int lower,upper,month,year,loan;double money,rate;lower=5;upp

9、er=30;printf("請輸入貸款本金:loann");scanf("%d",&loan);printf("請輸入月利率:raten");scanf("%lf",&rate);printf("還款年限t月還款額n");for(year=lower;year<=upper;year+)month=year*12;money=(loan*rate*pow(1+rate),month)/(pow(1+rate),month)-1);printf("%dtt%lfn&

10、quot;,year,money);7編寫程序，輸入一個正整數(shù)n，求2i（i從1到n），可調(diào)用pow（）函數(shù)求冪。答：程序：#include<>#include<>void main()int i,n;double sum,item;sum=0;printf("input:nn");scanf("%d",&n);for(i=0;i<=n;i+)item=pow(2,i);sum=sum+item;printf("sum=%lfn",sum);8編寫程序，輸入一個正整數(shù)n，求e=i!（i從0到n）。

11、要求定義和調(diào)用函數(shù)fact(n)計算n!，函數(shù)類型是double.答：程序：#include<>double fact(int n);void main()int i,n;double sum;sum=0;printf("input:nn");scanf("%d",&n);for(i=0;i<=n;i+)sum=sum+fact(i);printf("sun=%lfn",sum);double fact(int n)int i;double product;product=;for(i=1;i<=n;i

12、+)product=product*i;return product;第三章作業(yè)1.#include<>#include<>void main()int a,b,c;double s,area,perimeter;printf("請輸入三角形三條邊：a,b,cn");scanf("%d%d%d",&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a)perimeter=a+b+c;s=(a+b+c)/;area=sqrt(s*(s-a)*(s-b

13、)*(s-c);printf("三角形的周長perimeter=%.2lfn三角形的面積area=%.2lfn",perimeter,area);2、#include<>#include<>void main()double salary,tax,rate;printf("請輸入職工的月薪：salaryn");scanf("%lf",&salary);if(salary<=850) rate=0;else if(salary<=1350) rate=5;else if(salary<=

14、2850) rate=10;else if(salary<=5850) rate=15;else rate=20;tax=rate*(salary-850)/100;printf("職工應繳個人所得稅tax=%.2lfn",tax);3、#include<>void main()double m,n,y;printf("請輸入行駛里程(公里)：mn等待時間(分鐘)：nn");scanf("%lf%lf",&m,&n);if(m+n/<=3) y=10;else if(m+n/<=10) y

15、=2*(m+n/;else y=2*10+3*(m+n/;printf("乘客應付車費y=%dn",(int)(y*10+/);4、#include<>void main()int i,n,A,B,C,D,E;double score,total;printf("請輸入一個數(shù)n：n");scanf("%d",&n);total=0;A=0;B=0;C=0;D=0;E=0;for(i=1;i<=n;i+)printf("請輸入第#%d個學生成績：n",i);scanf("%lf&q

16、uot;,&score);total=total+score;if(score>=90)A+;else if(score>=80)B+;else if(score>=70)C+;else if(score>=60)D+;else E+;printf("平均成績=%lfn",total/n);printf("等級成績個數(shù)：nA=%dnB=%dnC=%dnD=%dnE=%dn",A,B,C,D,E);5、#include<>void main()int year;printf("21世紀所有的閏年：n&q

17、uot;);for(year=2000;year<3000;year+)if(year%4=0&&year%100!=0|year%400=0)printf("%dn",year);第四章作業(yè)2、#include""#include""double fact(int n);void main()int i,n;double x,s;printf("請輸入一個實數(shù)x:n");scanf("%lf",&x);s=0;i=1;while(pow(x,i)/fact(i)&

18、gt;=s=pow(x,i)*fact(i)+s;i+;printf("s=%.2lfn",s);double fact(int n)int i;double result;result=1;for(i=1;i<=n;i+)result=result*i;return result;3、#include""int main(void)int x,a,count,sum;printf("請輸入一個整數(shù)x:n");scanf("%d",&x);sum=0;count=0;if(x<0) x=-x;d

19、oa=x%10;sum=sum+a;x=x/10;count+;while(x!=0);printf("位數(shù)=%dn",count);printf("各個位數(shù)之和為:%dn",sum);return 0;5、#include""void main()int a,n,i=1,s=0,t=0;printf("請輸入兩個正整數(shù)a,n=:n");scanf("%d%d",&a,&n);while(i<=n)t=t+a;s=s+t;a=a*10;+i;printf("a+a

20、a+aaa+aaa=%dn",s);7、#include""void main()int i,j,k,l,n;printf("1-10000之間的水仙花數(shù)有:n");for(n=10;n<10000;n+)i=n/1000;j=n/100%10;k=n/10%10;l=n%10;if(i*1000+j*100+k*10+l=i*i*i+j*j*j+k*k*k+l*l*l)printf("%-5d",n);printf("n");9、#include""#include"

21、"void main()int i,n,m,j,k;i=0;printf("請輸入一個多位整數(shù):n");scanf("%d",&n);k=n;while(k!=0)i+;k=k/10;k=n;m=pow(10,i-1);printf("逐位輸出：%d",n/m%10);printf(",");for(j=m/10;j>0;j=j/10)n=k/j;printf("%d",n%10);if(j!=1)printf(",");11、#include&quo

22、t;"void main()int p,r,n,m,temp;printf("請輸入兩個正整數(shù):n");scanf("%d%d",&n,&m);if(n<m) temp=n;n=m;m=temp;p=n*m;while(m!=0)r=n%m; n=m;m=r;printf("最大公約數(shù)為:%dn",n);printf("最小公倍數(shù)為:%dn",p/n);13、#include""void main()int i,j;for(i=0;i<=3;i+)for(j

23、=0;j<=2-i;j+)printf(" ");for(j=0;j<=2*i;j+)printf("*");printf("n"); for(i=0;i<=2;i+)for(j=0;j<=i;j+)printf(" ");for(j=0;j<=4-2*i;j+)printf("*");printf("n"); 第五章1.#include<>#include <>long fac(int n,int a)long sum;

24、if(n=1)sum=a; else sum=(long)(pow(10,n-1)*a)+fac(n-1,a);return(sum);main()int a,n,i;long temp,sum=0;printf("請輸入一個數(shù)a,nn");scanf("%d%d",&a,&n); for(i=1;i<=n;i+) temp=fac(i,a); sum+=temp; printf("它們的和是=%ld",sum); return 0; 2.#include<>int countdight(int nu

25、mber,int dight);int main(void)int number;printf("輸入一個數(shù):");scanf("%d",&number);countdight(number,2);return 0;countdight(int number,int dight)int a,count;count=0;while(number!=0)a=number%10;number=number/10;if(a=dight)count+;printf("%dn",count);return count;3.#include

26、<>int fib(int n);int main(void)int m,n,num1;num1=1;printf("請輸入兩個正整數(shù)m和n(m>=1,n<=10000)n");scanf("%d%d",&m,&n);if(num1>=m&&num1<=n)fib(n);return 0;int fib(int n)int i,x1,x2,x,t;x1=1;x2=1;for(i=0;i<n;i+)x=x1+x2;printf("%5d",x);t=x;x1=x2

27、;x2=t;printf("n");return x;5. #include<>void is(int num);int main(void)int n,m,num1;num1=1;printf("輸入兩個數(shù)m和n(m>=1,n<=1000)n");scanf("%d%d",&m,&n);if(num1>=m&&num1<=n)is(num1);return 0;void is(int num)int i,j,k;for(num=1;num<1000;num+)

28、i=num/100;j=num/10%10;k=num%10;if(i*100+j*10+k*1=i*i*i+j*j*j+k*k*k)printf("%5d",num);printf("n");6.#include<>int reverse(int number);int main(void)int x;printf("請輸入一個正整數(shù):n");scanf("%d",&x);reverse(x);return 0;int reverse(int number)while(number!=0)pr

29、intf("%d",number%10);number=number/10;printf("n");return number;第七章作業(yè)1.#include<>void main() int i,j=0,k=0,n,p,q,max,min; int a10; printf("請輸入n(1<n<10)的值: n");scanf("%d",&n);printf("請輸入%d個數(shù): n",n);for(i=0;i<n;i+)scanf("%d"

30、;,&ai);min=a0;max=a9;if(ai<min)min=ai;k=i;if(ai>max)max=ai;j=i;p=a9;a9=aj;aj=p;q=a0;a0=ak;ak=q;for(i=0;i<n;i+)printf("%8d",ai);printf("n");4.#include<>int main(void)int m,n,i,j,sum;int a66,x80;printf("請輸入m,n(1<=m,n<=6)的值: n");scanf("%d%d&qu

31、ot;,&m,&n);printf("請輸入%d個數(shù): n",m*n);for(i=0;i<m;i+)for(j=0;i<n;j+)scanf("%d",&aij);for(i=0;i<m;i+)for(j=0;j<n;j+)printf("%4d",aij);printf("n");for(i=0;i<m;i+)sum=0;for(j=0;j<n;j+)sum=sum+aij;xi=sum;for(i=0;i<m;i+)printf("%

32、dn",xi);return 0;5.#include<>void main()int a33,max,max1,max2,i,j,flag=1;printf("請輸入9個數(shù): n");for(i=0;i<=2;i+)for(j=0;j<=2;j+)scanf("%d",&aij);for(i=0;i<=2;i+)max=ai0;for(j=0;j<=2;j+)if(aij>max)max=aij;max1=j;for(max2=0;max2<=2;max2+)if(max>amax

33、1max2)flag=0;break;if(flag=1) printf("鞍點是 %dn",amax2max1); if(flag=0) printf("no numbern");flag=1;8.#include<>#include<>int main(void)int i,n;char s80;printf("請輸入n(n<80)的值: n");scanf("%d",&n);printf("請輸入%d個字符: n",n);for(i=0;i<n;

34、i+)scanf("%s",s);for(i=0;si!='0'i+)if(si>='A'&&si<='Z')si=155-si;for(i=0;si!='0'i+)putchar(si);printf("n");return 0;#include<>#include<>int main(void) int i, n; char f,s80;printf("Enter a string: "); /*輸入字符串*/i =

35、 0;while(si = getchar( ) != 'n') i+; si = '0'n = 0;for(i = 0; si != '0' i+)if(si <= 7f&& si >= 20)si=si+;elsebreak; for(i = 0; si != '0' i+)putchar(si);return 0; 第八章作業(yè)1.#include<>int main(void)char ch;int a10;int i,j,temp;printf("請輸入10個整數(shù):n&qu

36、ot;);for(i=0;i<10;i+)scanf("%d",&ai);printf("請輸入A或D:");scanf(" %c",&ch);if(ch='A')for(i=0;i<9;i+)for(j=i+1;j<10;j+)if(ai>aj)temp=ai;ai=aj;aj=temp;for(i=0;i<10;i+)printf("%dn",ai);else if(ch='D')for(i=0;i<9;i+)for(j=i+1

37、;j<10;j+)if(ai<aj)temp=ai;ai=aj;aj=temp;for(i=0;i<10;i+)printf("%dn",ai);return 0;5.#include<>#include<>void mcopy(char *s,int m);int main(void) int i,m,l;char str100;printf("請輸入您要輸入的字符串:");gets(str);printf("您將從原字符串的第m位復制新字符串，請輸入m:n");scanf("%d

38、",&m);printf("復制后，新的字符串為:"); mcopy(str,m);return 0;void mcopy(char *s,int m)printf("%sn",s+m-1);11.#include<>#include<>void fushu(char *p);int main(void)char str80;printf("請輸入一個英語名詞單詞:");scanf("%s",str); fushu(str);puts(str);return 0;void

39、fushu(char *p) int i,l;l=0;for(i=0;*(p+i)!='0'i+)l+;if(*(p+l-1)='y')*(p+l)='e'*(p+l+1)='s'*(p+l+2)='0'else if(*(p+l-1)='s')|(*(p+l-1)='x')|(*(p+l-2)='c')&&(*(p+l-1)='h')|(*(p+l-2)='s')&&(*(p+l-1)='h&#

40、39;)*(p+l)='e'*(p+l+1)='s'*(p+l+2)='0'else if(*(p+l-1)='o')*(p+l)='e'*(p+l+1)='s'*(p+l+2)='0'else*(p+l)='s'*(p+l+1)='0'12.#include<>#include<>int main(void)int i,j,a,n,sum,avg;int *p;printf("Enter n:");scan

41、f("%d",&n);if(p=(int*)calloc(n,sizeof(int)=NULL)printf("Not able to allocate memory.n");exit(1);printf("請輸入%d個學生的成績:n",n);for(i=0;i<n;i+)scanf("%d",p+i);sum=0;for(i=0;i<n;i+)sum=sum+*(p+i);avg=sum/n;for(i=0;i<n-1;i+)for(j=i+1;j<n;j+)if(*(p+i)&g

42、t;*(p+j)a=*(p+i);*(p+i)=*(p+j);*(p+j)=a;printf("學生的平均成績是:%dn",avg);printf("學生的最高成績是:%dn",*(p+n-1);printf("學生的最低成績是:%dn",*p);return 0;第九章作業(yè)1.#include<>structint hour,minute,second;time;int main(void)scanf("%d:%d:%d",;+;if=60)+;=0;if=60)+;=0;if=24)=0;print

43、f("%d:%d:%d",;return 0;2.struct s1char c1,c2;int n;struct s2int n; struct s1 m;int main(void)printf("nt%dt%dt%cn",return 0;8.#include<>#define N 10struct personchar num10;char name20;double jbgz,jj,zc,sfgz;struct person gzN;int main() int i,index;printf("請輸入%d名工人的基本信息：

44、n", N);for(i=0;i<N;i+)printf("請輸入第%d名工人的基本信息：n",i+1);scanf("%s%s%lf%lf%lf",gzi.num,,&gzi.jbgz,&gzi.jj,&gzi.zc);printf("%d名工人的基本信息：n",N);printf("編號t姓名t基本工資t獎金t支出t實發(fā)工資n");for(i=0;i<N;i+)printf("%st%st%.2lftt%.2lft%.2lft%.2lfn",gzi.num,,gzi.jbgz,gzi.jj,gzi.zc,gzi.sfgz=gzi.jbgz+gzi.jj-gzi.zc);in